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100+ Free Schleswig-Holstein Abitur Biology Practice Questions

Schleswig-Holstein Zentralabitur Biology (Biologie) practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: Schleswig-Holstein Abitur Biology Exam

300 min

Total Bearbeitungszeit for the written Biologie exam, covering selection among 4 Aufgaben and completion of 3 (no separate Auswahlzeit); up to +60 min for a completed fachpraktische Aufgabe

IQSH FAQ Zentralabitur Biologie, Stand Mai 2026

4 gegeben / 3 bearbeitet

The school receives four Aufgaben; each candidate chooses and completes three, changeable until the end of the working time

IQSH FAQ Zentralabitur Biologie, Stand Mai 2026

120 BE

Total Bewertungseinheiten across the three worked Aufgaben (40 BE each); AFB I 28-33%, AFB II 43-53%, AFB III 20-25% at erhöhtem Niveau

IQSH FAQ Zentralabitur Biologie, Stand Mai 2026

22.04.2026

Written Biologie Profilfach exam date in the 2026 main session — Biologie's first year on the IQB Gemeinsamer Aufgabenpool; 2027 sitting confirmed for 16.04.2027

za.schleswig-holstein.de Terminplanung 2026; profiling-institut.de; schullv.de

2025 / 2026

Chemie and Physik moved to the IQB task pool for the 2025 Abitur; Biologie followed for the 2026 Abitur, after a one-time Probeabitur in autumn 2025

za.schleswig-holstein.de, Das Zentralabitur an allgemeinbildenden Schulen; IQSH FAQ Zentralabitur Biologie

0-15 Punkte

Grading scale for each Prüfungsfach, from Note 1 (15-13 Punkte) to Note 6 (0 Punkte)

Landesverordnung über die Gestaltung der Oberstufe und der Abiturprüfung (OAPVO), Schleswig-Holstein

Free 100-question English-language MCQ study bank for Schleswig-Holstein Zentralabitur Biologie, weighted across the five taught content strands (Leben und Energie ~22%, Informationsverarbeitung in Lebewesen ~20%, Lebewesen in ihrer Umwelt ~18%, Molekulargenetische Grundlagen des Lebens ~22%, Entstehung und Entwicklung des Lebens ~18%) per the Fachanforderungen Biologie (2023). Official exam: 4 Aufgaben given, 3 completed (40 BE each, 120 BE total), up to one with a fachpraktischer Anteil; 300 minutes total; written date 22.04.2026 — Biologie's first year on the IQB Aufgabenpool (Chemie/Physik moved in 2025). Not an official-format simulation; no fee for regular school candidates.

Sample Schleswig-Holstein Abitur Biology Practice Questions

Try these sample questions to test your Schleswig-Holstein Abitur Biology exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1What is the active site of an enzyme?
A.The specific region where a substrate binds and the catalyzed reaction occurs
B.The part of the enzyme that is destroyed during the reaction
C.A storage site where excess substrate molecules accumulate
D.The region that anchors the enzyme to the cell membrane
Explanation: The active site is a three-dimensional pocket formed by the enzyme's folded tertiary structure. Its shape and chemical properties allow a specific substrate to bind, and catalysis of the reaction takes place there.
2How does the induced-fit model differ from the simple lock-and-key model of enzyme-substrate binding?
A.In induced fit, the active site changes shape slightly as it binds the substrate, improving the fit
B.In induced fit, the substrate changes its own chemical structure before binding occurs
C.Induced fit describes enzymes that bind many unrelated substrates equally well
D.Induced fit only applies to enzymes that work outside of cells
Explanation: The induced-fit model proposes that the enzyme's active site is flexible rather than rigid: it subtly reshapes around the substrate as binding occurs, strengthening the interaction and helping to align catalytic groups correctly.
3How do enzymes increase the rate of a biochemical reaction?
A.By lowering the activation energy needed for the reaction to proceed
B.By increasing the total free-energy difference between substrate and product
C.By supplying additional heat energy directly to the reacting molecules
D.By permanently changing the chemical equilibrium of the reaction
Explanation: Enzymes stabilize the transition state of a reaction, which lowers the activation energy barrier that must be overcome. This allows the reaction to proceed much faster at body temperature without altering its overall energy release.
4Why does enzyme activity typically decline sharply above its temperature optimum?
A.Rising temperature disrupts the weak bonds holding the enzyme's tertiary structure, denaturing the active site
B.The substrate molecules stop moving at higher temperatures
C.Enzymes convert to a different, inactive type of protein above the optimum
D.Higher temperatures increase the enzyme's affinity for its substrate indefinitely
Explanation: Beyond the optimum temperature, excess kinetic energy breaks the hydrogen bonds and other weak interactions that maintain the enzyme's folded three-dimensional shape. This denatures the active site so the substrate can no longer bind properly, and activity falls off rapidly.
5Why does pepsin, a stomach enzyme, work best at a strongly acidic pH of around 2, while most human enzymes prefer near-neutral pH?
A.Each enzyme has evolved an optimal pH matching the ionic environment it normally functions in, since pH affects the charge of amino acid side chains that shape the active site
B.Pepsin is not actually a protein and is therefore unaffected by pH
C.All enzymes function identically regardless of surrounding pH
D.Acidic pH always destroys enzyme activity completely
Explanation: pH affects the ionization state of acidic and basic side chains in an enzyme's structure, which in turn affects the three-dimensional shape and charge distribution of the active site. Pepsin evolved to keep its correct conformation and catalytic charges in the acidic gastric environment, while enzymes such as those in blood or cytoplasm are adapted to near-neutral conditions.
6How does a competitive enzyme inhibitor reduce reaction rate?
A.It resembles the natural substrate and binds reversibly to the active site, blocking the substrate from binding
B.It binds permanently to the active site and cannot be displaced under any conditions
C.It binds only at a site distinct from the active site and changes the enzyme's overall shape
D.It destroys the enzyme's tertiary structure irreversibly
Explanation: A competitive inhibitor has a structure similar enough to the true substrate that it can occupy the active site, competing directly with the substrate for binding. Because the binding is typically reversible, raising substrate concentration can outcompete the inhibitor and restore activity.
7How does an allosteric (noncompetitive) inhibitor typically affect an enzyme?
A.It binds at a site separate from the active site, changing the enzyme's shape so the active site no longer works properly
B.It competes directly with the substrate for the active site
C.It increases the enzyme's maximum reaction rate (Vmax)
D.It only affects enzymes that have no quaternary structure
Explanation: Allosteric inhibitors bind at a regulatory site distinct from the active site. This binding alters the enzyme's overall conformation, distorting the active site so that the substrate can no longer bind or react efficiently, even though the active site itself is not directly blocked.
8What role do cofactors and coenzymes play in enzyme function?
A.They are non-protein helper molecules or ions required by some enzymes to achieve full catalytic activity
B.They are the products released after the enzyme completes its reaction
C.They permanently bind to and inactivate the enzyme
D.They are alternative names for the substrate itself
Explanation: Many enzymes require additional non-protein components to function: inorganic cofactors such as metal ions (for example Mg2+ or Zn2+), or organic coenzymes such as NAD+ or FAD, which often assist in transferring electrons, atoms, or functional groups during catalysis.
9On a graph of reaction rate versus substrate concentration for an enzyme-catalyzed reaction, why does the rate eventually level off at Vmax even as substrate concentration keeps increasing?
A.At high substrate concentration, essentially all enzyme active sites are continuously occupied, so adding more substrate cannot further increase the rate
B.The enzyme is destroyed once substrate concentration becomes too high
C.Vmax represents the point where the substrate runs out completely
D.The reaction rate keeps increasing linearly and never actually levels off
Explanation: Vmax is reached when the fixed amount of enzyme present is saturated — essentially every active site is occupied with substrate at any given moment. Since the enzyme concentration limits how many reactions can occur per second, further increases in substrate concentration no longer raise the rate.
10What does the Michaelis constant (Km) represent for an enzyme-catalyzed reaction?
A.The substrate concentration at which the reaction rate is half of Vmax, indicating the enzyme's apparent affinity for its substrate
B.The maximum possible reaction rate an enzyme can achieve
C.The exact number of active sites present on a single enzyme molecule
D.The temperature at which the enzyme denatures
Explanation: Km is defined as the substrate concentration needed to reach half of Vmax. A low Km indicates the enzyme reaches half-maximal rate at a low substrate concentration, meaning it has high apparent affinity for the substrate; a high Km indicates lower apparent affinity.

About the Schleswig-Holstein Abitur Biology Practice Questions

Verified exam format metadata for Schleswig-Holstein Zentralabitur Biology (Biologie) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.