All Practice Exams
100+ Free MLT Registration Practice Questions
Pass your Medical Laboratory Technologists Board of Hong Kong Registration Assessment exam on the first try — instant access, no signup required.
✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately
~75% Pass Rate
100+ Questions
100% Free
Loading practice questions...
Same family resources
Explore More Hong Kong Healthcare Licensing Exams
Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.
Sample MLT Registration Practice Questions
Try these sample questions to test your MLT Registration exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1Which of the following describes the chemical basis of the classic Jaffe reaction for measuring creatinine, and what is a common positive interferent?
A.Reaction with copper sulfate in alkaline solution; interfered with by lipids
B.Reaction with picric acid in alkaline solution; interfered with by acetoacetate
C.Enzymatic oxidation by creatinine amidohydrolase; interfered with by uric acid
D.Reaction with sodium nitroprusside in acid solution; interfered with by glucose
Explanation: The Jaffe reaction is based on the reaction of creatinine with picric acid in an alkaline medium to form a red-orange Janovski complex. Common non-creatinine chromogens that serve as positive interferents (especially in the kinetic Jaffe method's early phase) include acetoacetate, acetone, glucose, pyruvate, and certain cephalosporin antibiotics. Lipids typically cause negative interference due to light scattering in some methods. Copper sulfate is used in biuret protein assays.
2A patient's arterial blood gas (ABG) results are as follows: pH = 7.25, pCO2 = 60 mmHg, HCO3- = 26 mEq/L. Which of the following is the correct acid-base classification?
A.Uncompensated metabolic acidosis
B.Fully compensated respiratory acidosis
C.Uncompensated (or acute) respiratory acidosis
D.Partially compensated metabolic alkalosis
Explanation: The pH of 7.25 is below the normal range (7.35-7.45), indicating acidosis. The pCO2 of 60 mmHg is elevated (normal 35-45 mmHg), which points to a respiratory origin. The HCO3- of 26 mEq/L is at the upper limit of normal (22-26 mEq/L), indicating that renal compensation has not yet significantly occurred (typical of acute respiratory acidosis). Therefore, this is classified as acute or uncompensated respiratory acidosis.
3Which of the following conditions is most likely to produce a falsely decreased Hemoglobin A1c (HbA1c) level when measured by ion-exchange chromatography?
A.Iron deficiency anemia
B.Splenectomy
C.Presence of Hemoglobin S or Hemoglobin C
D.Chronic renal failure with erythropoietin therapy
Explanation: Conditions that shorten red blood cell survival, such as hemolytic anemias or treatment of renal failure with erythropoietin (which stimulates rapid production of new RBCs), result in a younger average erythrocyte population and falsely decreased HbA1c. Conversely, iron deficiency anemia increases RBC lifespan and can falsely elevate HbA1c. Splenectomy prolongs RBC survival, leading to falsely high HbA1c. Hb variants like HbS/HbC can cause varying chromatography interferences, but shortened cell lifespan under EPO therapy is a physiologic cause of false decreases.
4Why is the hexokinase method considered the reference method for glucose determination over the glucose oxidase method?
A.Hexokinase is highly specific for beta-D-glucose and requires no mutarotase enzyme
B.The hexokinase coupled reaction is not affected by common reducing substances like uric acid or ascorbic acid
C.Hexokinase directly produces a colored compound without requiring a secondary coupled enzyme indicator reaction
D.Hexokinase reagents are much cheaper and have a longer shelf life
Explanation: The glucose oxidase method uses a coupled peroxidase reaction (Trinder reaction) where reducing substances like ascorbic acid, uric acid, and bilirubin compete with the chromogen for hydrogen peroxide, causing falsely decreased glucose results. The hexokinase method uses a coupled reaction involving glucose-6-phosphate dehydrogenase (G6PD) to measure the reduction of NAD+ or NADP+ at 340 nm. This UV-based method is highly specific and lacks interference from common blood reducing agents.
5Under which of the following circumstances is the Friedewald equation for calculating LDL cholesterol invalid?
A.When the patient's HDL cholesterol is less than 35 mg/dL
B.When the total cholesterol level exceeds 300 mg/dL
C.When the triglyceride level is greater than 400 mg/dL (or 4.52 mmol/L)
D.When the patient is on active statin therapy
Explanation: The Friedewald equation states: LDL-C = Total Cholesterol - HDL-C - (Triglycerides / 5) (in mg/dL). This formula assumes that the ratio of triglycerides to cholesterol in VLDL is constant at 5:1. However, when triglyceride levels exceed 400 mg/dL (4.52 mmol/L), chylomicrons are typically present, and the triglyceride-to-VLDL-cholesterol ratio becomes highly variable, rendering the calculation invalid. In such cases, direct LDL measurement is required.
6Which of the following best explains how severe hyperproteinemia or hyperlipidemia causes pseudohyponatremia in laboratory measurements?
A.Proteins and lipids bind sodium ions, preventing them from interacting with the electrode membrane
B.Indirect ion-selective electrodes (ISE) dilute the sample, underestimating sodium concentration in the total volume because lipids/proteins occupy the non-aqueous fraction
C.Direct ion-selective electrodes (ISE) are calibrated incorrectly for high-density solutions
D.Proteins alter the temperature coefficient of the measuring chamber, lowering the apparent sodium activity
Explanation: Indirect ISE methods involve a dilution step. Sodium is restricted to the water phase of plasma (normally ~93%). If lipids or proteins are greatly increased, the water phase percentage drops (e.g., to 80%). The dilution is calculated assuming a normal 93% plasma water volume, which mathematically underestimates the true sodium concentration in the water phase (pseudohyponatremia). Direct ISE measures sodium activity directly in the undiluted sample and is unaffected by this volume displacement effect.
7In the Jendrassik-Grof method for bilirubin determination, what is the purpose of adding caffeine-benzoate reagent?
A.To oxidize bilirubin to biliverdin for green spectrophotometric reading
B.To solubilize and release unconjugated bilirubin from albumin, allowing it to react with the diazo reagent
C.To destroy hemoglobin interference which acts as a positive chromogen
D.To act as a pH buffer, shifting the reaction to an alkaline endpoint
Explanation: In the Jendrassik-Grof assay, conjugated (direct) bilirubin reacts quickly with diazo reagent in aqueous solution. Unconjugated (indirect) bilirubin is hydrophobic and bound tightly to albumin, preventing it from reacting. The addition of an accelerator like caffeine-sodium benzoate (or methanol in the Malloy-Evelyn method) dissociates unconjugated bilirubin from albumin, allowing total bilirubin to be measured.
8Which of the following cardiac markers is the first to rise following an acute myocardial infarction (AMI), and which provides the longest diagnostic window?
A.CK-MB rises first; Troponin T provides the longest window
B.Myoglobin rises first; Troponin T/I provides the longest window
C.Troponin I rises first; Myoglobin provides the longest window
D.LDH rises first; CK-MB provides the longest window
Explanation: Myoglobin is a small heme protein that rises rapidly within 1-3 hours of myocardial injury (making it the earliest marker, though non-specific). Cardiac troponins (cTnI and cTnT) rise within 3-6 hours. Troponins remain elevated for an extended period (cTnI for 5-10 days, cTnT for up to 10-14 days), providing the longest diagnostic window. CK-MB peaks around 18-24 hours and returns to baseline in 48-72 hours.
9A patient presents with a significantly elevated Alkaline Phosphatase (ALP). To differentiate whether the origin of this elevation is hepatobiliary or bone disease, which secondary enzyme test is most clinical useful?
A.Alanine aminotransferase (ALT)
B.Gamma-glutamyltransferase (GGT)
C.Amylase
D.Lactate dehydrogenase (LDH)
Explanation: Gamma-glutamyltransferase (GGT) and 5'-nucleotidase are elevated in hepatobiliary disorders but are not present in significant amounts in bone tissue. Thus, if a patient has an elevated ALP and an elevated GGT, the source of the ALP is hepatobiliary. If the GGT is normal, the ALP elevation is likely of bone origin (e.g., Paget's disease, osteomalacia, rapid growth).
10A 24-hour urine collection has a volume of 1440 mL. Urine creatinine is 100 mg/dL, and serum creatinine is 1.0 mg/dL. What is the calculated creatinine clearance (uncorrected for body surface area)?
A.10 mL/min
B.100 mL/min
C.144 mL/min
D.1000 mL/min
Explanation: Creatinine clearance (CrCl) = (U_cr * V) / P_cr. First convert urine volume to mL/min: 1440 mL / 1440 min (24 hours * 60 min) = 1.0 mL/min. Then CrCl = (100 mg/dL * 1.0 mL/min) / 1.0 mg/dL = 100 mL/min.
About the MLT Registration Exam
This practice exam covers clinical chemistry, hematology, transfusion science, medical microbiology, virology, histopathology, cytology, and QA/safety.
Assessment
100 multiple-choice questions
Time Limit
3 hours
Passing Score
60%
Exam Fee
Free (Medical Laboratory Technologists Board of Hong Kong)
MLT Registration Exam Content Outline
20%
Clinical Chemistry
Renal/liver function tests, endocrinology assays, lipids, enzymes, and blood gas analysis.
20%
Hematology & Transfusion Science
CBC, coagulation profiles, leukemia typing, blood grouping, crossmatching, and blood banking safety.
20%
Medical Microbiology & Virology
Bacterial isolation, identification, susceptibility testing, viral serology, and PCR diagnostics.
20%
Histopathology & Cytology
Tissue processing, sectioning, staining (H&E, special stains), immunohistochemistry, and cytological screening.
20%
Quality Assurance & Safety
IQC, EQA, laboratory safety, chemical hazards, and bio-waste management regulations.
How to Pass the MLT Registration Exam
What You Need to Know
- Passing score: 60%
- Assessment: 100 multiple-choice questions
- Time limit: 3 hours
- Exam fee: Free
Keys to Passing
- Complete 500+ practice questions
- Score 80%+ consistently before scheduling
- Focus on highest-weighted sections
- Use our AI tutor for tough concepts
Frequently Asked Questions
What is the format of the MLT Registration exam?
The exam consists of 100 multiple-choice questions covering all five content domains.
What is the passing score for the MLT Registration exam?
Candidates must score at least 60% to pass the exam.