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100+ Free WBCHSE HS Chemistry Practice Questions

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Key Facts: WBCHSE HS Chemistry Exam

CHEM

Official WBCHSE subject code

https://wbchse.wb.gov.in/subjects/

30%

Minimum pass in theory and practical/project independently

https://wbchse.wb.gov.in/frequently-asked-questions-examination

INR 215

Class XII semester enrolment total (INR 190 to Council)

WBCHSE Memo L/PR/305/2025

bn+en

Non-language elective paper media (Bengali and English)

WBCHSE examination regulations

Sem I–IV

Higher Secondary semester system across Classes XI–XII

https://wbchse.wb.gov.in/annual-working-plan

Crucial for science students aiming for engineering or medical entrance exams. Requires deep conceptual understanding and problem-solving skills. English-language MCQ study adaptation for WBCHSE HS—not an official board paper.

Sample WBCHSE HS Chemistry Practice Questions

Try these sample questions to test your WBCHSE HS Chemistry exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1What is the total number of atoms present per unit cell in a primitive (simple) cubic lattice?
A.1 atom
B.2 atoms
C.4 atoms
D.8 atoms
Explanation: In a primitive cubic unit cell, atoms are located only at the 8 corners. Each corner atom is shared equally by 8 adjacent unit cells, giving a net total of 8 × (1/8) = 1 atom per unit cell.
2A metallic element crystallizes in a face-centred cubic (fcc) lattice with a unit cell edge length of 400 pm. If the atomic mass of the element is 60 g/mol, what is the density of the crystal? (Avogadro's number = 6.022 × 10²³ mol⁻¹)
A.3.12 g/cm³
B.6.22 g/cm³
C.1.55 g/cm³
D.12.44 g/cm³
Explanation: For an fcc crystal, the number of atoms per unit cell Z = 4. Using the density formula d = (Z × M) / (a³ × N_A), with edge length a = 400 pm = 4.0 × 10⁻⁸ cm, d = (4 × 60) / ((4.0 × 10⁻⁸)³ × 6.022 × 10²³) = 240 / (6.4 × 10⁻²³ × 6.022 × 10²³) = 6.22 g/cm³.
3In a close-packed arrangement of N spheres, what are the respective numbers of tetrahedral and octahedral voids created in the lattice?
A.N tetrahedral and 2N octahedral voids
B.2N tetrahedral and N octahedral voids
C.N tetrahedral and N octahedral voids
D.2N tetrahedral and 2N octahedral voids
Explanation: For a close-packed lattice containing N atoms or spheres, the number of octahedral voids formed is equal to N, whereas the number of tetrahedral voids formed is equal to 2N.
4A sample of ferrous oxide has the non-stoichiometric formula Fe₀.₉₅O. What type of crystal defect is responsible for this non-stoichiometric composition?
A.Frenkel defect
B.Metal excess defect due to anionic vacancies
C.Metal deficiency defect due to cation vacancies
D.Impurity defect
Explanation: Fe₀.₉₅O is a non-stoichiometric compound exhibiting a metal deficiency defect. Some Fe²⁺ ions are missing from their lattice sites, and the charge neutrality is maintained by the presence of a required number of Fe³⁺ ions.
5Which of the following crystalline solids is classified as a covalent network solid?
A.Sodium chloride (NaCl)
B.Silicon carbide (SiC)
C.Iodine (I₂)
D.Copper (Cu)
Explanation: Silicon carbide (SiC), like diamond and quartz (SiO₂), consists of atoms bonded by continuous covalent bonds throughout a three-dimensional network, making it a covalent network solid.
6In a body-centred cubic (bcc) crystal lattice of a pure metal, what is the exact mathematical relation between the atomic radius (r) and the unit cell edge length (a)?
A.r = a / 2
B.r = (√2 / 4) a
C.r = (√3 / 4) a
D.r = (√3 / 2) a
Explanation: In a bcc lattice, the atoms touch each other along the body diagonal of length √3 a. The body diagonal equals 4 atomic radii (4r), so 4r = √3 a, which yields r = (√3 / 4) a.
7For an ideal binary liquid solution formed by mixing pure liquids A and B, which thermodynamic conditions must be satisfied?
A.ΔH_mix > 0 and ΔV_mix = 0
B.ΔH_mix = 0 and ΔV_mix = 0
C.ΔH_mix < 0 and ΔV_mix > 0
D.ΔH_mix = 0 and ΔV_mix > 0
Explanation: An ideal solution obeys Raoult's law over the entire range of concentration. In such solutions, solute-solvent intermolecular forces equal pure component forces, resulting in enthalpy of mixing ΔH_mix = 0 and volume change of mixing ΔV_mix = 0.
8What is the osmotic pressure of a 0.1 M aqueous solution of NaCl at 300 K, assuming complete dissociation of NaCl? (R = 0.0821 L·atm·K⁻¹·mol⁻¹)
A.2.46 atm
B.4.93 atm
C.1.23 atm
D.9.85 atm
Explanation: NaCl dissociates completely into Na⁺ and Cl⁻ ions, giving a van 't Hoff factor i = 2. Using the osmotic pressure formula Π = i C R T = 2 × (0.1 mol/L) × (0.0821 L·atm·K⁻¹·mol⁻¹) × 300 K = 4.926 atm ≈ 4.93 atm.
9When 18 g of glucose (C₆H₁₂O₆, molar mass = 180 g/mol) is dissolved in 1 kg of pure water, what is the boiling point of the solution? (K_b for water = 0.52 K·kg·mol⁻¹)
A.100.052 °C
B.100.52 °C
C.99.948 °C
D.101.04 °C
Explanation: Moles of glucose = 18 / 180 = 0.1 mol. Molality m = 0.1 mol / 1 kg = 0.1 m. The boiling point elevation ΔT_b = K_b × m = 0.52 × 0.1 = 0.052 °C. Thus, the boiling point of the solution is 100 °C + 0.052 °C = 100.052 °C.
10Potassium ferrocyanide, K₄[Fe(CN)₆], undergoes 80% dissociation in an aqueous solution. What is the van 't Hoff factor (i) for the solute under these conditions?
A.4.2
B.5.0
C.3.2
D.4.0
Explanation: K₄[Fe(CN)₆] dissociates into 4 K⁺ ions and 1 [Fe(CN)₆]⁴⁻ complex ion, yielding n = 5 total ions. With degree of dissociation α = 0.80, the van 't Hoff factor i = 1 + (n - 1)α = 1 + (5 - 1)(0.80) = 1 + 3.2 = 4.2.

About the WBCHSE HS Chemistry Exam

The WBCHSE Class 12 Chemistry exam is a comprehensive assessment covering Physical, Inorganic, and Organic Chemistry based on the latest syllabus. This OpenExamPrep bank is an English-language four-option MCQ study aid for WBCHSE Higher Secondary; it does not replace official Bengali/English board papers, descriptive answers, or required practical/project/performance evidence.

Assessment

WBCHSE Higher Secondary subject CHEM: Semesters I–IV across Classes XI–XII; theory examinations plus practical/project/performance where the syllabus requires them.

Time Limit

As per semester notification (typically 2–3 hours for theory sittings)

Passing Score

30% minimum in theory and in practical/project independently (WBCHSE examination FAQ)

Exam Fee

Semester enrolment fee structure (Council): Sem III/IV student total INR 215 (155 enrolment + 30 processing + 30 convenience), with INR 190 to Council and INR 25 centre grant; supplementary often INR 50/paper. Separately, the public Fees page lists Class XII examination fees (within schedule) about INR 205 lab / INR 195 non-lab / INR 135 special. Confirm the applicable circular for the sitting. (West Bengal Council of Higher Secondary Education (WBCHSE))

WBCHSE HS Chemistry Exam Content Outline

core

Section 1: Core Concepts

Detailed review and practice questions covering essential topics for in-wbchse-hs-chemistry.

core

Section 2: Core Concepts

Detailed review and practice questions covering essential topics for in-wbchse-hs-chemistry.

core

Section 3: Core Concepts

Detailed review and practice questions covering essential topics for in-wbchse-hs-chemistry.

How to Pass the WBCHSE HS Chemistry Exam

What You Need to Know

  • Passing score: 30% minimum in theory and in practical/project independently (WBCHSE examination FAQ)
  • Assessment: WBCHSE Higher Secondary subject CHEM: Semesters I–IV across Classes XI–XII; theory examinations plus practical/project/performance where the syllabus requires them.
  • Time limit: As per semester notification (typically 2–3 hours for theory sittings)
  • Exam fee: Semester enrolment fee structure (Council): Sem III/IV student total INR 215 (155 enrolment + 30 processing + 30 convenience), with INR 190 to Council and INR 25 centre grant; supplementary often INR 50/paper. Separately, the public Fees page lists Class XII examination fees (within schedule) about INR 205 lab / INR 195 non-lab / INR 135 special. Confirm the applicable circular for the sitting.

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

WBCHSE HS Chemistry Study Tips from Top Performers

1Practice numerical problems daily from Electrochemistry and Kinetics.
2Maintain a separate notebook for Organic Chemistry named reactions and conversions.
3Understand the trends in the periodic table for p-block and d-block elements.
4Solve previous 5-10 years' question papers to understand the pattern.
5Give equal importance to practicals as they carry 30 marks.

Frequently Asked Questions

What is the weightage of Physical Chemistry?

Physical Chemistry typically carries around 23-25 marks out of the 70 theory marks.

Are there numericals in the exam?

Yes, numerical problems are primarily asked from Physical Chemistry topics like Solutions, Electrochemistry, and Chemical Kinetics.

How important are named reactions?

Named reactions in Organic Chemistry are extremely important and frequently asked directly or as part of conversions.

What is the passing criteria?

Students must secure at least 30% in theory and in practical/project independently for the mandatory best-of-five subjects (two languages and three electives), per the Council examination FAQ.

Is NCERT enough for WBCHSE?

While the syllabus aligns closely with NCERT, practicing from state board recommended textbooks like Chhaya Prakashani or Santra Publication is highly advised.

Can I use a calculator during the exam?

Usually, standard non-programmable calculators are allowed, but students should verify with the current year's admit card instructions.

Are these MCQs identical to the official WBCHSE CHEM question paper?

No. Official non-language elective papers are set in Bengali and English under the semester system and may include descriptive and practical/project components. These items are an English MCQ study adaptation only.