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110+ Free ENAFM Cameroon Practice Questions

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2026 Statistics

Key Facts: ENAFM Cameroon Exam

20,000 FCFA

Concours fee, payable only by Orange Money or MTN Mobile Money on concoursdauq.com

MINESUP Arrêté N° 26/00769 of 6 July 2026, Article 7

3 Hours

Duration fixed by the arrêté for the Biology-Chemistry-Physics written paper

MINESUP Arrêté N° 26/00769 of 6 July 2026, Article 16(1)

20/100

Eliminatory threshold — a mark below 20 on either written paper eliminates the candidate

MINESUP Arrêté N° 26/00769 of 6 July 2026, Article 16(2)

1,140 Places

2026-2027 national quota: 770 medicine, 250 pharmacy, 120 odontostomatology

MINESUP Arrêté N° 26/00769 of 6 July 2026, Article 1

23 Years

Maximum age for candidates in the year of the examination

MINESUP Arrêté N° 26/00769 of 6 July 2026, Article 5

The ENAFM is Cameroon's centralized entrance examination for medical, pharmacy and dentistry studies: four hours of multiple-choice written testing in Biology-Chemistry-Physics and culture générale, plus a school-record assessment, selecting 1,140 students for 2026-2027 across nine accredited faculties.

Sample ENAFM Cameroon Practice Questions

Try these sample questions to test your ENAFM Cameroon exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 110+ question experience with AI tutoring.

1Which eukaryotic organelle is primarily responsible for synthesizing transmembrane proteins, secretory proteins, and N-linked oligosaccharide core additions?
A.Rough endoplasmic reticulum
B.Smooth endoplasmic reticulum
C.Peroxisome
D.Lysosome
Explanation: The rough endoplasmic reticulum (RER) is studded with ribosomes on its cytosolic face that co-translationally translocate polypeptides destined for secretion, lysosomes, or integration into plasma membranes. The RER lumen also houses chaperones and oligosaccharyltransferase enzymes that catalyze initial N-linked glycosylation.
2During transcription in eukaryotic cells, in which direction does RNA polymerase synthesize the pre-mRNA transcript, and what is the orientation of the template DNA strand it reads?
A.Synthesizes 5' to 3'; reads template 3' to 5'
B.Synthesizes 3' to 5'; reads template 5' to 3'
C.Synthesizes 5' to 3'; reads template 5' to 3'
D.Synthesizes 3' to 5'; reads template 3' to 5'
Explanation: All known RNA polymerases catalyze phosphodiester bond formation by adding incoming ribonucleoside triphosphates (rNTPs) to the free 3'-hydroxyl (-OH) group of the growing RNA chain, synthesizing RNA in the 5' to 3' direction while moving 3' to 5' along the complementary antisense template strand.
3How does a reversible competitive inhibitor alter the kinetic parameters Michaelis constant (Km) and maximum velocity (Vmax) of an enzymatic reaction?
A.Increases apparent Km while leaving Vmax unchanged
B.Decreases apparent Km while leaving Vmax unchanged
C.Decreases Vmax while leaving Km unchanged
D.Decreases both apparent Km and Vmax by the same ratio
Explanation: A competitive inhibitor structurally resembles the substrate and competes directly for the enzyme's active site. At sufficiently high substrate concentrations, the substrate outcompetes the inhibitor, allowing the reaction to reach its original Vmax; however, a higher substrate concentration is required to reach half-maximal velocity, thus increasing the apparent Km.
4In the complete breakdown of one molecule of glucose via aerobic glycolysis, what is the net yield of ATP synthesized strictly by substrate-level phosphorylation prior to pyruvate entering the mitochondria?
A.2 ATP
B.4 ATP
C.6 ATP
D.32 ATP
Explanation: During the energy investment phase of glycolysis, 2 ATP molecules are consumed (catalyzed by hexokinase and phosphofructokinase-1). In the energy payoff phase, 4 ATP molecules are produced (2 by phosphoglycerate kinase and 2 by pyruvate kinase per glucose), resulting in a net yield of 4 - 2 = 2 ATP via substrate-level phosphorylation.
5How does an uncoupling agent such as 2,4-dinitrophenol (DNP) alter mitochondrial electron transport and ATP synthesis?
A.It dissipates the inner membrane proton electrochemical gradient, stimulating electron transport while halting ATP synthesis
B.It binds to Complex IV (cytochrome c oxidase), blocking electron transfer to oxygen and stopping the proton pump
C.It inhibits the F1 catalytic subunit of ATP synthase without altering the proton gradient across the inner membrane
D.It prevents pyruvate transport across the outer mitochondrial membrane into the matrix
Explanation: Chemical uncouplers like 2,4-dinitrophenol (DNP) are lipophilic weak acids that carry protons across the inner mitochondrial membrane into the matrix, collapsing the proton-motive force (chemiosmotic gradient). Because respiratory complexes are no longer restrained by back-pressure, electron transport and oxygen consumption accelerate, but ATP synthase cannot generate ATP, releasing energy as heat.
6During human meiosis, in which sub-stage of Prophase I does reciprocal genetic recombination (crossing over) take place between non-sister chromatids of homologous chromosomes?
A.Pachytene
B.Leptotene
C.Zygotene
D.Diplotene
Explanation: Prophase I of meiosis progresses through five stages: leptotene (chromatin condensation), zygotene (synapsis and synaptonemal complex assembly), pachytene (crossing over and genetic recombination between non-sister chromatids), diplotene (desynapsis and visualization of chiasmata), and diakinesis (terminalization of chiasmata).
7What is the primary ionic mechanism maintaining the negative resting membrane potential (approximately -70 mV) of a human peripheral neuron?
A.High resting membrane permeability to K+ through non-gated leak channels and active Na+/K+ ATPase electrogenic pumping
B.High resting membrane permeability to Na+ through voltage-gated channels and passive Cl- influx
C.Active pumping of 3 K+ ions into the cell in exchange for 2 Na+ ions out of the cell by the sodium-potassium pump
D.Complete impermeability of the plasma membrane to all inorganic cations and anions
Explanation: The resting membrane potential is determined largely by the high resting permeability of the membrane to potassium ions (K+) through open leak channels relative to sodium (Na+), allowing K+ to diffuse down its concentration gradient until its equilibrium potential is approached (near -90 mV). The Na+/K+ ATPase continuously maintains the concentration gradients by pumping 3 Na+ out for every 2 K+ brought in, making an electrogenic contribution of approximately -3 to -5 mV.
8What molecular event is directly responsible for the absolute refractory period in a mammalian excitable neuronal axon?
A.Inactivation of voltage-gated sodium channels by their cytoplasmic inactivation gate
B.Delayed closure of voltage-gated potassium channels causing temporary hyperpolarization
C.Complete depletion of intracellular ATP stores required by the sodium-potassium ATPase
D.Transient opening of calcium-activated chloride channels in the axon hillock
Explanation: During the upstroke and peak of an action potential, voltage-gated Na+ channels open and then rapidly transition into an inactivated, non-conducting state via closure of their intracellular inactivation gate (ball-and-chain / h-gate). Until the membrane repolarizes sufficiently to allow these channels to transition back to the closed, de-inactivated resting state, no stimulus of any strength can initiate a second action potential.
9At a chemical neuromuscular junction, what specific event directly triggers the fusion of synaptic vesicles with the presynaptic plasma membrane and acetylcholine release?
A.Influx of Ca2+ ions through voltage-gated calcium channels opened by membrane depolarization
B.Efflux of K+ ions through delayed rectifier channels during repolarization
C.Influx of Na+ ions through nicotinic acetylcholine receptor ionophores
D.Active transport of acetylcholine into the synaptic cleft by an ATP-driven antiporter
Explanation: When an action potential invades the presynaptic terminal, depolarization opens voltage-gated Ca2+ channels. The resulting rapid influx of Ca2+ into the active zone allows Ca2+ to bind to synaptotagmin, triggering SNARE-complex-mediated fusion of acetylcholine vesicles with the presynaptic membrane and subsequent exocytosis into the synaptic cleft.
10In the human hypothalamic-pituitary-adrenal (HPA) axis, what is the primary negative feedback mechanism exerted by circulating cortisol under physiological conditions?
A.Direct inhibition of CRH release from the paraventricular nucleus and ACTH secretion from the anterior pituitary
B.Direct stimulation of aldosterone synthesis in the adrenal zona glomerulosa
C.Inhibition of epinephrine synthesis in the adrenal medulla through down-regulation of PNMT
D.Stimulation of pro-opiomelanocortin (POMC) gene transcription in corticotrope cells
Explanation: Free circulating cortisol crosses the blood-brain barrier and binds to glucocorticoid and mineralocorticoid receptors in the hypothalamus (paraventricular nucleus) and anterior pituitary gland. This receptor activation suppresses the transcription and secretion of both Corticotropin-Releasing Hormone (CRH) and Adrenocorticotropic Hormone (ACTH), maintaining endocrine homeostasis.

About the ENAFM Cameroon Exam

The Examen National d'Aptitude à la Formation Médicale, Pharmaceutique et Odontostomatologique (ENAFM) is Cameroon's sole national competitive entrance examination for admission to medical, pharmaceutical and odontostomatological training. Organized by MINESUP through the Commission Nationale de la Formation Médicale, Pharmaceutique et Odontostomatologique, it standardizes recruitment across seven public faculties (FMSB/Université de Yaoundé I, FMSP/Université de Douala, FHS/University of Buea, FHS/University of Bamenda, FMSP/Université de Dschang, FMSB/Université de Garoua, and FMSP de Sangmélima/Université d'Ebolowa) and two accredited private institutions (SHMS/CATUC Kumbo and ISSS/Université des Montagnes). The official papers are set in French and in English; this 110-question bank is an English-language study adaptation of the examined programme, weighted to the official coefficients rather than reproducing the real paper's length.

Assessment

Article 14 of the arrêté sets three weighted components: a school-record assessment (coefficient 1, based on Probatoire/GCE O-Level results, Baccalauréat/GCE A-Level results and the candidate's age), a written Biology-Chemistry-Physics paper (coefficient 4, 3 hours) and a written culture générale paper (coefficient 1). Within the science paper the subject coefficients differ by track: Biology 2 / Physics 1 / Chemistry 1 for Medicine and Odontostomatology, and Chemistry 2 / Biology 1 / Physics 1 for Pharmacy. Each written paper is marked out of 100 and a mark below 20/100 on either is eliminatory. A jury then ranks candidates by merit against the quota published in Article 1 — 1,140 places for 2026-2027 (770 medicine, 250 pharmacy, 120 odontostomatology) across nine accredited institutions.

Time Limit

4 hours of written testing in one day: 3 hours for the Biology-Chemistry-Physics paper (Article 16(1)) and 1 hour for the culture générale paper

Passing Score

No fixed pass mark — admission is by merit ranking against the national quota (1,140 places for 2026-2027). Each written paper is marked out of 100 and any mark below 20/100 on either written paper is eliminatory (Article 16(2)).

Exam Fee

20,000 FCFA (Ministère de l'Enseignement Supérieur (MINESUP))

ENAFM Cameroon Exam Content Outline

35%

Biology (Bac C/D and GCE A-Level programme)

Cell structure and metabolism, molecular genetics, DNA replication, transcription, translation, neurophysiology, endocrine regulation, cardiovascular, renal and respiratory physiology, immunology, human reproduction, and infectious diseases. Coefficient 2 for Medicine and Odontostomatology.

25%

Chemistry (Bac C/D and GCE A-Level programme)

Chemical kinetics, chemical equilibrium, acid-base reactions, buffers, redox processes, electrochemistry, stereochemistry, organic functional groups, carbohydrates, lipids, and amino acids. Coefficient 2 for Pharmacy.

20%

Physics (Bac C/D and GCE A-Level programme)

Newtonian mechanics, fluids and blood flow, geometric optics, vision correction, wave phenomena, bioelectricity, circuit analysis, radioactivity, radiation physics, and nuclear decay. Coefficient 1 in every track.

20%

Culture générale (general knowledge, logic, and language)

General knowledge of Cameroon and its health system, medical ethics and patient rights, epidemiology and scientific reasoning, formal logic and numerical reasoning, and English usage, vocabulary and reading comprehension.

How to Pass the ENAFM Cameroon Exam

What You Need to Know

  • Passing score: No fixed pass mark — admission is by merit ranking against the national quota (1,140 places for 2026-2027). Each written paper is marked out of 100 and any mark below 20/100 on either written paper is eliminatory (Article 16(2)).
  • Assessment: Article 14 of the arrêté sets three weighted components: a school-record assessment (coefficient 1, based on Probatoire/GCE O-Level results, Baccalauréat/GCE A-Level results and the candidate's age), a written Biology-Chemistry-Physics paper (coefficient 4, 3 hours) and a written culture générale paper (coefficient 1). Within the science paper the subject coefficients differ by track: Biology 2 / Physics 1 / Chemistry 1 for Medicine and Odontostomatology, and Chemistry 2 / Biology 1 / Physics 1 for Pharmacy. Each written paper is marked out of 100 and a mark below 20/100 on either is eliminatory. A jury then ranks candidates by merit against the quota published in Article 1 — 1,140 places for 2026-2027 (770 medicine, 250 pharmacy, 120 odontostomatology) across nine accredited institutions.
  • Time limit: 4 hours of written testing in one day: 3 hours for the Biology-Chemistry-Physics paper (Article 16(1)) and 1 hour for the culture générale paper
  • Exam fee: 20,000 FCFA

Keys to Passing

  • Work through all 110 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Frequently Asked Questions

What is the ENAFM in Cameroon?

The Examen National d'Aptitude à la Formation Médicale (ENAFM) is Cameroon's national competitive entrance examination organized by MINESUP for selecting candidates for first-year medical, pharmacy, and dentistry studies.

What subjects are tested on the ENAFM?

Biology, Chemistry and Physics in a 3-hour multiple-choice paper of 100 QCM (coefficient 4), and culture générale — general knowledge, logic, and French or English — in a 1-hour paper of 50 QCM (coefficient 1). The syllabus is the Baccalauréat C or D and GCE A-Level programme in biology, chemistry and physics.

Who is eligible to take the ENAFM?

Candidates must be aged 23 at most in the year of the examination and hold the Baccalauréat série C or D, or the GCE Advanced Level with Biology and Chemistry passed in the same session, or a diploma granted equivalence by the Minister of Higher Education.

How are candidates selected for admission?

There is no fixed pass mark. A jury ranks candidates by merit on the two written papers plus the school-record assessment, and places are filled against the quota set in the arrêté — 1,140 for 2026-2027. Each written paper is marked out of 100 and any mark below 20/100 on either paper is eliminatory.

What language is the ENAFM set in, and is this practice bank an official paper?

Cameroon is officially bilingual, and MINESUP issues the ENAFM in French and in English; the culture générale paper covers French or English. This practice bank is an English-language study adaptation written to the examined programme and the official coefficient weighting. It is not an official MINESUP paper, an official translation, or a reproduction of the real paper's length.

How much does the ENAFM cost and how do you register?

Registration is online only, on the MINESUP platform concoursdauq.com. The concours fee is 20,000 FCFA, payable by Orange Money or MTN Mobile Money; the arrêté states that no other payment method is accepted. Supporting documents are uploaded as PDFs of 1 MB or less each.