Is this the old Yetkin geotechnical examination?

No. The current identity comes from İMO's 2026 geotechnical programme and SİM specialty endorsement announcement. The historical Yetkin scheme must not supply its eligibility or assessment rules.

What assessment languages and additional components are confirmed?

The reviewed announcement confirms an examination but does not specify permitted response languages or oral, practical and assignment requirements. Confirm these directly with İMOSEM; no official English sitting is established by the sources reviewed.

Are the seven modules equally weighted in the official examination?

No official assessment weights are published in the reviewed announcement. This bank gives each announced module four practice items for broad study coverage; that is an editorial distribution, not an official blueprint.

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Sample İMO Geoteknik Uzmanlığı Practice Questions

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1A saturated soil has water content 28% and solids specific gravity 2.70. Using Se = wGs with S = 1, what is its void ratio?

A.0.280

B.0.756

C.2.700

D.9.643

Explanation: Water content must be entered as a fraction: e = 0.28 × 2.70 = 0.756. Saturation relates the water volume to the entire void volume.

2For an SPT, N = 16, CE = 0.75, CR = 0.85, CB = CS = 1, and effective overburden is 76.8 kPa. Using N60 = NCECRCBCS and CN = sqrt(100/σ'v), what is (N1)60 = CNN60, rounded to the nearest integer?

A.8

B.10

C.12

D.16

Explanation: N60 = 16 × 0.75 × 0.85 = 10.2, and CN = sqrt(100/76.8) ≈ 1.141. Their product is 11.64, which rounds to 12.

3In a consolidated-undrained triaxial test, total cell pressure is 200 kPa, failure deviator stress is 160 kPa, and TOTAL pore pressure at failure is 80 kPa. Assuming c' = 0, use sin φ' = (σ'1 - σ'3)/(σ'1 + σ'3). What is φ'?

A.16.6°

B.20.0°

C.30.0°

D.23.6°

Explanation: The effective principal stresses are 120 kPa and 280 kPa after subtracting the total pore pressure. Thus sin φ' = 160/400 = 0.40, giving φ' ≈ 23.6°.

4A constant-head test passes 480 cm³ of water in 180 s through a sand specimen with area 78.54 cm² and length 15 cm. The head difference is 45 cm. Using k = VL/(Ath), what is hydraulic conductivity?

A.0.0113 cm/s

B.0.0340 cm/s

C.0.00566 cm/s

D.0.679 cm/s

Explanation: The hydraulic gradient is 45/15 = 3 and the discharge rate is 480/180 = 2.667 cm³/s. Therefore k = 2.667/(78.54 × 3) = 0.0113 cm/s.

5For a strip footing in undrained clay, use net ultimate capacity qnet,ult = Nc cu and divide this net value by the specified safety factor. Given Nc = 5.7, cu = 50 kPa, overburden at base = 27 kPa and safety factor 3, what is net allowable capacity?

A.104 kPa

B.122 kPa

C.285 kPa

D.95 kPa

Explanation: Net ultimate capacity is 5.7 × 50 = 285 kPa. Dividing this net value by three gives 95 kPa; overburden is not added when reporting net capacity under the stated convention.

6A normally consolidated clay layer is 4 m thick with e0 = 0.80 and Cc = 0.36. Effective stress increases from 100 to 200 kPa. Using S = CcH log10(σ'f/σ'0)/(1+e0), what is primary consolidation settlement?

A.120 mm

B.241 mm

C.433 mm

D.555 mm

Explanation: The thickness coefficient is 0.36 × 4/1.80 = 0.80 m. Multiplying by log10(2) gives 0.2408 m, or approximately 241 mm.

7An overconsolidated clay layer has H = 3.4 m, e0 = 0.70, Cr = 0.04, Cc = 0.30, initial effective stress 80 kPa, preconsolidation stress 120 kPa, and final stress 160 kPa. Using base-ten compression curves, what is settlement?

A.24 mm

B.181 mm

C.89 mm

D.151 mm

Explanation: Recompression to 120 kPa gives (0.04 × 3.4/1.7)log10(120/80) = 0.0141 m. Virgin compression from 120 to 160 kPa adds (0.30 × 3.4/1.7)log10(160/120) = 0.0750 m, giving about 89 mm overall.

8A pile group has a specified sum of individual ultimate capacities of 4,524 kN. Its square block envelope is 2.8 m wide and 12 m deep in clay with cu = 50 kPa. Using block resistance = perimeter × depth × cu + 9cu × base area, which failure resistance governs?

A.4,524 kN, individual pile failure

B.10,248 kN, block failure

C.7,386 kN, the average resistance

D.3,528 kN, block base resistance

Explanation: Block shaft resistance is 4 × 2.8 × 12 × 50 = 6,720 kN and block base resistance is 9 × 50 × 2.8² = 3,528 kN. The block total is 10,248 kN, so the smaller individual-pile sum governs this capacity comparison.

9For a smooth vertical wall with horizontal cohesionless backfill and φ' = 30°, use Ka = (1-sin φ')/(1+sin φ'). What is the Rankine active coefficient?

A.0.500

B.0.333

C.3.000

D.0.750

Explanation: Since sin 30° = 0.5, Ka = 0.5/1.5 = 0.333. The reciprocal, 3.0, describes the corresponding passive coefficient under these assumptions.

10A 6 m wall retains dry sand with γ = 18 kN/m³ and Ka = 1/3. A uniform 24 kPa surcharge covers the backfill. What is active thrust per metre of wall using Pa = KaγH²/2 + KaqH?

A.48 kN/m

B.108 kN/m

C.204 kN/m

D.156 kN/m

Explanation: Soil self-weight contributes 108 kN/m and the surcharge contributes 48 kN/m. Adding the triangular and rectangular pressure components gives 156 kN/m.

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