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100+ Free PAU Mathematics II (La Rioja) Practice Questions

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Key Facts: PAU Mathematics II (La Rioja) Exam

La Rioja PAU Mathematics II (UR 2026) evaluates 2º Bachillerato linear algebra, differential calculus, integral calculus, and 3D analytical geometry over a 90-minute examination. Base registration fee: EUR 55.43. Graded on a 0-10 scale with a minimum 4.0 needed in the Access Phase. This English-language practice bank provides 100 numerical worked questions aligned with the syllabus.

Sample PAU Mathematics II (La Rioja) Practice Questions

Try these sample questions to test your PAU Mathematics II (La Rioja) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Given the matrices A = [[2, -1], [3, 4]] and B = [[1, 5], [-2, 0]], calculate the matrix expression 2A - 3B.
A.[[1, -17], [12, 8]]
B.[[1, 13], [0, 8]]
C.[[1, -17], [0, 8]]
D.[[7, -17], [12, 8]]
Explanation: Compute scalar multiplications first: 2A = [[4, -2], [6, 8]] and 3B = [[3, 15], [-6, 0]]. Subtract component-wise: 2A - 3B = [[4-3, -2-15], [6-(-6), 8-0]] = [[1, -17], [12, 8]].
2What is the determinant of the upper triangular 3x3 matrix A = [[1, 2, 3], [0, 4, 5], [0, 0, 6]]?
A.10
B.24
C.0
D.15
Explanation: For any triangular matrix (upper or lower), the determinant equals the product of the diagonal elements. Therefore, det(A) = 1 * 4 * 6 = 24.
3Calculate the determinant of the 2x2 matrix A = [[3, -2], [5, 4]].
A.22
B.2
C.-2
D.7
Explanation: The determinant of a 2x2 matrix [[a, b], [c, d]] is ad - bc. Here det(A) = (3)(4) - (-2)(5) = 12 - (-10) = 12 + 10 = 22.
4Find the inverse of the matrix A = [[2, 1], [5, 3]].
A.[[3, -1], [-5, 2]]
B.[[-3, 1], [5, -2]]
C.[[2, -5], [-1, 3]]
D.[[3, 1], [5, 2]]
Explanation: First find det(A) = 2*3 - 1*5 = 6 - 5 = 1. The inverse of [[a, b], [c, d]] is (1/det(A)) * [[d, -b], [-c, a]]. Thus A^-1 = (1/1) * [[3, -1], [-5, 2]] = [[3, -1], [-5, 2]].
5Solve for matrix X in the matrix equation A * X = B, where A = [[1, 2], [3, 5]] and B = [[4, 1], [2, 0]].
A.[[-16, -5], [10, 3]]
B.[[16, 5], [-10, -3]]
C.[[-16, 5], [10, -3]]
D.[[4, 1], [2, 0]]
Explanation: Multiply both sides by A^-1 on the left: X = A^-1 * B. First, det(A) = 1*5 - 2*3 = -1. A^-1 = (1/-1) * [[5, -2], [-3, 1]] = [[-5, 2], [3, -1]]. Multiply A^-1 * B = [[-5, 2], [3, -1]] * [[4, 1], [2, 0]] = [[-5(4)+2(2), -5(1)+2(0)], [3(4)+(-1)(2), 3(1)+(-1)(0)]] = [[-16, -5], [10, 3]].
6If A is a 3x3 matrix with det(A) = -4, what is the value of det(2A)?
A.-8
B.-32
C.32
D.-16
Explanation: For an n x n square matrix A, det(k * A) = k^n * det(A). For n = 3 and k = 2: det(2A) = 2^3 * det(A) = 8 * (-4) = -32.
7What is the rank of the matrix A = [[1, 2, 3], [2, 4, 6], [0, 1, 5]]?
A.1
B.2
C.3
D.0
Explanation: Notice that Row 2 is 2 times Row 1, so Row 2 is linearly dependent and can be eliminated. Row 1 (1, 2, 3) and Row 3 (0, 1, 5) are linearly independent. Thus, the matrix has 2 linearly independent rows, so rank(A) = 2.
8Calculate the determinant of the 3x3 matrix A = [[1, 0, 2], [-1, 3, 1], [2, 1, 4]].
A.3
B.-3
C.7
D.5
Explanation: Expand along the first row: det(A) = 1 * det([[3, 1], [1, 4]]) - 0 + 2 * det([[-1, 3], [2, 1]]) = 1 * (12 - 1) + 2 * (-1 - 6) = 11 + 2(-7) = 11 - 14 = -3.
9Consider the system of linear equations with parameter k: x + y + z = 1, x + 2y + 3z = 2, x + 4y + k*z = 5. For what value of k is the system inconsistent (incompatible)?
A.k = 7
B.k = 5
C.k = 3
D.k = 0
Explanation: Compute the determinant of the coefficient matrix: det(A) = det([[1, 1, 1], [1, 2, 3], [1, 4, k]]) = k - 7. When k = 7, det(A) = 0 so rank(A) = 2. Row reduction of the augmented matrix A* yields third row (0, 0, 0 | 1), so rank(A*) = 3. By Rouché-Capelli theorem, rank(A) = 2 != rank(A*) = 3, making the system inconsistent (incompatible) when k = 7.
10Use Cramer's rule to find the value of y in the system 2x + y = 5, 3x - 2y = 4.
A.1
B.2
C.3
D.-1
Explanation: The main determinant is det(A) = det([[2, 1], [3, -2]]) = -4 - 3 = -7. The numerator determinant for y replaces column 2 with constant terms: det(A_y) = det([[2, 5], [3, 4]]) = 8 - 15 = -7. By Cramer's rule, y = det(A_y) / det(A) = -7 / -7 = 1.

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Verified exam format metadata for La Rioja PAU Mathematics II (Matemáticas II - UR 2026) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.