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100+ Free Galicia PAU Technical Drawing Applied to Plastic Arts and Design II Practice Questions
Galicia PAU Technical Drawing Applied to Plastic Arts and Design II (Dibujo Técnico Aplicado a las Artes Plásticas y al Diseño II - CIUG 2026) practice questions are available now; exam metadata is being verified.
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2026 Statistics
Key Facts: Galicia PAU Technical Drawing Applied to Plastic Arts and Design II Exam
63.67 €
Ordinary registration fee for PAU in Galicia
Comisión Interuniversitaria de Galicia (CIUG)
90 Mins
Official examination duration
CIUG PAU Guidelines
Min 4.0
Minimum Access Phase score required to combine with Bachillerato GPA
CIUG / Spanish University Access Regulations
4 Categories
Core technical drawing syllabus domains
2º Bachillerato LOMLOE Applied Technical Drawing Syllabus
100
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Galicia PAU Technical Drawing Applied to Plastic Arts and Design II tests 2º Bachillerato Arts students on plane geometry, dihedral system, axonometry, perspective, and ISO drafting standards over 90 minutes.
Sample Galicia PAU Technical Drawing Applied to Plastic Arts and Design II Practice Questions
Try these sample questions to test your Galicia PAU Technical Drawing Applied to Plastic Arts and Design II exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1When constructing a Golden Rectangle with width 'a' to achieve dynamic balance in a graphic layout, what is the exact mathematical ratio of its length to width?
A.(1 + √5) / 2 ≈ 1.618
B.(1 + √3) / 2 ≈ 1.366
C.√2 / 1 ≈ 1.414
D.(1 + √2) / 2 ≈ 1.207
Explanation: The Golden Ratio φ (Phi) is defined as (1 + √5) / 2, approximately 1.618. In plastic arts and visual composition, Golden Rectangles provide classic aesthetic proportions derived from self-similar geometric division.
2In the geometric construction of a regular pentagon inscribed in a circle of radius R, which step correctly identifies the side length of the pentagon?
A.The hypotenuse of a right triangle formed by the radius and the midpoint of a perpendicular radius.
B.The segment connecting the circle center to the midpoint of the radius.
C.The distance from the center to the intersection of the radius with the main circumference.
D.The length of the chord subtending a 90-degree central angle.
Explanation: In the classic compass-and-straightedge construction of an inscribed pentagon, drawing a radius perpendicular to a diameter and taking the hypotenuse from its midpoint to the top vertex yields the segment whose difference gives the pentagon side length l₅ = R √(10 - 2√5) / 2.
3To construct a circle of radius R tangent to two intersecting lines forming an angle θ, where must the center of the tangent circle be located?
A.On the angle bisector of the two lines, at a distance of R / sin(θ/2) from the intersection vertex.
B.On the perpendicular bisector of the segment connecting the line endpoints.
C.At a distance R measured directly along one of the lines from the vertex.
D.On a line parallel to one of the given lines at a distance 2R.
Explanation: The center of any circle tangent to two intersecting lines lies on their angle bisector. Using right-triangle trigonometry at the point of tangency, the distance from the vertex to the center is R / sin(θ/2).
4In planar inversion with center O and positive power k (k > 0), what is the inverse figure of a circle passing through the center of inversion O?
A.A straight line not passing through O, perpendicular to the diameter containing O.
B.Another circle of equal radius also passing through O.
C.A straight line passing directly through O at a 45-degree inclination.
D.A parabola whose vertex is located at the center of inversion O.
Explanation: Under planar inversion, any circle that passes through the center of inversion O transforms into a straight line that does not pass through O. This line is perpendicular to the diameter of the original circle that connects O with its center.
5A designer applies a central homothety (dilation) with ratio k = -1/2 to a polygon centered at O. How do the transformed figure's orientation and area compare to the original?
A.The figure is inverted (rotated 180°) and its area becomes 1/4 of the original area.
B.The figure remains erect and its area becomes 1/2 of the original area.
C.The figure is reflected across a line and its area remains unchanged.
D.The figure is inverted (rotated 180°) and its area becomes 1/2 of the original area.
Explanation: A negative homothety ratio k = -1/2 scales all linear dimensions by |-1/2| = 1/2 and rotates the figure 180° around the center O. Since area scales with k², the transformed area becomes (-1/2)² = 1/4 of the original area.
6In an ellipse with major axis 2a = 100 mm and minor axis 2b = 60 mm, what is the exact focal distance 2c between its two foci F1 and F2?
A.80 mm
B.40 mm
C.70 mm
D.64 mm
Explanation: For any ellipse, the relationship between semi-major axis 'a', semi-minor axis 'b', and semi-focal distance 'c' is given by a² = b² + c². Here a = 50 mm and b = 30 mm, so c = √(50² - 30²) = √(2500 - 900) = √1600 = 40 mm. Thus the focal distance 2c = 80 mm.
7What is the primary geometric difference between a technical oval (óvalo) and a true mathematical ellipse in plastic arts drawing?
A.An oval is composed of compound circular arcs with discrete centers, whereas an ellipse has continuously changing curvature defined by a single quadratic equation.
B.An oval has two perpendicular axes of symmetry, while an ellipse has only one axis of symmetry.
C.An oval can only be constructed inside a square, whereas an ellipse requires a rectangular bounding box.
D.An oval has four foci, whereas an ellipse has only one central focus.
Explanation: A technical oval is a polycentric closed curve formed by joining circular arcs tangentially at transition points, resulting in piecewise constant curvature. An ellipse is a smooth conic section with continuously variable radius of curvature along its entire perimeter.
8In classical tangency theory, how many distinct solution circles generally exist for the Apollonius problem of finding circles tangent to three given non-intersecting circles (CCC)?
A.8 solution circles
B.4 solution circles
C.2 solution circles
D.16 solution circles
Explanation: The general Apollonius problem of finding circles tangent to three given circles (CCC) yields up to 8 distinct solution circles, corresponding to the 2³ possible combinations of internal and external tangencies.
9An ogee curve (talón / cyma reversa) used in architectural moulding and product design consists of two tangential circular arcs. Where is the inflection point of the ogee located?
A.At the point of tangency where the curvature changes from concave to convex.
B.At the center of the lower circular arc.
C.At the top extremity where the curve meets the vertical fillet.
D.At the midpoint of the chord connecting the two centers.
Explanation: The point of inflection of an ogee curve is the exact point of tangency connecting the two reverse circular arcs. At this point, the curvature changes sign (from convex to concave or vice versa), creating a smooth S-shaped transition.
10To construct a Golden Rectangle starting from a square ABCD of side 'a', what is the radius of the circular arc centered at the midpoint M of side AB used to locate the extended vertex?
A.The distance from midpoint M to the opposite vertex C.
B.Half the length of the side a/2.
C.The full length of the diagonal AC.
D.The side length 'a' multiplied by √2.
Explanation: Starting with a square of side 'a', locate the midpoint M of base AB. The distance MC equals √[a² + (a/2)²] = (a/2)√5. Swinging an arc of radius MC centered at M extends base AB to point E such that AE = a/2 + (a/2)√5 = a(1 + √5)/2, creating a Golden Rectangle.
About the Galicia PAU Technical Drawing Applied to Plastic Arts and Design II Practice Questions
Verified exam format metadata for Galicia PAU Technical Drawing Applied to Plastic Arts and Design II (Dibujo Técnico Aplicado a las Artes Plásticas y al Diseño II - CIUG 2026) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.