7.3 Multi-Data Synthesis, Composite Tables, and Common Distractors

Key Takeaways

  • Multi-data synthesis questions require cross-referencing values across two or more discrete statistical exhibits (e.g., combining demographic counts with departmental expenditure to derive per-capita metrics).

  • Weighted average calculations across groups must be used rather than simple arithmetic averages of subgroup percentages or means.

  • Adjusting nominal figures for inflation using price indices exposes whether apparent budgetary growth represents real volume expansion or purchasing power erosion.

  • Unit conversion errors—especially conflating HK$ thousands, millions, and billions, or percentages with raw counts—are a common source of wrong options.

  • The 'Cannot be determined from the given data' option is a legitimate mathematical conclusion when critical link parameters, denominators, or baseline population totals are missing, but functions as a trap for under-prepared candidates who fail to synthesize available clues.

Last updated: October 2026

7.3 Multi-Data Synthesis, Composite Tables, and Common Distractors

The most cognitively demanding questions in the Aptitude Test's 8-item data interpretation section do not present a single self-contained table or chart. Instead, they present paired or composite exhibits—such as a demographic census table paired with a fiscal expenditure chart, or an employment survey paired with a Consumer Price Index (CPI) time series. These multi-data synthesis items evaluate a candidate's ability to cross-reference disjoint information, reconcile divergent measurement scales, and execute multi-stage quantitative reasoning under extreme time constraints.

To master these advanced items, candidates must master three analytical disciplines: cross-exhibit bridging, weighted aggregation, and deflator adjustment, while systematically immunizing themselves against the predictable distractor patterns designed into multiple-choice options.


The Cross-Exhibit Synthesis Protocol

When a question requires synthesizing information across Exhibit 1 and Exhibit 2, apply the structured Four-Step Synthesis Protocol:

[Step 1: Locate Common Key]   --> Identify the Linking Variable (e.g., District Name, Fiscal Year)
[Step 2: Check Scale Alignment]--> Reconcile Units (e.g., Exhibit 1 in 'Thousands', Exhibit 2 in 'HK\$ Millions')
[Step 3: Execute Target Formula]--> Calculate Rate, Per-Capita, or Weighted Composite Metric
[Step 4: Audit Dimension Match] --> Verify Output Units (e.g., HK\$ per Person vs HK\$ Thousand per Capita)

1. Per-Capita and Density Metrics

Cross-exhibit questions frequently require computing per-capita spending, service density, or resource distribution:

Per-Capita Metric=Aggregate Value from Exhibit 2Target Population from Exhibit 1\text{Per-Capita Metric} = \frac{\text{Aggregate Value from Exhibit 2}}{\text{Target Population from Exhibit 1}}

Important

Audit Dimension Match: When calculating per-capita metrics, always ensure numerator and denominator units are aligned before dividing. Mixing thousands of persons with single dollars without scaling leads directly to magnitude distractors.

Unit Reconciliation Check: If Exhibit 2 reports municipal expenditure in HK$ Millions and Exhibit 1 reports district population in Thousands of Persons, direct division yields:

HK$450 Million300 Thousand Persons=450,000,000300,000=HK$1,500 per person\frac{\text{HK\textdollar } 450\text{ Million}}{300\text{ Thousand Persons}} = \frac{450{,}000{,}000}{300{,}000} = \text{HK\textdollar } 1{,}500\text{ per person}

A rapid mental shortcut: MillionsThousands=Thousands\frac{\text{Millions}}{\text{Thousands}} = \text{Thousands}. Therefore, 450300=1.5 Thousand\frac{450}{300} = 1.5\text{ Thousand}, corresponding to HK$ 1,5001{,}500 per person.

2. Weighted Averages vs. Simple Arithmetic Means

A perennial trap in data questions is calculating the average of averages. When combining data from multiple groups of unequal size, the simple arithmetic mean of subgroup percentages or averages produces a mathematically invalid result. You must calculate the weighted average:

Xˉw=∑i=1knixˉi∑i=1kni=n1xˉ1+n2xˉ2+⋯+nkxˉkn1+n2+⋯+nk\bar{X}_{w} = \frac{\sum_{i=1}^{k} n_i \bar{x}_i}{\sum_{i=1}^{k} n_i} = \frac{n_1 \bar{x}_1 + n_2 \bar{x}_2 + \dots + n_k \bar{x}_k}{n_1 + n_2 + \dots + n_k}

Why Simple Means Fail: Suppose Division A has 100100 officers with a passing rate of 90%90\%, and Division B has 900900 officers with a passing rate of 60%60\%.

  • The naive simple mean is 90%+60%2=75.0%\frac{90\% + 60\%}{2} = 75.0\%.
  • The true weighted mean is: Xˉw=(100×0.90)+(900×0.60)100+900=90+5401,000=6301,000=63.0%\bar{X}_w = \frac{(100 \times 0.90) + (900 \times 0.60)}{100 + 900} = \frac{90 + 540}{1{,}000} = \frac{630}{1{,}000} = 63.0\%
  • Because Division B accounts for 90%90\% of the total workforce, the true composite passing rate lies far closer to 60%60\% than to 90%90\%. Distractors will invariably feature the unweighted 75.0%75.0\% prominently.

3. Nominal vs. Real (Inflation-Adjusted) Figures

Financial tables often display nominal public expenditure alongside the Composite Consumer Price Index (CPI). To assess whether public services genuinely expanded in physical volume or purchasing power, you must convert nominal expenditure to real terms using the price index deflator:

Real Expendituret=(Nominal ExpendituretComposite CPIt)×100\text{Real Expenditure}_{t} = \left( \frac{\text{Nominal Expenditure}_{t}}{\text{Composite CPI}_{t}} \right) \times 100

Real Growth Rate≈Nominal Growth Rate−Inflation Rate\text{Real Growth Rate} \approx \text{Nominal Growth Rate} - \text{Inflation Rate}

If nominal municipal expenditure increases by 6%6\% over a period where the Composite CPI increases by 9%9\%, real expenditure has contracted by approximately 3%3\%, despite the nominal dollar increase.

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Multi-Exhibit Synthesis & Clue Sufficiency Workflow

Distractor Pathology Checklist

Incorrect options in data questions tend to follow recurring mathematical fallacies. Memorizing this checklist allows you to eliminate distractors at sight:

Distractor TrapMathematical PathologyConcrete Exam Example
Unit Mismatch (Order of Magnitude)An option is mathematically off by a factor of 1010, 1,0001{,}000, or 1,000,0001{,}000{,}000 due to mishandling column-header scales.Conflating HK$ 4.54.5 Million with HK$ 450,000450{,}000 or answering in thousands instead of single dollars.
Highest Rate vs. Largest Absolute TotalAssuming that the entity with the highest percentage growth or highest rate must have the largest absolute volume.Sector A grew by 50%50\% (from 1010 to 1515), while Sector B grew by 10%10\% (from 1,0001{,}000 to 1,1001{,}100). Sector B added 100100 units; Sector A added only 55.
Denominator ShiftingCalculating a proportion or percentage change using the wrong sub-population base.Calculating female managers as a percentage of all managers rather than as a percentage of all female employees.
The Unweighted Average FallacyAveraging rates or percentages directly without weighting by subgroup population sizes.Stating overall passing rate is (80%+40%)/2=60%(80\% + 40\%) / 2 = 60\% when Group 1 has 1010 people and Group 2 has 100100 people.
The False 'Cannot Be Determined' DistractorOffering 'Cannot be determined from the given data' when the missing intermediate step can actually be solved via algebraic substitution.Claiming total expenditure cannot be determined when both per-capita spending and total population are explicitly provided across two separate exhibits.

The Clinical Evaluation of 'Cannot Be Determined'

When an option reads "Cannot be determined from the given data", it can be either the answer or a trap.

When 'Cannot Be Determined' is CORRECT:

  • Missing Denominators: You are given percentage distributions (e.g., Department X has 40%40\% graduate officers, Department Y has 60%60\% graduate officers), but neither department's total headcount is provided. You cannot determine which department has more graduate officers in absolute numbers.
  • Unlinked Time Baselines: You are given two separate index series with different base years (e.g., Index A with 2015=1002015 = 100, Index B with 2020=1002020 = 100) without an overlapping conversion factor. You cannot compare their absolute values in 2024.
  • External Exclusions: The question asks for total municipal waste, but the table footnote states "Excludes construction and demolition debris", with no data on construction debris provided.

When 'Cannot Be Determined' is a TRAP:

  • Candidates choose it out of cognitive fatigue when an answer requires cross-referencing three separate exhibits.
  • If an algebraic chain exists connecting Exhibit 1 to Exhibit 2 (e.g., District Population×Per-Capita Rate=Total\text{District Population} \times \text{Per-Capita Rate} = \text{Total}), the quantity is fully determinable. Never select this option merely because the calculation appears complex.
Test Your Knowledge

Two statistical exhibits provide data on four regional municipal districts:

Exhibit 1: Resident Population and Geographic Land Area

  • District North: Population = 320,000; Land Area = 140 sq km
  • District South: Population = 280,000; Land Area = 40 sq km
  • District East: Population = 450,000; Land Area = 50 sq km
  • District West: Population = 550,000; Land Area = 25 sq km

Exhibit 2: Annual Recurrent Municipal Sanitation Expenditure (in HK$ Millions)

  • District North: HK$ 448 Million
  • District South: HK$ 350 Million
  • District East: HK$ 540 Million
  • District West: HK$ 495 Million

Which district recorded the highest annual municipal sanitation expenditure per capita, and which district recorded the highest population density (residents per sq km)?

A

District North had the highest expenditure per capita; District West had the highest population density.

B

District East had the highest expenditure per capita; District West had the highest population density.

C

District North had the highest expenditure per capita; District East had the highest population density.

D

District West had the highest expenditure per capita; District West had the highest population density.

E

District South had the highest expenditure per capita; District East had the highest population density.

Test Your Knowledge

A civil service department conducts an internal professional qualification assessment across three operational branches: Administration, Operations, and Information Technology. The examination results are summarized below:

  • Administration Branch: 120 candidates sat the examination; mean score = 74.0
  • Operations Branch: 200 candidates sat the examination; mean score = 68.0
  • Information Technology Branch: 80 candidates sat the examination; mean score = 82.0

What was the overall weighted mean score across all candidates in the department?

A

70.2

B

71.3

C

72.6

D

73.2

E

74.7

Test Your Knowledge

The table below presents the annual IT budget (in HK$ Millions) and the Composite Consumer Price Index (CPI) for a municipal bureau from 2021 to 2024:

YearNominal IT Budget (HK$ Millions)Composite CPI (Base Year: 2021 = 100.0)Total Departmental Staff
2021240.0100.01,200
2022260.0104.01,250
2023275.0110.01,300
2024288.0120.0Not available

Based strictly on the data provided, which of the following statements is/are mathematically correct?

I. In real terms (at constant 2021 prices), the bureau's IT budget in 2024 was lower than its real IT budget in 2023. II. The nominal IT budget per departmental staff member increased between 2021 and 2022. III. The nominal IT budget per departmental staff member in 2024 was exactly HK$ 210,000.

A

Statement I only

B

Statement II only

C

Statements II and III only

D

Statements I, II, and III

E

Statements I and II only

Sections you finish are checked off in the contents.