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100+ Free Catalonia PAU Technical Drawing (Dibuix Tècnic II) Practice Questions
Catalonia PAU Technical Drawing Examination — Dibuix Tècnic II 2º Bachillerato CIC 2026 practice questions are available now; exam metadata is being verified.
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2026 Statistics
Key Facts: Catalonia PAU Technical Drawing (Dibuix Tècnic II) Exam
EUR 110.00+ access phase (EUR 41.30 exam right + EUR 68.70 access phase; plus EUR 13.80 per admission exercise, Generalitat de Catalunya 2026)
Base registration fee set by Generalitat de Catalunya
Consell Interuniversitari de Catalunya (CIC)
90 Mins
Official examination duration
Consell Interuniversitari de Catalunya (CIC)
Min 4.0
Minimum Access Phase score required to calculate admission mark
Generalitat de Catalunya Regulations
English MCQ
Study adaptation of official graphic exam
OpenExamPrep
100
Practice questions covering complete 2º Bachillerato Dibuix Tècnic II syllabus
OpenExamPrep
The Catalonia PAU Dibuix Tècnic II exam evaluates mastery of plane geometry, dihedral projection, axonometry, conic perspective, and ISO technical drawing standards. This question bank is an English MCQ study adaptation.
Sample Catalonia PAU Technical Drawing (Dibuix Tècnic II) Practice Questions
Try these sample questions to test your Catalonia PAU Technical Drawing (Dibuix Tècnic II) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1In plane geometry, what is the circumcenter of a triangle, and what fundamental geometric property does it exhibit?
A.The point of intersection of the three perpendicular bisectors of the sides; it is equidistant from the three vertices.
B.The point of intersection of the three internal angle bisectors; it is equidistant from the three sides.
C.The point of intersection of the three altitudes; it forms the orthic triangle vertices.
D.The point of intersection of the three medians; it divides each median in a 2:1 ratio.
Explanation: The circumcenter is defined as the intersection point of the perpendicular bisectors of a triangle's sides. Because every point on a perpendicular bisector is equidistant from the endpoints of that side segment, the circumcenter is equidistant from all three vertices, serving as the center of the circumscribed circle.
2Which triangle center is located at the intersection of the internal angle bisectors and forms the center of the inscribed circle?
A.Orthocenter
B.Incenter
C.Circumcenter
D.Centroid
Explanation: The incenter is constructed by intersecting the three internal angle bisectors of a triangle. Since any point on an angle bisector is equidistant from the two sides defining that angle, the incenter is equidistant from all three sides and acts as the center of the inscribed circle (incircle).
3In a triangle, how is the orthocenter constructed?
A.By intersecting the three medians.
B.By intersecting the perpendicular bisectors of the sides.
C.By intersecting the three altitudes drawn perpendicular from each vertex to the opposite side.
D.By intersecting the external angle bisectors.
Explanation: The orthocenter is the common intersection point of the three altitudes of a triangle, where each altitude is a line segment passing through a vertex and perpendicular to the opposite side (or its extension).
4What property defines the centroid (baricenter) regarding its location along each median of a triangle?
A.It bisects each median into two equal halves.
B.It lies at a distance from each vertex equal to two-thirds of the total length of that median.
C.It lies at a distance from each vertex equal to one-third of the total length of that median.
D.It is located at the midpoint of the circumcenter-incenter line segment.
Explanation: The centroid divides every median in a 2:1 ratio, meaning the segment connecting the vertex to the centroid is twice as long as the segment connecting the centroid to the midpoint of the opposite side. Therefore, the distance from the vertex to the centroid is two-thirds of the median's full length.
5Which three remarkable points of any non-equilateral triangle always lie on the Euler line?
A.Incenter, circumcenter, and centroid.
B.Orthocenter, centroid, and circumcenter.
C.Incenter, orthocenter, and excenter.
D.Orthocenter, incenter, and Fermat point.
Explanation: The Euler line passes through the orthocenter, centroid, and circumcenter of any non-equilateral triangle. Furthermore, the centroid divides the segment connecting the orthocenter and circumcenter in a 2:1 ratio.
6In a plane homothety with center O and ratio k = -0.5, how are transformed figures oriented relative to the original?
A.They are enlarged and oriented in the same direction.
B.They are inverted (rotated 180°) and scaled to half size on opposite sides of O.
C.They are rotated by 90° clockwise around O.
D.They are translated along a parallel vector without scaling.
Explanation: A negative scale factor k = -0.5 causes corresponding points to lie on opposite sides of the center of homothety O, creating an inverted figure rotated by 180°. Since |k| = 0.5, all linear dimensions are scaled down to half their original size.
7What is the radical axis of two non-concentric circumferences in a plane?
A.The line segment connecting the two circle centers.
B.The straight line that is the locus of all points having equal power with respect to both circumferences.
C.The circle whose diameter is the line segment joining the centers.
D.The tangent line drawn from the center of one circle to the edge of the second.
Explanation: The radical axis of two circles is the locus of points from which tangent segments drawn to both circles have equal lengths, meaning points on this straight line possess equal geometric power with respect to both circles. It is always perpendicular to the line connecting the centers of the two circles.
8How is the radical center of three circles with non-collinear centers located?
A.By finding the centroid of the triangle formed by their centers.
B.By constructing the intersection of the radical axes of the three pairs of circles taken two at a time.
C.By drawing the common tangent lines to all three circles simultaneously.
D.By taking the average radius of the three circles along their line of centers.
Explanation: The radical center of three circles with non-collinear centers is the single point of intersection of their three pairwise radical axes. From this point, tangent segments drawn to all three circles are equal in length.
9In a plane inversion with center O and positive constant k, what is the inverse of a straight line that passes through the center of inversion O?
A.A circumference passing through O.
B.The same straight line itself, transformed point-by-point along itself.
C.A parabola with vertex at O.
D.A circle centered at O with radius sqrt(k).
Explanation: Any straight line passing through the center of inversion O is transformed into itself (it is invariant as a line, though individual points exchange positions along the line such that OP * OP' = k).
10In plane inversion centered at O, what geometric figure is obtained as the inverse of a straight line r that does NOT pass through O?
A.A straight line parallel to r.
B.A circumference that passes through the center of inversion O.
C.A circumference that does not pass through O.
D.A hyperbola with focus at O.
Explanation: The inverse of a straight line not passing through the center of inversion O is a circle that passes through O. The diameter of this circle passing through O lies on the perpendicular dropped from O to line r.
About the Catalonia PAU Technical Drawing (Dibuix Tècnic II) Practice Questions
Verified exam format metadata for Catalonia PAU Technical Drawing Examination — Dibuix Tècnic II 2º Bachillerato CIC 2026 is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.