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100+ Free CHSE Odisha Elective Chemistry Practice Questions

Council of Higher Secondary Education, Odisha (CHSE Odisha) Higher Secondary (+2) Elective Chemistry (Science stream) practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: CHSE Odisha Elective Chemistry Exam

70 + 30

Typical theory + practical marks per year for CHSE Chemistry

CHSE Odisha Chemistry / Science Courses of Studies

Year-2 Council

AHSE paper that counts toward the final pass certificate

CHSE Odisha scheme of studies

3 hours

Typical duration of the 70-mark Chemistry theory paper

CHSE Chemistry syllabus (theory timing)

Bureau + NCERT

Prescribed +2 Chemistry Vol-I/II and NCERT Class XI–XII texts

Chemistry-CHSE-2023 prescribed books

In AHSE fee

No separate elective marketplace fee; included in session exam fee

CHSE Odisha AHSE fee structure via colleges

CHSE Odisha Elective Chemistry is a +2 Science elective (typically 70 theory + 30 practical per year). Council Year-2 AHSE counts for the pass certificate. This free 2026 bank is an English MCQ study adaptation aligned to official units—not a pure official-format simulation.

Sample CHSE Odisha Elective Chemistry Practice Questions

Try these sample questions to test your CHSE Odisha Elective Chemistry exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1The number of moles in 36 g of water (H2O; M = 18 g mol^-1) is:
A.2.0 mol
B.1.0 mol
C.0.5 mol
D.18 mol
Explanation: n = m/M = 36/18 = 2.0 mol. One mole of water has mass 18 g, so 36 g is two moles.
2How many molecules are present in 0.5 mol of CO2? (NA = 6.022 x 10^23 mol^-1)
A.3.011 x 10^23
B.6.022 x 10^23
C.1.204 x 10^24
D.3.011 x 10^22
Explanation: Number of molecules = n x NA = 0.5 x 6.022 x 10^23 = 3.011 x 10^23.
3A sample contains 40% C, 6.7% H and 53.3% O by mass. Its empirical formula is: (C=12, H=1, O=16)
A.CH2O
B.C2H4O
C.CH2O2
D.C2H6O
Explanation: Assume 100 g: C 40/12=3.33, H 6.7/1=6.7, O 53.3/16=3.33. Divide by 3.33 → C1 H2 O1 → CH2O.
4In the reaction 2H2 + O2 → 2H2O, if 4 mol H2 and 1 mol O2 react, the limiting reagent is:
A.O2
B.H2
C.H2O
D.Neither; both are exactly stoichiometric
Explanation: Stoichiometry needs 2 mol H2 per 1 mol O2. With 4 mol H2 you could use 2 mol O2, but only 1 mol O2 is present, so O2 limits the product to 2 mol H2O.
5Molarity of a solution prepared by dissolving 5.85 g NaCl (M = 58.5 g mol^-1) in water to make 500 mL solution is:
A.0.20 M
B.0.10 M
C.1.0 M
D.0.50 M
Explanation: n = 5.85/58.5 = 0.10 mol; V = 0.500 L; M = n/V = 0.10/0.50 = 0.20 M.
6According to the law of definite proportions, a pure compound:
A.Always contains the same elements in the same mass ratio
B.May change composition with temperature only
C.Has variable composition depending on source
D.Is always a mixture of isotopes only
Explanation: The law of definite proportions (Proust) states that a given pure compound always contains the same elements combined in a fixed mass ratio, independent of source or method of preparation.
7How many grams of CaCO3 (M = 100 g mol^-1) are needed to produce 4.4 g CO2 on complete decomposition? (CaCO3 → CaO + CO2)
A.10 g
B.4.4 g
C.100 g
D.44 g
Explanation: n(CO2) = 4.4/44 = 0.10 mol; from 1:1 stoichiometry n(CaCO3)=0.10 mol; mass = 0.10 x 100 = 10 g.
8Normality of 0.5 M H2SO4 used as a diprotic acid (for complete H+ neutralization) is:
A.1.0 N
B.0.5 N
C.0.25 N
D.2.0 N
Explanation: For H2SO4, n-factor = 2 for complete neutralization. N = M x n-factor = 0.5 x 2 = 1.0 N.
9The mass of 1.204 x 10^24 molecules of O2 (M = 32 g mol^-1) is: (NA = 6.022 x 10^23)
A.64 g
B.32 g
C.16 g
D.8 g
Explanation: n = N/NA = 1.204e24 / 6.022e23 = 2.0 mol; mass = 2 x 32 = 64 g.
10If 4.0 g of a gas occupies 2.24 L at STP, its molar mass is approximately:
A.40 g mol^-1
B.22.4 g mol^-1
C.4.0 g mol^-1
D.2.24 g mol^-1
Explanation: At STP, 22.4 L = 1 mol. 2.24 L = 0.10 mol. M = m/n = 4.0/0.10 = 40 g mol^-1.

About the CHSE Odisha Elective Chemistry Practice Questions

Verified exam format metadata for Council of Higher Secondary Education, Odisha (CHSE Odisha) Higher Secondary (+2) Elective Chemistry (Science stream) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.