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100+ Free PAU Technology & Engineering II (Cantabria) Practice Questions
Cantabria PAU Technology and Engineering II 2026 (Pruebas de Acceso a la Universidad, Universidad de Cantabria) practice questions are available now; exam metadata is being verified.
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2026 Statistics
Key Facts: PAU Technology & Engineering II (Cantabria) Exam
90 min
Exam duration for the PAU Technology and Engineering II paper
University of Cantabria (UNICAN) PAU Organising Commission
0–10 scale
Scoring scale (minimum 4.0 required in Access Phase)
Cantabria PAU Regulations
0.2 Weight
Maximum admission weighting parameter for engineering degrees in Spain
UNICAN Degree Admission Weighting Table
5 Blocks
Core content areas (Materials, Thermodynamics, Electrical, Control/Pneumatics, Digital/Programming)
2º Bachillerato Curriculum (RD 243/2022)
100
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Sample PAU Technology & Engineering II (Cantabria) Practice Questions
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1A cylindrical metal specimen with an initial cross-sectional area of 100 mm² is subjected to an axial tensile force of 50 kN. What is the engineering stress induced in the specimen?
A.500 MPa
B.50 MPa
C.5000 MPa
D.0.5 MPa
Explanation: Engineering stress (σ) is defined as force divided by the initial cross-sectional area: σ = F / A₀. Converting force to Newtons gives F = 50,000 N, so σ = 50,000 N / 100 mm² = 500 N/mm² = 500 MPa.
2A steel tie rod of original gauge length L₀ = 200 mm elongates by ΔL = 0.4 mm under tension. What is the engineering strain (ε) of the rod?
A.0.02 (2.0%)
B.0.002 (0.2%)
C.0.0002 (0.02%)
D.0.004 (0.4%)
Explanation: Engineering strain is defined as unit elongation: ε = ΔL / L₀. Substituting the values gives ε = 0.4 mm / 200 mm = 0.002, which corresponds to 0.2%.
3An elastic structural component experiences an engineering stress of σ = 210 MPa at a strain of ε = 0.001. What is the Young's modulus (E) of the material?
A.2.1 GPa
B.21 GPa
C.210 GPa
D.2100 GPa
Explanation: According to Hooke's Law in the elastic regime, E = σ / ε. Substituting σ = 210 × 10⁶ Pa and ε = 0.001 yields E = 210 × 10⁹ Pa = 210 GPa, typical for structural steel.
4Which indenter geometry and material are standardized for performing a Brinell hardness test (HB)?
A.A square-based diamond pyramid with a 136° face angle
B.A 120° diamond cone with a spherical tip
C.A 1/16-inch steel ball indenter for soft metals
D.A hardened steel or tungsten carbide spherical ball
Explanation: The Brinell hardness test utilizes a hardened steel or tungsten carbide spherical ball indenter (typically 10 mm in diameter) pressed into the test piece under a specified load.
5What fundamental material property is measured by the Charpy impact test?
A.Impact energy absorbed during dynamic fracture (toughness/resilience)
B.Yield strength under static loading
C.Resistance to localized plastic surface deformation
D.Fatigue limit under cyclic loading
Explanation: The Charpy pendulum impact test measures impact energy absorbed (in Joules or J/cm²) when a notched specimen is fractured under high-strain-rate impact, evaluating material resilience and toughness.
6Why can thermoplastic polymers be repeatedly melted, reshaped, and recycled, whereas thermosetting polymers cannot?
A.Thermoplastics possess cross-linked covalent network bonds between chains.
B.Thermoplastics consist of linear or branched polymer chains joined by weak secondary van der Waals bonds.
C.Thermosets have no covalent bonds in their molecular structure.
D.Thermoplastics expand irreversibly when heated due to chemical degradation.
Explanation: Thermoplastics consist of linear or branched macromolecular chains held together by weak secondary forces (van der Waals or hydrogen bonds) that break easily upon heating, allowing remelting. Thermosets contain permanent, highly cross-linked covalent network bonds that decompose rather than melt when heated.
7A solid cylindrical alloy rod with diameter d = 10 mm is subjected to a tensile force F = 15.71 kN. Calculate the tensile stress σ in the rod.
A.100 MPa
B.157 MPa
C.200 MPa
D.400 MPa
Explanation: First calculate the cross-sectional area: A₀ = (π/4) × d² = (π/4) × (10 mm)² ≈ 78.54 mm². Then calculate stress: σ = F / A₀ = 15,710 N / 78.54 mm² = 200 N/mm² = 200 MPa.
8In a Brinell hardness test, a load P = 3000 kgf applied with a D = 10 mm diameter ball indenter produces an indentation diameter d = 4 mm. Calculate the Brinell Hardness Number (HB).
A.143 kgf/mm²
B.352 kgf/mm²
C.475 kgf/mm²
D.229 kgf/mm²
Explanation: The Brinell hardness formula is HB = 2P / [π D (D - √(D² - d²))]. Substituting values: √(D² - d²) = √(100 - 16) = √84 ≈ 9.165 mm. Indentation area A = π × 10 × (10 - 9.165) / 2 = 5π × 0.835 ≈ 13.116 mm². Thus HB = 3000 / 13.116 ≈ 228.7 ≈ 229 kgf/mm².
9A Charpy test uses a pendulum of mass m = 20 kg released from height h₁ = 1.5 m. After fracturing a specimen with cross-section S₀ = 80 mm² (0.8 cm²), the pendulum rises to height h₂ = 0.6 m. Taking g = 9.8 m/s², calculate the resilience K (absorbed energy per unit area) in J/cm².
A.220.5 J/cm²
B.110.25 J/cm²
C.176.4 J/cm²
D.275.6 J/cm²
Explanation: Absorbed energy ΔE = m·g·(h₁ - h₂) = 20 kg × 9.8 m/s² × (1.5 m - 0.6 m) = 196 N × 0.9 m = 176.4 J. Resilience K is absorbed energy per unit cross-sectional area: K = ΔE / S₀ = 176.4 J / 0.8 cm² = 220.5 J/cm².
10In materials fatigue analysis, what does the 'fatigue limit' (or endurance limit) on a Wöhler S-N curve represent?
A.The maximum stress a material can withstand for a single load cycle
B.The stress level below which the material can endure an infinite number of cyclic loads without failing
C.The stress at which necking initiates during a fatigue test
D.The energy required to propagate a fatigue crack to catastrophic failure
Explanation: The fatigue limit (endurance limit) is the horizontal asymptote on a Wöhler (S-N) diagram; for stress amplitudes below this limit, ferrous alloys can theoretically withstand infinite loading cycles without fatigue failure.
About the PAU Technology & Engineering II (Cantabria) Practice Questions
Verified exam format metadata for Cantabria PAU Technology and Engineering II 2026 (Pruebas de Acceso a la Universidad, Universidad de Cantabria) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.