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100+ Free Catalonia PAU Technology and Engineering II Practice Questions
Catalonia PAU Technology and Engineering II Examination / Tecnologia i Enginyeria II 2n de Batxillerat 2026 practice questions are available now; exam metadata is being verified.
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2026 Statistics
Key Facts: Catalonia PAU Technology and Engineering II Exam
90 min
Time limit for Catalonia PAU Technology and Engineering II examination
Consell Interuniversitari de Catalunya (CIC)
EUR 110.00+ access phase (EUR 41.30 exam right + EUR 68.70 access phase; plus EUR 13.80 per admission exercise, Generalitat de Catalunya 2026)
Base registration fee set by Generalitat de Catalunya for Access Phase
Generalitat de Catalunya PAU Regulations
4.0 / 10
Minimum score required in Access Phase to combine with Batxillerat GPA
Consell Interuniversitari de Catalunya (CIC)
100
High-yield worked engineering calculation practice questions
OpenExamPrep
Catalonia PAU Technology and Engineering II is a 90-minute university entrance exam covering materials science, heat engines, electrical circuits, Boolean logic, fluid power, and feedback control systems.
Sample Catalonia PAU Technology and Engineering II Practice Questions
Try these sample questions to test your Catalonia PAU Technology and Engineering II exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1A cylindrical steel test bar with an initial diameter of 10 mm is subjected to an axial tensile force of 20 kN. What is the normal tensile stress induced in the cross-section of the specimen?
A.254.65 MPa
B.63.66 MPa
C.200.00 MPa
D.1018.59 MPa
Explanation: Normal tensile stress is defined as σ = F / A0. The cross-sectional area is A0 = (π · d²) / 4 = (π · (10 mm)²) / 4 = 78.54 mm². Dividing 20,000 N by 78.54 mm² yields 254.65 N/mm² or 254.65 MPa.
2A metal specimen with an initial gauge length of 150 mm elongates by 0.30 mm when subjected to an axial load within its elastic limit. What is the engineering unit strain of the specimen?
A.0.020 (2.0%)
B.0.002 (0.2%)
C.0.005 (0.5%)
D.0.0002 (0.02%)
Explanation: Engineering unit strain is defined as ε = ΔL / L0. Dividing the elongation of 0.30 mm by the initial gauge length of 150 mm gives ε = 0.002, which corresponds to 0.2%.
3A metallic alloy specimen experiences a tensile stress of 300 MPa and an elastic strain of 0.0015. What is the modulus of elasticity (Young's modulus E) of this material?
A.450 GPa
B.20 GPa
C.200 GPa
D.2000 GPa
Explanation: According to Hooke's Law in the elastic regime, E = σ / ε. Dividing 300 MPa (300 × 10⁶ Pa) by 0.0015 yields E = 200,000 MPa, which equals 200 GPa.
4Which formula correctly represents the Brinell hardness number (HB) calculation for a spherical indenter of diameter D and indentation diameter d under load P (in kgf)?
A.HB = (2 · P) / [ π · D · (D - √(D² - d²)) ]
B.HB = P / [ π · D · d ]
C.HB = (2 · P) / [ π · d · (D + √(D² - d²)) ]
D.HB = (P · D) / [ 2 · π · √(D² - d²) ]
Explanation: The Brinell hardness number HB is determined by dividing the applied load P by the curved surface area of the spherical indentation, given by HB = (2 · P) / [ π · D · (D - √(D² - d²)) ].
5What physical property of a material is primarily evaluated using a Charpy pendulum impact test?
A.Ductility
B.Hardness
C.Resilience and impact toughness
D.Electrical conductivity
Explanation: The Charpy pendulum impact test measures impact toughness and resilience (energy absorbed during dynamic fracture per unit cross-sectional area).
6What is the primary objective of performing a tempering (revenut) heat treatment on steel after quenching (temprat)?
A.To maximize grain size and increase internal stress
B.To transform ferrite completely into un-tempered austenite
C.To increase carbon concentration at the outer surface
D.To relieve internal stresses and increase toughness while slightly reducing extreme hardness
Explanation: Tempering involves reheating quenched martensitic steel below the lower critical temperature to relieve internal residual stresses, reduce brittleness, and restore toughness and ductility.
7Which heat treatment process involves heating steel to an austenitic temperature followed by very slow furnace cooling to produce maximum softness and ductility?
A.Annealing (recuit)
B.Quenching (temprat)
C.Carburizing (cementació)
D.Flame hardening
Explanation: Annealing (recuit) consists of heating steel to the austenitic phase followed by slow furnace cooling to refine grain structure, eliminate internal stresses, and achieve minimum hardness and maximum softness.
8What is the main mechanism of carburizing (cementació) in surface heat treatment of low-carbon steels?
A.Diffusing carbon atoms into the surface layer at elevated temperature to form a hard case upon quenching
B.Diffusing nitrogen to form brittle iron nitrides without subsequent quenching
C.Rapidly cooling the steel core using liquid nitrogen spray
D.Adding copper to increase thermal conductivity throughout the bulk specimen
Explanation: Carburizing diffuses carbon atoms into the austenitic surface layer of low-carbon steel at high temperatures, creating a high-carbon outer skin that becomes very hard after quenching while keeping a tough core.
9A steel bar of initial length 2.0 m and cross-sectional area 100 mm² is pulled by a tensile force of 15 kN. Given Young's modulus E = 200 GPa, what is the total elongation ΔL of the bar?
A.0.15 mm
B.1.50 mm
C.15.00 mm
D.0.75 mm
Explanation: Elongation is given by ΔL = (F · L0) / (A0 · E). Substituting F = 15,000 N, L0 = 2000 mm, A0 = 100 mm², and E = 200,000 MPa yields ΔL = (15,000 · 2000) / (100 · 200000) = 30,000,000 / 20,000,000 = 1.50 mm.
10In a Brinell hardness test on a steel block using a standard 10 mm diameter hardened steel ball under a load P = 3000 kgf, an indentation diameter d = 4.0 mm is measured. What is the Brinell hardness value (HB)?
A.149.2 HB
B.228.7 HB
C.350.0 HB
D.477.5 HB
Explanation: HB = (2 · P) / [ π · D · (D - √(D² - d²)) ]. Here D = 10 mm, d = 4 mm. √(100 - 16) = √84 = 9.16515 mm. The denominator is π · 10 · (10 - 9.16515) = 31.4159 · 0.83485 = 26.227 mm². HB = 6000 / 26.227 = 228.7 HB.
About the Catalonia PAU Technology and Engineering II Practice Questions
Verified exam format metadata for Catalonia PAU Technology and Engineering II Examination / Tecnologia i Enginyeria II 2n de Batxillerat 2026 is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.