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Key Facts: Extremadura PAU Physics Exam

UEx 2026

Organized by Universidad de Extremadura and Junta de Extremadura

Comisión Organizadora PAU Extremadura

90 Mins

Official examination duration

UEx PAU Guidelines

Min 4.0

Minimum mark required in Access Phase to combine with Bachillerato GPA

PAU Extremadura Regulations

5 Core Blocks

Gravitational Field, Electromagnetism, Waves & Optics, Relativity, Quantum & Nuclear Physics

LOMLOE 2º Bachillerato Physics Syllabus

100

Practice questions available in this OpenExamPrep question bank

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Sample Extremadura PAU Physics Practice Questions

Try these sample questions to review concepts for the Extremadura PAU Physics exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Two point masses of m1 = 500 kg and m2 = 800 kg are separated by a distance of r = 2.0 m. Using Newton's law of universal gravitation with G = 6.674 x 10^-11 N*m^2/kg^2, what is the magnitude of the gravitational force between them?
A.6.67 x 10^-6 N
B.1.33 x 10^-5 N
C.3.34 x 10^-6 N
D.2.67 x 10^-5 N
Explanation: According to Newton's law of universal gravitation, F = G * m1 * m2 / r^2. Substituting the values: F = (6.674 x 10^-11) * (500) * (800) / (2.0)^2 = (6.674 x 10^-11) * 400,000 / 4 = (6.674 x 10^-11) * 100,000 = 6.674 x 10^-6 N.
2Planet A orbits a star at a mean orbital radius rA, with an orbital period of TA = 8.0 years. Planet B orbits the same star at a mean orbital radius rB = 4 * rA. According to Kepler's Third Law (T^2 / r^3 = constant), what is the orbital period of Planet B?
A.32 years
B.64 years
C.16 years
D.128 years
Explanation: Kepler's Third Law states that T^2 / r^3 is constant. Therefore, (TB / TA)^2 = (rB / rA)^3 = (4)^3 = 64. Taking the square root gives TB / TA = 8. Thus, TB = 8 * TA = 8 * 8.0 years = 64 years.
3What is the gravitational field strength g at an altitude h = RE above the surface of the Earth, where RE is the Earth's radius and g0 = 9.80 m/s^2 is the surface gravitational acceleration?
A.4.90 m/s^2
B.1.23 m/s^2
C.2.45 m/s^2
D.9.80 m/s^2
Explanation: The distance from Earth's center to the altitude h = RE is r = RE + h = 2 * RE. Gravitational field strength varies inversely with the square of distance: g(r) = G * ME / r^2 = G * ME / (2 * RE)^2 = (1/4) * (G * ME / RE^2) = g0 / 4 = 9.80 / 4 = 2.45 m/s^2.
4Which statement correctly describes the sign and physical interpretation of gravitational potential energy Ep = -G * M * m / r for a two-body bound system?
A.Ep is always negative because energy must be added to the system to separate the masses to infinity where Ep = 0.
B.Ep is always positive because gravity is an attractive force.
C.Ep is zero at the surface of the primary body and becomes negative at infinity.
D.Ep is positive for bound orbits and negative for unbound hyperbolic trajectories.
Explanation: Gravitational potential energy is conventionally set to zero at infinity (r -> infinity). Because gravity is attractive, work must be done against the gravitational field to move a mass from distance r to infinity. Hence, Ep(r) < 0 for any finite distance r.
5A satellite of mass m = 1000 kg orbits Earth in a circular path at distance r = 4 * RE from Earth's center. Given Earth's surface gravity g0 = 9.80 m/s^2 and RE = 6.37 x 10^6 m, what is the satellite's circular orbital speed?
A.7.90 km/s
B.5.59 km/s
C.3.95 km/s
D.11.2 km/s
Explanation: For a circular orbit, gravitational force provides centripetal acceleration: G * ME * m / r^2 = m * vorb^2 / r => vorb = sqrt(G * ME / r). Since g0 = G * ME / RE^2, we have G * ME = g0 * RE^2. Thus vorb = sqrt(g0 * RE^2 / (4 * RE)) = sqrt(g0 * RE / 4) = 0.5 * sqrt(g0 * RE) = 0.5 * sqrt(9.80 * 6.37 x 10^6) = 0.5 * 7901 m/s = 3950 m/s = 3.95 km/s.
6What is the escape velocity v_esc from the surface of Earth (RE = 6.37 x 10^6 m, g0 = 9.80 m/s^2)?
A.7.90 km/s
B.11.2 km/s
C.15.8 km/s
D.9.80 km/s
Explanation: Escape velocity is obtained by setting total mechanical energy E = E_k + E_p = 0: (1/2) * m * v_esc^2 - G * ME * m / RE = 0 => v_esc = sqrt(2 * G * ME / RE) = sqrt(2 * g0 * RE). Substituting RE = 6.37 x 10^6 m and g0 = 9.80 m/s^2: v_esc = sqrt(2 * 9.80 * 6.37 x 10^6) = sqrt(1.2485 x 10^8) = 11174 m/s approx 11.2 km/s.
7According to Kepler's Second Law (Law of Equal Areas), how does the speed of a planet at perihelion (closest distance rp) compare to its speed at aphelion (farthest distance ra)?
A.Speed at perihelion is higher, satisfying vp * rp = va * ra due to angular momentum conservation.
B.Speed at aphelion is higher because the planet is farther from the Sun.
C.Speed is equal at perihelion and aphelion because mechanical energy is constant.
D.Speed at perihelion is lower because gravitational potential energy is maximum.
Explanation: Kepler's Second Law is a direct consequence of the conservation of angular momentum (L = m * r * v * sin(theta) = constant). At perihelion and aphelion, velocity is perpendicular to the position vector, so L = m * rp * vp = m * ra * va => vp * rp = va * ra. Since rp < ra, vp > va.
8A comet in an elliptical orbit around the Sun has a perihelion distance rp = 0.50 AU with speed vp = 54 km/s. What is its orbital speed va at aphelion, located at ra = 4.5 AU?
A.6.0 km/s
B.12 km/s
C.27 km/s
D.3.0 km/s
Explanation: Using conservation of angular momentum at perihelion and aphelion: vp * rp = va * ra => va = vp * (rp / ra) = 54 km/s * (0.50 / 4.5) = 54 / 9 = 6.0 km/s.
9How much work must be done by an external agent to lift a m = 200 kg satellite from Earth's surface (r1 = RE) to an altitude h = RE (r2 = 2 * RE)? (Use RE = 6.37 x 10^6 m, g0 = 9.80 m/s^2).
A.1.25 x 10^10 J
B.6.24 x 10^9 J
C.3.12 x 10^9 J
D.2.49 x 10^10 J
Explanation: Work done W = Ep(r2) - Ep(r1) = -G * ME * m / (2 * RE) - (-G * ME * m / RE) = G * ME * m / (2 * RE) = (1/2) * m * g0 * RE. Substituting m = 200 kg, g0 = 9.80 m/s^2, RE = 6.37 x 10^6 m: W = 0.5 * 200 * 9.80 * 6.37 x 10^6 = 6.2426 x 10^9 J approx 6.24 x 10^9 J.
10Two point masses M1 = 16 * M and M2 = M are fixed at a distance d = 10 m apart. At what distance x from M1 along the line connecting them does the net gravitational field intensity equal zero?
A.8.0 m
B.6.0 m
C.5.0 m
D.9.0 m
Explanation: The gravitational fields due to M1 and M2 point in opposite directions between the masses. Setting g1 = g2: G * M1 / x^2 = G * M2 / (d - x)^2 => 16 * M / x^2 = M / (10 - x)^2. Taking square roots: 4 / x = 1 / (10 - x) => 4 * (10 - x) = x => 40 - 4x = x => 5x = 40 => x = 8.0 m.

About the Extremadura PAU Physics Exam

Comprehensive practice exam bank for Extremadura PAU 2026 Physics (Física), aligned with the LOMLOE curriculum for 2º Bachillerato defined by the Comisión Organizadora de la PAU de Extremadura and Universidad de Extremadura (UEx).

Exam sponsor: Comisión Organizadora de la PAU de Extremadura (Universidad de Extremadura - UEx / Consejería de Educación de la Junta de Extremadura). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Question count not published by the exam provider

Time Limit

90 minutes (1.5 hours)

Passing Score

Marked on a 0–10 scale. Minimum 4.0 required in Access Phase to combine with Bachillerato GPA (60% Bachillerato + 40% PAU >= 5.0 to pass).

Exam / Certification Fees

EUR 78.26 ordinary registration fee for PAU (50% discount EUR 39.13 for general large family; full exemption for special large family, disability, or terrorism victims).

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

20%

Gravitational Field

Kepler laws, Newton law of universal gravitation, gravitational potential energy, escape velocity, and satellite orbits.

25%

Electromagnetic Field

Coulomb law, electric field and potential, Lorentz magnetic force, Biot-Savart law, and Faraday-Lenz electromagnetic induction.

25%

Wave Motion & Optics

Harmonic wave equation, interference, diffraction, Snell law, total internal reflection, and thin lens / mirror ray tracing.

15%

Special Relativity

Postulates of special relativity, time dilation, length contraction, relativistic momentum, and mass-energy equivalence.

15%

Quantum & Nuclear Physics

Photoelectric effect, de Broglie wavelength, nuclear binding energy, radioactive decay laws, and mass defect.

Preparing for the Extremadura PAU Physics Exam

What You Need to Know

  • Passing score: Marked on a 0–10 scale. Minimum 4.0 required in Access Phase to combine with Bachillerato GPA (60% Bachillerato + 40% PAU >= 5.0 to pass).
  • Assessment: Question count not published by the exam provider
  • Time limit: 90 minutes (1.5 hours)
  • Exam / certification fees: EUR 78.26 ordinary registration fee for PAU (50% discount EUR 39.13 for general large family; full exemption for special large family, disability, or terrorism victims). Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Extremadura PAU Physics: Suggested Study Strategy

1Master gravitational field calculations, including orbital velocity, period, escape velocity, and mechanical energy conservation for bound vs unbound orbits.
2Practice vector mechanics in electrostatics and magnetostatics: calculating net electric/magnetic field vectors, potential superposition, Lorentz force trajectories, and Faraday-Lenz induced EMF.
3Be comfortable with wave equation formulations y(x,t) = A sin(wt - kx + phi_0), decibel calculations, optical path differences, Snell's law, critical angles, and lens/mirror sign conventions.
4Understand special relativity formulas (Lorentz factor gamma, time dilation, length contraction, relativistic total and kinetic energy) and quantum mechanics (photoelectric threshold frequency, stopping potential, de Broglie wavelength, mass defect, binding energy per nucleon, decay constant lambda, and half-life T_1/2).

Frequently Asked Questions

What is the fee for taking the PAU exam in Extremadura (UEx 2026)?

The ordinary registration fee for the PAU Access Phase in Extremadura is EUR 78.26. A 50% discount (EUR 39.13) applies to general large family category, and a 100% exemption applies to special large family members, students with disabilities (>=33%), or victims of terrorism.

What passing score is required on the PAU Physics exam in Extremadura?

The exam is marked on a 0–10 scale. A minimum mark of 4.0 is required in the PAU Access Phase block to calculate the overall admission score (60% Bachillerato GPA + 40% PAU Access Phase >= 5.0).

What is the duration and structure of the PAU Physics exam in Extremadura?

The exam lasts 90 minutes (1.5 hours) and consists of problem-solving exercises and theoretical questions covering 2º Bachillerato Physics topics.

Which university organizes the PAU exam in Extremadura?

The examination is organized by the Comisión Organizadora de la PAU de Extremadura, managed by the Universidad de Extremadura (UEx) in coordination with the Consejería de Educación de la Junta de Extremadura.