1.2 Radioactive Decay Kinetics & Half-Life Calculations
Key Takeaways
- Radioactive decay is governed by first-order exponential kinetics: A = A₀ · e^(-λt) or A = A₀ · (1/2)^(t / T_1/2).
- The decay constant (λ) is inversely proportional to half-life: λ = ln(2) / T_1/2 ≈ 0.693 / T_1/2.
- One Curie (Ci) equals exactly 3.7 × 10¹⁰ disintegrations per second (37 GBq), while one Becquerel (Bq) equals 1 disintegration per second.
- Specific activity represents the radioactivity per unit mass (Ci/g or TBq/g); high specific activity enables physically small focal spot sizes for sharp radiography.
- Industrial isotopes are manufactured primarily in nuclear research reactors via thermal neutron capture reactions (n, γ).
The Fundamental Law of Radioactive Decay
Radioactive decay is a purely stochastic (probabilistic) nuclear process. For any single unstable nucleus, it is physically impossible to predict the exact instant of disintegration. However, for a macroscopic collection of $N$ identical radioactive atoms, the rate of nuclear disintegration ($-dN/dt$), termed the activity ($A$), is strictly proportional to the number of radioactive atoms present at that moment: where $\lambda$ is the characteristic decay constant of the specific radioisotope (expressed in units of $\text{time}^{-1}$, such as $\text{s}^{-1}$, $\text{hr}^{-1}$, or $\text{day}^{-1}$). The decay constant represents the constant fractional probability per unit time that a given nucleus will decay.
Exponential Decay Equations
Integrating the differential decay equation yields the classical exponential decay law: Because activity $A$ is directly proportional to $N$ ($A = \lambda N$): where:
- $A(t)$ = Activity remaining after elapsed time $t$,
- $A_0$ = Initial activity at time $t = 0$,
- $\lambda$ = Decay constant,
- $t$ = Elapsed time (in the same units as $\lambda$).
Half-Life ($T_{1/2}$) and the Half-Life Formula
The half-life ($T_{1/2}$) is defined as the time required for one-half (50%) of the radioactive atoms in a sample to disintegrate, or for the activity of the sample to decrease to exactly half its initial value ($A = A_0 / 2$).
Setting $A(t) = A_0 / 2$ and $t = T_{1/2}$ in the exponential decay law: Taking the natural logarithm of both sides:
Substituting $\lambda$ back into the exponential equation yields the highly practical half-life decay equation utilized across all industrial radiography field operations: where $n = t / T_{1/2}$ represents the number of elapsed half-lives (which does not need to be an integer).
Step-by-Step Decay Factor Progression
| Elapsed Half-Lives ($n$) | Fraction of Activity Remaining | Decimal Decay Factor ($DF$) | Percent of Initial Activity Remaining |
|---|---|---|---|
| 0 | $1$ | 1.0000 | 100.0% |
| 1 | $1/2$ | 0.5000 | 50.0% |
| 2 | $1/4$ | 0.2500 | 25.0% |
| 3 | $1/8$ | 0.1250 | 12.5% |
| 4 | $1/16$ | 0.0625 | 6.25% |
| 5 | $1/32$ | 0.03125 | 3.125% |
| 7 | $1/128$ | 0.00781 | 0.78% (decayed by > 99%) |
| 10 | $1/1024$ | 0.000976 | < 0.1% (rule of thumb: essentially decayed) |
Worked Field Calculation Example
Problem: A radiographer receives a newly loaded Iridium-192 source certified at 100 Curies on September 1. What will be the source activity after 148 days? (Half-life of Ir-192 = 74 days).
- Calculate the number of elapsed half-lives ($n$):
- Calculate remaining activity using the half-life formula: Answer: Exactly 25 Curies remain.
Now consider a fractional half-life problem: What is the activity after 45 days?
- $n = 45 / 73.83 = 0.6095$
- $A = 100 \times (0.5)^{0.6095} = 100 \times 0.6554 = 65.54\text{ Ci}$ Radiographers use printed manufacturer decay charts or daily calculation tables derived from this exact mathematical formula to set radiography exposure times.
Specific Activity and Source Pellet Geometry
Specific activity is defined as the radioactivity per unit mass of the isotope, expressed in Curies per gram (Ci/g) or Terabecquerels per gram (TBq/g): where $N_A$ is Avogadro's number ($6.022 \times 10^{23}\text{ atoms/mol}$) and $M$ is the molar mass.
Why Specific Activity Dictates Radiographic Quality
In non-destructive examination, the sharpness of the radiographic image depends on minimizing geometric unsharpness ($U_g$): where $F$ is the physical dimension of the radiation focal spot (the source pellet diameter), $d$ is the object-to-film distance, and $D$ is the source-to-object distance. A smaller focal spot ($F$) produces sharper, higher-resolution radiographs that reveal minute weld cracks and lack of fusion.
Because Iridium-192 can be activated to exceptionally high specific activity (often 200 to 450 Ci/g), a 100-Curie Ir-192 source pellet measures only 2.5 mm to 3.0 mm in diameter. Conversely, Cobalt-60 has a lower specific activity (typically 50 to 100 Ci/g), meaning a 100-Curie Co-60 source requires a larger physical pellet (4 to 6 mm diameter), resulting in greater geometric unsharpness.
Artificial Radioisotope Production in Nuclear Reactors
None of the primary radioisotopes used in modern industrial radiography exist in nature; they are artificially created by exposing stable target elements to high thermal neutron fluxes inside nuclear research reactors:
- Iridium-192 Production: Stable Iridium-191 ($37.3%$ natural abundance) captures a thermal neutron via the $(n, \gamma)$ reaction:
- Cobalt-60 Production: Stable natural Cobalt-59 ($100%$ abundance) undergoes neutron capture:
- Selenium-75 Production: Enriched Selenium-74 targets capture a neutron:
If an Iridium-192 source has an activity of 80 Curies on June 1, what will its approximate activity be on October 13 (148 days later, assuming a 74-day half-life)?
Why is a high specific activity (Ci/g) critically advantageous for industrial radiography sealed sources?
What is the relationship between the decay constant (λ) and the radioactive half-life (T_1/2)?