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China's national statutory licensing examination for senior environmental engineers, administered by MEE, MOHURD, and MOHRSS across Foundation and Professional stages, testing environmental laws, biological wastewater kinetics, air scrubbing/ESP/FGD, hazardous waste thermal destruction, sanitary landfill liners, and acoustic/vibration control.

Sample Registered Environmental Protection Engineer Practice Questions

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1Under China's Discharge Standard of Pollutants for Municipal Wastewater Treatment Plants (GB 18918-2002), what are the statutory maximum allowable daily average effluent concentrations for Chemical Oxygen Demand (COD_Cr), Biochemical Oxygen Demand (BOD_5), Suspended Solids (SS), and Total Phosphorus (TP, for facilities built after Jan 1, 2006) under the Class 1A (一级A标准) standard?

A.COD_Cr ≤ 50 mg/L, BOD_5 ≤ 10 mg/L, SS ≤ 10 mg/L, TP ≤ 0.5 mg/L

B.COD_Cr ≤ 60 mg/L, BOD_5 ≤ 20 mg/L, SS ≤ 20 mg/L, TP ≤ 1.0 mg/L

C.COD_Cr ≤ 50 mg/L, BOD_5 ≤ 10 mg/L, SS ≤ 10 mg/L, TP ≤ 1.0 mg/L

D.COD_Cr ≤ 40 mg/L, BOD_5 ≤ 6 mg/L, SS ≤ 5 mg/L, TP ≤ 0.3 mg/L

Explanation: According to Table 1 of GB 18918-2002 (城镇污水处理厂污染物排放标准), the Class 1A (一级A) effluent limits for municipal wastewater treatment plants discharging into scenic or recreation water bodies are: COD_Cr ≤ 50 mg/L, BOD_5 ≤ 10 mg/L, SS ≤ 10 mg/L, NH_3-N ≤ 5 (8) mg/L, Total Nitrogen (TN) ≤ 15 mg/L, and Total Phosphorus (TP) ≤ 0.5 mg/L (for facilities built after 2006-01-01).

2According to the PRC Environmental Protection Law (中华人民共和国环境保护法), what is the statutory requirement of the 'Three Simultaneities' (三同时) environmental management system for construction projects?

A.Environmental impact assessment, public consultation, and technical review must be conducted simultaneously before project approval.

B.Pollution prevention and control installations must be designed, constructed, and put into operation simultaneously with the main engineering structure.

C.Air pollution control, water pollution control, and solid waste disposal facilities must be inspected and accepted simultaneously within three months.

D.Pollutant discharge permits, water abstraction permits, and hazardous waste disposal permits must be applied for simultaneously.

Explanation: Article 41 of the PRC Environmental Protection Law stipulates the 'Three Simultaneities' (三同时) doctrine: Installations for the prevention and control of pollution at a construction project must be designed, constructed, and put into operation simultaneously with the principal parts of the project (防治污染的设施，应当与主体工程同时设计、同时施工、同时投产使用).

3Under the Regulations on the Administration of Pollutant Discharge Permits (排污许可管理条例), how are stationary pollutant-discharging enterprises categorized for administrative supervision based on their pollutant generation and environmental impact?

A.Class A Permitting, Class B Permitting, and Class C Exemption

B.Special Permitting, General Permitting, and Temporary Permitting

C.Key Management (重点管理), Simplified Management (简化管理), and Registration Management (登记管理)

D.State-Controlled Enterprises, Province-Controlled Enterprises, and City-Controlled Enterprises

Explanation: Under China's unified pollutant discharge permitting system (排污许可管理条例), pollutant-discharging entities are classified into three tiered categories according to the amount of pollutants generated, discharged, and the degree of environmental hazard: Key Management (重点管理 - requiring comprehensive emission caps and online CEMS), Simplified Management (简化管理 - streamlined licensing requirements), and Registration Management (登记管理 - simple online filing on the national pollutant discharge permit platform without formal license issuance).

4Wastewater with dynamic viscosity μ = 1.0 × 10^-3 Pa·s and density ρ = 1000 kg/m^3 flows through a circular delivery pipeline with internal diameter D = 0.20 m at a mean velocity v = 1.5 m/s. What is the Reynolds number (Re) of the pipe flow, and which flow regime does it represent?

A.Re = 30,000; laminar flow

B.Re = 3,000; transitional flow

C.Re = 300,000; laminar flow

D.Re = 300,000; fully developed turbulent flow

Explanation: The Reynolds number for pipe flow is defined as Re = (ρ * v * D) / μ = (1000 kg/m^3 * 1.5 m/s * 0.20 m) / (1.0 × 10^-3 Pa·s) = 300,000. In circular pipe hydraulics, the critical Reynolds number Re_crit is approximately 2,000–2,300. Since Re = 300,000 >> 2,300, the flow is in the fully turbulent regime.

5Water at 20°C flows through a smooth cast-iron pipe with length L = 100 m and internal diameter d = 0.10 m at a flow velocity v = 2.0 m/s. Assuming the Darcy friction factor is λ = 0.020 and gravitational acceleration g = 9.81 m/s^2, what is the frictional head loss (h_f) along this pipe section?

A.4.08 m

B.2.04 m

C.8.15 m

D.0.41 m

Explanation: According to the Darcy-Weisbach formula for frictional pipe head loss: h_f = λ * (L / d) * (v^2 / (2 * g)) = 0.020 * (100 m / 0.10 m) * ((2.0 m/s)^2 / (2 * 9.81 m/s^2)) = 0.020 * 1000 * (4.0 / 19.62) = 20 * 0.20387 = 4.077 m ≈ 4.08 m.

6An industrial flue gas stream has an actual volumetric flow rate of Q_act = 50,000 m^3/h measured at operating conditions of T_act = 150°C and absolute pressure P_act = 98.0 kPa. What is the normalized flue gas volumetric flow rate (Q_N) under standard conditions (Standard State: T_N = 273.15 K / 0°C, P_N = 101.325 kPa)?

A.42,350 m^3/h

B.31,192 m^3/h

C.80,148 m^3/h

D.36,250 m^3/h

Explanation: Using the ideal gas state equation correction: Q_N = Q_act * (T_N / T_act) * (P_act / P_N). With T_act = 150 + 273.15 = 423.15 K, T_N = 273.15 K, P_act = 98.0 kPa, and P_N = 101.325 kPa: Q_N = 50,000 * (273.15 / 423.15) * (98.0 / 101.325) = 50,000 * 0.6455 * 0.9672 = 31,192 m^3/h.

7At 25°C, the Henry's law constant for oxygen gas dissolved in water is k_H = 1.30 × 10^-3 mol/(L·atm). If ambient air contains 20.95% oxygen by volume at an atmospheric pressure of 1.0 atm, what is the equilibrium saturation concentration of dissolved oxygen (DO) in water in mg/L (molecular weight of O_2 = 32.0 g/mol)?

A.41.60 mg/L

B.6.85 mg/L

C.8.72 mg/L

D.10.25 mg/L

Explanation: Partial pressure of oxygen in dry air: P_O2 = y_O2 * P_total = 0.2095 * 1.0 atm = 0.2095 atm. According to Henry's Law: C_eq = k_H * P_O2 = (1.30 × 10^-3 mol/(L·atm)) * 0.2095 atm = 2.7235 × 10^-4 mol/L. Converting to mass concentration: DO_sat = 2.7235 × 10^-4 mol/L * 32,000 mg/mol = 8.715 mg/L ≈ 8.72 mg/L.

8According to Whitman's Two-Film Theory for gas-liquid mass transfer, when a highly soluble gas (such as NH_3 or HCl) is absorbed into water, which resistance dominates the overall mass transfer rate?

A.The liquid-phase film resistance (1 / k_L), making mass transfer liquid-film controlled

B.Both liquid and gas film resistances are exactly equal

C.The chemical reaction boundary layer resistance only, independent of fluid films

D.The gas-phase film resistance (1 / k_G), making mass transfer gas-film controlled

Explanation: In Two-Film mass transfer theory, the overall liquid-phase resistance is 1/K_L = 1/k_L + 1/(H * k_G), where H is Henry's constant (P_i = H * C_i). For highly soluble gases, H is very small (solubility is high), meaning 1/k_L becomes negligible compared to 1/(H * k_G). In gas-phase terms (1/K_G = 1/k_G + H/k_L), H/k_L ≈ 0, so 1/K_G ≈ 1/k_G. Therefore, the absorption of highly soluble gases (NH_3, HCl, SO_3) is gas-film controlled. Conversely, poorly soluble gases (O_2, CO_2, N_2) are liquid-film controlled.

9Under the Comprehensive Emission Standard of Air Pollutants (GB 16297-1996), if a new industrial exhaust stack has a geometric height of H = 25 m, while the standard tabulated maximum allowable emission rate is given for standard reference heights of 20 m (Q_20 = 2.0 kg/h) and 30 m (Q_30 = 4.5 kg/h), what is the maximum allowable emission rate (Q) for this 25 m stack determined by interpolation?

A.3.125 kg/h

B.3.250 kg/h

C.2.850 kg/h

D.3.500 kg/h

Explanation: According to Appendix B of GB 16297-1996, interpolation for intermediate stack heights between two tabulated heights (H_a and H_b) follows the quadratic height interpolation formula: Q = Q_a + (Q_b - Q_a) * (H^2 - H_a^2) / (H_b^2 - H_a^2). Here, H_a = 20 m, H_b = 30 m, H = 25 m, Q_a = 2.0 kg/h, Q_b = 4.5 kg/h. Thus: Q = 2.0 + (4.5 - 2.0) * (25^2 - 20^2) / (30^2 - 20^2) = 2.0 + 2.5 * (625 - 400) / (900 - 400) = 2.0 + 2.5 * (225 / 500) = 2.0 + 2.5 * 0.45 = 2.0 + 1.125 = 3.125 kg/h.

10Under the Boiler Air Pollutant Emission Standard (GB 13271-2014) for coal-fired boilers in key regions (重点地区), what are the statutory maximum allowable emission concentration limits for Particulate Matter (PM), Sulfur Dioxide (SO_2), and Nitrogen Oxides (NO_x)?

A.PM ≤ 50 mg/m^3, SO_2 ≤ 100 mg/m^3, NO_x ≤ 300 mg/m^3

B.PM ≤ 20 mg/m^3, SO_2 ≤ 50 mg/m^3, NO_x ≤ 200 mg/m^3 (or 100 mg/m^3 in special control zones)

C.PM ≤ 30 mg/m^3, SO_2 ≤ 200 mg/m^3, NO_x ≤ 400 mg/m^3

D.PM ≤ 5 mg/m^3, SO_2 ≤ 35 mg/m^3, NO_x ≤ 50 mg/m^3

Explanation: GB 13271-2014 (锅炉大气污染物排放标准) Table 3 establishes special emission limit requirements for boilers in key regions: for coal-fired boilers, Particulates ≤ 20 mg/m^3 (or 30 mg/m^3 for existing), SO_2 ≤ 50 mg/m^3 (or 300 mg/m^3 for general), and NO_x ≤ 200 mg/m^3 (or 100 mg/m^3 for gas/selected coal units). In contrast, ultra-low emission limits (5 / 35 / 50 mg/m^3) apply specifically to thermal power station boilers under separate standards.

About the Registered Environmental Protection Engineer Exam

The China National Registered Environmental Protection Engineer Qualification Examination (全国注册环保工程师执业资格考试) is a national survey-and-design professional qualification administered under the MEE, MOHURD, and MOHRSS framework. It assesses environmental regulations and fundamentals, water and air pollution control, solid-waste treatment and disposal, and physical-pollution control engineering.

Assessment

Foundation Examination (Day 1): Public Foundation (120 single-choice questions, 120 points, 4.0 hrs) + Professional Foundation (60 single-choice questions, 120 points, 4.0 hrs); Professional Examination (Days 2 & 3): Professional Knowledge (Day 2: Morning 40 single + 30 multiple choice = 100 pts, Afternoon 40 single + 30 multiple choice = 100 pts, total 200 pts) + Professional Case Analysis (Day 3: Morning 25 problem sets, 50 pts, Afternoon 25 problem sets, 50 pts, total 100 pts).

Time Limit

4.0 hours per Foundation session (8.0 hrs total); 3.0 hours per Professional session (12.0 hrs total across 2 days)

Passing Score

60% (Professional Exam: 120/200 pts Knowledge, 60/100 pts Case; Foundation Exam: 132/240 pts / 55%)

Exam Fee

Set by the provincial examination authority; consult the current registration notice (Ministry of Ecology and Environment (MEE, 中华人民共和国生态环境部), Ministry of Housing and Urban-Rural Development (MOHURD, 中华人民共和国住房和城乡建设部), and Ministry of Human Resources and Social Security (MOHRSS, 中华人民共和国人力资源和社会保障部))

Registered Environmental Protection Engineer Exam Content Outline

20%

environmental-regulations-and-fundamentals

Statutory legal frameworks, pollution standards, and fundamental engineering sciences: PRC Environmental Protection Law (环境保护法), Air Pollution Prevention and Control Law, Water Pollution Prevention and Control Law, Solid Waste Pollution Environment Prevention Law, Environmental Impact Assessment (EIA) Law, and Pollutant Discharge Permitting System (排污许可管理条例). Mandatory environmental quality and emission standards: Surface Water Environmental Quality Standard (GB 3838-2002), Ambient Air Quality Standard (GB 3095-2012), Municipal Wastewater Treatment Plant Discharge Standard (GB 18918-2002 Class 1A/1B/2/3), Integrated Wastewater Discharge Standard (GB 8978-1996), Comprehensive Emission Standard of Air Pollutants (GB 16297-1996), Boiler Air Pollutant Emission Standard (GB 13271-2014), and Industrial Enterprise Boundary Noise Standard (GB 12348-2008). Engineering fundamentals: environmental fluid mechanics (hydrostatic pressure, continuity equation, energy Bernoulli equation with head losses, Darcy-Weisbach friction equation h_f = lambda * (L/d) * (v^2 / 2g), Reynolds number Re, laminar vs turbulent boundary layers), environmental thermodynamics (First and Second Laws, ideal gas laws, reaction enthalpy Delta H, Gibbs free energy Delta G, phase equilibria and Henry's Law C = k_H * P), and multiphase mass transfer (two-film theory, Whitman mass transfer equation N_A = k_L * (C_i - C_L) = k_G * (P_G - P_i), overall volumetric mass transfer coefficient K_L*a).

25%

water-pollution-control-engineering

Physical, chemical, and biological unit operations for municipal and industrial wastewater engineering: Physical pretreatment (bar screens head loss via Kirschmer formula, grit chamber surface hydraulic loading, aerated grit chamber air supply, horizontal and radial primary sedimentation tank design, Camp weir loading and overflow rates per GB 50014). Biological treatment kinetics: Monod microbial growth model, activated sludge reactor volume sizing via complete-mix activated sludge (CMAS) and plug-flow models (V = Q * theta_c * Y * (S0 - Se) / [X * (1 + Kd * theta_c)]), sludge retention time (SRT / theta_c), food-to-microorganism ratio (F/M = Q * S0 / (V * X)), sludge volume index (SVI), return sludge ratio (R = X / (X_r - X)), actual and standard oxygen requirements (AOR = a'*Q*(S0-Se) + b'*V*X + c'*Q*(N0-Ne) and SOR conversion via alpha, beta, theta, and saturation dissolved oxygen C_sw), aeration diffuser efficiency and blower sizing. Advanced biological nutrient removal: Anaerobic-Anoxic-Oxic (A2O) process, Modified Bardenpho 5-stage configuration, Sequencing Batch Reactor (SBR/CAST), internal nitrate recycle ratio (R_i = (NO3_in - NO3_eff) / NO3_eff), biological phosphorus removal (polyphosphate-accumulating organisms PAOs, anaerobic VFA uptake and luxury aerobic phosphate uptake), chemical phosphorus precipitation (alum/ferric dosing stoichiometry). Membrane Bioreactors (MBR, hollow-fiber vs flat-sheet, critical flux, TMP, chemical cleaning). Advanced Oxidation Processes (Fenton reaction Fe2+/H2O2 molar ratios, ozone O3/UV photolysis, hydroxyl radical generation). Sludge treatment and disposal: gravity thickening, dissolved air flotation (A/S ratio), anaerobic digestion (volatile solids destruction, mesophilic 35 deg C kinetics, biogas production V_gas = 0.5-0.6 m3/kg COD_rem), and mechanical dewatering (filter press, belt press, centrifuge solid capture rates).

25%

air-pollution-control-engineering

Particulate matter mechanics and gaseous pollutant abatement systems: Dust collection theory: cyclone separator cut diameter (Lapple model d_pc = sqrt(9 * mu * W / (pi * Ne * vi * (rho_p - rho)))), fractional efficiency curves, inlet velocity optimization (15-25 m/s), and pressure drop Delta P = xi * rho_g * vi^2 / 2; Fabric filter (baghouse) design: cloth filtration velocity / air-to-cloth ratio (v_f = Q / A_cloth = 0.8-1.2 m/min for pulse-jet), bag spacing, pulse cleaning pressure, filter media selection (woven vs needle felt, PTFE membrane, PPS for SO2 resistance, fiberglass for high temperature); Electrostatic Precipitators (ESP): Deutsch-Anderson efficiency formula (eta = 1 - exp(-w * A / Q)), effective migration velocity w, particle charging mechanisms (field charging vs diffusion charging), specific collection area (SCA), electrical resistivity ranges (optimal 10^4 - 10^10 ohm*cm), high-resistivity back-corona prevention. Gaseous emissions control: Wet limestone-gypsum flue gas desulfurization (FGD): SO2 absorption chemistry (CaCO3 + SO2 + 0.5O2 + 2H2O -> CaSO4*2H2O + CO2), liquid-to-gas ratio (L/G = 10-18 L/m3), limestone stoichiometry (Ca/S = 1.02-1.05), spray tower gas velocity (3.0-4.5 m/s), slurry pH (5.2-5.8), forced oxidation aeration; DeNOx technologies: Selective Catalytic Reduction (SCR) TiO2-V2O5-WO3 operating temperature window (300-400 deg C), NH3/NOx molar ratio (0.90-1.05), ammonia slip limit (<= 2.5 mg/m3 per ultra-low emission standards), catalyst space velocity and pitch; Selective Non-Catalytic Reduction (SNCR 850-1100 deg C); Volatile Organic Compounds (VOCs) abatement: fixed-bed activated carbon adsorption breakthrough curves, Wheeler-Jonas equation, bed carbon replacement cycle calculation, Regenerative Thermal Oxidizer (RTO 760-850 deg C, >= 99% destruction, heat recovery >= 95%), Regenerative Catalytic Oxidizer (RCO 300-400 deg C), and condensation recovery.

15%

solid-waste-treatment-and-disposal

Solid waste characterization, hazardous waste management, thermochemical treatment, and landfill engineering: Statutory classification under the National Hazardous Waste Inventory (国家危险废物名录) and GB 5085 series identification standards (corrosivity pH <= 2.0 or >= 12.5 per GB 5085.1, acute toxicity oral LD50 <= 200 mg/kg per GB 5085.2, leaching toxicity toxicity characteristic leaching procedure TCLP / HJ/T 299 limits per GB 5085.3, ignitability flash point < 60 deg C per GB 5085.4, reactivity GB 5085.5, toxic substance content GB 5085.6). Hazardous waste incineration engineering per GB 18484-2020: rotary kiln and secondary combustion chamber (SCC) design, combustion temperature requirements (>= 1100 deg C for hazardous wastes containing >= 1% organohalogens, >= 850 deg C for others), flue gas residence time >= 2.0 s in SCC, combustion efficiency CE >= 99.9% (CE = [CO2] / ([CO2] + [CO]) * 100%), destruction and removal efficiency DRE >= 99.99% for principal organic hazardous constituents (POHCs), flue gas rapid quenching (from >= 500 deg C to < 200 deg C within 1.0 s) to suppress de novo synthesis of polychlorinated dibenzo-p-dioxins and dibenzofurans (PCDD/Fs <= 0.1 ng TEQ/m3). Municipal solid waste sanitary landfill design per GB 16889-2008: bottom and side composite liner engineering (single composite: HDPE geomembrane >= 1.5 mm thick over compacted clay liner CCL >= 0.75 m thick with hydraulic conductivity k <= 1.0 x 10^-7 cm/s or geosynthetic clay liner GCL; double composite liner for hazardous waste landfills per GB 18598), leachate collection and drainage layer (gravel drainage layer >= 30 cm, k >= 1.0 x 10^-1 cm/s, slope >= 2%), leachate generation estimation using hydrologic water balance (HELP model / empirical rainfall coefficient method Q = 10 * C * I * A), leachate membrane treatment (two-stage DTRO / MBR + NF/RO), and aerobic composting design (optimum C/N ratio 25-30:1, initial moisture 50-60%, oxygen concentration >= 10%, thermophilic phase temperature >= 55 deg C maintained for >= 5 days for pathogen and weed seed destruction per GB 7959).

15%

physical-pollution-control

Environmental acoustics, noise abatement engineering, and mechanical vibration control: Acoustic fundamentals: sound power level (L_W), sound intensity level (L_I), sound pressure level (L_p), decibel addition L_sum = 10 * lg(sum(10^(L_i / 10))), decibel subtraction L_diff = 10 * lg(10^(L_total / 10) - 10^(L_bg / 10)), A-weighting spectral corrections, equivalent continuous sound level (L_eq per GB 3096 and GB 12348). Noise propagation and attenuation: geometric divergence of point sources (spherical spreading Delta L = 20 * lg(r2 / r1)), line sources (cylindrical spreading Delta L = 10 * lg(r2 / r1)), atmospheric absorption attenuation, ground surface reflection and absorption, acoustic barrier diffraction attenuation (Fresnel number N = 2 * delta / lambda, Maekawa empirical formula Delta L_b = 10 * lg(3 + 20N)). Sound insulation engineering: single-leaf solid partition Mass Law transmission loss (TL = 20 * lg(m * f) - 48 dB for normal incidence, TL = 20 * lg(m * f) - 43 dB for diffuse field), critical coincidence frequency (f_c = c^2 / (2 * pi) * sqrt(m / B)), double-leaf partition cavity resonance frequency and sound transmission class (STC). Sound absorption: reverberation time room acoustics, Sabine reverberation equation (T60 = 0.161 * V / A_total where A_total = sum(S_i * alpha_i)), Eyring equation for high absorption rooms (T60 = 0.161 * V / (-S * ln(1 - alpha_avg))). Silencer engineering: dissipative resistive silencers (sound attenuation Delta L = psi * (P / S) * l), reactive expansion chamber silencers (transmission loss TL = 10 * lg(1 + 0.25 * (m_area - 1/m_area)^2 * sin^2(k*l))), Helmholtz resonator silencers. Vibration isolation: single degree of freedom (SDOF) spring-mass model, undamped natural frequency f0 = (1 / 2pi) * sqrt(k / m) = (1 / 2pi) * sqrt(g / delta_st), excitation frequency f, frequency ratio r = f / f0, vibration transmissibility eta = 1 / |1 - (f / f0)^2| (undamped) or eta = sqrt((1 + (2*zeta*r)^2) / ((1 - r^2)^2 + (2*zeta*r)^2)), isolation effectiveness (eta_iso = 1 - eta), critical isolation threshold r > sqrt(2) (where r < sqrt(2) amplifies vibration, r = 1 causes catastrophic resonance).

How to Pass the Registered Environmental Protection Engineer Exam

What You Need to Know

Passing score: 60% (Professional Exam: 120/200 pts Knowledge, 60/100 pts Case; Foundation Exam: 132/240 pts / 55%)
Assessment: Foundation Examination (Day 1): Public Foundation (120 single-choice questions, 120 points, 4.0 hrs) + Professional Foundation (60 single-choice questions, 120 points, 4.0 hrs); Professional Examination (Days 2 & 3): Professional Knowledge (Day 2: Morning 40 single + 30 multiple choice = 100 pts, Afternoon 40 single + 30 multiple choice = 100 pts, total 200 pts) + Professional Case Analysis (Day 3: Morning 25 problem sets, 50 pts, Afternoon 25 problem sets, 50 pts, total 100 pts).
Time limit: 4.0 hours per Foundation session (8.0 hrs total); 3.0 hours per Professional session (12.0 hrs total across 2 days)
Exam fee: Set by the provincial examination authority; consult the current registration notice

Keys to Passing

Work through all 100 available questions
Review every answer and explanation
Track weak areas and revisit them
Use our AI tutor for tough concepts

Registered Environmental Protection Engineer Study Tips from Top Performers

1Master Biological Wastewater Design Formulas: Memorize the Monod activated sludge volume equation V = Q * theta_c * Y * (S0 - Se) / [X * (1 + Kd * theta_c)], actual and standard oxygen requirements (AOR/SOR), sludge volume index (SVI), return sludge ratio (R), and internal recycle ratio for denitrification (R_i = (NO3_in - NO3_eff) / NO3_eff).

2Calculate Gas Cleaning Unit Operations: Drill cyclone cut diameter d_pc = sqrt(9 * mu * W / (pi * Ne * vi * (rho_p - rho))), pulse-jet baghouse air-to-cloth ratio (v_f = 0.8-1.2 m/min), ESP Deutsch collection efficiency (eta = 1 - exp(-w * A / Q)), wet limestone FGD L/G ratio, and SCR NH3/NOx stoichiometric molar balance.

3Internalize Hazardous Waste & Landfill Criteria: Review GB 5085 identification thresholds (corrosivity pH <= 2 or >= 12.5, flash point < 60 deg C), GB 18484 incineration metrics (temperature >= 1100 deg C, residence time >= 2.0 s, DRE >= 99.99%, rapid quenching < 200 deg C in 1s), and GB 16889 composite liner permeability (k <= 1.0 x 10^-7 cm/s).

4Solve Logarithmic Acoustics & Vibration Transmissibility: Practice multi-source decibel additions (L = 10 * lg(sum(10^(Li/10)))), Sabine reverberation time (T60 = 0.161 * V / A), barrier Fresnel number diffraction (Maekawa model), and vibration isolation transmissibility (eta = 1 / |1 - (f/f0)^2|) ensuring frequency ratio r = f/f0 > sqrt(2).

5Review Environmental Legislation & Permitting Rules: Study the PRC Environmental Protection Law, Pollutant Discharge Permitting Regulation, 'Three Simultaneities' (三同时) environmental management system, and standard limits for GB 18918 Class 1A effluent (COD <= 50 mg/L, BOD5 <= 10 mg/L, SS <= 10 mg/L, NH3-N <= 5 mg/L, TP <= 0.5 mg/L).

Frequently Asked Questions

What is the Registered Environmental Protection Engineer qualification in China?

The Registered Environmental Protection Engineer (注册环保工程师) is a national survey-and-design professional qualification administered under the MEE, MOHURD, and MOHRSS framework. Its examination scope covers water and air pollution control, solid-waste treatment, and noise and vibration control engineering.

What is the official structure, duration, and passing threshold of the examination?

The examination comprises two successive stages: (1) Foundation Examination (基础考试), an 8-hour objective test split into Morning Public Foundation (120 single-choice questions, 120 points) and Afternoon Professional Foundation (60 single-choice questions, 120 points), with a fixed passing score of 132/240 points (55%) that remains valid permanently. (2) Professional Examination (专业考试), conducted over two consecutive days, comprising Professional Knowledge (专业知识, Day 1 Morning & Afternoon, 200 points total) and Professional Case Analysis (专业案例, Day 2 Morning & Afternoon, 100 points total). The professional passing benchmark is fixed at 60% (120/200 for Knowledge, 60/100 for Case), and both professional papers must be passed within the same examination year.

What key national emission and environmental standards are tested?

The examination evaluates rigorous compliance with China's core national environmental standards, including GB 18918-2002 (Discharge Standard of Pollutants for Municipal Wastewater Treatment Plants), GB 16297-1996 (Comprehensive Emission Standard of Air Pollutants), GB 13271-2014 (Emission Standard of Air Pollutants for Boilers), GB 18484-2020 (Hazardous Waste Incineration Pollution Control), GB 16889-2008 (Municipal Solid Waste Landfill Pollution Control), GB 18598-2019 (Hazardous Waste Landfill Pollution Control), GB 5085.1~7 (Identification Standards for Hazardous Wastes), GB 3838-2002 (Surface Water Quality), GB 3095-2012 (Ambient Air Quality), and GB 12348-2008 (Industrial Enterprise Boundary Noise).

What quantitative engineering calculations are essential for the Professional Case paper?

Candidates must master step-by-step engineering calculations across: (1) Activated sludge aeration tank volume using Monod kinetics, F/M ratios, standard oxygen requirements (SOR), and internal nitrate recycle ratios; (2) Cyclone separator cut diameter (d_pc), baghouse filtration velocity, and electrostatic precipitator collection efficiency using the Deutsch formula (eta = 1 - exp(-w*A/Q)); (3) Wet limestone FGD liquid-to-gas (L/G) ratio and SCR ammonia injection grid molar ratios (NH3/NOx); (4) Hazardous waste incineration combustion efficiency (CE >= 99.9%) and destruction removal efficiency (DRE >= 99.99%); (5) Landfill leachate water balance and composting C/N stoichiometry (25-30:1); and (6) Logarithmic decibel additions, barrier diffraction (Maekawa model), room reverberation time (Sabine T60), and vibration isolator transmissibility (eta = 1 / |1 - (f/f0)^2|).

Why is this OpenExamPrep question bank presented in English?

This is an English-language MCQ study adaptation, not an official translation or format simulation and not a substitute for professional case-analysis and design work. Official Chinese regulatory terms and GB/HJ identifiers integral to the syllabus are retained for cross-reference.