PracticeVideosBlogFlashcardsEspañol
All Practice Exams

100+ Free CHSE Odisha Elective Mathematics Practice Questions

Council of Higher Secondary Education, Odisha (CHSE Odisha) Higher Secondary (+2) Elective Mathematics (Arts stream) practice questions are available now; exam metadata is being verified.

✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately
100+ Questions
100% Free

Loading practice questions...

Same family resources

Explore More Odisha CHSE Higher Secondary Elective Subjects

Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.

Odisha CHSE Higher Secondary Accountancy — Elective

Practice Questions

Odisha CHSE Higher Secondary Anthropology — Elective

Practice Questions

Odisha CHSE Higher Secondary Banking and Insurance — Elective

Practice Questions

Odisha CHSE Higher Secondary Biology — Elective

Practice Questions

Odisha CHSE Higher Secondary Biotechnology — Elective

Practice Questions

Odisha CHSE Higher Secondary Business Economics — Elective

Practice Questions
2026 Statistics

Key Facts: CHSE Odisha Elective Mathematics Exam

200 marks

Elective Mathematics total across Year 1 (100) + Year 2 (100) pure theory

CHSE Odisha Arts Courses of Studies

5 × 20

Year-2 unit marks: Relations–LP, Algebra–Probability, Diff. Calc., Int. Calc., Vectors–3D

CHSE Odisha Mathematics (+2 2nd year) course structure

10+60+30

Official Group A/B/C mark split on the Year-2 theory paper

CHSE Odisha Mathematics general instructions

No practical

Mathematics is pure theory 100 marks (unlike Statistics 70+30)

CHSE Odisha Arts/Science Mathematics syllabus

In AHSE fee

No separate elective marketplace fee; included in session exam fee

CHSE Odisha AHSE fee structure via colleges

CHSE Odisha Elective Mathematics is a +2 elective (200 marks: 100+100 pure theory). Year-2 AHSE uses five equal 20-mark units and Group A/B/C written format—not a pure MCQ board paper. This free 2026 bank is a calculation-heavy English MCQ study adaptation aligned to official units.

Sample CHSE Odisha Elective Mathematics Practice Questions

Try these sample questions to test your CHSE Odisha Elective Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Let R be a relation on the set A = {1, 2, 3} given by R = {(1,1), (2,2), (3,3), (1,2), (2,1)}. Which property does R satisfy that makes it an equivalence relation when combined with the other required properties?
A.R is only reflexive
B.R is reflexive, symmetric, and transitive on A
C.R is only symmetric
D.R is neither reflexive nor symmetric
Explanation: R contains all diagonal pairs (reflexive), is closed under swap of ordered pairs (symmetric), and checking chains (e.g. 1R2 and 2R1 gives 1R1 already present; no path forces missing pairs) shows transitivity. Hence R is an equivalence relation on A.
2A relation R on Z is defined by a R b if and only if a − b is divisible by 5. How many equivalence classes does R determine on Z?
A.1
B.5
C.10
D.Infinitely many with no modular structure
Explanation: a ≡ b (mod 5) is the standard congruence relation. The equivalence classes are the residue classes [0], [1], [2], [3], [4] — exactly 5 classes.
3Let f: R → R be defined by f(x) = 2x + 3. Which statement is correct?
A.f is one-one but not onto
B.f is onto but not one-one
C.f is neither one-one nor onto
D.f is both one-one and onto
Explanation: If f(x1)=f(x2) then 2x1+3=2x2+3 ⇒ x1=x2 (one-one). For any y∈R, x=(y−3)/2 is a real preimage (onto). Linear functions with nonzero slope are bijections R→R.
4If f(x) = x + 1 and g(x) = 2x − 3, then (f ∘ g)(2) equals:
A.2
B.3
C.1
D.5
Explanation: g(2)=2(2)−3=1. Then f(g(2))=f(1)=1+1=2. So (f∘g)(2)=2.
5If f: R → R is given by f(x) = 3x − 5, then f⁻¹(x) is:
A.(x − 5)/3
B.3x + 5
C.(x + 5)/3
D.1/(3x − 5)
Explanation: Set y = 3x − 5 ⇒ x = (y + 5)/3. Swapping variables, f⁻¹(x) = (x + 5)/3. Check: f(f⁻¹(x)) = 3·(x+5)/3 − 5 = x.
6The principal value of sin⁻¹(1/2) is:
A.π/3
B.π/2
C.π/6
D.π/4
Explanation: sin(π/6)=1/2 and π/6 lies in the principal range [−π/2, π/2] of sin⁻¹. Hence sin⁻¹(1/2)=π/6.
7The principal value of cos⁻¹(−1/2) is:
A.2π/3
B.π/3
C.π/6
D.5π/6
Explanation: cos(2π/3)=−1/2 and 2π/3 ∈ [0, π], the principal range of cos⁻¹. Note 5π/6 has cos = −√3/2, not −1/2.
8If tan⁻¹ x + tan⁻¹ y = π/4 and xy < 1, then:
A.x + y = 1 + xy
B.x − y = 1 + xy
C.x + y = 1 − xy
D.xy = 1
Explanation: tan(tan⁻¹x + tan⁻¹y) = (x+y)/(1−xy) when xy<1. This equals tan(π/4)=1, so (x+y)/(1−xy)=1 ⇒ x+y=1−xy.
9The domain of the function f(x) = sin⁻¹(2x − 1) is:
A.[0, 1]
B.[−1, 1]
C.[1/2, 1]
D.[0, 2]
Explanation: sin⁻¹ is defined for argument in [−1,1], so −1 ≤ 2x−1 ≤ 1 ⇒ 0 ≤ 2x ≤ 2 ⇒ 0 ≤ x ≤ 1.
10In a linear programming problem, the feasible region is the set of points that:
A.Satisfy only the objective function
B.Lie only outside all half-planes
C.Maximise the objective without any constraint
D.Satisfy all the constraints simultaneously
Explanation: By definition, the feasible region is the intersection of all constraint half-planes (including non-negativity if present). Optimal solutions, when they exist, occur at corner points of this region for linear objectives.

About the CHSE Odisha Elective Mathematics Practice Questions

Verified exam format metadata for Council of Higher Secondary Education, Odisha (CHSE Odisha) Higher Secondary (+2) Elective Mathematics (Arts stream) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.