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100+ Free La Rioja PAU Technical Drawing II Practice Questions

La Rioja PAU Technical Drawing II Examination — UR (Dibujo Técnico II 2º Bachillerato UR 2026) practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: La Rioja PAU Technical Drawing II Exam

90 Minutes

Exam duration

Universidad de La Rioja PAU Commission

EUR 55.43

Base registration fee

Universidad de La Rioja 2026 Fees

0–10 Scale

Grading scale (minimum 4.0 required)

Spanish Ministry of Education

4 Core Blocks

Plane Geometry, Dihedral System, Axonometry/Perspective, and Technical Standardization

UR Syllabus

100 Questions

Practice bank question count

OpenExamPrep

La Rioja PAU Technical Drawing II (UR 2026) is a 90-minute university entrance exam assessing 2º Bachillerato Technical Drawing II across plane geometry, dihedral system, axonometry, and ISO standardization.

Sample La Rioja PAU Technical Drawing II Practice Questions

Try these sample questions to test your La Rioja PAU Technical Drawing II exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1What is the measure of each interior angle in a regular convex hexagon?
A.108°
B.120°
C.135°
D.140°
Explanation: The sum of interior angles of an n-sided convex polygon is given by (n - 2) × 180°. For a hexagon (n = 6), the sum is (6 - 2) × 180° = 720°. Dividing 720° by 6 equal angles yields 120° for each interior angle.
2In an equilateral triangle circumscribed about a circle of radius r, what is the side length s of the triangle in terms of r?
A.s = r√3
B.s = 2r√3
C.s = 3r
D.s = 2r
Explanation: The inradius r of an equilateral triangle is related to its altitude h by r = h / 3. Since h = (s√3) / 2, we have r = (s√3) / 6, which rearranges to s = 6r / √3 = 2r√3.
3Which algebraic expression defines the exact numerical value of the Golden Ratio (Phi, Φ)?
A.Φ = (1 + √3) / 2 ≈ 1.366
B.Φ = (1 + √5) / 2 ≈ 1.618
C.Φ = (1 + √2) / 2 ≈ 1.207
D.Φ = (2 + √5) / 2 ≈ 2.118
Explanation: The Golden Ratio Φ is derived from dividing a segment into extreme and mean ratio (x² - x - 1 = 0), yielding the positive root Φ = (1 + √5) / 2 ≈ 1.6180339...
4A point P is located at a distance d = 10 cm from the center O of a circle with radius R = 6 cm. What is the power of point P with respect to this circle?
A.16 cm²
B.64 cm²
C.36 cm²
D.100 cm²
Explanation: The power of a point P with respect to a circle centered at O with radius R is defined as Power(P) = d² - R², where d is the distance PO. Here, Power(P) = 10² - 6² = 100 - 36 = 64 cm².
5What geometric locus is defined as the set of all points in a plane that have equal power with respect to two non-concentric circles?
A.The radical center
B.The radical axis
C.The polar line
D.The axis of homothety
Explanation: The radical axis (eje radical) is the straight line perpendicular to the line connecting the centers of two non-concentric circles, comprising all points with equal power to both circles.
6Given three circles with non-collinear centers, how is their radical center constructed?
A.As the centroid of the triangle formed by the three circle centers
B.As the point of intersection of the three pairwise radical axes
C.As the circumcenter of the triangle formed by the three circle centers
D.As the center of the circle tangent to all three given circles
Explanation: The radical center (centro radical) of three circles is the unique point where their three pairwise radical axes intersect, possessing equal power with respect to all three circles.
7In Apollonius tangency problems, what does the PPP case represent, and how many solutions exist for three non-collinear points?
A.Circle passing through 3 points; exactly 1 solution (circumcircle)
B.Circle tangent to 3 lines; exactly 4 solutions (incircle and 3 excircles)
C.Circle tangent to 3 circles; up to 8 solutions
D.Circle passing through 3 points; exactly 2 solutions
Explanation: The PPP case requires constructing a circle passing through three given non-collinear points. This is the unique circumcircle of the triangle formed by the three points, giving exactly 1 solution.
8In a plane inversion with center O and positive power K, what is the inverse image of a circle passing through the center of inversion O?
A.A circle passing through the center of inversion O
B.A straight line not passing through the center of inversion O
C.A point at infinity
D.A circle concentric with the inversion circle
Explanation: Under plane inversion centered at O, any circle that passes through O is transformed into a straight line that does not pass through O (and is parallel to the tangent of the circle at O).
9In a plane inversion with center O and positive inversion power K > 0, which geometric figure consists entirely of invariant points (points that invert to themselves)?
A.The center of inversion point O
B.The circle of inversion (círculo de inversión) centered at O with radius R = √K
C.Any line passing through O
D.The radical axis of any two inverse circles
Explanation: The circle of inversion centered at O with radius R = √K has power OP × OP' = R² = K. For any point P on this circle, OP = R, so OP' = R and P' = P, making every point on the circle invariant.
10In a plane homothety centered at O with a negative scale factor k = -0.5, where does the image of a point P lie relative to O?
A.On the ray OP at half the distance from O
B.On the opposite ray from O (180° turned) at half the distance from O
C.Perpendicular to ray OP at distance 0.5 OP
D.At twice the distance from O on the ray OP
Explanation: Homothety vectors satisfy OP' = k · OP. When k is negative (k = -0.5), the image point P' lies on the line OP but on the opposite side of O from P, with distance OP' = |k| · OP = 0.5 OP.

About the La Rioja PAU Technical Drawing II Practice Questions

Verified exam format metadata for La Rioja PAU Technical Drawing II Examination — UR (Dibujo Técnico II 2º Bachillerato UR 2026) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.