Distribution Selection and Budget Assembly

Key Takeaways

  • Convert bounds and certificate uncertainties to standard uncertainties using justified distribution and coverage information.

  • A uniform resolution model uses half the display step divided by √3.

  • Budget tables retain units, input estimates, standard uncertainties, sensitivity coefficients, and relevant degrees of freedom.

Last updated: October 2026

Probability Distributions for Type B Evaluations

When evaluating a Type B component, the technician determines the bounding limit (semi-range aa) and selects an appropriate probability distribution:

Probability DistributionGraphical ShapeWhen to Apply in MetrologyDivisor (dd)Standard Uncertainty (u=a/du = a / d)
Normal (Gaussian)Symmetric bell curveData from calibration certificates with stated coverage factor (k=2k = 2 or k=1.96k = 1.96); averages of multiple processeskk (typically 22)u=Uku = \frac{U}{k}
Rectangular (Uniform)Flat plateau between −a-a and +a+a; zero outsideManufacturer specifications (±a\pm a); digital display resolution (a=δx/2a = \delta x / 2); certified bounds with no central tendency knowledge3≈1.732\sqrt{3} \approx 1.732u=a3u = \frac{a}{\sqrt{3}}
TriangularSymmetric triangle peaking at nominal centerSum of two identical rectangular distributions; a supported triangular model, not automatically every regulated room6≈2.449\sqrt{6} \approx 2.449u=a6u = \frac{a}{\sqrt{6}}
U-Shaped (Arc-sine)Bathtub curve peaking at bounds ±a\pm a, trough at centerSinusoidal oscillations (e.g., HVAC temperature cycling); RF mismatch reflection coefficients; mechanical cam oscillation2≈1.414\sqrt{2} \approx 1.414u=a2u = \frac{a}{\sqrt{2}}

Synthesizing the Uncertainty Budget Table

Once all input components are evaluated, the Law of Propagation of Uncertainty combines them. For uncorrelated input quantities:

uc(y)=∑i=1n[ci⋅u(xi)]2=∑i=1n[ui(y)]2u_c(y) = \sqrt{\sum_{i=1}^n [c_i \cdot u(x_i)]^2} = \sqrt{\sum_{i=1}^n [u_i(y)]^2}

The Expanded Uncertainty (UU) is obtained by multiplying uc(y)u_c(y) by the coverage factor kk (often k=2k = 2 for nearly normal output with adequate degrees of freedom; do not assume this coverage for every distribution):

U=k⋅uc(y)U = k \cdot u_c(y)

Practical Calibration Budget Example: Calibrating a 100 mm100\text{ mm} Digital Micrometer

Consider calibrating a 100 mm100\text{ mm} digital micrometer (resolution δx=0.001 mm\delta x = 0.001\text{ mm}) using an calibrated reference gauge block (Lref=100.0000 mmL_{\text{ref}} = 100.0000\text{ mm}) at nominal laboratory conditions (20±1∘C20 \pm 1^\circ\text{C}):

Input Quantity (XiX_i)Value / BoundsStandard Uncertainty u(xi)u(x_i)DistributionDivisorSensitivity Coeff (cic_i)Contribution ui(y)u_i(y)Evaluation Type
1. Reference Block CalU=0.120 μmU = 0.120\ \mu\text{m} (k=2k=2)0.060 μm0.060\ \mu\text{m}Normal2.02.0+1.0+1.00.060 μm0.060\ \mu\text{m}Type B
2. Reference Block Drifta=0.050 μma = 0.050\ \mu\text{m}0.029 μm0.029\ \mu\text{m}Rectangular3\sqrt{3}+1.0+1.00.029 μm0.029\ \mu\text{m}Type B
3. UUT Digital Resolutionδx=1.000 μm\delta x = 1.000\ \mu\text{m} (a=0.500 μma = 0.500\ \mu\text{m})0.289 μm0.289\ \mu\text{m}Rectangular3\sqrt{3}+1.0+1.00.289 μm0.289\ \mu\text{m}Type B
4. UUT Repeatabilitys=0.350 μms = 0.350\ \mu\text{m}, n=5n=50.157 μm0.157\ \mu\text{m}Normal (mean)5\sqrt{5}+1.0+1.00.157 μm0.157\ \mu\text{m}Type A
5. Temperature DifferenceΔT=±0.5∘C\Delta T = \pm 0.5^\circ\text{C}, α=11.5×10−6/K\alpha = 11.5 \times 10^{-6}/\text{K}a=0.575 μm  ⟹  0.332 μma = 0.575\ \mu\text{m} \implies 0.332\ \mu\text{m}Rectangular3\sqrt{3}+1.0+1.00.332 μm0.332\ \mu\text{m}Type B
6. Anvil Parallelism / Forcea=0.200 μma = 0.200\ \mu\text{m}0.115 μm0.115\ \mu\text{m}Rectangular3\sqrt{3}+1.0+1.00.115 μm0.115\ \mu\text{m}Type B

Combine unrounded contributions

Using micrometres throughout, the squared contributions are 0.06020.060^2, 0.0502/30.050^2/3, 0.5002/30.500^2/3, 0.3502/50.350^2/5, 0.5752/30.575^2/3, and 0.2002/30.200^2/3. Their sum is 0.23580833 μm20.23580833\ \mu\text{m}^2, giving uc=0.4856010022 μmu_c=0.4856010022\ \mu\text{m}. For this illustrative choice of k=2k=2, U=0.9712020044 μmU=0.9712020044\ \mu\text{m}, reported as 0.97 μm0.97\ \mu\text{m}. Rounded table values are for display; do not recompute from them when unrounded contributions are available.

Notice that UUT resolution (0.289 μm0.289\ \mu\text{m}) and differential temperature (0.332 μm0.332\ \mu\text{m}) heavily dominate the uncertainty budget, demonstrating why high-accuracy calibration standards cannot overcome poor environment or coarse UUT resolution.


Common Calibration Traps & CCT Exam Pitfalls

Warning

Trap 1: Double-Counting the Quantization Interval For a digital display with resolution δx\delta x, the bounding limit (semi-range aa) is δx/2\delta x / 2, NOT δx\delta x. The standard uncertainty is ures=δx/23=δx23≈0.289δxu_{\text{res}} = \frac{\delta x / 2}{\sqrt{3}} = \frac{\delta x}{2\sqrt{3}} \approx 0.289 \delta x. Dividing the full resolution by 3\sqrt{3} overstates the uncertainty by a factor of 2!

Caution

Trap 2: Adding Uncertainties Directly Instead of Root-Sum-Squaring Standard uncertainties are standard deviations. You do not add them linearly when the inputs are uncorrelated (u1+u2u_1 + u_2). Linear addition assumes perfect correlation (r=+1r = +1) and can overestimate uncertainty for uncorrelated contributions; covariance must be used where correlation exists. Uncorrelated components must always be combined via the root-sum-of-squares (RSS).

Tip

Trap 3: Forgetting the Sensitivity Coefficient When Units Differ In an indirect measurement such as P=V⋅IP = V \cdot I, you cannot RSS u(V)u(V) in volts with u(I)u(I) in amperes. You must multiply each by its respective sensitivity coefficient (cV=Ic_V = I, cI=Vc_I = V) so that all contributions are converted into watts (W\text{W}) before squaring and summing.

Official references (checked October 10, 2026): BIPM JCGM publications: GUM and VIM.

Reviewing the model before accepting the total

The micrometer budget is hypothetical. Its five-observation repeatability estimate comes from an independent characterization using a finer readout, not five readings rounded to the 1 µm display step; such rounded readings cannot produce the stated 0.350 µm sample deviation. The reported mean and remaining resolution contribution use the stated measurement model. Assume the components represent separate effects and justify that assumption to avoid double counting. A single-reading result instead uses the appropriate single-observation repeatability component. More repetitions do not reduce every certificate, drift, temperature, or quantization contribution by the same square-root rule.

The listed temperature term uses a length of 100 mm, a coefficient of 11.5 ppm per kelvin, and a bounded temperature difference of half a kelvin. That produces a length bound of 0.575 micrometres before distribution conversion. The row expresses the environmental effect in length units, so its displayed sensitivity is one. An alternative table could retain temperature in kelvin with a length-per-kelvin sensitivity. Those are equivalent representations; including both rows would double count the same effect.

Check correlation and overlap among other rows. Repeatability observations can already contain some quantization, contact-force, or short-term environmental variation. A separate contribution is justified only for the effect not adequately represented, or under a clearly stated conservative model. Do not delete a contribution merely because it is large, but do not add the same observed variation twice without rationale.

Finally, identify corrections and their uncertainty separately. Apply an established reference-block correction to the result; include uncertainty in that correction in the budget. The magnitude of the correction is not automatically its standard uncertainty. Keep assumptions, source records, relevant distributions, and unrounded calculation values with the work package so another qualified person can reproduce the result.

Test Your Knowledge

A digital micrometer displays readings with a least significant digit of 0.001 mm0.001\text{ mm} (1.0 μm1.0\ \mu\text{m}). What is the standard uncertainty associated with the digital display resolution of this instrument when modeled as a rectangular distribution?

A

0.289 μm0.289\ \mu\text{m} (derived from half-width a=0.500 μma = 0.500\ \mu\text{m} divided by 3\sqrt{3})

B

0.577 μm0.577\ \mu\text{m} (derived from full span 1.000 μm1.000\ \mu\text{m} divided by 3\sqrt{3})

C

0.500 μm0.500\ \mu\text{m} (derived from half-width with no divisor applied)

D

0.204 μm0.204\ \mu\text{m} (derived from half-width divided by 6\sqrt{6})

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