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Exam Review

Key Facts: Nepal SEE Mathematics Exam

75

Theory Marks

25

Internal Assessment Marks

3 hours

Theory Paper Duration

35%

Minimum Theory Score

NEB

Conducting Board

The SEE Class 10 Compulsory Mathematics examination is conducted by the National Examinations Board (NEB) of Nepal through its Office of the Controller of Examinations (Class 10). It consists of a 75-mark written theory paper (3 hours) plus 25 marks of internal assessment, and students need at least 35% in theory to avoid a Non-Graded (NG) result. OpenExamPrep offers free independent practice questions on sets and arithmetic, geometry and mensuration, algebra, and statistics and probability. OpenExamPrep's questions are an independent English-language multiple-choice study adaptation of the curriculum topics. They are not an official translation of the board paper or a simulation of its written format.

Sample Nepal SEE Mathematics Practice Questions

Try these sample questions to review concepts for the Nepal SEE Mathematics exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1In a survey of 100 students in a secondary school, 65 like tea, 45 like coffee, and 15 like neither beverage. How many students like both tea and coffee?
A.25
B.15
C.20
D.30
Explanation: Let U be the universal set of surveyed students, T be the set of students who like tea, and C be the set who like coffee. We are given n(U) = 100, n(T) = 65, n(C) = 45, and n(T ∪ C)' = 15. The number of students who like at least one beverage is n(T ∪ C) = n(U) - n(T ∪ C)' = 100 - 15 = 85. Using the union cardinality formula n(T ∪ C) = n(T) + n(C) - n(T ∩ C), we have 85 = 65 + 45 - n(T ∩ C) = 110 - n(T ∩ C). Solving for the intersection gives n(T ∩ C) = 110 - 85 = 25 students.
2In a class of 50 students, 30 study Computer Science, 25 study Accountancy, and 8 study neither subject. How many students study only Computer Science?
A.13
B.21
C.25
D.17
Explanation: Let C and A represent the sets of students studying Computer Science and Accountancy respectively. The total number who study at least one subject is n(C ∪ A) = n(U) - n(C ∪ A)' = 50 - 8 = 42. The number studying both subjects is n(C ∩ A) = n(C) + n(A) - n(C ∪ A) = 30 + 25 - 42 = 55 - 42 = 13. The number studying only Computer Science is n_only(C) = n(C) - n(C ∩ A) = 30 - 13 = 17.
3In a community of 120 people, 70 speak Nepali, 55 speak Newari, and the ratio of those who speak both languages to those who speak neither language is 2:1. How many people speak both languages?
A.5
B.10
C.15
D.20
Explanation: Let n(N ∩ W) = 2x and n(N ∪ W)' = x. By the universal set formula, n(U) = n(N) + n(W) - n(N ∩ W) + n(N ∪ W)'. Substituting the given values: 120 = 70 + 55 - 2x + x, which simplifies to 120 = 125 - x. Solving for x gives x = 5. Therefore, the number of people who speak both languages is 2x = 2 * 5 = 10.
4In a school survey of 100 students, 48 play football (F), 45 play volleyball (V), and 40 play basketball (B). 18 play football and volleyball, 15 play volleyball and basketball, 17 play football and basketball, and 8 play all three games. How many students do not play any of the three games?
A.7
B.11
C.14
D.9
Explanation: By the three-set principle of inclusion-exclusion: n(F ∪ V ∪ B) = n(F) + n(V) + n(B) - [n(F ∩ V) + n(V ∩ B) + n(F ∩ B)] + n(F ∩ V ∩ B). Substituting the values: n(F ∪ V ∪ B) = 48 + 45 + 40 - (18 + 15 + 17) + 8 = 133 - 50 + 8 = 91. The number of students who play none of the three games is n(U) - n(F ∪ V ∪ B) = 100 - 91 = 9.
5Out of 80 tourists visiting Pokhara, 45 visited Sarangkot (S), 40 visited Peace Pagoda (P), and 35 visited Davis Fall (D). 20 visited both S and P, 18 visited both P and D, and 15 visited both S and D. If 5 tourists visited none of these three destinations, how many visited all three?
A.6
B.8
C.10
D.12
Explanation: The number of tourists visiting at least one destination is n(S ∪ P ∪ D) = 80 - 5 = 75. Let x = n(S ∩ P ∩ D). Using the inclusion-exclusion formula: n(S ∪ P ∪ D) = n(S) + n(P) + n(D) - [n(S ∩ P) + n(P ∩ D) + n(S ∩ D)] + x. Substituting: 75 = 45 + 40 + 35 - (20 + 18 + 15) + x = 120 - 53 + x = 67 + x. Solving for x yields x = 75 - 67 = 8 tourists.
6For two sets A and B, n(A) = 32, n(B) = 28 and n(A ∩ B) = 12. How many elements belong to exactly one of the two sets (only A or only B)?
A.24
B.48
C.60
D.36
Explanation: The symmetric difference of sets A and B consists of elements that belong to A or B but not to both: A Δ B = (A - B) ∪ (B - A). In terms of cardinalities: n(A Δ B) = n(A) + n(B) - 2 * n(A ∩ B). Substituting the values: n(A Δ B) = 32 + 28 - 2(12) = 60 - 24 = 36. Alternatively, n_only(A) = 32 - 12 = 20 and n_only(B) = 28 - 12 = 16, so 20 + 16 = 36.
7In an examination, 80% of candidates passed in English, 70% passed in Mathematics, and 10% failed in both subjects. If 360 candidates passed in both subjects, find the total number of candidates who appeared in the examination.
A.500
B.540
C.600
D.640
Explanation: Let total candidates be 100%. The percentage passing at least one subject is 100% - 10% = 90%. By the union formula: % passing both = % English + % Math - % at least one = 80% + 70% - 90% = 60%. We are given that 60% of the total candidates equals 360. Therefore, Total = 360 / 0.60 = 600 candidates.
8In a group of people, 65% like folk music, 55% like modern music, and each person likes at least one type of music. What percentage of people like only folk music?
A.45%
B.35%
C.40%
D.50%
Explanation: Since every person likes at least one type of music, n(F ∪ M) = 100%. The percentage who like both types is n(F ∩ M) = n(F) + n(M) - n(F ∪ M) = 65% + 55% - 100% = 120% - 100% = 20%. The percentage of people who like only folk music is n_only(F) = n(F) - n(F ∩ M) = 65% - 20% = 45%.
9Find the compound amount on NPR 20,000 for 2 years at an annual interest rate of 10% compounded annually.
A.NPR 22,000
B.NPR 24,000
C.NPR 24,200
D.NPR 25,410
Explanation: The formula for compound amount compounded annually is CA = P * (1 + R/100)^T. Substituting P = NPR 20,000, R = 10%, and T = 2 years: CA = 20000 * (1 + 10/100)^2 = 20000 * (1.1)^2 = 20000 * 1.21 = NPR 24,200.
10What is the compound interest on NPR 50,000 for 1.5 years (1 year 6 months) at 12% per annum compounded semi-annually?
A.NPR 9,550.80
B.NPR 9,000.00
C.NPR 9,360.00
D.NPR 9,702.61
Explanation: When compounded semi-annually, the half-yearly rate is R' = 12 / 2 = 6%, and the number of compounding periods is n = 1.5 * 2 = 3. The compound amount is CA = P * (1 + R'/100)^n = 50,000 * (1 + 0.06)^3 = 50,000 * 1.191016 = NPR 59,550.80. The compound interest is CI = CA - P = 59,550.80 - 50,000 = NPR 9,550.80.

About the Nepal SEE Mathematics Exam

The Secondary Education Examination (SEE) Class 10 Compulsory Mathematics examination is the national secondary exit test administered annually across Nepal by the National Examinations Board (NEB) Office of the Controller of Examinations in Sanothimi, Bhaktapur. As a mandatory core subject for all secondary candidates, it evaluates problem-solving proficiency, algebraic manipulation, geometric deductive reasoning, mensuration calculations, and statistical interpretation required for senior secondary (+2) and vocational technical curricula.

Exam sponsor: National Examinations Board (NEB) / Office of the Controller of Examinations (Class 10), Sanothimi, Bhaktapur. The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Written board examination: a 75-mark written theory paper (3 hours) plus 25 marks of internal assessment.

Time Limit

3 hours (theory paper)

Passing Score

At least 35% in the theory paper (below that: Non-Graded, NG)

Exam / Certification Fees

Set annually by NEB; paid through the school

Exam sponsor website

Reported exam pass rate: Not published by subject. Under NEB's letter-grading rules, a theory score below 35% is recorded as Non-Graded (NG) for that subject. Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

25% of practice bank

Sets & Arithmetic

Sets, compound interest, population growth and depreciation, and currency and taxation.

35% of practice bank

Geometry & Mensuration

Area and volume of plane and solid figures, triangles and quadrilaterals, and circle theorems.

25% of practice bank

Algebra

HCF and LCM, algebraic fractions, indices, and quadratic equations.

15% of practice bank

Statistics & Probability

Mean, median and quartiles of grouped data, and probability.

Preparing for the Nepal SEE Mathematics Exam

What You Need to Know

  • Passing score: At least 35% in the theory paper (below that: Non-Graded, NG)
  • Assessment: Written board examination: a 75-mark written theory paper (3 hours) plus 25 marks of internal assessment.
  • Time limit: 3 hours (theory paper)
  • Exam / certification fees: Set annually by NEB; paid through the school Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Nepal SEE Mathematics: Suggested Study Strategy

1Master high-yield arithmetic formulas for compound interest (annual and semi-annual), population growth, compound depreciation, and currency exchange.
2Memorize and practice the formal geometric proofs for circle theorems: angle at center is double the angle at circumference, angles in the same segment are equal, and opposite angles of cyclic quadrilaterals sum to 180°.
3Practice factoring polynomials thoroughly to solve HCF/LCM and algebraic fraction simplification problems without sign errors.
4Work through past CDC model questions under timed 3-hour conditions, ensuring neat diagram construction with pencil and ruler.

Frequently Asked Questions

What is the format of the SEE Class 10 Compulsory Mathematics examination?

The official assessment is a 75-mark written theory paper (3 hours) plus 25 marks of internal assessment. It is a written board examination, not a multiple-choice test.

What score is needed to pass SEE Class 10 Compulsory Mathematics?

Under NEB's letter-grading rules, students need at least 35% of the theory marks. A lower theory score is recorded as Non-Graded (NG) for the subject.

What happens if a student is Non-Graded (NG) in Compulsory Mathematics?

Students who are NG in up to two subjects can sit the grade-increment (supplementary) examination announced by NEB after the results; others take the subject again in a later regular examination.

Are these practice questions official NEB papers?

No. OpenExamPrep's questions are an independent English-language multiple-choice study adaptation of the curriculum topics. They are not an official translation of the board paper or a simulation of its written format. OpenExamPrep is independent and is not affiliated with or endorsed by NEB or the Curriculum Development Centre (CDC).