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Free Practice Questions for Thai Optometry License

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Key Facts: Thai Optometry License Exam

60%

Passing score standard set by the Professional Board of Optometry

Department of Health Service Support Guidelines

6 Years

Curricular duration of accredited Doctor of Optometry (O.D.) degree programs in Thailand

Commission on Higher Education / MOPH

B.E. 2542

Governing statute: Practice of the Healing Arts Act (พระราชบัญญัติการประกอบโรคศิลปะ พ.ศ. 2542)

Department of Health Service Support Legal Registry

2 Stages

Licensing examination structure: written theoretical paper followed by clinical practical assessment

Professional Board of Optometry Notice

1,000–2,000 THB

Typical written examination fee under MOPH ministerial schedule

Ministry of Public Health Ministerial Regulations

Independent practice by OpenExamPrep for the Thai Optometry Healing Arts License: an English-language MCQ study adaptation covering clinical refraction, contact lens practice, ocular anatomy and pathology, binocular vision, ophthalmic optics, and the Practice of the Healing Arts Act B.E. 2542. This resource is not an official examination translation or simulation of the Thai clinical testing environment.

Sample Thai Optometry License Practice Questions

Try these sample questions to review concepts for the Thai Optometry License exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1During static retinoscopy at a working distance of 67 cm, an examiner achieves neutrality in all meridians with a +3.50 DS trial lens. What is the patient's net refractive error?
A.+2.00 DS
B.+1.50 DS
C.+3.50 DS
D.+5.00 DS
Explanation: Net refractive error equals gross retinoscopy power minus the working distance vergence. At 67 cm, the working distance vergence is 1 / 0.67 m = +1.50 D. Subtracting +1.50 D from the gross value of +3.50 DS yields a net spherical power of +2.00 DS.
2Using a streak retinoscope in the standard sleeve-down (divergent beam) position, what does an observed 'with-motion' reflex signify regarding the patient's far point?
A.The far point is located behind the examiner or behind the patient's retina
B.The far point is located exactly at the retinoscope peephole plane
C.The far point is located between the patient's eye and the examiner's eye
D.The eye possesses high myopic astigmatism exceeding -6.00 D
Explanation: In sleeve-down streak retinoscopy, 'with-motion' occurs when rays exiting the eye have not yet come to a focus, indicating the far point is located behind the examiner (hyperopia, emmetropia, or myopia less than the working distance). Plus lenses are added to move the far point forward to the retinoscope peephole.
3At a 50 cm working distance, an optometrist observes neutrality along the 90-degree meridian with +3.00 DS and along the 180-degree meridian with +4.50 DS. What is the net spectacle prescription in minus cylinder format?
A.+2.50 DS -1.50 DC x 180
B.+1.00 DS +1.50 DC x 90
C.+2.50 DS -1.50 DC x 90
D.+1.00 DS -1.50 DC x 180
Explanation: At 50 cm, working distance compensation is 1 / 0.50 m = 2.00 D. Net powers are +1.00 D in the 90-degree meridian and +2.50 D in the 180-degree meridian. In minus cylinder format, taking the more positive meridian (+2.50 DS) requires -1.50 DC cylinder power acting along the 90-degree meridian, which aligns its axis at 180 degrees (+2.50 DS -1.50 DC x 180).
4When refining astigmatic cylinder axis using a Jackson Cross-Cylinder (JCC / ครอสไซลินเดอร์), how must the JCC handle be aligned relative to the trial cylinder axis?
A.Parallel to (superimposed upon) the trial cylinder axis
B.At 45 degrees to the trial cylinder axis
C.Perpendicular (at 90 degrees) to the trial cylinder axis
D.Along the vertical 90-degree phoropter meridian regardless of axis
Explanation: For cylinder axis refinement, the JCC handle (or flip axis) is aligned directly parallel to the trial frame cylinder axis. This places the two principal power axes of the JCC straddling 45 degrees on either side of the test axis; twirling the cross-cylinder changes which power axis dominates, prompting the patient to steer toward the sharper position.
5During JCC cylinder power refinement, an optometrist increases the minus cylinder power by -0.50 DC. To maintain the circle of least confusion on the retina, what spherical adjustment must be made?
A.Add +0.25 DS
B.Add -0.25 DS
C.Add +0.50 DS
D.No spherical adjustment is required
Explanation: The spherical equivalent is defined as Sphere + (Cylinder / 2). Adding -0.50 DC alters the spherical equivalent by -0.25 D, shifting the circle of least confusion behind the retina. To keep the focal midpoint anchored on the photoreceptors, +0.25 DS of plus sphere must be added (the 1:2 rule of cylinder refinement).
6What primary physical optics phenomenon forms the foundation of the duochrome (bichrome / red-green) test in subjective refraction?
A.Longitudinal chromatic aberration of the human eye
B.Spherical aberration produced by the crystalline lens cortex
C.Diffraction through the natural pupil aperture
D.Purkinje shift between scotopic and photopic visual states
Explanation: The human ocular optical media exhibit longitudinal chromatic aberration of approximately 0.50 D between red (approx. 650 nm) and green (approx. 535 nm) wavelengths. Green light refracts more strongly than red light, focusing anterior to red. The duochrome test uses this physical disparity to identify spherical endpoint neutrality.
7A patient undergoing monocular subjective refraction reports that the letters on the red background are significantly darker and sharper than those on the green background. How should the optometrist adjust the trial lens?
A.Add minus sphere in -0.25 DS steps until both backgrounds are equally distinct
B.Add plus sphere in +0.25 DS steps until both backgrounds are equally distinct
C.Increase cylinder power by -0.25 DC
D.Rotate cylinder axis by 10 degrees clockwise
Explanation: Because red wavelengths focus posterior to green wavelengths in the eye, clearer letters on red indicate that the red focus is closer to the retina than the green focus, meaning the eye's refractive focal point lies in front of the retina (or accommodation is relaxed in a hyperope, leaving the focal plane posterior). In an under-minused or over-plussed state, letters on red are clearer; adding minus sphere (or reducing plus) shifts both focal planes posteriorly until they straddle the retina symmetrically.
8During binocular balancing using the von Graefe prism dissociation method, what standard prism arrangement is introduced in front of the patient's eyes?
A.3–4 prism diopters Base Down in the right eye and 3–4 prism diopters Base Up in the left eye
B.6 prism diopters Base In in both eyes
C.10 prism diopters Base Out in the right eye only
D.2 prism diopters Base Up in both eyes
Explanation: Vertical prism dissociation in the von Graefe technique typically uses 3 to 4 prism diopters Base Down before OD (projecting the right eye's image superiorly) and 3 to 4 prism diopters Base Up before OS (projecting the left eye's image inferiorly). This dissociates binocular fusion vertically into two distinct horizontal lines of letters, enabling simultaneous subjective accommodation comparison.
9In the Humphriss Immediate Contrast (HIC) method of binocular balancing and subjective refraction, how is fusion maintained while testing the viewing eye?
A.Placing a +0.75 DS to +1.00 DS fogging lens in front of the non-tested eye
B.Placing an opaque black occluder over the non-tested eye
C.Inserting crossed polarizers at 45 and 135 degrees
D.Applying 6 prism diopters Base In over the tested eye
Explanation: The Humphriss Immediate Contrast (HIC) technique maintains peripheral binocular fusion and locks ciliary accommodation binocularly by fogging the non-tested eye with +0.75 DS to +1.00 DS. This degrades foveal visual acuity in the non-tested eye to roughly 20/60 while retaining binocular peripheral fusion locks, allowing monocular foveal refraction under true binocular conditions.
10What is the primary underlying anatomical and physiological etiology of presbyopia in aging human eyes?
A.Loss of crystalline lens capsular elasticity and sclerosis of lens nuclear fibers
B.Complete atrophy and paralysis of the ciliary muscle circular fibers
C.Flattening of the central anterior corneal radius of curvature
D.Progressive shortening of the axial length of the globe
Explanation: Presbyopia is primarily caused by progressive age-related biomechanical changes in the crystalline lens: increased lens thickness, lens capsule loss of elasticity, and sclerosis/stiffening of cortical and nuclear fibers. Ultrasonographic and pharmacologic studies show that the ciliary muscle retains substantial contractile force well into advanced age.

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