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2026 Statistics
Key Facts: PAU Physics (Aragón) Exam
90 min
Time Limit
UNIZAR / Comisión PAU Aragón
0–10
Grading Scale
Gobierno de Aragón
4.0
Min. Access Phase Mark
PAU Regulations
EUR 75.00
Ordinary Registration Fee
UNIZAR PAU inscription page 2026
100
Practice Questions
English Study Adaptation
The Aragón PAU Physics (Física) exam is a 90-minute examination set by the PAU Organising Commission of Aragón / UNIZAR with a registration fee of EUR 75.00 (Access Phase base fee). Grades are awarded on a 0–10 scale, with a minimum 4.0 required to average with high school GPA. This study portal provides an English-language MCQ study adaptation featuring 100 practice questions with real calculations covering all official curriculum modules.
Sample PAU Physics (Aragón) Practice Questions
Try these sample questions to test your PAU Physics (Aragón) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1Two point masses of m1 = 2000 kg and m2 = 5000 kg are separated by a distance of r = 5.0 m in a vacuum. Using Newton's Law of Universal Gravitation with G = 6.67 x 10^-11 N m^2/kg^2, what is the magnitude of the gravitational force between them?
A.1.33 x 10^-4 N
B.5.34 x 10^-6 N
C.2.67 x 10^-7 N
D.2.67 x 10^-5 N
Explanation: Applying Newton's law of universal gravitation: F = G * m1 * m2 / r^2 = (6.67 x 10^-11) * (2000) * (5000) / (5.0)^2 = (6.67 x 10^-11) * (1.0 x 10^7) / 25 = 2.668 x 10^-5 N.
2If the gravitational field strength at Earth's surface is g0 = 9.80 N/kg, what is the field strength g at an altitude h = 2 R_E above Earth's surface, where R_E is Earth's radius?
A.3.27 N/kg
B.2.45 N/kg
C.4.90 N/kg
D.1.09 N/kg
Explanation: The distance from Earth's center is r = R_E + h = R_E + 2 R_E = 3 R_E. Since g = G M_E / r^2, g = G M_E / (3 R_E)^2 = g0 / 9 = 9.80 / 9 = 1.089 N/kg.
3A satellite moves in a circular orbit around Earth at an altitude h = R_E equal to Earth's radius (R_E = 6.37 x 10^6 m). Taking g0 = 9.80 m/s^2 at the surface, what is the satellite's orbital speed?
A.5.59 km/s
B.11.2 km/s
C.3.95 km/s
D.7.91 km/s
Explanation: At radial distance r = 2 R_E, centripetal force equals gravitational force: m v^2 / r = G M_E m / r^2 => v = sqrt(G M_E / r) = sqrt(g0 R_E^2 / (2 R_E)) = sqrt(g0 R_E / 2) = sqrt(9.80 * 6.37 x 10^6 / 2) = sqrt(3.1213 x 10^7) = 5587 m/s = 5.59 km/s.
4Given the Moon's mass M_M = 7.35 x 10^22 kg and radius R_M = 1.74 x 10^6 m, what is the escape velocity from the lunar surface? (G = 6.67 x 10^-11 N m^2/kg^2)
A.2.37 km/s
B.3.35 km/s
C.4.74 km/s
D.1.68 km/s
Explanation: Escape velocity is v_esc = sqrt(2 G M / R) = sqrt(2 * 6.67 x 10^-11 * 7.35 x 10^22 / 1.74 x 10^6) = sqrt(5.6356 x 10^6) = 2374 m/s = 2.37 km/s.
5What is the gravitational potential energy of a 500 kg satellite in a circular orbit of radius r = 1.28 x 10^7 m around Earth? (M_E = 5.97 x 10^24 kg, G = 6.67 x 10^-11 N m^2/kg^2)
A.-3.11 x 10^10 J
B.-7.78 x 10^9 J
C.+1.56 x 10^10 J
D.-1.56 x 10^10 J
Explanation: Gravitational potential energy is E_p = -G M_E m / r = -(6.67 x 10^-11 * 5.97 x 10^24 * 500) / (1.28 x 10^7) = -(1.991 x 10^17) / (1.28 x 10^7) = -1.555 x 10^10 J.
6Planet A orbits a star with radius r_A and orbital period T_A = 1.0 year. Planet B orbits the same star at a radius r_B = 4.0 r_A. According to Kepler's Third Law, what is planet B's orbital period?
A.4.0 years
B.16.0 years
C.8.0 years
D.2.0 years
Explanation: Kepler's Third Law states T^2 / r^3 = constant. Thus (T_B / T_A)^2 = (r_B / r_A)^3 = 4.0^3 = 64. Taking square roots gives T_B / T_A = 8.0, so T_B = 8.0 years.
7What is the total mechanical energy of a satellite of mass m = 1000 kg orbiting Earth in a circular path of radius r = 2.0 x 10^7 m? (M_E = 5.97 x 10^24 kg, G = 6.67 x 10^-11 N m^2/kg^2)
A.-4.98 x 10^9 J
B.-9.95 x 10^9 J
C.-1.99 x 10^10 J
D.+9.95 x 10^9 J
Explanation: Total mechanical energy of a circular orbit is E = K + E_p = -G M_E m / (2 r) = -(6.67 x 10^-11 * 5.97 x 10^24 * 1000) / (2 * 2.0 x 10^7) = -3.982 x 10^17 / 4.0 x 10^7 = -9.955 x 10^9 J.
8At what distance from Earth's center along the Earth-Moon line is the net gravitational field intensity equal to zero? (Earth mass M_E = 81 M_M, distance D between centers = 3.84 x 10^8 m)
A.3.46 x 10^8 m
B.1.92 x 10^8 m
C.3.07 x 10^8 m
D.3.70 x 10^8 m
Explanation: Setting field magnitudes equal: G M_E / x^2 = G M_M / (D - x)^2 => 81 / x^2 = 1 / (D - x)^2. Taking square roots: 9 / x = 1 / (D - x) => 9 D - 9 x = x => 10 x = 9 D => x = 0.9 D = 0.9 * 3.84 x 10^8 = 3.456 x 10^8 m.
9What is the orbital radius of a geostationary satellite around Earth with period T = 24 hours (86,400 s)? (M_E = 5.97 x 10^24 kg, G = 6.67 x 10^-11 N m^2/kg^2)
A.4.22 x 10^7 m
B.3.58 x 10^7 m
C.6.37 x 10^6 m
D.1.28 x 10^8 m
Explanation: Using Kepler's Third Law r^3 = G M_E T^2 / (4 pi^2) = (6.67 x 10^-11 * 5.97 x 10^24 * 86400^2) / (39.478) = 2.973 x 10^24 / 39.478 = 7.53 x 10^22 m^3. Taking cube root: r = 4.22 x 10^7 m (42,200 km).
10What altitude above Earth's surface corresponds to a geostationary orbit? (Earth radius R_E = 6.37 x 10^6 m, geostationary radius r = 4.22 x 10^7 m)
A.4.22 x 10^7 m
B.3.58 x 10^7 m
C.2.58 x 10^7 m
D.1.79 x 10^7 m
Explanation: Altitude h is the distance from Earth's surface: h = r - R_E = 4.22 x 10^7 m - 0.637 x 10^7 m = 3.583 x 10^7 m (35,830 km).
About the PAU Physics (Aragón) Practice Questions
Verified exam format metadata for Aragón PAU Physics Exam / Física 2º Bachillerato is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.