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MECEE-PG Medical Education Common Entrance Examination (Nepal)

Practice Questions114 questions

Exam Review

Key Facts: MECEE-BL Nepal Exam

200

Total Questions

180 min

Exam Time

50th

Min Qualifying Percentile

4,000 NPR

Nepali Applicant Fee

MECEE-BL is Nepal's common entrance examination for bachelor-level medical and health-science programmes, run by the Medical Education Commission (MEC). The single paper has 200 single-best-response multiple-choice questions worth 200 marks over 3 hours: Physics 50, Chemistry 50, Botany 40, Zoology 40, and Mental Agility Test 20. Candidates must reach at least the 50th percentile to qualify for the merit list. OpenExamPrep provides free independent practice questions.

Sample MECEE-BL Nepal Practice Questions

Try these sample questions to review concepts for the MECEE-BL Nepal exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A projectile is launched from ground level with an initial velocity of 30 m/s at an elevation angle of 30° to the horizontal. Assuming g = 10 m/s² and negligible air resistance, what is the maximum vertical height reached by the projectile?

A.22.5 m

B.45 m

C.5.6 m

D.11.25 m

Explanation: The maximum height for a projectile launched with speed u at angle θ is H = (u² sin²θ) / (2g). Here u = 30 m/s, sin 30° = 0.5 and g = 10 m/s², so H = [900 × 0.25] / 20 = 225 / 20 = 11.25 m.

2A curved roadway with a radius of curvature of 200 m is banked for an optimum design speed of 72 km/h without relying on friction. Taking g = 10 m/s², what is the required banking angle θ of the road?

A.tan⁻¹(0.4)

B.tan⁻¹(0.2)

C.tan⁻¹(0.1)

D.tan⁻¹(0.5)

Explanation: Convert speed: v = 72 km/h = 72 × (5/18) = 20 m/s. For a banked curve without friction, the horizontal component of the normal reaction provides the centripetal force: N sinθ = m v² / r, and N cosθ = m g. Dividing gives tanθ = v² / (r g) = (20)² / (200 × 10) = 400 / 2000 = 0.2. Hence, θ = tan⁻¹(0.2).

3A vehicle traveling along a horizontal straight road at 20 m/s brakes to a complete halt. If the coefficient of kinetic friction between the tyres and the road surface is μ = 0.5 and g = 10 m/s², what is the minimum stopping distance?

A.20 m

B.80 m

C.40 m

D.10 m

Explanation: By the work-energy theorem or kinematics: v² - u² = 2 a s. Here v = 0, u = 20 m/s, and deceleration is a = -μ g = -(0.5 × 10) = -5 m/s². Therefore, 0 - (20)² = 2 (-5) s, which gives -400 = -10 s, yielding s = 40 m.

4A solid uniform sphere and a solid cylinder having identical mass M and outer radius R roll down the same inclined plane from rest without slipping. What is the ratio of the linear acceleration of the sphere to that of the cylinder (a_sphere / a_cylinder)?

A.14 / 15

B.15 / 14

C.5 / 4

D.7 / 6

Explanation: For any rigid body rolling without slipping down an incline θ: a = (g sinθ) / [1 + I / (M R²)]. For a solid sphere, I = (2/5) M R², so a_sphere = (g sinθ) / [1 + 2/5] = (5/7) g sinθ. For a solid cylinder, I = (1/2) M R², so a_cylinder = (g sinθ) / [1 + 1/2] = (2/3) g sinθ. The ratio a_sphere / a_cylinder = (5/7) / (2/3) = (5/7) × (3/2) = 15/14.

5At what depth d below the surface of the Earth will the acceleration due to gravity become one-fourth (g/4) of its value at the surface? (Let R be the radius of the Earth, assumed spherical of uniform density).

A.R / 4

B.R / 2

C.R / 8

D.3R / 4

Explanation: The acceleration due to gravity at depth d below the Earth's surface is given by g_d = g (1 - d/R). Setting g_d = g/4: g/4 = g (1 - d/R) => 1 - d/R = 1/4 => d/R = 1 - 1/4 = 3/4 => d = 3R/4.

6A particle executes simple harmonic motion (SHM) with amplitude A about an equilibrium position. At what displacement x from the mean position is its kinetic energy exactly equal to its potential energy?

A.A / 2

B.A / √2

C.A / (2√2)

D.(A√3) / 2

Explanation: In SHM, kinetic energy is K = (1/2) m ω² (A² - x²) and potential energy is U = (1/2) m ω² x². Equating K = U: A² - x² = x² => 2 x² = A² => x² = A² / 2 => x = ± A / √2.

7What is the excess pressure inside a hollow spherical soap bubble of radius r = 2 mm floating in air, given that the surface tension of the soap solution is T = 0.03 N/m?

A.30 Pa

B.60 Pa

C.120 Pa

D.15 Pa

Explanation: A soap bubble in air has two liquid-air interfaces (inner and outer surfaces). Therefore, the excess pressure is ΔP = 4T / r. Here, T = 0.03 N/m and r = 2 mm = 2 × 10⁻³ m. Thus: ΔP = (4 × 0.03) / (2 × 10⁻³) = 0.12 / 0.002 = 60 N/m² (60 Pa).

8Two spherical water droplets with radii in the ratio 1 : 3 fall through calm air at terminal velocity, governed by Stokes' law. What is the ratio of their terminal velocities (v₁ : v₂)?

A.1 : 3

B.1 : 27

C.1 : 9

D.3 : 1

Explanation: By Stokes' law, terminal velocity is v_t = [2 r² (ρ - σ) g] / (9 η), so v_t ∝ r². With radii in the ratio 1 : 3, the terminal velocities are in the ratio 1² : 3² = 1 : 9.

9A pendulum clock keeps accurate time at 15°C. The pendulum rod has a linear thermal expansion coefficient α = 2.0 × 10⁻⁵ K⁻¹. If the ambient temperature increases to 35°C, how much time does the clock lose in a full 24-hour day?

A.8.64 s

B.17.28 s

C.34.56 s

D.4.32 s

Explanation: The fractional change in period for a pendulum undergoing thermal expansion is ΔT / T = (1/2) α Δθ. Here Δθ = 35 - 15 = 20 K. So ΔT / T = (1/2) × (2.0 × 10⁻⁵) × 20 = 2.0 × 10⁻⁴. In one day (86,400 seconds), time lost is Δt = 86,400 × (2.0 × 10⁻⁴) = 17.28 seconds.

10A sample of a monoatomic ideal gas (γ = 5/3) initially at an absolute temperature of 300 K and volume V₁ is compressed adiabatically to one-eighth of its initial volume (V₂ = V₁ / 8). What is the final temperature T₂ of the gas?

A.600 K

B.900 K

C.1200 K

D.2400 K

Explanation: For a reversible adiabatic process: T V^(γ - 1) = constant. Therefore, T₂ = T₁ × (V₁ / V₂)^(γ - 1). Here γ = 5/3, so γ - 1 = 2/3. With V₁ / V₂ = 8: T₂ = 300 × (8)^(2/3) = 300 × (2³)^(2/3) = 300 × 2² = 300 × 4 = 1200 K.

About the MECEE-BL Nepal Exam

The MECEE-BL (Medical Education Common Entrance Examination for Bachelor Level) is Nepal's single national common entrance examination for undergraduate medical, dental, and health sciences programs (MBBS, BDS, BSc Nursing, BAMS, B.Pharm, BPT, B.Sc. MLT, BPH). Administered by the Medical Education Commission (MEC), the examination tests 200 multiple-choice questions across Physics (50 marks), Chemistry (50 marks), Botany (40 marks), Zoology (40 marks), and Mental Agility Test (20 marks) with a 0.25 mark penalty for wrong answers.

Exam sponsor: Medical Education Commission (MEC), Government of Nepal. The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Single paper of 200 single-best-response multiple-choice questions (200 marks) in 180 minutes: Physics 50, Chemistry 50, Botany 40, Zoology 40, and Mental Agility Test 20.

Time Limit

180 minutes

Passing Score

Minimum 50th percentile

Exam / Certification Fees

4,000 NPR

Exam sponsor website

Reported exam pass rate: Merit-based admission rank determining allocation of government scholarship and paying seats. Top ranks are required for subsidized scholarship seats in public medical colleges such as IOM Maharajgunj, BPKIHS Dharan, and PAHS Patan. Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

25%

Physics

50 marks total covering mechanics, heat and thermodynamics, wave motion, geometric and wave optics, electrostatics, current electricity, magnetism, electromagnetic induction, modern physics, nuclear physics, and semiconductors.

25%

Chemistry

50 marks total covering physical chemistry (atomic structure, chemical kinetics, thermodynamics, solutions, electrochemistry, ionic equilibria), inorganic chemistry (periodic properties, non-metals, metals and metallurgy, transition metals), and organic chemistry (hydrocarbons, organic halogen/oxygen/nitrogen compounds, polymers, and biomolecules).

20%

Botany

40 marks total covering plant diversity (monera, fungi, algae, bryophytes, pteridophytes, gymnosperms, angiosperms), plant morphology and anatomy, plant physiology (photosynthesis, cellular respiration, transpiration, mineral nutrition, growth regulators), cell biology, genetics, and ecology.

20%

Zoology

40 marks total covering animal diversity (invertebrate phyla and chordates), animal tissues, human organ systems (digestive, circulatory, respiratory, excretory, nervous, endocrine, and reproductive systems), embryology, genetics, organic evolution, and human health, diseases, and parasites.

10%

Mental Agility Test (MAT)

20 marks total covering verbal reasoning, numerical ability, arithmetic problem solving, logical deduction, sequence and series completion, and abstract spatial reasoning.

Preparing for the MECEE-BL Nepal Exam

What You Need to Know

Passing score: Minimum 50th percentile
Assessment: Single paper of 200 single-best-response multiple-choice questions (200 marks) in 180 minutes: Physics 50, Chemistry 50, Botany 40, Zoology 40, and Mental Agility Test 20.
Time limit: 180 minutes
Exam / certification fees: 4,000 NPR Official sources

Using Our Practice Resources

Work through all 100 available questions
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MECEE-BL Nepal: Suggested Study Strategy

1Physics and Chemistry carry 50 marks each, so practise numerical problems in mechanics, electricity, stoichiometry and equilibrium.

2Revise Grade 11 and 12 Biology diagrams, cycles and classification for the 80 Botany and Zoology marks.

3Practise Mental Agility Test (MAT) questions regularly to secure its 20 marks quickly.

4Take full 200-question timed practice sets to build stamina for the 3-hour paper.

Frequently Asked Questions

What is the examination pattern and marking scheme for MECEE-BL?

The examination has 200 single-best-response multiple-choice questions with four options each, taken over 180 minutes (3 hours). Each question carries 1 mark, for a total of 200 marks.

What is the subject breakdown in the MECEE-BL paper?

The 200 marks are divided into Physics (50 marks), Chemistry (50 marks), Botany (40 marks), Zoology (40 marks), and Mental Agility Test (20 marks).

What is the passing score or qualifying cutoff for MECEE-BL?

Candidates must reach at least the 50th percentile to be included in the merit list for seat allocation and counselling.

Is OpenExamPrep affiliated with the Medical Education Commission (MEC) Nepal?

No. OpenExamPrep is an independent educational prep platform and is not affiliated with, authorized, endorsed, or sponsored by the Medical Education Commission (MEC) or the Government of Nepal. All questions and learning materials are prepared independently for exam practice.

What programs are included under MECEE-BL entrance in Nepal?

MECEE-BL is the common entrance for bachelor-level medical and health-science programmes in Nepal, such as MBBS, BDS, B.Sc. Nursing, B.Pharm, BAMS and other health programmes, as listed in the annual MEC notice.