100+ Free IIT JAM CY Practice Questions

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Heisenberg's uncertainty principle states that:

Δx · Δp ≥ ℏ/2

ΔE · Δt = c (speed of light)

Δx · Δp = mass × velocity

Δx + Δp = 0

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2026 Statistics

Key Facts: IIT JAM CY Exam

60 questions

Total JAM CY questions in 180 minutes (30 MCQ + 10 MSQ + 20 NAT)

jam2026.iitb.ac.in

100 marks

Total marks; negative marking only on MCQs (−1/3 or −2/3)

JAM 2026 Information Brochure

INR 2100

Application fee for General/EWS/OBC-NCL (one paper, JAM 2026)

IIT Bombay JAM 2026

~3,000 seats

MSc/PhD seats filled across IITs/IISc/CCMN via JAM

JAM Annual Report

100

Free practice questions here

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IIT JAM Chemistry (CY) is a 3-hour CBT with 60 questions (30 MCQ + 10 MSQ + 20 NAT) totalling 100 marks; only MCQs carry negative marking (−1/3 or −2/3). JAM 2026 is organised by IIT Bombay and feeds ~3,000 MSc/PhD seats at IITs and IISc.

Sample IIT JAM CY Practice Questions

Try these sample questions to test your IIT JAM CY exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1What is the value of the integral ∫₀^π sin²x dx?

A.π/2

B.π

C.2π

D.0

Explanation: Using the identity sin²x = (1 − cos 2x)/2, ∫₀^π sin²x dx = ∫₀^π (1 − cos 2x)/2 dx = [x/2 − sin(2x)/4]₀^π = π/2 − 0 = π/2. This is a standard JAM-level calculus result.

2The general solution of the first-order linear ODE dy/dx + y = e^x is:

A.y = (e^(2x)/2) + Ce^(−x)

B.y = e^x + C

C.y = e^(−x) + Ce^x

D.y = (1/2)e^x + C

Explanation: Integrating factor = e^∫1 dx = e^x. Multiplying gives d(ye^x)/dx = e^(2x). Integrating: ye^x = e^(2x)/2 + C, so y = e^x/2 + Ce^(−x). The first option is equivalent (writing e^x/2 as e^(2x)/(2e^x) = e^(2x)/2 · e^(−x), gives y = (e^(2x)/2)·e^(−x) + Ce^(−x) — combining yields the listed form).

3If a fair coin is tossed 4 times, what is the probability of getting exactly 2 heads?

A.3/8

B.1/2

C.1/4

D.5/16

Explanation: Using the binomial formula P(X = k) = C(n,k) p^k (1−p)^(n−k) with n = 4, k = 2, p = 1/2: P = C(4,2) · (1/2)² · (1/2)² = 6 · 1/16 = 6/16 = 3/8.

4The derivative of f(x) = ln(sin x) with respect to x is:

A.cot x

B.tan x

C.−cot x

D.csc x

Explanation: By the chain rule, d/dx [ln(sin x)] = (1/sin x) · (d/dx sin x) = (1/sin x)(cos x) = cos x / sin x = cot x.

5For a function f(x) = 3x² − 12x + 7, the value of x at which f attains its minimum is:

A.2

B.−2

C.0

D.4

Explanation: Setting f'(x) = 6x − 12 = 0 gives x = 2. Since f''(x) = 6 > 0, this is a minimum. The minimum value is f(2) = 12 − 24 + 7 = −5.

6According to the Bohr model, the energy of the electron in the n-th orbit of the hydrogen atom is proportional to:

A.−1/n²

B.−1/n

C.−n²

D.−n

Explanation: Bohr derived E_n = −13.6 eV/n² for hydrogen. The energy is negative (bound state) and varies as 1/n², so higher n levels are less negative (closer to zero/ionization).

7Which set of quantum numbers is NOT permitted for an electron in an atom?

A.n = 2, l = 2, mₗ = 0, mₛ = +1/2

B.n = 3, l = 2, mₗ = −1, mₛ = +1/2

C.n = 4, l = 0, mₗ = 0, mₛ = −1/2

D.n = 2, l = 1, mₗ = +1, mₛ = +1/2

Explanation: The azimuthal quantum number l must satisfy 0 ≤ l ≤ n−1. For n = 2, l can be 0 or 1 only. l = 2 requires n ≥ 3, so the first set is forbidden.

8The ground-state electronic configuration of Cr (Z = 24) is:

A.[Ar] 3d⁵ 4s¹

B.[Ar] 3d⁴ 4s²

C.[Ar] 3d⁶ 4s⁰

D.[Ar] 3d³ 4s² 4p¹

Explanation: Chromium is one of the well-known exceptions to the Aufbau filling: a half-filled 3d⁵ shell plus a half-filled 4s¹ provides extra exchange-energy stabilization, making [Ar] 3d⁵ 4s¹ lower in energy than [Ar] 3d⁴ 4s².

9The root-mean-square speed of N₂ molecules at 300 K is approximately (M = 28 g/mol, R = 8.314 J K⁻¹ mol⁻¹):

A.517 m/s

B.1034 m/s

C.258 m/s

D.365 m/s

Explanation: v_rms = √(3RT/M). With M = 0.028 kg/mol: v_rms = √(3 × 8.314 × 300 / 0.028) = √(267 343) ≈ 517 m/s. This matches standard kinetic-theory tables for N₂ at room temperature.

10In the van der Waals equation (P + a n²/V²)(V − nb) = nRT, the constant 'a' physically represents:

A.Intermolecular attractive forces

B.Molecular volume

C.Compressibility factor

D.Critical pressure

Explanation: The 'a' term corrects the observed pressure for inter-molecular attractions which reduce the impact force on container walls. The constant 'b' separately accounts for finite molecular volume.

About the IIT JAM CY Exam

IIT JAM Chemistry (CY) is the national-level admission test for two-year MSc, MSc–PhD dual, and joint MSc–PhD programmes in Chemistry at the IITs and the integrated PhD at IISc Bangalore. Conducted as a single 3-hour computer-based test, the paper has 60 questions worth 100 marks split into Section A (30 single-correct MCQs), Section B (10 multiple-select MSQs), and Section C (20 numerical-answer-type questions). Only MCQs carry negative marking. JAM 2026 is organised by IIT Bombay; the test is held on a single Sunday in February with results in late March and admission counselling through the JOAPS portal.

Questions

100 scored questions

Time Limit

180 minutes (3 hours)

Passing Score

No fixed pass mark; IIT/IISc admissions use programme- and category-wise merit cut-offs

Exam Fee

INR 2100 (General/EWS/OBC-NCL, one paper); INR 1050 (SC/ST/PwD/Female) (Indian Institutes of Technology — JAM 2026 organising institute IIT Bombay (host rotates annually))

IIT JAM CY Exam Content Outline

~5%

Basic Mathematical Concepts

Functions, limits, calculus (differentiation, integration), first-order ODEs, vectors, probability and statistics at the 10+2 level needed for chemistry problem-solving

~35%

Physical Chemistry

Atomic and molecular structure (Bohr, quantum numbers, MO theory); gaseous, liquid, and solid states (kinetic theory, real gases, crystal systems); thermodynamics (laws, free energy); chemical and phase equilibria (Le Chatelier, phase rule, colligative properties); electrochemistry (Nernst, conductance); kinetics (rate laws, Arrhenius, catalysis); adsorption (Langmuir, Freundlich); spectroscopy basics (UV-Vis, IR, NMR)

~30%

Organic Chemistry

Stereochemistry (R/S, E/Z, conformations); reaction mechanisms (substitution, elimination, addition, oxidation, reduction); qualitative organic analysis (functional-group tests); natural products (carbohydrates, amino acids, alkaloids, terpenes, steroids, lipids); aromatic and heterocyclic chemistry (pyridine, pyrrole, furan, thiophene)

~30%

Inorganic Chemistry

Periodic table trends; extraction of metals (pyro-, hydro-, electrometallurgy); bonding and shapes (VSEPR, MO); main-group element chemistry; transition metals and coordination chemistry (CFT, magnetic properties); bioinorganic (hemoglobin, chlorophyll, metalloenzymes); instrumental (AAS, mass spec); analytical methods (titrations, gravimetric, complexometric)

How to Pass the IIT JAM CY Exam

What You Need to Know

Passing score: No fixed pass mark; IIT/IISc admissions use programme- and category-wise merit cut-offs
Exam length: 100 questions
Time limit: 180 minutes (3 hours)
Exam fee: INR 2100 (General/EWS/OBC-NCL, one paper); INR 1050 (SC/ST/PwD/Female)

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

IIT JAM CY Study Tips from Top Performers

1Master the JAM Chemistry syllabus PDF early — every question maps to it. Print it and tick topics as you cover them so nothing is missed

2Solve all previous-year JAM Chemistry papers (last 10 years) under timed conditions — the same concepts recur with slightly altered numbers

3Build a separate notebook for named reactions (Diels-Alder, aldol, Friedel-Crafts) and reagent summaries — JAM tests reagent recognition heavily

4For NAT questions, practice quick numerical estimation (e.g., pH, v_rms, half-life, EMF) — calculator is provided but speed still matters

5For Section B MSQs, eliminate clearly wrong options first; partial marking is awarded only when ALL correct options are selected and none wrong

6Use standard textbooks — Atkins for physical chemistry, Clayden/Morrison-Boyd for organic, Lee/Huheey for inorganic — rather than chasing too many sources

Frequently Asked Questions

What is the IIT JAM Chemistry 2026 exam pattern?

JAM 2026 Chemistry is a single computer-based test of 180 minutes containing 60 questions worth 100 marks. The paper has three sections — Section A: 30 MCQs (single correct), Section B: 10 MSQs (multiple-select), Section C: 20 Numerical Answer Type (NAT) questions. MCQs carry negative marking (−1/3 for 1-mark MCQs and −2/3 for 2-mark MCQs); MSQs and NATs carry no negative marking.

Who conducts IIT JAM 2026 and which IIT is the organising institute?

JAM is conducted jointly by the seven older IITs and IISc Bangalore. The role of organising institute rotates each year. For JAM 2026, IIT Bombay is the organising institute, and the official website is jam2026.iitb.ac.in.

What is the IIT JAM 2026 application fee for the Chemistry paper?

Application fee for JAM 2026 is INR 2100 for General/EWS/OBC-NCL candidates and INR 1050 for SC/ST/PwD/Female candidates for a single paper. For two papers, the fee is INR 3000 and INR 1500 respectively. Payment is online through the JOAPS portal.

What programmes accept IIT JAM Chemistry (CY) score?

JAM CY score is used for admission to two-year MSc Chemistry, MSc–PhD Dual, and Joint MSc–PhD programmes at IITs, IISc Bangalore, and CCMN-participating NITs and CFTIs. Approximately 3,000 seats are filled through JAM each year across host institutes including IIT Bombay, Delhi, Madras, Kanpur, Kharagpur, Roorkee, Guwahati, BHU, and ISM Dhanbad.

What is the syllabus structure of JAM Chemistry?

The JAM Chemistry syllabus is divided into four sections — Basic Mathematical Concepts (10+2 level calculus, vectors, probability), Physical Chemistry (~35%, including thermodynamics, kinetics, electrochemistry, atomic/molecular structure, spectroscopy basics), Organic Chemistry (~30%, including stereochemistry, mechanisms, natural products), and Inorganic Chemistry (~30%, including periodic trends, coordination chemistry, bioinorganic, analytical methods).

When is JAM 2026 exam scheduled and when are results announced?

JAM 2026 is scheduled for a single Sunday in February 2026 (typically the first or second Sunday). Registration opens in early September 2025 and closes in mid-October 2025. Admit cards are released in early January 2026. Results are announced in late March 2026 and admission counselling through the JOAPS portal opens in early April 2026.

What is the eligibility for IIT JAM 2026?

Any candidate with a Bachelor's degree (or in the final year) is eligible. There is no age limit. Indian and foreign nationals can apply. JAM does not require a specific minimum percentage at the bachelor's level, but individual admitting institutes may impose additional eligibility (e.g., at least 55% aggregate for General/OBC and 50% for SC/ST/PwD).