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3.3 Voltage Drop Limits & Calculation Methods

Key Takeaways

  • DEWA regulations limit maximum cumulative voltage drop from the supply origin (MDB/Transformer) to 3% (6.9 V) for lighting circuits and 5% (11.5 V single-phase / 20.0 V three-phase) for power and equipment circuits.

  • Voltage drop in conductors arises from resistive (R) and inductive reactive (X) impedance, causing reduced equipment voltage, motor overheating, and increased line power losses.

  • The single-phase voltage drop formula is Vd = (mV/A/m) · I · L / 1000, while the three-phase line-to-line voltage drop formula is Vd = (mV/A/m) · I · L / 1000 using tabulated 3-phase values.

  • For large conductors (≥ 35 mm²) operating at low power factor (cos φ < 1.0), both resistive r and reactive x components must be evaluated using Z = r cos φ + x sin φ.

  • Dividing total allowable voltage drop between sub-main feeders (typically ≤ 2.0%) and final branch circuits (typically ≤ 3.0%) ensures full system compliance and prevents cumulative failure.

Last updated: July 2026

3.3 Voltage Drop Limits & Calculation Methods

Study focus: Voltage drop compliance is strictly audited by DEWA during building inspection. Candidates must know the exact maximum percentage limits—3% for lighting (6.9 V) and 5% for power (11.5 V single-phase / 20.0 V three-phase)—and apply the mV/A/mmV/A/m formulas for both single-phase and three-phase sub-mains and branch circuits.

Even if an electrical cable satisfies thermal current-carrying capacity criteria (Iz≥InI_z \ge I_n), long circuit route lengths can cause excessive voltage drop along the conductor resistance and reactance. Excessive voltage drop impairs equipment performance, causes motor stalling and overheating, creates flickering in luminaires, and wastes electrical energy as line heat losses.


Principles of Voltage Drop in AC Circuits

When alternating current (II) flows through a conductor of length LL, the internal conductor resistance (RR) and inductive reactance (XX) create a complex voltage drop vector:

ΔV=I⋅(R+jX)\mathbf{\Delta V} = \mathbf{I} \cdot (R + jX)

Operational Consequences of Under-Voltage

  1. Electric Motors: Electromagnetic torque decreases with the square of terminal voltage (T∝V2T \propto V^2). A 10%10\% voltage drop reduces motor starting torque by 19%19\%, forcing the motor to draw higher current to drive the mechanical load, causing severe winding overheating.
  2. Lighting Systems: Incandescent and discharge lighting experience dramatic lumen output drops; LED drivers experience increased input current, reducing electronic component lifespan.
  3. Control Relays & Contactors: Excessive line drop causes magnetic contactor chatter, contact welding, or drop-out during motor starting surges.

DEWA Statutory Voltage Drop Limits

DEWA defines standard nominal low-voltage supply parameters as:

  • Three-Phase Supply: 400 V400\text{ V} line-to-line (50 Hz50\text{ Hz}).
  • Single-Phase Supply: 230 V230\text{ V} line-to-neutral (50 Hz50\text{ Hz}).
                      DEWA Permissible Voltage Drop Allocations
  ┌─────────────────────────────────────────────────────────────────────────┐
  │ Total Lighting Limit: 3.0% Max (6.9 V Single-Phase / 12.0 V Three-Phase)│
  ├─────────────────────────────────────────────────────────────────────────┤
  │ Sub-Main Feeder Target: ≤ 1.5% to 2.0%  │ Final Branch Target: ≤ 1.0% to 1.5%│
  ├─────────────────────────────────────────────────────────────────────────┤
  │ Total Power Limit: 5.0% Max (11.5 V Single-Phase / 20.0 V Three-Phase)  │
  ├─────────────────────────────────────────────────────────────────────────┤
  │ Sub-Main Feeder Target: ≤ 2.0% to 2.5%  │ Final Branch Target: ≤ 2.5% to 3.0%│
  └─────────────────────────────────────────────────────────────────────────┘

Statutory Maximum Voltage Drop Table

Circuit TypeMax Allowable % DropMax Voltage Drop (230V 1-Phase)Max Voltage Drop (400V 3-Phase)
Lighting Circuits3.0%3.0\%6.90 V6.90\text{ V}12.00 V12.00\text{ V}
Power / Sockets / HVAC / Motors5.0%5.0\%11.50 V11.50\text{ V}20.00 V20.00\text{ V}

Note: Voltage drop is cumulative, measured from the primary point of supply (DEWA meter/transformer secondary or Main Distribution Board) to the furthest final utilization point or outlet.


The Tabulated mV/A/mmV/A/m Calculation Method

BS 7671 and cable manufacturers express voltage drop capability as tabulated millivolts per ampere per meter (mV/A/mmV/A/m).

1. Single-Phase Voltage Drop Formula

Vd(1Φ)=(mV/A/m)1Φ×I×L1000[Volts]V_{d(1\Phi)} = \frac{(mV/A/m)_{1\Phi} \times I \times L}{1000} \quad \text{[Volts]} %,Vd(1Φ)=(Vd(1Φ)230)×100%\%,V_{d(1\Phi)} = \left(\frac{V_{d(1\Phi)}}{230}\right) \times 100\%

Where:

  • (mV/A/m)1Φ(mV/A/m)_{1\Phi} = Tabulated single-phase voltage drop factor.
  • II = Design load current (IbI_b) flowing in the circuit (Amperes).
  • LL = One-way circuit route length (Meters).

2. Three-Phase Voltage Drop Formula

For balanced three-phase systems, line-to-line voltage drop is calculated as:

Vd(3Φ)=(mV/A/m)3Φ×I×L1000[Volts Line-to-Line]V_{d(3\Phi)} = \frac{(mV/A/m)_{3\Phi} \times I \times L}{1000} \quad \text{[Volts Line-to-Line]} %,Vd(3Φ)=(Vd(3Φ)400)×100%\%,V_{d(3\Phi)} = \left(\frac{V_{d(3\Phi)}}{400}\right) \times 100\%

Important Note: Standard BS 7671 tables publish (mV/A/m)3Φ(mV/A/m)_{3\Phi} values that already incorporate the 3\sqrt{3} multiplier. If you calculate voltage drop using individual conductor single-phase resistance (rr) and reactance (xx) values, you must multiply by 3\sqrt{3}:

Vd(3Φ)=3×r2+x2×I×L1000V_{d(3\Phi)} = \frac{\sqrt{3} \times \sqrt{r^2 + x^2} \times I \times L}{1000}

Power Factor (cos⁡ϕ\cos\phi) & Inductive Reactance Adjustment

For small conductors (<35 mm2< 35\text{ mm}^2), cable impedance is almost purely resistive (RR). For larger conductors (≥35 mm2\ge 35\text{ mm}^2), inductive reactance (XX) becomes significant.

When a load operates at a lagging power factor (cos⁡ϕ<1.0\cos\phi < 1.0), the combined effective impedance ZrZ_r per unit length is:

Zr=rcos⁡ϕ+xsin⁡ϕ[mV/A/m]Z_r = r \cos\phi + x \sin\phi \quad \text{[mV/A/m]}

Where:

  • rr = Conductor resistance per meter at maximum operating temperature (mV/A/mmV/A/m).
  • xx = Conductor inductive reactance per meter (mV/A/mmV/A/m).
  • cos⁡ϕ\cos\phi = Load power factor (e.g., 0.850.85).
  • sin⁡ϕ=1−cos⁡2ϕ\sin\phi = \sqrt{1 - \cos^2\phi} (e.g., sin⁡(arccos⁡0.85)=0.527\sin(\arccos 0.85) = 0.527).

Step-by-Step Worked Numerical Example

Problem Statement

A 3-phase, 400 V400\text{ V} sub-main feeder cable connects a Main Distribution Board (MDB) to a Sub-Main Distribution Board (SMDB) in a commercial building over a route length of 95 meters95\text{ meters}. The design current is Ib=145 AI_b = 145\text{ A} at a power factor of 0.850.85 lagging. Protection is a 160 A160\text{ A} MCCB (In=160 AI_n = 160\text{ A}). Candidate cable selected based on current capacity: 70 mm270\text{ mm}^2 4-core Cu/XLPE/SWA/LSZH.

  • Tabulated 3-phase voltage drop factor for 70 mm270\text{ mm}^2 XLPE cable (BS 7671 Table 4E4B): (mV/A/m)3Φ=0.60 mV/A/m(mV/A/m)_{3\Phi} = 0.60\text{ mV/A/m}.

Determine whether the candidate cable complies with DEWA voltage drop limits.

Step 1: Calculate Absolute 3-Phase Line Voltage Drop (VdV_d)

Vd(3Φ)=(mV/A/m)3Φ×Ib×L1000=0.60×145×951000=82651000=8.265 VV_{d(3\Phi)} = \frac{(mV/A/m)_{3\Phi} \times I_b \times L}{1000} = \frac{0.60 \times 145 \times 95}{1000} = \frac{8265}{1000} = 8.265\text{ V}

Step 2: Calculate Percentage Voltage Drop on Sub-Main Feeder

%,Vd(sub−main)=(8.265 V400 V)×100%=2.066%\%,V_{d(sub-main)} = \left(\frac{8.265\text{ V}}{400\text{ V}}\right) \times 100\% = 2.066\%

Step 3: Evaluate Remaining Allowance for Final Branch Circuits

  • Maximum allowable cumulative drop for power circuits = 5.0%5.0\% (20.0 V20.0\text{ V}).
  • Remaining voltage drop budget for final power sub-circuits fed downstream from the SMDB:
%,Vd(final)=5.0%−2.066%=2.934%(equivalent to 11.74 V on 400V 3-phase or 6.75 V on 230V 1-phase)\%,V_{d(final)} = 5.0\% - 2.066\% = 2.934\% \quad (\text{equivalent to } 11.74\text{ V on 400V 3-phase or } 6.75\text{ V on 230V 1-phase})

Step 4: Evaluate Lighting Circuit Constraints

  • Maximum allowable cumulative drop for lighting = 3.0%3.0\% (12.0 V12.0\text{ V} 3-phase / 6.9 V6.9\text{ V} 1-phase).
  • If lighting panels are supplied from this SMDB, the remaining voltage drop allowance for final lighting circuits is:
%,Vd(final_light)=3.0%−2.066%=0.934%(only 2.15 V on 230V 1-phase)\%,V_{d(final\_light)} = 3.0\% - 2.066\% = 0.934\% \quad (\text{only } 2.15\text{ V on 230V 1-phase})

Conclusion

The 70 mm270\text{ mm}^2 cable is fully compliant for the sub-main power distribution (2.07%≤2.5%2.07\% \le 2.5\% sub-main allocation). However, to ensure final lighting branch circuits do not exceed the 3.0%3.0\% cumulative limit, lighting circuits should either use larger final conductor sizes (4 mm24\text{ mm}^2) or be supplied from a dedicated lighting sub-main closer to the MDB.

Test Your Knowledge

According to DEWA regulations, what are the maximum allowable cumulative voltage drop limits from the supply origin to final outlets for lighting and power circuits, respectively?

A

5% for lighting circuits and 10% for power circuits.

B

2% for lighting circuits and 4% for power circuits.

C

3% for lighting circuits (6.9 V) and 5% for power circuits (11.5 V on 230 V single-phase).

D

1% for lighting circuits and 3% for power circuits.

Test Your Knowledge

What is the correct formula to calculate the three-phase line-to-line voltage drop Vd using tabulated (mV/A/m) values, design current I (Amperes), and run length L (Meters)?

A

Vd = (mV/A/m) * I * L

B

Vd = (mV/A/m) * I * L / 100

C

Vd = 3 * (mV/A/m) * I * L / 1000

D

Vd = (mV/A/m) * I * L / 1000

Test Your Knowledge

Why must both resistive (r) and inductive reactive (x) components of cable impedance be evaluated when calculating voltage drop for large cross-section conductors (≥ 35 mm²)?

A

At larger conductor cross-sections, inductive reactance x becomes significant relative to resistance r, causing additional voltage drop at lagging power factors.

B

Inductive reactance x cancels out resistance r in large cables, reducing total voltage drop to zero.

C

Resistive component r becomes completely negligible above 35 mm², making x the sole contributor to voltage drop.

D

DEWA regulations mandate ignoring reactance x for all copper cables below 185 mm².

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