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100+ Free Kerala Plus Two Physics (DHSE) Practice Questions

Kerala Higher Secondary (Plus Two / Class 12) Physics under the Directorate of Higher Secondary Education (DHSE), Kerala practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: Kerala Plus Two Physics (DHSE) Exam

100 marks

Subject total via TE + CE + PE (exact splits as notified)

DHSE Kerala Plus Two assessment pattern

~2 h + cool-off

Typical Physics theory duration for practical subjects

DHSE Plus Two timetable logistics

D+ / ~30%

Common pass grade/aggregate with separate TE floor

Kerala Plus Two grading / pass criteria reporting

Mixed + practical

Official format is mixed written TE plus PE and CE, not pure MCQ

DHSE Kerala Plus Two Physics assessment pattern

English MCQ adaptation

This free local bank is not the official mixed paper format

OpenExamPrep practice policy

DHSE Kerala

Administrator: Directorate of Higher Secondary Education

Government of Kerala Higher Secondary system

Kerala Plus Two Physics (DHSE) totals 100 marks via TE + CE + PE; theory is commonly ~2 h plus cool-off. Pass is commonly D+/~30% aggregate with ~30% in TE separately as notified. Fees are paid through schools. This free 2026 bank is an English MCQ study adaptation — not an official paper simulation.

Sample Kerala Plus Two Physics (DHSE) Practice Questions

Try these sample questions to test your Kerala Plus Two Physics (DHSE) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Two point charges +q and +4q are separated by distance d in vacuum. The electric field is zero at a point on the line joining them, a distance x from +q toward +4q. The value of x is:
A.d/3
B.d/5
C.d/4
D.2d/5
Explanation: Between like charges the null point lies closer to the smaller charge. Set kq/x² = k(4q)/(d−x)², so 1/x = 2/(d−x), hence d−x = 2x and x = d/3.
2The electrostatic force between two point charges separated by distance r in vacuum is F. If both charges and the separation are each doubled, the new force is:
A.F/2
B.F
C.2F
D.4F
Explanation: F' = k(2q₁)(2q₂)/(2r)² = k(4q₁q₂)/(4r²) = kq₁q₂/r² = F. Charge and distance factors cancel.
3Electric flux through a closed surface is zero. Which statement must be true?
A.Electric field is zero everywhere on the surface
B.Net charge enclosed by the surface is zero
C.The surface is an equipotential
D.No charge exists anywhere in space
Explanation: By Gauss’s law, Φ_E = Q_encl/ε₀. Zero flux means Q_encl = 0. Field on the surface need not vanish.
4A charge Q is placed at the centre of a cube of side a. The electric flux through one face of the cube is:
A.Q/(6ε₀)
B.Q/(8ε₀)
C.Q/(24ε₀)
D.Q/ε₀
Explanation: Total flux through the closed cube is Q/ε₀. By symmetry each of the six faces carries equal flux Q/(6ε₀).
5An electric dipole of moment p is placed in a uniform electric field E. The torque on the dipole has maximum magnitude when the angle between p and E is:
A.0°
B.45°
C.90°
D.180°
Explanation: τ = pE sinθ. Maximum torque is pE when sinθ = 1, i.e., θ = 90°.
6The electric field due to an infinite non-conducting plane sheet of surface charge density σ in vacuum has magnitude:
A.σ/(2ε₀)
B.σ/ε₀
C.σ/(4ε₀)
D.2σ/ε₀
Explanation: Using a Gaussian pillbox, 2EA = (σA)/ε₀ gives E = σ/(2ε₀), independent of distance for an infinite sheet.
7Two charges +2 μC and −2 μC form an electric dipole of separation 2 cm. Dipole moment magnitude is:
A.4 × 10⁻⁸ C·m
B.2 × 10⁻⁸ C·m
C.4 × 10⁻⁶ C·m
D.2 × 10⁻⁶ C·m
Explanation: p = q × separation = (2 × 10⁻⁶ C)(0.02 m) = 4 × 10⁻⁸ C·m.
8A proton is released from rest in a uniform electric field of 500 N/C. Acceleration of the proton (m_p ≈ 1.67 × 10⁻²⁷ kg, e = 1.6 × 10⁻¹⁹ C) is approximately:
A.4.8 × 10¹⁰ m/s²
B.4.8 × 10⁷ m/s²
C.8.0 × 10¹⁰ m/s²
D.1.6 × 10⁻¹⁶ m/s²
Explanation: a = qE/m = (1.6 × 10⁻¹⁹)(500)/(1.67 × 10⁻²⁷) ≈ 4.8 × 10¹⁰ m/s².
9Which of the following is not a property of electrostatic field lines?
A.They start on positive charges and end on negative charges
B.They never form closed loops in electrostatics
C.Two field lines can intersect at a point
D.Their density represents field strength
Explanation: Field lines never intersect: intersection would imply two different field directions at one point.
10A thin spherical shell of radius R carries uniform surface charge Q. Electric field magnitude at r = R/2 from the centre is:
A.zero
B.kQ/R²
C.kQ/(4R²)
D.kQ/(2R²)
Explanation: For a thin spherical shell, all charge is on the surface. By Gauss’s law, for r < R the enclosed charge is zero, so E = 0 inside.

About the Kerala Plus Two Physics (DHSE) Practice Questions

Verified exam format metadata for Kerala Higher Secondary (Plus Two / Class 12) Physics under the Directorate of Higher Secondary Education (DHSE), Kerala is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.