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3.3 Number Sequences & Pattern Recognition

Key Takeaways

  • An arithmetic sequence has a constant common difference d = a_n - a_{n-1}, with the n-th term given by a_n = a_1 + (n-1)d.

  • A geometric sequence has a constant common ratio r = a_n / a_{n-1}, with the n-th term given by a_n = a_1 · r^{n-1}.

  • Pattern recognition on the EIAT requires analyzing single-operation, multi-operation (e.g., 2n + 1), and alternating term progression rules.

  • Step-up and step-down transformers utilize integer turns ratios (N_p/N_s) that generate geometric progression voltage levels across multi-tapped windings.

  • Multi-stage electrical load drops and ladder networks follow precise arithmetic or geometric sequences useful for troubleshooting voltage degradation.

Last updated: August 2026

3.3 Number Sequences & Pattern Recognition

Quick Summary: A number sequence is an ordered list of numbers following a systematic mathematical rule. The EIAT heavily tests pattern recognition through arithmetic sequences (constant common difference dd), geometric sequences (constant common ratio rr), multi-operational rules, and alternating progressions. Electricians utilize sequence formulas (an=a1+(n−1)da_n = a_1 + (n-1)d and an=a1⋅rn−1a_n = a_1 \cdot r^{n-1}) to solve practical problems involving transformer voltage step-up/step-down ratios, multi-stage motor starting currents, and ladder resistance networks.


Fundamentals of Number Sequences

A sequence is an ordered set of numbers where each individual number is called a term. Terms are designated by subscripted variables:

a1,a2,a3,a4,…,ana_1, a_2, a_3, a_4, \dots, a_n
  • a1a_1 represents the first term of the sequence.
  • ana_n represents the nn-th term (also called the general term or explicit formula).
  • nn represents the term position index (n=1,2,3,…n = 1, 2, 3, \dots).

Part 1 of the EIAT features numerous number series items. Recognizing sequence structures allows candidates to find missing intermediate terms or extrapolate distant terms efficiently.


Arithmetic Sequences (an=a1+(n−1)da_n = a_1 + (n-1)d)

An arithmetic sequence (or arithmetic progression) is a sequence in which the difference between any two consecutive terms is constant.

The Common Difference (dd)

The constant change between consecutive terms is called the common difference (dd):

d=ak+1−akd = a_{k+1} - a_k
  • If d>0d > 0, the sequence is increasing (e.g., 5,11,17,23,⋯  ⟹  d=+65, 11, 17, 23, \dots \implies d = +6).
  • If d<0d < 0, the sequence is decreasing (e.g., 100,85,70,55,⋯  ⟹  d=−15100, 85, 70, 55, \dots \implies d = -15).

Explicit Formula for the nn-th Term

To find any term ana_n without writing out all preceding terms, use the explicit arithmetic formula:

an=a1+(n−1)da_n = a_1 + (n - 1)d

Derivation Logic

  • a1=a1a_1 = a_1
  • a2=a1+da_2 = a_1 + d
  • a3=a1+2da_3 = a_1 + 2d
  • a4=a1+3da_4 = a_1 + 3d
  • …\dots
  • To reach the nn-th term, you must add the common difference dd exactly (n−1)(n - 1) times to the initial term a1a_1.

Step-by-Step Example: Finding a Large Term

Problem: What is the 30th term of the arithmetic sequence: 11,17,23,29,…11, 17, 23, 29, \dots?

  1. Identify the first term (a1a_1): a1=11a_1 = 11
  2. Calculate the common difference (dd): d=17−11=6(Verify: 23−17=6, 29−23=6)d = 17 - 11 = 6 \quad (\text{Verify: } 23 - 17 = 6, \ 29 - 23 = 6)
  3. Identify the target position (nn): n=30n = 30
  4. Apply the explicit formula: a30=a1+(30−1)da_{30} = a_1 + (30 - 1)d a30=11+(29)×6a_{30} = 11 + (29) \times 6
  5. Perform multiplication before addition: 29×6=(30−1)×6=180−6=17429 \times 6 = (30 - 1) \times 6 = 180 - 6 = 174 a30=11+174=185a_{30} = 11 + 174 = 185

Thus, the 30th term of the sequence is 185.


Geometric Sequences (an=a1⋅rn−1a_n = a_1 \cdot r^{n-1})

A geometric sequence (or geometric progression) is a sequence in which each term after the first is obtained by multiplying the previous term by a constant non-zero number called the common ratio (rr).

The Common Ratio (rr)

r=ak+1akr = \frac{a_{k+1}}{a_k}
  • If r>1r > 1, the sequence exhibits exponential growth (e.g., 3,6,12,24,48,⋯  ⟹  r=23, 6, 12, 24, 48, \dots \implies r = 2).
  • If 0<r<10 < r < 1, the sequence exhibits exponential decay (e.g., 1000,500,250,125,⋯  ⟹  r=0.51000, 500, 250, 125, \dots \implies r = 0.5).
  • If r<0r < 0, the sequence terms alternate in sign (e.g., 5,−15,45,−135,⋯  ⟹  r=−35, -15, 45, -135, \dots \implies r = -3).

Explicit Formula for the nn-th Term

The general term of a geometric sequence is given by:

an=a1⋅rn−1a_n = a_1 \cdot r^{n-1}

Example

To find the 7th term of 2,6,18,54,…2, 6, 18, 54, \dots:

  • a1=2a_1 = 2, r=62=3r = \frac{6}{2} = 3, n=7n = 7.
  • a7=2⋅37−1=2⋅36=2⋅729=1,458a_7 = 2 \cdot 3^{7-1} = 2 \cdot 3^6 = 2 \cdot 729 = 1,458.

Advanced EIAT Pattern Recognition Strategies

EIAT number series questions often extend beyond simple arithmetic or geometric progressions. Test takers must recognize multi-operational, polynomial, and alternating patterns.

1. Two-Step Operational Sequences (an=k⋅an−1+ca_n = k \cdot a_{n-1} + c)

In these patterns, obtaining the next term requires combining two operations—such as multiplying by a constant and adding/subtracting a number.

Step-by-Step Example: Missing Term Identification

Problem: What is the missing number in the sequence: 7,15,31,63,‾,2557, 15, 31, 63, \underline{\quad}, 255?

  1. Analyze term differences:

    • 15−7=815 - 7 = 8
    • 31−15=1631 - 15 = 16
    • 63−31=3263 - 31 = 32 Notice that the differences double each step (8,16,32,…8, 16, 32, \dots).
  2. Formulate the recursive rule:

    • Test multiplication and addition: 7×2+1=14+1=157 \times 2 + 1 = 14 + 1 = 15 15×2+1=30+1=3115 \times 2 + 1 = 30 + 1 = 31 31×2+1=62+1=6331 \times 2 + 1 = 62 + 1 = 63

    The operational pattern is: Multiply the previous term by 2 and add 1.

  3. Calculate the missing term (a5a_5):

    a5=63×2+1=126+1=127a_5 = 63 \times 2 + 1 = 126 + 1 = 127
  4. Verify with the subsequent term (a6=255a_6 = 255):

    127×2+1=254+1=255✓127 \times 2 + 1 = 254 + 1 = 255 \quad \checkmark

The missing number is 127.


2. Perfect Square & Cube Sequences

Check if the sequence terms (or the differences between terms) correspond to squares (n2n^2) or cubes (n3n^3):

  • Pure Squares: 1,4,9,16,25,36,49,…1, 4, 9, 16, 25, 36, 49, \dots
  • Square Differences: 2,3,7,16,32,57,…2, 3, 7, 16, 32, 57, \dots (Differences are 12,22,32,42,52  ⟹  +1,+4,+9,+16,+251^2, 2^2, 3^2, 4^2, 5^2 \implies +1, +4, +9, +16, +25).

3. Interleaved (Alternating) Sequences

Some test questions combine two independent sequences into a single alternating series:

  • Example: 5,50,10,45,15,40,‾,‾5, 50, 10, 45, 15, 40, \underline{\quad}, \underline{\quad}
  • Odd Position Terms (a1,a3,a5,a7a_1, a_3, a_5, a_7): 5,10,15,205, 10, 15, \mathbf{20} (+5+5 progression).
  • Even Position Terms (a2,a4,a6,a8a_2, a_4, a_6, a_8): 50,45,40,3550, 45, 40, \mathbf{35} (−5-5 progression).

Trade Applications: Motor Currents & Transformer Taps

Pattern recognition and sequence formulas directly translate to industrial electrical installations.

Application 1: Reduced-Voltage Motor Start-Up Current Progression

Heavy industrial electric motors draw severe inrush currents during direct-on-line starting. To prevent utility voltage sags, electricians install multi-stage reduced-voltage soft starters or autotransformer starters that step down starting current across sequential timing stages.

An electrician logs motor current draws across 5 starting stages:

  • Stage 1: 321 A321\text{ A}
  • Stage 2: 281 A281\text{ A}
  • Stage 3: 241 A241\text{ A}
  • Stage 4: 201 A201\text{ A}

Analysis

  1. Calculate the common difference (dd): d=281−321=−40 Ad = 281 - 321 = -40\text{ A} 241−281=−40 A241 - 281 = -40\text{ A} 201−241=−40 A201 - 241 = -40\text{ A}
  2. Recognize an arithmetic progression with initial term a1=321 Aa_1 = 321\text{ A} and common difference d=−40 Ad = -40\text{ A}.
  3. Predict the expected Stage 5 current (a5a_5): a5=a4+d=201−40=161 Aa_5 = a_4 + d = 201 - 40 = 161\text{ A} (Using formula: a5=321+(5−1)(−40)=321−160=161 Aa_5 = 321 + (5-1)(-40) = 321 - 160 = 161\text{ A})

Application 2: Multi-Tap Step-Down Transformers

Distribution transformers frequently utilize primary or secondary tap sequences configured in geometric ratios (e.g., ±2.5%\pm 2.5\% and ±5.0%\pm 5.0\% voltage tap steps). Calculating step voltages across multi-tap windings relies on geometric ratio multiplication, allowing electricians to set tap changers accurately under varying line conditions.

Test Your Knowledge

What is the 30th term of the arithmetic sequence: 11,17,23,29,…11, 17, 23, 29, \dots?

A

191

B

185

C

179

D

197

Test Your Knowledge

What is the missing number in the sequence: 7,15,31,63,‾,2557, 15, 31, 63, \underline{\quad}, 255?

A

125

B

127

C

129

D

131

Test Your Knowledge

An electrician notes motor current draws during start-up over 5 stages: Stage 1 = 321 A, Stage 2 = 281 A, Stage 3 = 241 A, Stage 4 = 201 A. What is the expected current at Stage 5?

A

151 A

B

161 A

C

171 A

D

141 A

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