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3.4 Linear Graphs, Slopes & Coordinate Planes

Key Takeaways

  • The slope m = (y_2 - y_1) / (x_2 - x_1) measures the rate of change and steepness of a line on the Cartesian coordinate plane.

  • Slope-intercept form y = mx + b explicitly reveals both the rate of change (m) and the vertical starting value (b).

  • Parallel lines have identical slopes (m_1 = m_2), while perpendicular lines have negative reciprocal slopes (m_1 · m_2 = -1).

  • Horizontal lines have a slope of zero (m = 0), whereas vertical lines have an undefined slope.

  • On a Voltage-Current (V-I) graph, Ohm's law dictates that the slope Delta V / Delta I equals the circuit resistance R in Ohms.

Last updated: August 2026

3.4 Linear Graphs, Slopes & Coordinate Planes

Quick Summary: Coordinate geometry bridges algebraic equations and visual graphs. Linear graphs on the Cartesian coordinate plane depict relationships with a constant rate of change, known as the slope (m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}). Lines are represented using slope-intercept form (y=mx+by = mx + b). Parallel lines share identical slopes (m1=m2m_1 = m_2), while perpendicular lines feature negative reciprocal slopes (m1⋅m2=−1m_1 \cdot m_2 = -1). In electrical circuit analysis, plotting Voltage (VV) against Current (II) produces a linear slope representing circuit Resistance (R=ΔVΔIR = \frac{\Delta V}{\Delta I}), directly demonstrating Ohm's Law.


The Cartesian Coordinate System

The Cartesian coordinate plane is formed by two perpendicular number lines that intersect at a central point called the origin (0,0)(0, 0):

  • Horizontal Axis (xx-axis): Positive values extend to the right; negative values extend to the left.
  • Vertical Axis (yy-axis): Positive values extend upward; negative values extend downward.

Any point on the plane is identified by an ordered pair (x,y)(x, y), where xx represents the horizontal position (abscissa) and yy represents the vertical position (ordinate). The plane is divided into four quadrants:

  • Quadrant I: (+,+)(+, +) [Upper Right]
  • Quadrant II: (−,+)(-, +) [Upper Left]
  • Quadrant III: (−,−)(-, -) [Lower Left]
  • Quadrant IV: (+,−)(+, -) [Lower Right]

The Concept of Slope (mm)

The slope of a non-vertical line measures its steepness and direction. Mathematically, slope is defined as the ratio of vertical change (rise) to horizontal change (run) between any two distinct points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) on the line.

The Slope Formula

m=RiseRun=ΔyΔx=y2−y1x2−x1m = \frac{\text{Rise}}{\text{Run}} = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1}

Where x2≠x1x_2 \neq x_1.

Four Classifications of Slope

  1. Positive Slope (m>0m > 0): The line rises from left to right (↗\nearrow).
  2. Negative Slope (m<0m < 0): The line falls from left to right (↘\searrow).
  3. Zero Slope (m=0m = 0): The line is completely horizontal (→\rightarrow). The yy-coordinates are identical (y2=y1  ⟹  Rise=0y_2 = y_1 \implies \text{Rise} = 0).
  4. Undefined Slope: The line is completely vertical (↑\uparrow). The xx-coordinates are identical (x2=x1  ⟹  Run=0x_2 = x_1 \implies \text{Run} = 0, causing division by zero).

Step-by-Step Example: Calculating Slope

Problem: Calculate the slope of the line passing through points (3,8)(3, 8) and (7,0)(7, 0).

  1. Designate coordinates: (x1,y1)=(3,8),(x2,y2)=(7,0)(x_1, y_1) = (3, 8), \quad (x_2, y_2) = (7, 0)
  2. Substitute into the slope formula: m=y2−y1x2−x1=0−87−3m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 8}{7 - 3}
  3. Simplify numerator and denominator: m=−84m = \frac{-8}{4}
  4. Divide: m=−2m = -2

The slope of the line is −2-2 (indicating that for every 11 unit increase in xx, yy decreases by 22 units).


Forms of Linear Equations

Linear relationships can be expressed algebraically in several standard forms:

1. Slope-Intercept Form (y=mx+by = mx + b)

The most versatile form for graphing and analysis on the EIAT is slope-intercept form:

y=mx+by = mx + b

Where:

  • mm = Slope of the line.
  • bb = yy-intercept (the point (0,b)(0, b) where the line crosses the vertical yy-axis).

2. Point-Slope Form (y−y1=m(x−x1)y - y_1 = m(x - x_1))

Useful when you know the slope mm and one point (x1,y1)(x_1, y_1) on the line:

y−y1=m(x−x1)y - y_1 = m(x - x_1)

3. Standard Form (Ax+By=CAx + By = C)

Where AA, BB, and CC are integers (with A≥0A \ge 0). The slope of a line in standard form is m=−ABm = -\frac{A}{B}.


Parallel & Perpendicular Line Dynamics

Geometric relationships between two lines on a coordinate plane depend strictly on their relative slopes.

Parallel Lines (m1=m2m_1 = m_2)

Parallel lines run side-by-side in the same direction and never intersect.

  • Rule: Two non-vertical lines are parallel if and only if they have identical slopes and distinct yy-intercepts: m1=m2andb1≠b2m_1 = m_2 \quad \text{and} \quad b_1 \neq b_2

Example: y=3x+4y = 3x + 4 and y=3x−7y = 3x - 7 are parallel because both have slope m=3m = 3.


Perpendicular Lines (m1⋅m2=−1m_1 \cdot m_2 = -1)

Perpendicular lines intersect at a precise 90∘90^\circ right angle.

  • Rule: Two non-vertical lines are perpendicular if and only if their slopes are negative reciprocals of each other: m2=−1m1orm1⋅m2=−1m_2 = -\frac{1}{m_1} \quad \text{or} \quad m_1 \cdot m_2 = -1

To find the negative reciprocal of a fraction ab\frac{a}{b}:

  1. Flip the fraction upside down: ba\frac{b}{a}.
  2. Change the sign: −ba-\frac{b}{a}.

Step-by-Step Example: Finding a Perpendicular Line

Problem: Which equation represents a line perpendicular to y=−25x+4y = -\frac{2}{5}x + 4 and passing through the point (0,−3)(0, -3)?

  1. Identify the original slope (m1m_1): m1=−25m_1 = -\frac{2}{5}
  2. Calculate the perpendicular slope (m2m_2): Take the negative reciprocal of −25-\frac{2}{5}: m2=−(−52)=+52m_2 = -\left( -\frac{5}{2} \right) = +\frac{5}{2}
  3. Identify the yy-intercept (bb): The line passes through (0,−3)(0, -3), which is the vertical yy-intercept, so b=−3b = -3.
  4. Construct the equation in slope-intercept form: y=m2x+b  ⟹  y=52x−3y = m_2 x + b \implies y = \frac{5}{2}x - 3

Electrical Engineering Application: V-I Graphs & Ohm's Law

In electrical engineering, linear coordinate graphs provide a visual representation of Ohm's Law:

V=I⋅RV = I \cdot R

When circuit test data is plotted on a coordinate plane with Voltage (VV, in Volts) on the vertical yy-axis and Current (II, in Amperes) on the horizontal xx-axis:

Slope m=ΔyΔx=ΔVΔI\text{Slope } m = \frac{\Delta y}{\Delta x} = \frac{\Delta V}{\Delta I}

According to Ohm's Law, VI=R\frac{V}{I} = R. Therefore, the slope of a VV-II line directly equals the electrical Resistance (RR) of the circuit component in Ohms (Ω\Omega).

Trade Scenario: Determining Resistance from VV-II Graph Data

An electrician conducts testing on a heating element and plots the resulting circuit voltage versus current:

  • Point 1: (2 A,24 V)(2\text{ A}, 24\text{ V})
  • Point 2: (5 A,60 V)(5\text{ A}, 60\text{ V})

Step 1: Calculate the Slope of the VV-II Line

m=V2−V1I2−I1=60 V−24 V5 A−2 A=36 V3 A=12 Volts per Amperem = \frac{V_2 - V_1}{I_2 - I_1} = \frac{60\text{ V} - 24\text{ V}}{5\text{ A} - 2\text{ A}} = \frac{36\text{ V}}{3\text{ A}} = 12\text{ Volts per Ampere}

Step 2: Physical Interpretation

Since 1 Volt per Ampere=1 Ω1\text{ Volt per Ampere} = 1\ \Omega, the slope represents Electrical Resistance, and its value is 12 Ω12\ \Omega.

  • Ohmic Components (Linear Slopes): Resistors and heating elements maintain a constant straight-line slope, indicating constant resistance regardless of voltage level.
  • Non-Ohmic Components (Curved Slopes): Devices such as diodes and incandescent lamp filaments display curved VV-II lines, indicating variable resistance under thermal load.

Mastery of linear graphing, slope calculations, and coordinate geometry enables electrical apprentices to analyze circuit diagnostics quickly and excel on the EIAT.

Test Your Knowledge

What is the slope of the line passing through points (3,8)(3, 8) and (7,0)(7, 0)?

A

2

B

-1/2

C

-2

D

1/2

Test Your Knowledge

Which equation represents a line perpendicular to y=−25x+4y = -\frac{2}{5}x + 4 and passing through (0,−3)(0, -3)?

A

y = -2/5 x - 3

B

y = 2/5 x - 3

C

y = 5/2 x - 3

D

y = -5/2 x - 3

Test Your Knowledge

An electrician plots circuit voltage (VV, y-axis) vs current (II, x-axis) through a resistor. Point 1 is (2 A,24 V)(2\text{ A}, 24\text{ V}) and Point 2 is (5 A,60 V)(5\text{ A}, 60\text{ V}). What physical property does the slope represent, and what is its value?

A

Power; 12 W

B

Conductance; 0.08 S

C

Resistance; 12 Ohms

D

Voltage; 36 V

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