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Free Practice Questions for Somaliland Grade 8 Exam

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Sample Somaliland Grade 8 Exam Practice Questions

Try these sample questions to review concepts for the Somaliland Grade 8 Exam exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Evaluate the following arithmetic expression using the standard order of operations (BODMAS): 18 + 12 ÷ 3 - 4 × 2.
A.14
B.12
C.18
D.26
Explanation: According to the order of operations (BODMAS/PEMDAS), division and multiplication must be performed before addition and subtraction. First, 12 ÷ 3 = 4 and 4 × 2 = 8. The expression becomes 18 + 4 - 8. Then, working from left to right: 18 + 4 = 22, and 22 - 8 = 14.
2A merchant in Hargeisa monitored the temperature inside a meat cold-storage unit. At 6:00 AM, the temperature was -4°C. By noon, the temperature had risen by 9°C. By midnight, it dropped by 7°C. What was the temperature at midnight?
A.2°C
B.-6°C
C.-2°C
D.0°C
Explanation: Starting at -4°C, a rise of 9°C gives -4 + 9 = +5°C at noon. Then, dropping by 7°C gives +5 - 7 = -2°C at midnight.
3Express the terminating decimal 0.625 as a fraction in lowest terms.
A.5/8
B.1/8
C.3/5
D.25/40
Explanation: Write 0.625 as 625/1000. Dividing numerator and denominator by 125 gives 5/8, whose terms have no common factor greater than one.
4A tailor in Borama had 12 1/2 meters of fabric. He used 4 3/4 meters to sew a men's suit and 3 1/3 meters to sew a dress. How many meters of fabric were left?
A.5 1/12 meters
B.4 1/2 meters
C.3 7/12 meters
D.4 5/12 meters
Explanation: Total fabric used = 4 3/4 + 3 1/3. Converting to fractions with common denominator 12: 4 9/12 + 3 4/12 = 7 13/12 = 8 1/12 meters. Now subtract the total used from the starting amount: 12 1/2 - 8 1/12 = 12 6/12 - 8 1/12 = 4 5/12 meters.
5Convert the recurring decimal 0.3666... (where only the digit 6 repeats) into a common fraction in its lowest terms.
A.36/100
B.4/11
C.11/30
D.3/8
Explanation: Let x = 0.3666... Then 10x = 3.666... and 100x = 36.666... Subtracting 10x from 100x eliminates the repeating part: 100x - 10x = 36.666... - 3.666... which gives 90x = 33. Solving for x yields x = 33/90. Dividing both numerator and denominator by their greatest common divisor (3) gives 11/30.
6In a Grade 8 class of 40 students at a school in Burao, 65% of the students scored a grade of distinction. How many students scored distinction?
A.24
B.28
C.30
D.26
Explanation: Sixty-five percent is 0.65 of the group. Multiplying 40 by 0.65 gives 26 students.
7A trader bought a solar lantern for 160,000 Somaliland Shillings (Sl.Sh) and later sold it for 192,000 Sl.Sh. What was his percentage profit?
A.16.7%
B.20%
C.25%
D.32%
Explanation: Profit = Selling Price - Cost Price = 192,000 - 160,000 = 32,000 Sl.Sh. Percentage profit = (Profit / Cost Price) × 100% = (32,000 / 160,000) × 100% = (1/5) × 100% = 20%.
8An agricultural cooperative in Gabiley invested 500,000 Sl.Sh in an account paying simple interest at a rate of 8% per annum. After how many years will the total balance (principal plus interest) reach 660,000 Sl.Sh?
A.4 years
B.3 years
C.4.5 years
D.5 years
Explanation: Total interest earned = Total Amount - Principal = 660,000 - 500,000 = 160,000 Sl.Sh. Simple interest formula: I = (P × R × T) / 100. Substituting the values: 160,000 = (500,000 × 8 × T) / 100 = 40,000 × T. Therefore, T = 160,000 / 40,000 = 4 years.
9A herd of 45 goats is divided between two brothers in the ratio 2 : 3. How many goats does the brother with the smaller share receive?
A.15
B.27
C.18
D.30
Explanation: Total ratio parts = 2 + 3 = 5 parts. Each part represents 45 ÷ 5 = 9 goats. The smaller share has 2 parts: 2 × 9 = 18 goats.
10Twelve masons can construct a perimeter stone wall in Berbera in 15 days. If the project manager employs 20 masons working at the same pace, how many days will the construction take?
A.8 days
B.9 days
C.10 days
D.25 days
Explanation: This is an inverse proportion problem: more workers require fewer days. Total work = number of workers × days = 12 × 15 = 180 mason-days. With 20 masons, the time required is 180 ÷ 20 = 9 days.

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