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Sample Suriname VHN-toets Practice Questions
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1Solve 4(2x - 3) = 3(x + 6) + 4.
A.x = 2
B.x = 5
C.x = 6.8
D.x = 8.5
Explanation: Expanding gives 8x - 12 = 3x + 22. Hence 5x = 34 and x = 6.8; distribute the factors to every term inside each bracket.
2Solve 2x + 3y = 21 and 5x - 2y = 5 simultaneously.
A.x = 3, y = 5
B.x = 5, y = 3
C.x = 4, y = 4
D.x = 2, y = 6
Explanation: Multiplying the equations by 2 and 3 gives 4x + 6y = 42 and 15x - 6y = 15. Adding eliminates y and gives 19x = 57, so x = 3. Substitution then gives y = 5.
3What is the gradient of the line through (2, -3) and (6, 5)?
A.1/2
B.-2
C.4
D.2
Explanation: Gradient is change in y divided by change in x. It equals [5 - (-3)]/(6 - 2) = 8/4 = 2.
4The perpendicular sides of a right triangle have lengths in the ratio 3:4. Its perimeter is 60 cm. What is its hypotenuse?
A.20 cm
B.25 cm
C.30 cm
D.300/7 cm
Explanation: Write the legs as 3k and 4k; Pythagoras gives the hypotenuse as 5k. The perimeter is therefore 12k = 60, so k = 5 cm. The hypotenuse is 5k = 25 cm.
5Two similar triangles have corresponding side lengths in the ratio small:large = 3:5. If the smaller area is 36 cm², what is the larger area?
A.60 cm²
B.100 cm²
C.36 cm²
D.166.7 cm²
Explanation: Areas scale with the square of the corresponding length ratio. The larger area is 36 × (5/3)² = 100 cm².
6For an acute angle θ in a right triangle, sin θ = 5/13. What is tan θ?
A.12/5
B.5/13
C.12/13
D.5/12
Explanation: The opposite side and hypotenuse can be represented by 5 and 13. Pythagoras gives the adjacent side as √(13² - 5²) = 12. Therefore tan θ = opposite/adjacent = 5/12.
7A map has scale 1:250,000. Two sites are 18 cm apart on the map. What is their corresponding straight-line distance?
A.45 km
B.4.5 km
C.450 km
D.0.45 km
Explanation: One centimetre represents 250,000 cm, or 2.5 km. Multiplying by 18 gives a ground distance of 45 km.
8Which set gives all solutions of 5 - 2(3x - 1) ≥ 19?
A.x ≥ -2
B.x ≤ 2
C.x ≤ -2
D.x ≥ 2
Explanation: Expansion gives 7 - 6x ≥ 19, hence -6x ≥ 12. Dividing by -6 reverses the inequality and gives x ≤ -2.
9An ideal hydraulic lift has circular pistons of diameters 4 cm and 20 cm. A 200 N force acts on the small piston. Ignoring piston weights, friction and height differences, what load force can the large piston balance?
A.1,000 N
B.1,250 N
C.5,000 N
D.40 N
Explanation: Equal fluid pressure gives F₂/F₁ = A₂/A₁. Circular areas scale with squared diameter, so the area ratio is (20/4)² = 25. The balanced load is 200 × 25 = 5,000 N.
10A hoist raises a 250 kg beam vertically by 4 m in 10 s. Using g = 10 m/s², what is its average useful mechanical power?
A.10,000 W
B.1,000 W
C.2,500 W
D.100 W
Explanation: The useful work is the gain in gravitational potential energy: mgh = 250 × 10 × 4 = 10,000 J. Dividing by 10 s gives average useful power of 1,000 W.
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