8.2 Real-World Linear Equation Word Problems & Writing Equations from Context
Key Takeaways
- Assessment targets A.2.b and A.2.c test writing equations from workplace/consumer contexts (bills, wages, rentals) and everyday number relationships (consecutive integers, comparisons)
- "5 less than a number" translates to x − 5, not 5 − x — reversing subtraction order is the most common translation error
- Fixed-fee-plus-rate problems always follow the template: fixed amount + (rate × unknown) = total
- Always define your variable in words first (e.g., "let t = number of texts") before writing the equation
- Check your final answer against the context: a fractional or negative number of texts, miles, or people signals a setup error
Why Real-World Equation Word Problems Matter on the GED
Assessment target A.2.b and A.2.c ask you to write a linear equation from a real-world context and then solve it — and the GED Testing Service's own Assessment Guide is explicit that these items are drawn from workplace and consumer contexts (cell phone bills, wages, rental fees, shopping) as well as everyday number relationships (consecutive integers, comparisons between quantities). This is not a side skill: on the actual test, the majority of A.2 items are presented as a paragraph of text rather than a bare equation, so translating words into algebra correctly is often the harder half of the problem — the solving step itself is usually a one- or two-step equation once it's set up. Missing the translation means missing the question even if your arithmetic is flawless.
Translating Words Into Algebra
Every word problem is built from a small vocabulary of phrases that map directly onto math symbols. Memorize this translation table:
| Phrase | Math symbol | Example |
|---|---|---|
| "more than," "increased by," "sum of," "total" | + | "8 more than a number" → x + 8 |
| "less than," "decreased by," "difference" | − (careful with order) | "5 less than a number" → x − 5, NOT 5 − x |
| "times," "product of," "twice," "triple" | × | "twice a number" → 2x |
| "per," "each," "at a rate of" | rate multiplier | "$0.10 per text" → 0.10t |
| "is," "equals," "was," "will be," "results in" | = | "the total was $34" → ... = 34 |
| "a number," "an unknown quantity" | variable (x, n) | define this first |
The most common translation error is reversing subtraction order. "5 less than a number" means you start with the number and subtract 5, so it translates to x − 5, not 5 − x. Reading the phrase in the order it's written, rather than translating word-by-word left to right, avoids this trap.
A Repeatable Process for Word Problems
- Read the whole problem first, then identify exactly what quantity is unknown and assign it a variable (state what the variable represents in a short note, e.g., "let t = number of texts").
- Separate constants from rates. A constant is a one-time or fixed amount (a monthly fee, a flat deposit); a rate is multiplied by the unknown (a per-unit cost, a per-mile charge).
- Translate the sentence into an equation, term by term, using the table above.
- Solve using the standard multi-step order from Section 8.1: distribute, clear fractions, combine like terms, isolate the variable.
- Check your answer in context — does the number make sense (a whole number of texts, a positive number of miles), and does it satisfy the original sentence?
Worked Example 1 — Fixed Fee Plus Rate (Consumer Context)
"A cell phone plan charges a $25 monthly fee plus $0.10 per text message. If Maria's bill was $34, how many texts did she send?"
- Let t = number of texts sent.
- Fixed fee ($25) plus rate ($0.10 per text) equals total: 25 + 0.10t = 34
- Subtract 25: 0.10t = 9
- Divide by 0.10: t = 90 texts
Worked Example 2 — Consecutive Integers
"The sum of three consecutive integers is 51. Find the integers."
- Let n = the first integer, so the next two are (n + 1) and (n + 2).
- n + (n + 1) + (n + 2) = 51
- Combine like terms: 3n + 3 = 51
- Subtract 3: 3n = 48
- Divide by 3: n = 16, so the integers are 16, 17, and 18.
Worked Example 3 — Direct Phrase Translation
"5 less than twice a number is 13. Find the number."
- Twice a number is 2x. "5 less than" that quantity is 2x − 5.
- Equation: 2x − 5 = 13
- Add 5: 2x = 18
- Divide by 2: x = 9
Common Problem Templates on the GED
| Problem type | Equation template |
|---|---|
| Fixed fee plus per-unit rate | fixed amount + (rate × unknown) = total |
| Consecutive integers | n + (n + 1) + (n + 2) = given sum |
| Direct phrase translation | build left-to-right from the sentence's own word order |
| Comparison between two people/items | define one variable, express the second in terms of the first (e.g., "Sam has 3 more than twice what Ana has" → s = 2a + 3) |
Recognizing which template a paragraph fits is often faster than re-deriving the equation from scratch every time — practice spotting the pattern within the first sentence or two of the problem.
Worked Example 4 — Comparison Problems
"Ana worked 3 more hours than twice the hours Sam worked. Together they worked 33 hours. How many hours did Sam work?"
- Let s = Sam's hours. Ana's hours are described in terms of Sam's: 2s + 3.
- Together they worked 33 hours, so: s + (2s + 3) = 33
- Combine like terms: 3s + 3 = 33
- Subtract 3: 3s = 30
- Divide by 3: s = 10 hours (and Ana worked 2(10) + 3 = 23 hours)
Comparison problems like this one are a favorite GED format because they force you to translate two related quantities with only one variable — define the simpler quantity first, then build the second quantity's expression from it before writing the final equation.
A car rental company charges a flat $40 fee plus $0.25 per mile driven. If a customer's total charge was $67.50, how many miles did they drive?
Which equation correctly represents "7 less than three times a number is 20"?
The sum of two consecutive even integers is 46. What is the larger integer?