All Practice Exams
100+ Free Cantabria PAU Technical Drawing II (Dibujo Técnico II) Practice Questions
Cantabria PAU Technical Drawing II Examination — Dibujo Técnico II 2º Bachillerato UNICAN 2026 practice questions are available now; exam metadata is being verified.
✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately
100+ Questions
100% Free
Loading practice questions...
Same family resources
Explore More Spain Cantabria PAU (Prueba de Acceso a la Universidad)
Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.
2026 Statistics
Key Facts: Cantabria PAU Technical Drawing II (Dibujo Técnico II) Exam
UNICAN 2026
University of Cantabria PAU Organising Commission authority
UNICAN PAU Regulations
90 Mins
Official examination duration
UNICAN PAU Regulations
Min 4.0
Minimum Access Phase score required to calculate university admission mark
UNICAN Admission Regulations
5 Blocks
Plane Geometry, Dihedral, Axonometry, Conic Perspective, Normalization
LOMLOE 2º Bachillerato Syllabus
100
Practice questions available in this OpenExamPrep bank
OpenExamPrep
The Cantabria PAU Technical Drawing II exam evaluates core competency across plane geometry, dihedral system, axonometric projection, conic perspective, and ISO drafting standards for 2º Bachillerato students. This English-language MCQ bank is a study adaptation of the knowledge behind the official written exam, not a format simulation.
Sample Cantabria PAU Technical Drawing II (Dibujo Técnico II) Practice Questions
Try these sample questions to test your Cantabria PAU Technical Drawing II (Dibujo Técnico II) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1What is the name of the intersection point of a triangle’s three side perpendicular bisectors, and what fundamental property does it have?
A.Circumcenter; it is the center of the circle circumscribed about the triangle.
B.Incenter; it is the center of the circle inscribed in the triangle.
C.Orthocenter; it is the intersection of the triangle’s three altitudes.
D.Centroid; it is the center of gravity and intersection of the medians.
Explanation: The circumcenter is equidistant from all three vertices, so it is the center of the circumscribed circle.
2Which triangle center is obtained as the intersection of its interior angle bisectors?
A.Orthocenter.
B.Incenter.
C.Circumcenter.
D.Centroid.
Explanation: The incenter is the intersection of the interior angle bisectors and center of the inscribed circle.
3The centroid G divides each median of a triangle into two segments. What is the ratio of the distance from the centroid to the vertex relative to the opposite side?
A.The centroid is halfway along the median from vertex to side.
B.The centroid is 3/4 of the median from the vertex and 1/4 from the side.
C.The centroid is 2/3 of the median’s total length from the vertex and 1/3 from the midpoint of the opposite side.
D.The centroid is exactly equidistant from the vertex and the triangle’s circumcenter.
Explanation: On each median, VG = 2·GM, i.e., 2/3 from vertex and 1/3 from the side midpoint.
4Given a circle of center O and radius R, and an exterior point P at distance d from O, what is the mathematical expression for the power of P with respect to that circle?
A.Pot(P) = d + R.
B.Pot(P) = d² + R².
C.Pot(P) = (d - R)².
D.Pot(P) = d² - R².
Explanation: Power of a point is Pot(P)=d²−R² (positive outside, zero on, negative inside).
5What geometric property characterizes the radical axis of two non-concentric circles?
A.It is the locus of points in the plane with equal power with respect to both circles, and is always perpendicular to the line of centers.
B.It is a line oblique to the line joining the centers of both circles.
C.It is a common tangent circle to both given circles.
D.It is the segment joining the midpoints of the radii of both circles.
Explanation: The radical axis is the equal-power locus and is perpendicular to the line of centers.
6In a planar homothety of center O and ratio k (k ≠ 0), what relationship exists between any original line and its transformed (homologous) line?
A.They are always perpendicular to each other.
B.They are always parallel to each other.
C.They intersect forming an angle equal to the ratio k.
D.They are concentric with respect to center O.
Explanation: Homothety maps every line to a strictly parallel homologous line.
7How is the radical center of three circles whose centers are not collinear defined and determined?
A.It is the intersection of the perpendicular bisectors of the segments joining their three centers.
B.It is the centroid of the triangle formed by the three circle centers.
C.It is the unique intersection of the three radical axes taken pairwise, from which equal-length tangents can be drawn to all three circles.
D.It is the center of the circle passing through the centers of the three given circles.
Explanation: The radical center is the common intersection of the three pairwise radical axes (equal power to all three circles).
8In every non-equilateral triangle, which notable centers always lie on Euler’s line and in what relative order?
A.Incenter, centroid and orthocenter.
B.Circumcenter, incenter and orthocenter, with the incenter midpoint of the other two.
C.Centroid, incenter and circumcenter forming a golden ratio.
D.Orthocenter (H), centroid (G) and circumcenter (O), with G between H and O such that HG = 2·GO.
Explanation: Euler’s line contains H, G and O with HG=2·GO.
9Given a planar inversion of center O and constant K>0, what is the inverse figure of a line r that does NOT pass through the inversion center O?
A.A circle that passes through inversion center O and whose diameter on the perpendicular from O to r passes through O.
B.Another line r′ parallel to the original line r.
C.A parabola with focus at inversion center O.
D.A circle concentric with the circle of double points.
Explanation: The inverse of a line not through O is a circle through O.
10In planar inversion, what happens if we invert a circle c that passes through the inversion center O?
A.It transforms into a single point coincident with O.
B.It transforms into a line that does not pass through O and is perpendicular to the diameter of c through O.
C.It transforms into a high-eccentricity ellipse.
D.It transforms into another identical displaced circle.
Explanation: By reciprocity, a circle through O inverts to a line not through O.
About the Cantabria PAU Technical Drawing II (Dibujo Técnico II) Practice Questions
Verified exam format metadata for Cantabria PAU Technical Drawing II Examination — Dibujo Técnico II 2º Bachillerato UNICAN 2026 is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.