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100+ Free SCE FE Chemical Practice Questions

Pass your Saudi Council of Engineers Fundamentals of Engineering (FE) — Chemical exam on the first try — instant access, no signup required.

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Key Facts: SCE FE Chemical Exam

50

Discipline Questions

SCE / Qiyas

3 hours

Discipline Time Limit

SCE / Qiyas

400 SAR

Discipline Exam Fee

SCE FAQ

Pass/Fail

Scaled Scoring

SCE / Qiyas

English

Exam Language

SCE / Qiyas

Associate

SCE Classification

Saudi Council of Engineers

The SCE FE Chemical discipline exam is a 3-hour computer-based test with 50 multiple-choice questions in English, administered by Qiyas. The discipline portion costs 400 SAR (800 SAR total with the 90-question general part). Each part is scored pass/fail on a scaled basis; SCE/Qiyas do not publish a fixed percentage threshold. This practice bank targets the chemical discipline syllabus for Associate Engineer credentialing.

Sample SCE FE Chemical Practice Questions

Try these sample questions to test your SCE FE Chemical exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1An ideal gas at 300 K and 150 kPa occupies 2 m³. If pressure is increased isothermally to 300 kPa, what is the final volume?
A.0.5 m³
B.1.0 m³
C.1.5 m³
D.4.0 m³
Explanation: Isothermal ideal gas: P₁V₁ = P₂V₂ → V₂ = P₁V₁/P₂ = (150)(2)/300 = 300/300 = 1.0 m³.
2For a closed system, the first law of thermodynamics with heat in positive and work out positive is:
A.ΔU = Q − W
B.ΔU = Q + W for all processes
C.Q = W for any isothermal process
D.ΔH = 0 for all adiabatic processes
Explanation: With the common engineering sign convention (heat added positive, work done by system positive), ΔU = Q − W relates internal energy change to heat and work.
3A Carnot engine operates between 600 K (hot) and 300 K (cold). What is the maximum thermal efficiency?
A.25%
B.50%
C.75%
D.100%
Explanation: Carnot efficiency η = 1 − T_L/T_H = 1 − 300/600 = 1 − 0.5 = 0.5 = 50%. Temperatures must be absolute (kelvin).
4Steam at 1 MPa with quality x = 0.90. To find specific enthalpy h, you need from steam tables at 1 MPa:
A.h_f and h_g (saturated liquid and vapor enthalpies)
B.Superheated table only
C.Compressed liquid table only
D.Ideal gas cpT alone
Explanation: For a wet mixture, h = h_f + x(h_g − h_f), requiring saturated liquid enthalpy h_f and saturated vapor enthalpy h_g at 1 MPa.
5During an isobaric heating of an ideal gas, 500 kJ of heat is added and 200 kJ of boundary work is done by the gas. The change in internal energy is:
A.200 kJ
B.300 kJ
C.500 kJ
D.700 kJ
Explanation: First law: ΔU = Q − W = 500 − 200 = 300 kJ. Work done by the system reduces the internal energy increase from heat alone.
6The Gibbs free energy change ΔG for a reaction at constant T and P indicates:
A.Maximum non-expansion work and spontaneity (ΔG < 0 spontaneous)
B.Only heat transfer rate
C.Reynolds number in reactors
D.Pipe friction factor
Explanation: ΔG = ΔH − TΔS at constant T,P. Negative ΔG means the reaction is spontaneous; ΔG equals maximum useful non-PV work obtainable.
7Raoult's law for an ideal solution states that the vapor pressure of component i is:
A.P_i = x_i P_i°
B.P_i = γ_i x_i only for nonideal solutions
C.P_total = P_i° regardless of composition
D.P_i = x_i / P_i°
Explanation: Raoult's law: P_i = x_i P_i°, where x_i is liquid mole fraction and P_i° is pure-component vapor pressure at the same temperature.
8A binary mixture at 80°C has component A with P_A° = 40 kPa and x_A = 0.50 (ideal solution). What is P_A in the vapor?
A.10 kPa
B.20 kPa
C.40 kPa
D.80 kPa
Explanation: Raoult's law: P_A = x_A P_A° = (0.50)(40) = 20 kPa. Partial pressure is proportional to liquid mole fraction for ideal solutions.
9The standard heat of reaction ΔH°_rxn is calculated from heats of formation by:
A.ΔH°_rxn = Σ n_p ΔH_f°(products) − Σ n_r ΔH_f°(reactants)
B.ΔH°_rxn = Σ reactants − Σ products
C.ΔH°_rxn = ΔG° / T always
D.ΔH°_rxn equals activation energy
Explanation: Hess's law with formation enthalpies: ΔH°_rxn = Σν_p ΔH_f°(products) − Σν_r ΔH_f°(reactants), using stoichiometric coefficients.
10For an ideal gas undergoing isentropic compression with k = 1.4 from T₁ = 300 K to pressure ratio P₂/P₁ = 4, T₂ ≈
A.300 K
B.401 K
C.500 K
D.1200 K
Explanation: T₂/T₁ = (P₂/P₁)^((k−1)/k) = 4^(0.4/1.4) = 4^0.2857 ≈ 1.337 → T₂ ≈ 300 × 1.337 ≈ 401 K.

About the SCE FE Chemical Exam

The SCE Fundamentals of Engineering (FE) Chemical discipline exam is the specialized portion of the Qiyas-administered FE credentialing pathway for chemical engineers in Saudi Arabia. After passing the 90-question general engineering session, candidates sit a 50-question, 3-hour chemical discipline exam covering thermodynamics, transport phenomena, reaction engineering, materials science for chemical service, and process design including safety and control. Passing both parts supports SCE Associate Engineer classification.

Assessment

50 multiple-choice discipline questions (140 total across general + discipline FE exam)

Time Limit

3 hours (discipline portion)

Passing Score

Pass/fail scaled score on each part (minimum threshold not published)

Exam Fee

400 SAR (discipline portion) (Saudi Council of Engineers (SCE) / Qiyas (NCA))

SCE FE Chemical Exam Content Outline

20%

Thermodynamics

First and second laws, ideal gases, steam tables, phase equilibrium, Raoult's law, Gibbs energy, and psychrometrics

20%

Transport Phenomena

Fourier and Fick's laws, convection and radiation, Reynolds number, Bernoulli equation, LMTD, and mass transfer coefficients

20%

Reaction Engineering

Rate laws, Arrhenius kinetics, CSTR and PFR design, conversion, catalysis, RTD, and equilibrium

20%

Materials

Corrosion mechanisms, stainless steels and alloys, polymers, phase diagrams, glass-lined equipment, and material selection

20%

Process Design

P&IDs, relief systems, HAZOP, PID control, distillation, economics, utilities, scale-up, and SCE professional practice

How to Pass the SCE FE Chemical Exam

What You Need to Know

  • Passing score: Pass/fail scaled score on each part (minimum threshold not published)
  • Assessment: 50 multiple-choice discipline questions (140 total across general + discipline FE exam)
  • Time limit: 3 hours (discipline portion)
  • Exam fee: 400 SAR (discipline portion)

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

SCE FE Chemical Study Tips from Top Performers

1Review CSTR and PFR design equations and know when to use X = kτ/(1+kτ) versus X = 1 − e^{−kτ} for first-order reactions.
2Practice material and energy balances with phase change — steam table quality problems appear frequently in thermodynamics.
3Master Reynolds number, friction factor, and simple LMTD calculations for transport and heat exchanger questions.
4Study corrosion types (galvanic, pitting, SCC) and common materials (304/316 SS, Hastelloy, PTFE, FRP) for chemical service.
5Familiarize yourself with P&ID symbols, relief device purpose, and basic PID control loop behavior for process design.
6Use Arrhenius and half-life relations for first-order kinetics — calculation problems are common in reaction engineering.

Frequently Asked Questions

What is the SCE FE Chemical discipline exam?

The SCE FE Chemical discipline exam is Part 2 of the Qiyas Fundamentals of Engineering exam for chemical engineers in Saudi Arabia. It consists of 50 multiple-choice questions over 3 hours, testing core chemical engineering fundamentals required for SCE Associate Engineer classification.

How is the full SCE FE exam structured?

The full SCE/Qiyas FE exam has two sessions: a 90-question general engineering part (3 hours) covering mathematics, physics, and basic engineering sciences, followed by a 50-question discipline-specific part (3 hours) in civil, mechanical, electrical, chemical, industrial, or structural engineering.

Who is eligible to take the SCE FE Chemical exam?

Senior students, recent graduates, and practicing engineers with a bachelor's degree in chemical engineering (or equivalent) from an accredited institution may register. Candidates must hold valid SCE membership and complete qualification verification before scheduling through Qiyas.

What is the passing score and exam fee?

SCE/Qiyas report FE results as pass or fail on a scaled basis; a fixed percentage passing score is not published on saudieng.sa. Per SCE FAQ, the Qiyas FE general portion costs 400 SAR and the discipline portion costs 400 SAR (800 SAR total per full attempt). Fees are paid through SADAD during Qiyas registration.

What topics are covered on the chemical discipline portion?

The chemical discipline exam covers thermodynamics, transport phenomena (heat, mass, and momentum transfer), reaction engineering, materials for chemical service, and process design including safety, control, and separation fundamentals.

Is the exam administered in Arabic or English?

The SCE/Qiyas FE exam is administered in English via computer-based testing at official Qiyas centers throughout Saudi Arabia. Candidates should be comfortable reading technical chemical engineering terminology in English.