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Key Facts: NMT Physics Exam

Official Tasks

UCEQA 2026 subject guidance

120 min

Shared Stage

UCEQA 2026 NMT structure

5/32

Raw Conversion Threshold

2026 admission rules, Appendix 5

NMT Physics: 22 official computer-based tasks, maximum 32 raw points. Stage 2: History of Ukraine and the selected elective share 120 minutes. Candidates allocate time within the stage; there is no fixed 60-minute subject limit. Independent English-language four-option MCQ study adaptation by OpenExamPrep. These selected-topic exercises are supplementary, not an official translation, an official-format simulation, or a substitute for the full range of official tasks.

Sample NMT Physics Practice Questions

Try these sample questions to review concepts for the NMT Physics exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A cyclist moves along a straight road at a constant speed, covering a distance of $36\text{ km}$ in $1.0\text{ hour}$. What is the cyclist's speed in SI units (meters per second)?

A.10 m/s

B.36 m/s

C.100 m/s

D.3.6 m/s

Explanation: To convert kilometers per hour to meters per second, divide by $3.6$: $v = \frac{36\text{ km/h}}{3.6} = 10\text{ m/s}$. Alternatively: $v = \frac{36000\text{ m}}{3600\text{ s}} = 10\text{ m/s}$.

2A vehicle starts from rest ($v_0 = 0$) and accelerates uniformly along a straight track at $a = 2.0\text{ m/s}^2$ for $5.0\text{ seconds}$. What distance does the vehicle cover during this time?

A.25 m

B.50 m

C.10 m

D.12.5 m

Explanation: For rectilinear motion with constant acceleration starting from rest, the distance covered is given by $s = \frac{a t^2}{2}$. Substituting the given values: $s = \frac{2.0 \times 5.0^2}{2} = \frac{2.0 \times 25}{2} = 25\text{ m}$.

3A stone is released from rest from a bridge at height $h = 20\text{ m}$ above a river. Neglecting air resistance and taking $g = 10\text{ m/s}^2$, how long does the stone take to hit the water?

A.2.0 s

B.4.0 s

C.1.0 s

D.2.8 s

Explanation: For free fall from rest, $h = \frac{g t^2}{2} \implies t = \sqrt{\frac{2h}{g}}$. Substituting $h = 20\text{ m}$ and $g = 10\text{ m/s}^2$: $t = \sqrt{\frac{2 \times 20}{10}} = \sqrt{4} = 2.0\text{ s}$.

4A small metal ball is projected horizontally with an initial speed of $v_0 = 15\text{ m/s}$ from the edge of a horizontal cliff of height $h = 20\text{ m}$. Neglecting air resistance and taking $g = 10\text{ m/s}^2$, what is the horizontal distance (range) from the base of the cliff to the impact point?

A.30 m

B.15 m

C.45 m

D.60 m

Explanation: The vertical motion is free fall: $h = \frac{g t^2}{2} \implies t = \sqrt{\frac{2 \times 20}{10}} = 2.0\text{ s}$. The horizontal motion is uniform with constant velocity $v_x = v_0 = 15\text{ m/s}$. The horizontal range is $L = v_0 t = 15\text{ m/s} \times 2.0\text{ s} = 30\text{ m}$.

5A body moves at a constant speed of $v = 4.0\text{ m/s}$ along a circular trajectory of radius $R = 2.0\text{ m}$. What is the centripetal (normal) acceleration of the body?

A.$8.0\text{ m/s}^2$

B.$2.0\text{ m/s}^2$

C.$16.0\text{ m/s}^2$

D.$4.0\text{ m/s}^2$

Explanation: Centripetal acceleration is directed toward the center of the circular trajectory and is given by $a_c = \frac{v^2}{R}$. Substituting the given values: $a_c = \frac{4.0^2}{2.0} = \frac{16.0}{2.0} = 8.0\text{ m/s}^2$.

6A constant net horizontal force of $F = 12\text{ N}$ acts on a body with mass $m = 3.0\text{ kg}$ situated on a frictionless horizontal table. What is the acceleration imparted to the body?

A.$4.0\text{ m/s}^2$

B.$36\text{ m/s}^2$

C.$0.25\text{ m/s}^2$

D.$9.0\text{ m/s}^2$

Explanation: According to Newton's second law, acceleration is directly proportional to net force and inversely proportional to mass: $a = \frac{F}{m} = \frac{12\text{ N}}{3.0\text{ kg}} = 4.0\text{ m/s}^2$.

7When finding the net force on one body in Newtonian mechanics, why must its Newton's-third-law reaction partner not be added as a balancing force on that same body?

A.They act on two different interacting bodies, not on the same body

B.They have different magnitudes depending on the masses of the bodies

C.One force acts before the other with a measurable time delay

D.Action forces are real, whereas reaction forces are purely fictitious inertial forces

Explanation: The two forces act on different bodies, so only one belongs in the force sum for a particular body. For a system containing both bodies, their internal forces do cancel in the system's total force sum.

8Two spherical satellites in outer space attract each other gravitationally with force $F$. If the distance between their centers of mass is doubled, what will the new gravitational force between them be?

A.$0.25 F$ ($F/4$)

B.$0.5 F$ ($F/2$)

C.$2 F$

D.$4 F$

Explanation: Newton's law of universal gravitation states $F = G \frac{m_1 m_2}{r^2}$. Because gravitational force is inversely proportional to the square of the distance ($F \propto \frac{1}{r^2}$), doubling the distance ($r' = 2r$) reduces the force by a factor of $2^2 = 4$: $F' = \frac{F}{4} = 0.25 F$.

9A spring with a stiffness coefficient of $k = 200\text{ N/m}$ is compressed by $\Delta x = 5.0\text{ cm}$ ($0.050\text{ m}$). What is the magnitude of the elastic restoring force, and what potential energy is stored in the compressed spring?

A.$F = 10\text{ N}$ and $E_p = 0.25\text{ J}$

B.$F = 100\text{ N}$ and $E_p = 2.5\text{ J}$

C.$F = 10\text{ N}$ and $E_p = 0.50\text{ J}$

D.$F = 20\text{ N}$ and $E_p = 1.0\text{ J}$

Explanation: By Hooke's law: $F = k \Delta x = 200\text{ N/m} \times 0.050\text{ m} = 10\text{ N}$. The elastic potential energy stored in a deformed spring is $E_p = \frac{k (\Delta x)^2}{2} = \frac{200 \times (0.050)^2}{2} = 100 \times 0.0025 = 0.25\text{ J}$.

10A 5.0 kg crate is pulled horizontally along a horizontal floor at constant velocity. With coefficient of kinetic friction 0.20 and g = 10 m/s², what friction force opposes its motion?

A.10 N

B.50 N

C.2.5 N

D.1.0 N

Explanation: On a horizontal surface without vertical pulling components, the normal force equals gravity: $N = mg = 5.0\text{ kg} \times 10\text{ m/s}^2 = 50\text{ N}$. The kinetic friction force is $F_{\text{fric}} = \mu N = 0.20 \times 50\text{ N} = 10\text{ N}$.

About the NMT Physics Exam

NMT Physics is a selectable fourth subject of Ukraine’s National Multi-Subject Test for higher-education admission. Independent English-language four-option MCQ study adaptation by OpenExamPrep. These selected-topic exercises are supplementary, not an official translation, an official-format simulation, or a substitute for the full range of official tasks.

Exam sponsor: Ukrainian Center for Educational Quality Assessment (УЦОЯО / UCEQA). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Computer-based subject component of Національний мультипредметний тест (НМТ / NMT). 14 single-choice tasks, 2 matching tasks, and 6 short numerical-answer tasks.

Time Limit

Stage 2: History of Ukraine and the selected elective share 120 minutes. Candidates allocate time within the stage; there is no fixed 60-minute subject limit.

Passing Score

5 of 32 raw points is the minimum for a converted 100–200 result in 2026; it does not guarantee admission.

Exam / Certification Fees

Free participation; travel costs separate

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

UCEQA 2026 subject scope and task forms · Source checked 2026-10-23
UCEQA 2026 NMT structure and assessment languages · Source checked 2026-10-23
UCEQA 2026 candidate FAQ · Source checked 2026-10-23
2026 admission rules and score-conversion tables, Appendix 5 · Source checked 2026-10-23
UCEQA NMT participation procedure: no participation fee · Source checked 2026-10-23General participation procedure; the 2026 interview with the UCEQA director also discusses paid participation only as a possible future change.
UCEQA director interview, 19 May 2026 · Source checked 2026-10-23

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.