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Free Practice Questions for Concours IPSL — Saint-Louis
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Sample Concours IPSL — Saint-Louis Practice Questions
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1Evaluate lim(x→0) (e^(5x)−1)/x.
A.5
B.1
C.0
D.1/5
Explanation: Write the expression as 5(e^(5x)−1)/(5x). The standard exponential quotient tends to 1, giving the limit 5.
2In the complex plane, what locus is defined by |z+2−3i|=4?
A.Circle centered at (2,−3), radius 4
B.Circle centered at (−2,3), radius 4
C.Circle centered at (−2,3), radius 16
D.Line through (−2,3)
Explanation: The expression is |z−(−2+3i)|=4. It specifies a constant distance of 4 from the point with coordinates (−2,3), hence a circle.
3Evaluate ∫₁^(e²) (ln x)/x dx.
A.1
B.4
C.2
D.e²−1
Explanation: A primitive is (ln x)²/2. Evaluation gives 2²/2−0=2.
4Let u0=2 and u(n+1)=(2un+3)/(un+4). Define vn=(un−1)/(un+3). Which statement is correct? The sequences are well defined.
A.v(n+1)=5vn and un→+∞
B.v(n+1)=vn/2 and un→3
C.vn is constant and un→2
D.v(n+1)=vn/5 and un→1
Explanation: Subtracting 1 from the recurrence and adding 3 gives v(n+1)=(un−1)/(5(un+3))=vn/5. Since v0=1/5, vn tends to zero, and un=(1+3vn)/(1−vn) tends to 1.
5What is the oblique asymptote of (3x²+2x+1)/(x+1) at infinity?
A.y=3x−1
B.y=3x+2
C.y=3x+1
D.y=3x−2
Explanation: Polynomial division gives 3x−1+2/(x+1). The final fraction tends to zero at either infinity, leaving asymptote y=3x−1.
6Solve z²+6z+13=0 in ℂ.
A.3±2i
B.−3±2i
C.−6±4i
D.−3±4i
Explanation: The discriminant is 36−52=−16. Thus z=(−6±4i)/2=−3±2i.
7A function is continuous on [1,5] and differentiable on (1,5), with f(1)=3 and f(5)=15. Which derivative value is guaranteed somewhere in (1,5)?
A.12
B.4
C.3
D.15/4
Explanation: The mean value theorem gives f'(c)=(15−3)/(5−1)=3. Its assumptions concern continuity on the closed interval and differentiability in its interior.
8Solve y'+y=3 with y(0)=5.
A.3+5e^(−x)
B.5+3e^(−x)
C.3+2e^x
D.3+2e^(−x)
Explanation: A constant particular solution is 3, so the general solution is 3+Ce^(−x). The initial condition gives C=2.
9How many unordered pairs can be selected from eight distinct students?
A.28
B.56
C.16
D.64
Explanation: There are 8×7 ordered choices of two different students. Dividing by two for the two orders of each pair gives 28.
10Find the area between y=9−x² and the x-axis where the parabola is nonnegative.
A.18
B.36
C.54
D.27
Explanation: The roots are −3 and 3. The area is ∫₋₃³(9−x²)dx=[9x−x³/3]₋₃³=36 square units.
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