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Key Facts: NEB Class 12 Physics Exam

75

Theory Marks

25

Practical Examination Marks

3 hours

Theory Paper Duration

35%

Minimum Theory Score

NEB

Conducting Board

The NEB Class 12 Physics examination is conducted by the National Examinations Board (NEB) of Nepal. It consists of a 75-mark written theory paper (3 hours) plus 25 marks of practical examination, and students need at least 35% in theory to avoid a Non-Graded (NG) result. OpenExamPrep offers free independent practice questions on mechanics, waves and optics, thermodynamics, electricity and magnetism, and modern physics. OpenExamPrep's questions are an independent English-language multiple-choice study adaptation of the curriculum topics. They are not an official translation of the board paper or a simulation of its written format.

Sample NEB Class 12 Physics Practice Questions

Try these sample questions to review concepts for the NEB Class 12 Physics exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A uniform thin rod of mass M and length L is rotated about a transverse axis passing through its center of mass. What is its moment of inertia about this axis?
A.(1/12) M L^2
B.(1/3) M L^2
C.(1/2) M L^2
D.(1/4) M L^2
Explanation: By integrating dI = x^2 dm = (M/L) x^2 dx from x = -L/2 to x = +L/2, the moment of inertia of a uniform thin rod about an axis passing through its center and perpendicular to its length is I = (1/12) M L^2. If the transverse axis passes through one of its ends, the parallel axis theorem gives I = (1/12) M L^2 + M(L/2)^2 = (1/3) M L^2.
2A uniform solid cylinder of mass 4.0 kg and radius 0.20 m is rotated about its longitudinal axis of symmetry. What constant torque is required to produce an angular acceleration of 5.0 rad/s^2?
A.0.20 N·m
B.0.40 N·m
C.0.80 N·m
D.1.60 N·m
Explanation: For a solid cylinder rotating about its central longitudinal axis, the moment of inertia is I = (1/2) M R^2 = 0.5 * 4.0 kg * (0.20 m)^2 = 0.080 kg·m^2. Applying the rotational dynamic equation tau = I * alpha gives tau = 0.080 kg·m^2 * 5.0 rad/s^2 = 0.40 N·m.
3A heavy flywheel rotating at an initial speed of 600 rpm decelerates uniformly to 300 rpm in 10 seconds. How many complete revolutions does the flywheel execute during this 10-second interval?
A.75 revolutions
B.50 revolutions
C.100 revolutions
D.150 revolutions
Explanation: The average rotational speed during uniform angular deceleration is N_avg = (N1 + N2) / 2 = (600 + 300) / 2 = 450 rpm = 450 / 60 rev/s = 7.5 rev/s. The total number of revolutions executed in t = 10 s is theta = N_avg * t = 7.5 rev/s * 10 s = 75 revolutions.
4A uniform solid sphere of mass M and radius R rolls without slipping down a rough plane inclined at an angle theta to the horizontal. What is the linear acceleration of its center of mass?
A.(5/7) g sin(theta)
B.(3/5) g sin(theta)
C.(1/2) g sin(theta)
D.(2/3) g sin(theta)
Explanation: For any rigid body rolling without slipping down an inclined plane, the linear acceleration is a = (g sin(theta)) / (1 + k^2 / R^2). For a solid sphere, I = (2/5) M R^2, so k^2 / R^2 = 2/5. Substituting this value gives a = (g sin(theta)) / (1 + 2/5) = (g sin(theta)) / (7/5) = (5/7) g sin(theta).
5A child of mass 30 kg stands at the outer rim of a circular platform of mass 120 kg and radius 2.0 m rotating freely at 2.0 rad/s about its central vertical axis. If the child walks inward to the exact center of the platform, what is the new angular velocity?
A.2.5 rad/s
B.3.0 rad/s
C.3.5 rad/s
D.4.0 rad/s
Explanation: By conservation of angular momentum, L1 = L2, where L = I * omega. The platform's moment of inertia is I_p = (1/2) M R^2 = 0.5 * 120 * (2.0)^2 = 240 kg·m^2. Initially, with the child at the edge (r = 2.0 m), the child's moment of inertia is I_c1 = m r^2 = 30 * (2.0)^2 = 120 kg·m^2. The total initial moment of inertia is I1 = 240 + 120 = 360 kg·m^2. At the center (r = 0), the child's moment of inertia is zero, so I2 = 240 kg·m^2. Therefore, omega2 = omega1 * (I1 / I2) = 2.0 * (360 / 240) = 2.0 * 1.5 = 3.0 rad/s.
6What is the radius of gyration k of a uniform solid circular disc of radius R about an axis perpendicular to its plane and passing through its center?
A.R / 2
B.R / sqrt(3)
C.sqrt(2) R
D.R / sqrt(2)
Explanation: The moment of inertia of a uniform circular disc of mass M and radius R about its central transverse axis is I = (1/2) M R^2. By definition of radius of gyration, I = M k^2. Setting M k^2 = (1/2) M R^2 gives k^2 = R^2 / 2, which yields k = R / sqrt(2).
7A uniform meter rod of mass 0.60 kg is pivoted freely at one end and held horizontally. When released from rest, what is its initial angular acceleration? (Take g = 9.8 m/s^2)
A.9.8 rad/s^2
B.14.7 rad/s^2
C.19.6 rad/s^2
D.29.4 rad/s^2
Explanation: The center of mass of the uniform meter rod (L = 1.0 m) is located at L/2 = 0.50 m from the pivot. The torque due to gravity about the pivot is tau = M * g * (L / 2). The moment of inertia of the rod about an axis through one end is I = (1/3) M L^2. Using tau = I * alpha gives alpha = (M g L / 2) / ((1/3) M L^2) = (3 g) / (2 L). Substituting g = 9.8 m/s^2 and L = 1.0 m yields alpha = (3 * 9.8) / (2 * 1.0) = 29.4 / 2 = 14.7 rad/s^2.
8A particle executes simple harmonic motion (SHM) with amplitude A. At what displacement from the mean position is its kinetic energy three times its potential energy?
A.x = ± A / 4
B.x = ± A / sqrt(2)
C.x = ± A / 2
D.x = ± A / sqrt(3)
Explanation: In SHM, PE = (1/2) m omega^2 x^2 and KE = (1/2) m omega^2 (A^2 - x^2). Setting KE = 3 PE gives A^2 - x^2 = 3x^2, so 4x^2 = A^2 and x = ± A/2. At this point PE is one-quarter and KE three-quarters of the total energy.
9A block of mass 0.50 kg attached to an ideal horizontal spring of force constant k = 200 N/m oscillates with an amplitude of 0.10 m on a frictionless surface. What is the maximum speed of the block?
A.2.0 m/s
B.1.0 m/s
C.4.0 m/s
D.10.0 m/s
Explanation: The angular frequency of the mass-spring oscillator is omega = sqrt(k / m) = sqrt(200 / 0.50) = sqrt(400) = 20 rad/s. The maximum speed in SHM occurs at the equilibrium position and is given by v_max = A * omega = 0.10 m * 20 rad/s = 2.0 m/s.
10A simple pendulum has a time period of 2.0 s at the surface of the Earth. What would be its period on the Moon, where the acceleration due to gravity is approximately one-sixth of that on Earth?
A.0.33 s
B.0.82 s
C.4.90 s
D.12.0 s
Explanation: The period of a simple pendulum is T = 2 pi * sqrt(L / g). Therefore, T is inversely proportional to sqrt(g). Taking T_moon / T_earth = sqrt(g_earth / g_moon) = sqrt(6) ≈ 2.449. The period on the Moon is T_moon = 2.0 s * sqrt(6) ≈ 2.0 * 2.449 = 4.90 s.

About the NEB Class 12 Physics Exam

The Nepal NEB Class 12 Physics Examination is the national secondary school leaving board examination administered by the National Examinations Board (NEB), Bhaktapur. The theory curriculum encompasses Mechanics, Heat and Thermodynamics, Wave Motion and Optics, Electricity and Magnetism, and Modern Physics, evaluated via a 3-hour 75-mark written paper alongside practical laboratory assessment.

Exam sponsor: National Examinations Board (NEB), Sanothimi, Bhaktapur. The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Written board examination: a 75-mark written theory paper (3 hours) plus 25 marks of practical examination.

Time Limit

3 hours (theory paper)

Passing Score

At least 35% in the theory paper (below that: Non-Graded, NG)

Exam / Certification Fees

Set annually by NEB; paid through the school

Exam sponsor website

Reported exam pass rate: Not published by subject. Under NEB's letter-grading rules, a theory score below 35% is recorded as Non-Graded (NG) for that subject. Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

22% of practice bank

Mechanics

Rotational dynamics, periodic motion, fluids and elasticity.

23% of practice bank

Waves & Optics

Wave motion, sound, and wave optics.

15% of practice bank

Heat & Thermodynamics

Thermodynamic processes, the laws of thermodynamics, and kinetic theory.

25% of practice bank

Electricity & Magnetism

Electric circuits, magnetic effects of current, electromagnetic induction and AC.

15% of practice bank

Modern Physics

Electrons, photons, atomic and nuclear physics, and semiconductors.

Preparing for the NEB Class 12 Physics Exam

What You Need to Know

  • Passing score: At least 35% in the theory paper (below that: Non-Graded, NG)
  • Assessment: Written board examination: a 75-mark written theory paper (3 hours) plus 25 marks of practical examination.
  • Time limit: 3 hours (theory paper)
  • Exam / certification fees: Set annually by NEB; paid through the school Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

NEB Class 12 Physics: Suggested Study Strategy

1Master core mechanics and rotational dynamics numericals: moment of inertia calculations, angular momentum conservation, SHM energy equations, and terminal velocity problems.
2Thoroughly practice thermodynamics derivations and calculations: isothermal vs adiabatic work done, Cp - Cv = R Mayer's relation, and Carnot engine efficiencies.
3Understand wave optics formulas: Young's double-slit fringe width, single-slit diffraction minima, grating resolving conditions, Brewster's angle, and Malus's law.
4Solve DC circuit and AC resonance problems systematically: Kirchhoff's laws, potentiometer balance equations, Biot-Savart magnetic fields, and series LCR impedance.

Frequently Asked Questions

What is the format of the NEB Class 12 Physics examination?

The official assessment is a 75-mark written theory paper (3 hours) plus 25 marks of practical examination. It is a written board examination, not a multiple-choice test.

What score is needed to pass NEB Class 12 Physics?

Under NEB's letter-grading rules, students need at least 35% of the theory marks. A lower theory score is recorded as Non-Graded (NG) for the subject.

What happens if a student is Non-Graded (NG) in Physics?

Students who are NG in up to two subjects can sit the grade-increment (supplementary) examination announced by NEB after the results; others take the subject again in a later regular examination.

Are these practice questions official NEB papers?

No. OpenExamPrep's questions are an independent English-language multiple-choice study adaptation of the curriculum topics. They are not an official translation of the board paper or a simulation of its written format. OpenExamPrep is independent and is not affiliated with or endorsed by NEB or the Curriculum Development Centre (CDC).