7.2 NAC Voltage-Drop Calculations & End-of-Line Verification

Key Takeaways

  • The total circuit loop resistance formula is R_loop = 2 * L * (R_kft / 1000), where the factor of 2 accounts for the complete out-and-back conductor circuit.
  • Per NEC Chapter 9 Table 8, direct-current resistance values for uncoated copper at 75°C are 3.14 ohms/kft for 14 AWG stranded (3.07 ohms solid) and 1.98 ohms/kft for 12 AWG stranded (1.93 ohms solid).
  • Under UL 864 and UL 1971, notification appliances must operate reliably down to 16.0V DC (or 85% of nominal 20.4V DC FWR cutoff) under worst-case secondary battery conditions.
  • The lump-sum calculation method assumes the entire circuit current is concentrated at the furthest appliance, providing a fast and conservative worst-case verification.
  • The point-to-point method models segment-by-segment voltage drops as current diminishes past each appliance, accurately demonstrating that actual voltage drop is roughly half that of the lump-sum estimate.
Last updated: September 2026

7.2 NAC Voltage-Drop Calculations & End-of-Line Verification

Core Overview: Notification Appliance Circuits (NACs) must deliver sufficient electrical potential to the furthest appliance on the circuit to ensure listed audible sound pressure and visual candela outputs. An excessive voltage drop across field wiring causes strobes to flash out of synchronization, horns to sound at degraded decibel levels, or appliances to shut down entirely. Engineering technologists must calculate loop resistance using National Electrical Code (NEC Chapter 9, Table 8) conductor properties, model circuit topologies under lump-sum and point-to-point methods, and verify that the end-of-line voltage never falls below the UL 864 mandatory cutoff of 16.0V DC.


Ohm's Law and Circuit Loop Resistance

Voltage drop ($V_{\text{drop}}$) represents the potential lost across the circuit conductors due to conductor resistance when current flows through the circuit. In direct-current (DC) circuits, Ohm's law governs this behavior:

V_drop = I_circuit * R_loop

Where:

  • $I_{\text{circuit}}$ = Total current flowing through the circuit in Amperes (A)
  • $R_{\text{loop}}$ = Total resistance of both the positive and negative conductors combined in Ohms ($\Omega$)

The Out-and-Back Multiplier of 2

A critical rule in fire alarm circuit calculations is accounting for the complete closed circuit loop. Current leaves the power supply terminal, travels through the outgoing positive conductor, passes through the appliances, and returns through the negative conductor. Therefore, the conductor path length is twice the one-way physical raceway length:

R_loop = 2 * L * ( R_per_1000_ft / 1000 )

Where:

  • $L$ = One-way circuit distance from the power supply to the load in feet
  • $2$ = Conductor pair multiplier (outgoing feed conductor + return conductor)
  • $R_{\text{per_1000_ft}}$ = Conductor direct-current resistance in Ohms per 1,000 feet ($\Omega / 1000$ ft)
   +--- [ FACU (+) Terminal ] -----( Outgoing Conductor: Length L )-----> [ Appliance ]
   |                                                                          |
[24VDC]                                                                    [Load]
   |                                                                          |
   +--- [ FACU (-) Terminal ] <----( Return Conductor: Length L )------- [ Appliance ]
         Total Resistance R_loop = R_outgoing + R_return = 2 * L * (R_kft / 1000)

Conductor Properties per NEC Chapter 9, Table 8

The National Electrical Code (NFPA 70, Chapter 9, Table 8) establishes standardized direct-current (DC) resistance values for uncoated copper conductors. In commercial fire alarm engineering, resistance values at 75°C (167°F) are universally mandated. Using 75°C resistance values accounts for elevated ambient temperatures within conduits, ceiling spaces, and structural cavities during a fire condition.

Conductor Size (AWG)Solid Uncoated Copper Resistance ($\Omega$ / 1,000 ft at 75°C)Stranded Uncoated Copper Resistance ($\Omega$ / 1,000 ft at 75°C)Cross-Sectional Area (Circular Mils)
18 AWG7.77 $\Omega$8.08 $\Omega$1,620 cmil
16 AWG4.89 $\Omega$4.99 $\Omega$2,580 cmil
14 AWG3.07 $\Omega$3.14 $\Omega$4,110 cmil
12 AWG1.93 $\Omega$1.98 $\Omega$6,530 cmil
10 AWG1.21 $\Omega$1.24 $\Omega$10,380 cmil

[!NOTE] Solid vs. Stranded Conductor Discrepancy: Notice that stranded wire consistently exhibits a higher electrical resistance than solid wire of the identical AWG gauge (e.g., $3.14\ \Omega$ vs $3.07\ \Omega$ for 14 AWG). This occurs because the spiral lay of individual strands increases the true physical path length of the copper per linear foot of finished cable assembly. When designing with stranded FPLP/FPLR cable, always use the stranded resistance values from Table 8.


Supply Voltage Baselines & UL 864 Operating Thresholds

A frequent source of design error is calculating voltage drop starting from nominal 24.0V DC or from a 27.6V DC float charge. Fire alarm systems must function reliably during total power failure when the system is operating at the tail end of its secondary battery discharge cycle.

+-------------------------------------------------------------------------+
|                   VOLTAGE THRESHOLDS & OPERATING LIMITS                 |
|                                                                         |
|   27.6V DC  -- AC Normal Float Voltage (Battery Charging)              |
|   24.0V DC  -- Nominal Rated System Voltage                            |
|   20.4V DC  -- MANDATORY STARTING BASELINE (UL 864 Battery Cutoff)     |
|        |                                                                |
|        |    MAXIMUM PERMITTED VOLTAGE DROP = 4.4V DC                    |
|        v                                                                |
|   16.0V DC  -- MINIMUM ALLOWABLE END-OF-LINE VOLTAGE (UL 864 / UL 1971)|
|        |                                                                |
|   < 16.0V   -- NON-COMPLIANT (Strobe sync fail, horn decibel drop)     |
+-------------------------------------------------------------------------+

The 20.4V DC Battery Cutoff Baseline

Under UL 864 (Standard for Control Units and Accessories for Fire Alarm Systems, 10th edition), a nominal 24V storage battery bank consisting of two sealed lead-acid batteries (12 cells total) discharges to a final terminal voltage of 1.70 volts per cell at the conclusion of its 24-hour standby period:

V_source_baseline = 12 cells * 1.70 V/cell = 20.4V DC

The 16.0V DC Minimum Appliance Threshold

Under UL 1971 (Signaling Devices for the Hearing Impaired) and UL 464 (Audible Signaling Appliances), notification appliances listed for "Regulated 24V DC" must maintain their rated candela light output and sound pressure levels across an operating envelope of 16.0V DC to 33.0V DC.

Maximum Permissible Circuit Voltage Drop

By subtracting the minimum appliance operating voltage from the battery cutoff baseline, we establish the maximum voltage drop permissible across any notification appliance circuit:

V_drop_maximum = 20.4V DC - 16.0V DC = 4.4V DC

If the total calculated voltage drop on a NAC exceeds 4.4V DC, the voltage at the last appliance will drop below 16.0V DC under battery backup, violating NFPA 72 and UL 864.


Calculation Methodologies: Lump-Sum vs. Point-to-Point

Technologists utilize two distinct mathematical methodologies to evaluate NAC voltage drop: the Lump-Sum Method and the Point-to-Point (Distributed Load) Method.

LUMP-SUM METHOD (CONSERVATIVE WORST-CASE):
[FACU 20.4V] -----------------------------------------------------> [ALL 10 LOADS AT END]
             <------------------- Length L = 400 ft -------------->   (Current = 1.50A)
* Entire current travels entire 400 ft distance. High calculated drop (3.77V).

POINT-TO-POINT METHOD (DISTRIBUTED REALITY):
[FACU 20.4V] ---(1.50A)---> (Dev 1) ---(1.35A)---> (Dev 2) ---> ... ---> (Dev 10: 0.15A)
             |- 40 ft -|            |- 40 ft -|                           (EOLR)
* Current decreases after each appliance. True calculated drop is roughly 50% lower (2.07V).

1. The Lump-Sum Method

The lump-sum method assumes that the entire cumulative current of all connected appliances travels the full length of the circuit to the very last appliance.

  • Formula: $V_{\text{drop}} = I_{\text{total}} \times R_{\text{loop_total}}$
  • Characteristics: Extremely fast, simple, and conservative. Because it overestimates the actual voltage drop, any circuit that passes the lump-sum check is guaranteed to pass in the field. However, it often forces designers to unnecessarily up-size conductors from 14 AWG to 12 AWG or install unneeded auxiliary power boosters.

2. The Point-to-Point Method

The point-to-point method models the circuit as a series of discrete wire segments connecting successive appliances. The current flowing through any given segment is only the current required by the appliances located downstream of that segment.

  • Formula: $V_{\text{drop_total}} = \sum_{k=1}^{n} ( I_{\text{segment}k} \times R{\text{segment}_k} )$
  • Characteristics: Reflects true physical behavior. For circuits with uniformly spaced appliances having identical current draws, the actual point-to-point voltage drop can be approximated by: Vdrop_p2pVdrop_lump×(n+12n)V_{\text{drop\_p2p}} \approx V_{\text{drop\_lump}} \times \left( \frac{n + 1}{2n} \right) Where $n$ is the number of appliances. For a 10-appliance circuit, $(10+1)/(20) = 0.55$, meaning the true drop is roughly 55% of the lump-sum estimate!

Step-by-Step Worked Calculation Example

Circuit Specifications

  • Circuit Wiring: 14 AWG uncoated stranded copper ($R = 3.14\ \Omega / 1000$ ft per NEC Chapter 9, Table 8 at 75°C)
  • Total Appliances: 10 wall-mounted horn/strobes, drawing 150 mA (0.150 A) each
  • Total Circuit Current ($I_{\text{total}}$): $10 \times 0.150\text{ A} = \mathbf{1.50\text{ A}}$
  • Total One-Way Length ($L$): 400 feet to the furthest appliance
  • Appliance Spacing: Uniformly distributed every 40 feet along the run
  • Power Source Baseline: 20.4V DC (UL 864 battery cutoff)

Calculation A: Lump-Sum Method Execution

STEP 1: Calculate Total Conductor Loop Length
Loop_Length = 2 * L = 2 * 400 ft = 800 ft

STEP 2: Calculate Loop Resistance (R_loop)
R_loop = Loop_Length * ( R_kft / 1000 )
R_loop = 800 ft * ( 3.14 Ohms / 1000 ft ) = 2.512 Ohms

STEP 3: Calculate Lump-Sum Voltage Drop (V_drop)
V_drop = I_total * R_loop
V_drop = 1.50 A * 2.512 Ohms = 3.768V DC

STEP 4: Calculate End-of-Line Voltage (V_EOL)
V_EOL = V_source - V_drop
V_EOL = 20.40V - 3.768V = 16.632V DC

STEP 5: Verify UL Compliance
16.632V DC >= 16.000V DC  -->  PASS (Complies with UL 864 / UL 1971)
Safety Headroom = 16.632V - 16.000V = +0.632V DC

Calculation B: Point-to-Point Method Execution

Now calculate the identical circuit segment by segment. Each segment has a physical length of 40 feet, giving a segment loop length of $2 \times 40 = 80$ feet.

Segment Loop Resistance Rseg=80 ft×(3.14 Ω1000 ft)=0.2512 Ω\text{Segment Loop Resistance } R_{\text{seg}} = 80\text{ ft} \times \left( \frac{3.14\ \Omega}{1000\text{ ft}} \right) = \mathbf{0.2512\ \Omega}

Segment #Physical SpanDownstream DevicesSegment Current ($I_{\text{seg}}$)Segment Loop Resistance ($R_{\text{seg}}$)Segment Voltage Drop ($\Delta V$)Running Terminal Voltage
Panel0 ft1020.400V
Seg 10 to 40 ft101.50 A0.2512 $\Omega$$1.50 \times 0.2512 = \mathbf{0.3768V}$20.023V
Seg 240 to 80 ft91.35 A0.2512 $\Omega$$1.35 \times 0.2512 = \mathbf{0.3391V}$19.684V
Seg 380 to 120 ft81.20 A0.2512 $\Omega$$1.20 \times 0.2512 = \mathbf{0.3014V}$19.383V
Seg 4120 to 160 ft71.05 A0.2512 $\Omega$$1.05 \times 0.2512 = \mathbf{0.2638V}$19.119V
Seg 5160 to 200 ft60.90 A0.2512 $\Omega$$0.90 \times 0.2512 = \mathbf{0.2261V}$18.893V
Seg 6200 to 240 ft50.75 A0.2512 $\Omega$$0.75 \times 0.2512 = \mathbf{0.1884V}$18.705V
Seg 7240 to 280 ft40.60 A0.2512 $\Omega$$0.60 \times 0.2512 = \mathbf{0.1507V}$18.554V
Seg 8280 to 320 ft30.45 A0.2512 $\Omega$$0.45 \times 0.2512 = \mathbf{0.1130V}$18.441V
Seg 9320 to 360 ft20.30 A0.2512 $\Omega$$0.30 \times 0.2512 = \mathbf{0.0754V}$18.366V
Seg 10360 to 400 ft10.15 A0.2512 $\Omega$$0.15 \times 0.2512 = \mathbf{0.0377V}$18.328V
POINT-TO-POINT TOTAL RESULTS:
Total Cumulative Voltage Drop = Sum of Segments 1-10 = 2.0724V DC
Actual End-of-Line Voltage V_EOL = 20.400V - 2.0724V = 18.328V DC
Verification: 18.328V DC >= 16.000V DC  -->  PASS (Complies with 2.328V Headroom!)

Analytical Comparison

  • Lump-Sum Drop: 3.768V $\rightarrow$ $V_{\text{EOL}} = 16.632\text{V}$
  • Point-to-Point Drop: 2.072V $\rightarrow$ $V_{\text{EOL}} = 18.328\text{V}$
  • Conclusion: The lump-sum method overstated the voltage drop by 1.696V. While the lump-sum method proved compliance, the point-to-point calculation demonstrates that the circuit possesses substantial headroom, allowing the technologist to add more appliances or extend the circuit length without increasing the wire gauge to 12 AWG.

Realistic Exam Traps & NICET Level III Gotchas

Trap 1: Forgetting the Conductor Multiplier of 2

  • The Error: Calculating resistance using only the one-way distance: $R = 400\text{ ft} \times (3.14 / 1000) = 1.256\ \Omega$. This cuts the calculated voltage drop in half (1.88V instead of 3.77V).
  • Code Reality: A circuit is an out-and-back loop. The positive conductor carries current out, and the negative conductor carries current back. Forgetting to multiply distance by 2 will cause a failed installation to appear compliant on paper, leading to field failure during commissioning.

Trap 2: Sizing from Nominal 24.0V Instead of 20.4V Baseline

  • The Error: Subtracting calculated voltage drop from 24.0V: $V_{\text{EOL}} = 24.0\text{V} - 4.2\text{V} = 19.8\text{V}$ ("Passes!").
  • Code Reality: In an actual power outage, the batteries will reach 20.4V DC at the end of 24 hours. The true end-of-line voltage is $20.4\text{V} - 4.2\text{V} = 16.2\text{V}$. If the drop were 4.6V, calculating from 24V would show 19.4V (passing), but the real battery voltage would collapse to 15.8V (failing UL 864).

Trap 3: Solid vs. Stranded Table 8 Selection

  • The Error: Using the solid copper column ($3.07\ \Omega/\text{kft}$) when pulling stranded fire alarm wire ($3.14\ \Omega/\text{kft}$).
  • Code Reality: On marginal long-distance runs, using solid values for stranded cable produces an artificially low resistance calculation that fails inspection when the AHJ audits the design.
Test Your Knowledge

An engineering technologist is performing a lump-sum voltage-drop calculation for a 24VDC Notification Appliance Circuit (NAC) wired with 14 AWG uncoated stranded copper conductors. The circuit serves 8 strobe appliances drawing 120 mA each and extends 350 feet from the control panel to the last appliance. Using NEC Chapter 9 Table 8 (3.14 ohms/1000 ft at 75°C) and establishing the UL 864 battery cutoff baseline of 20.4V DC, what is the calculated voltage at the end-of-line appliance, and does it comply with the UL minimum operating threshold?

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Test Your Knowledge

When contrasting the lump-sum method against the point-to-point (distributed load) method for sizing notification appliance circuits, which statement accurately reflects the engineering distinction and physical behavior of the circuit?

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B
C
D
Test Your Knowledge

Why do fire alarm design engineers and AHJs mandate that NAC voltage-drop calculations use an initial power supply voltage baseline of 20.4V DC rather than nominal 24.0V DC or 27.6V DC float voltage?

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B
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D