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100+ Free Haryana BSEH Secondary Science Practice Questions

Board of School Education Haryana (BSEH) Secondary Examination Class 10 Science practice questions are available now; exam metadata is being verified.

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Overall Secondary pass percentages are published with each BSEH result; no fixed standing subject-wise Science pass-rate figure is used here. Pass Rate
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2026 Statistics

Key Facts: Haryana BSEH Secondary Science Exam

013

Date-sheet subject code (Science)

BSEH Secondary examination date sheet

80 + 20

Typical Theory + Internal Assessment

Standard BSEH Secondary marking pattern (confirm circular)

3 hours

Typical Theory Duration

BSEH Secondary date sheet / exam pattern

33%

Typical Pass (External & Aggregate)

BSEH Secondary passing criteria (confirm current circular)

NCERT X

Class 10 Science Alignment

BSEH Class 10 syllabus catalog / NCERT Science

BSEH Secondary Science (code 013) is Haryana’s Class 10 core science paper: typically Theory 80 + IA 20 = 100 marks, NCERT Class 10 syllabus, about 3 hours. Pass often 33% external and 33% aggregate. Fee is part of Secondary form-fill-up. This site offers free English MCQ practice with explanations—not a full written-paper simulation.

Sample Haryana BSEH Secondary Science Practice Questions

Try these sample questions to test your Haryana BSEH Secondary Science exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Which of the following is a chemical change?
A.Melting of ice
B.Burning of magnesium ribbon
C.Breaking of glass
D.Dissolving sugar in water
Explanation: Burning magnesium forms magnesium oxide, a new substance, so it is a chemical change.
2The reaction Zn + CuSO₄ → ZnSO₄ + Cu is an example of:
A.Combination reaction
B.Decomposition reaction
C.Displacement reaction
D.Double displacement reaction
Explanation: More reactive zinc displaces copper from copper sulphate solution—a single displacement reaction.
3When the equation Fe + H₂O → Fe₃O₄ + H₂ is balanced, the coefficient of H₂O is:
A.2
B.3
C.4
D.6
Explanation: Balanced equation: 3Fe + 4H₂O → Fe₃O₄ + 4H₂. The coefficient of water is 4.
4Rancidity of oils and fats is mainly due to:
A.Reduction by hydrogen
B.Oxidation by atmospheric oxygen
C.Neutralisation by bases
D.Polymerisation of fatty acids
Explanation: Rancidity occurs when oils and fats oxidise in air, producing unpleasant odour and taste.
5In the reaction 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂, the type of reaction is:
A.Combination
B.Thermal decomposition
C.Displacement
D.Double displacement
Explanation: Heating lead nitrate breaks it into lead oxide, nitrogen dioxide, and oxygen—thermal decomposition.
6According to the law of conservation of mass, if 12 g of carbon burns completely in 32 g of oxygen, the mass of CO₂ formed is:
A.12 g
B.32 g
C.44 g
D.20 g
Explanation: C + O₂ → CO₂. Mass is conserved: 12 g + 32 g = 44 g of carbon dioxide.
7A solution turns red litmus blue. The solution is:
A.Acidic
B.Basic
C.Neutral
D.Amphoteric
Explanation: Bases turn red litmus blue; acids turn blue litmus red.
8The pH of a solution is 3. The solution is:
A.Strongly basic
B.Weakly basic
C.Strongly acidic
D.Neutral
Explanation: pH < 7 indicates acidity; pH 3 is strongly acidic on the 0–14 scale.
9Bleaching powder is chemically represented as:
A.CaO
B.Ca(OH)₂
C.CaOCl₂
D.CaCO₃
Explanation: Bleaching powder is calcium oxychloride, commonly written as CaOCl₂.
10Plaster of Paris is obtained by heating gypsum at about 373 K. The formula of plaster of Paris is:
A.CaSO₄·2H₂O
B.CaSO₄·½H₂O
C.CaSO₄·H₂O
D.CaSO₄
Explanation: Gypsum (CaSO₄·2H₂O) loses water on heating to form plaster of Paris, CaSO₄·½H₂O.

About the Haryana BSEH Secondary Science Practice Questions

Verified exam format metadata for Board of School Education Haryana (BSEH) Secondary Examination Class 10 Science is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.