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100+ Free COLMILAV Prueba de Suficiencia Practice Questions

Prepare for the Colegio Militar de Aviación 'Tgral. Germán Busch Becerra' Prueba de Suficiencia Aeronáutica (Bolivia) exam with instant access — no signup required.

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2026 Statistics

Key Facts: COLMILAV Prueba de Suficiencia Exam

Bs 400

Prospectus Fee

Fuerza Aérea Boliviana

51/100

Physical Minimum

COLMILAV Prospecto 2026

6 Subject Areas

Academic Subjects

COLMILAV Prospecto 2026

17–22 years

Age Limit

FAB Admission Directive

Santa Cruz / El Alto

Academy Location

COLMILAV Institutional Portal

This 100-question practice test is an English-language study adaptation for the Bolivian Air Force Academy (COLMILAV) admission examination. It covers mathematics, physics, chemistry, language, English, and aviation history. Registration requires the Bs 400 prospectus, and candidates must meet aeromedical, physical fitness (minimum 51/100), and academic standards.

Sample COLMILAV Prueba de Suficiencia Practice Questions

Try these sample questions to test your COLMILAV Prueba de Suficiencia exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1What is the complete factorization of the polynomial expression 9x^2 - 25y^2?
A.(3x - 5y)(3x + 5y)
B.(3x - 5y)^2
C.(9x - 25y)(x + y)
D.(3x + 5y)^2
Explanation: The expression is a difference of two squares of the algebraic form a^2 - b^2 = (a - b)(a + b). Here a = sqrt(9x^2) = 3x and b = sqrt(25y^2) = 5y, yielding (3x - 5y)(3x + 5y).
2What are the real solutions to the quadratic equation 3x^2 - 7x + 2 = 0?
A.x = 2 and x = 1/3
B.x = -2 and x = -1/3
C.x = 3 and x = 2/3
D.x = 1 and x = 2/3
Explanation: Factoring by grouping: 3x^2 - 6x - x + 2 = 3x(x - 2) - 1(x - 2) = (3x - 1)(x - 2) = 0. Setting each factor equal to zero gives 3x - 1 = 0 => x = 1/3, and x - 2 = 0 => x = 2.
3Given two 2D vectors u = (4, -3) and v = (2, 5), what is their dot product (producto escalar u . v)?
A.-7
B.23
C.7
D.-23
Explanation: The dot product of two vectors u = (u_x, u_y) and v = (v_x, v_y) is u . v = (u_x * v_x) + (u_y * v_y) = (4 * 2) + (-3 * 5) = 8 - 15 = -7.
4Which of the following expressions is identically equal to (1 - cos(2*theta)) / 2 for all real angles theta?
A.sin^2(theta)
B.cos^2(theta)
C.tan^2(theta)
D.sin(2*theta)
Explanation: From the double-angle formula for cosine: cos(2*theta) = 1 - 2*sin^2(theta). Rearranging this identity gives 2*sin^2(theta) = 1 - cos(2*theta), hence sin^2(theta) = (1 - cos(2*theta)) / 2.
5Solve for x: log_3(2x + 1) + log_3(x - 1) = 2.
A.x = 5/2
B.x = 2
C.x = -2
D.x = 3
Explanation: Combine the logarithms: log_3((2x + 1)(x - 1)) = 2, so (2x + 1)(x - 1) = 9. This gives 2x^2 - x - 10 = 0 = (2x - 5)(x + 2). The roots are x = 5/2 and x = -2, but the logarithm domain requires x > 1, so x = 5/2.
6In an aerial reconnaissance grid, two ground stations A and B are separated by a distance c = 10 km. An aircraft C is sighted such that angle CAB = 45 degrees and angle CBA = 60 degrees. Using the Law of Sines, what is the distance b from station A to aircraft C?
A.10 * sin(60 deg) / sin(75 deg) km (approx. 8.97 km)
B.10 * sin(45 deg) / sin(75 deg) km (approx. 7.32 km)
C.10 * sin(75 deg) / sin(60 deg) km (approx. 11.15 km)
D.10 * tan(60 deg) km (approx. 17.32 km)
Explanation: In triangle ABC, the third angle C = 180 deg - (45 deg + 60 deg) = 75 deg. By the Law of Sines: b / sin(B) = c / sin(C) => b = c * sin(B) / sin(C) = 10 * sin(60 deg) / sin(75 deg) km.
7What is the perpendicular distance from the point P(2, 3) to the straight line given by 4x + 3y - 2 = 0?
A.3.0 units
B.2.5 units
C.1.5 units
D.4.2 units
Explanation: Using the point-to-line distance formula d = |A*x_0 + B*y_0 + C| / sqrt(A^2 + B^2): d = |4(2) + 3(3) - 2| / sqrt(4^2 + 3^2) = |8 + 9 - 2| / sqrt(25) = |15| / 5 = 3.0 units.
8Simplify the algebraic expression: ((x^3 * y^(-2))^2 * (x^(-1) * y^4)^3) / (x^2 * y^5).
A.x * y^3
B.x^3 * y
C.x^2 * y^2
D.x^(-1) * y^4
Explanation: Simplify numerator: (x^6 * y^(-4)) * (x^(-3) * y^12) = x^(6 - 3) * y^(-4 + 12) = x^3 * y^8. Dividing by denominator: (x^3 * y^8) / (x^2 * y^5) = x^(3 - 2) * y^(8 - 5) = x^1 * y^3.
9An aircraft maintenance unit has two types of fuel drums: Type A contains 200 L and Type B contains 150 L. A total of 35 drums hold 6,250 L of aviation fuel. How many Type A drums are there?
A.20 drums
B.15 drums
C.25 drums
D.18 drums
Explanation: Let A and B be the number of drums: A + B = 35 => B = 35 - A. Total volume: 200A + 150B = 6250 => 200A + 150(35 - A) = 6250 => 200A + 5250 - 150A = 6250 => 50A = 1000 => A = 20 drums.
10What is the eccentricity e of the ellipse given by the standard equation (x^2 / 25) + (y^2 / 16) = 1?
A.3/5 = 0.6
B.4/5 = 0.8
C.9/25 = 0.36
D.5/3 = 1.67
Explanation: For the ellipse with a^2 = 25 (a = 5) and b^2 = 16 (b = 4), the focal distance c satisfies c^2 = a^2 - b^2 = 25 - 16 = 9, so c = 3. Eccentricity is e = c / a = 3 / 5 = 0.6.

About the COLMILAV Prueba de Suficiencia Exam

Prepare for the Bolivian Air Force Academy (COLMILAV) admission exam with 100 free practice questions on mathematics, physics, chemistry, language, English, and Bolivian aviation history. Note: English-language study adaptation.

Assessment

Question count not published by the exam provider

Time Limit

Not published as a single fixed duration; administered in subject sessions

Passing Score

Competitive merit ranking; minimum 51/100 required in the physical evaluation phase

Exam Fee

Bs 400 for the official prospectus, plus separate aeromedical and laboratory expenses (Colegio Militar de Aviación 'Tgral. Germán Busch Becerra')

COLMILAV Prueba de Suficiencia Exam Content Outline

Practice bank: 17%

Matemáticas

Algebraic equations, vectors, trigonometry, analytic geometry, and conic sections.

Practice bank: 17%

Física

Relative motion, centripetal acceleration, work-energy, Bernoulli's principle, and aerodynamics.

Practice bank: 17%

Química

Electronic structure, chemical bonding, stoichiometry, ideal gases, and chemical solutions.

Practice bank: 17%

Lenguaje y Literatura

Spanish grammar, syntax, verbal periphrases, and classic Bolivian literary history.

Practice bank: 16%

Inglés

English grammar, aviation vocabulary, conditionals, reported speech, and weather reports.

Practice bank: 16%

Geografía e Historia de Bolivia

FAB history, Chaco War aerial dogfights, national geography, airspaces, and constitutional duties.

How to Pass the COLMILAV Prueba de Suficiencia Exam

What You Need to Know

  • Passing score: Competitive merit ranking; minimum 51/100 required in the physical evaluation phase
  • Assessment: Question count not published by the exam provider
  • Time limit: Not published as a single fixed duration; administered in subject sessions
  • Exam fee: Bs 400 for the official prospectus, plus separate aeromedical and laboratory expenses

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

COLMILAV Prueba de Suficiencia Study Tips from Top Performers

1Practice solving multi-step quantitative problems in physics, chemistry stoichiometry, and trigonometry by hand.
2Review technical aviation English vocabulary and standard ICAO phraseology.
3Memorize key milestones in Bolivian military aviation, including the 1923 founding, the Chaco War aerial combat of Rafael Pabón, and national airport elevations.
4Maintain a rigorous physical training routine in parallel with academic review to meet the 51/100 physical threshold.

Frequently Asked Questions

Where is the Colegio Militar de Aviación located?

COLMILAV operates facilities in Santa Cruz de la Sierra (El Trompillo) and conducts evaluation phases in El Alto / La Paz.

What is the cost of registration for COLMILAV?

The official prospectus costs Bs 400, payable into authorized fiscal accounts, with additional costs for external medical and laboratory checkups.