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2026 Statistics

Key Facts: Toelatingsexamen Arts Exam

80

Official four-option items (40 KIW + 40 GC)

Vlaanderen.be examenonderdelen

EUR 65

2026 enrolment fee per exam

Vlaanderen.be inschrijven

1878

2026 arts startquotum

Vlaanderen.be resultaat en inzage

+3 / 0 / −1

Scoring per item (240-point total)

Vlaanderen.be berekening examenresultaat

2 July 2026

Arts sitting at Brussels Expo

Vlaanderen.be toelatingsexamens

Dutch only

Official assessment language

Vlaanderen.be examenonderdelen en leerstofoverzicht

Flanders' 2026 Toelatingsexamen Arts is 80 Dutch four-option items (40 KIW + 40 GC) on 2 July at Brussels Expo, scored +3/0/−1 on 240 points, EUR 65, with ranking against a 1878 startquotum after ≥50% on both parts. This page is an English MCQ study aid, not the official paper.

Sample Toelatingsexamen Arts Practice Questions

Try these sample questions to test your Toelatingsexamen Arts exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A typical human hepatocyte is a eukaryotic cell. Which statement correctly distinguishes it from a prokaryotic bacterium of similar mass?
A.The hepatocyte contains membrane-bound organelles, including a nucleus and mitochondria.
B.The hepatocyte lacks ribosomes and therefore cannot synthesise proteins.
C.The hepatocyte stores its genome as a single circular chromosome free in the cytoplasm.
D.The hepatocyte has a peptidoglycan cell wall and only 70S ribosomes.
Explanation: Eukaryotic animal cells enclose their DNA in a nucleus and contain other membrane-bound organelles such as mitochondria. Prokaryotes lack those compartments: their DNA lies in the cytoplasm, often as a circular chromosome, and they typically have a peptidoglycan wall and 70S ribosomes. Both cell types have ribosomes, so protein synthesis is not unique to bacteria.
2Which statement correctly contrasts a typical human animal cell with a typical higher-plant cell?
A.Animal cells have a cellulose cell wall; plant cells never have a cell wall.
B.Animal cells contain a large central sap vacuole; plant cells have none.
C.Animal cells have centrioles used in mitosis, whereas plant cells have a cellulose cell wall and plastids such as chloroplasts.
D.Both cell types lack ribosomes and a plasma membrane.
Explanation: Higher-plant cells are distinguished by a cellulose wall, plastids (including chloroplasts) and often a large central vacuole. Typical animal cells lack those structures but possess centrioles that organise the mitotic spindle. Both cell types have a plasma membrane and ribosomes.
3Red blood cells remain stable in volume in 0.9% NaCl but swell and lyse when placed in distilled water. The distilled-water result is best explained by:
A.Active transport of Na+ from the water into the cells against its gradient
B.Net osmosis of water into the cells down the water-potential gradient
C.Endocytosis of bulk water by the plasma membrane
D.Diffusion of haemoglobin out of still-intact cells
Explanation: Distilled water has a higher water potential than the cytosol, so water enters by osmosis through the plasma membrane. The cells swell until the membrane ruptures (haemolysis). 0.9% NaCl is isotonic for human erythrocytes, so there is no net water movement in that medium.
4In a resting neuron, which pair of ions is most directly responsible for the steep electrochemical gradients maintained by the Na+/K+ ATPase?
A.Ca2+ and Fe2+
B.PO4 3- and Cl-
C.Fe2+ and Ca2+
D.Na+ and K+
Explanation: The Na+/K+ pump exports three Na+ ions and imports two K+ ions per ATP hydrolysed. That maintains high extracellular Na+ and high intracellular K+, which underlie the resting membrane potential and later action potentials. Ca2+, Cl-, phosphate and Fe2+ have important roles elsewhere, but they are not the pump's transported pair.
5In humans, fertilisation of a secondary oocyte by a sperm cell normally occurs in the:
A.Uterine tube (oviduct)
B.Endometrial cavity after the blastocyst has already implanted
C.Ovarian follicle before ovulation
D.Cervical canal at the moment of insemination
Explanation: Sperm reach a secondary oocyte in the ampulla of the uterine tube, where fertilisation usually occurs. The zygote then undergoes cleavage while travelling toward the uterus, and implantation happens days later in the endometrium. Ovulation releases the oocyte from the follicle; fertilisation is not completed in the ovary or cervix.
6Complete aerobic respiration of one glucose molecule in a human muscle cell yields far more ATP than anaerobic glycolysis because:
A.Anaerobic glycolysis consumes more ATP than it produces, so the net yield is negative
B.Molecular oxygen is a required substrate of hexokinase in the first glycolytic step
C.Pyruvate is fully oxidised in mitochondria via the citric acid cycle and oxidative phosphorylation
D.Lysosomes hydrolyse glucose directly to ATP by autophagy
Explanation: Anaerobic glycolysis stops at lactate and nets only 2 ATP per glucose. In air, pyruvate enters mitochondria, is oxidised in the citric acid cycle, and NADH/FADH2 drive oxidative phosphorylation, giving about 30 ATP per glucose. Oxygen is the terminal electron acceptor, not a hexokinase substrate, and lysosomes do not synthesise ATP from glucose.
7Non-disjunction of chromosome 21 during meiosis I in oogenesis produces an ovum with two copies of chromosome 21. After fertilisation by a chromosomally normal sperm, the zygote's karyotype is:
A.45,XX or 45,XY (monosomy 21)
B.47,XX,+21 or 47,XY,+21 (trisomy 21)
C.46,XX or 46,XY with a balanced reciprocal translocation
D.69,XXX or 69,XXY (triploidy)
Explanation: The disomic ovum already has two copies of chromosome 21; the sperm adds a third copy, producing trisomy 21 (47 chromosomes). This is the usual chromosomal basis of Down syndrome after meiotic non-disjunction. Monosomy would require a nullisomic gamete, a balanced translocation does not change chromosome count by one, and triploidy is a whole extra haploid set.
8In human oogenesis, the cell that is ovulated at mid-cycle is a:
A.Oogonium that has never entered meiosis
B.Primary oocyte still arrested in prophase I
C.Haploid ovum that has already completed meiosis II
D.Secondary oocyte arrested in metaphase II
Explanation: Oogonia enter meiosis before birth and arrest as primary oocytes in prophase I. The LH surge completes meiosis I and ovulates a secondary oocyte that is arrested in metaphase II. Meiosis II is completed only at fertilisation, so a fully haploid ovum is not what leaves the ovary.
9Red-green colour blindness is X-linked recessive. A colour-blind man and a homozygous normal woman have a daughter. That daughter later has a son with a colour-blind man. The probability that this son is colour-blind is:
A.1/2
B.0
C.1
D.1/4
Explanation: The colour-blind father is XcY and the mother is XC XC, so every daughter is an obligatory heterozygote XC Xc. Sons of that carrier daughter receive her X chromosome and the Y from their father. Half of her X chromosomes carry Xc, so each son has probability 1/2 of being colour-blind, independent of the partner being colour-blind (the partner contributes Y to sons).
10In PCR, a thermostable DNA polymerase repeatedly copies a chosen DNA segment. Starting from one double-stranded template molecule, the theoretical number of double-stranded copies after n complete cycles is:
A.n
B.2n
C.2^n
D.n^2
Explanation: Each PCR cycle doubles the amount of target DNA if primers, polymerase and nucleotides are in excess. After n cycles the theoretical yield is 2^n copies of the original double-stranded molecule. Linear functions n or 2n, and n^2, do not describe exponential amplification.

About the Toelatingsexamen Arts Exam

The Toelatingsexamen Arts is Flanders' numerus-clausus admission exam for the bachelor of geneeskunde. AHOVOKS runs a Dutch paper of 80 four-option items: 40 KIW science questions (10 each in biology, physics, chemistry and mathematics) in the morning and 40 GC items (15 EMCO empathy/communication plus 25 VAARDIG scientific-text questions) in the afternoon. 2026 returns to a single pen-and-paper site at Brussels Expo on Thursday 2 July. Scoring is +3 / 0 / −1 (240 points). You need at least half the points on both KIW and GC, then a total at or above the cesuur for the 1878 startquotum. The fee is EUR 65. This bank is an English-language MCQ study adaptation, not an official translation or a substitute for the Dutch sitting.

Assessment

One paper day: morning KIW (biology, physics, chemistry, mathematics; 3.5 hours from 09:45) and afternoon GC (EMCO then VAARDIG; 1.5 hours from 14:30). 2026 is a central pen-and-paper sitting at Brussels Expo. AHOVOKS supplies the formularium, periodic table, pen, highlighter and a simple calculator. This English four-option bank is a study adaptation of the 2026 leerstofoverzicht — not an official translation and not a simulation of the Dutch paper environment.

Time Limit

KIW 3.5 hours (09:45 start) and GC 1.5 hours (14:30–16:00). Site access from 08:00; late start allowed until 10:45 without extra time.

Passing Score

≥60/120 on KIW and ≥60/120 on GC to enter ranking; gunstige rangschikking requires a total at or above the cesuur set by the 1878 arts startquotum. +3 / 0 / −1 per item.

Exam Fee

EUR 65 per exam (non-refundable). Vlaanderen.be inschrijven, 2026. (AHOVOKS (Agentschap voor Hoger Onderwijs, Volwassenenonderwijs, Kwalificaties en Studietoelagen) and the examencommissie Toelatingsexamen Arts, Tandarts en Dierenarts)

Toelatingsexamen Arts Exam Content Outline

12.5%

KIW — Biologie

Cell, metabolism, genetics, human reproduction, immunity, neuro-muscular function and evolution from the 2026 KIW leerstofoverzicht

12.5%

KIW — Chemie

Stoichiometry, bonding, kinetics, equilibrium, acids/bases, redox and carbon chemistry

12.5%

KIW — Fysica

Pressure, heat, electricity, magnetism, nuclear decay, mechanics, waves and sound

12.5%

KIW — Wiskunde

Algebra, geometry, calculus and probability/statistics

18.75%

GC — EMCO

Empathy and communication scenarios for a future physician

31.25%

GC — VAARDIG

Analyse and integrate a short scientific health-theme text with figures

How to Pass the Toelatingsexamen Arts Exam

What You Need to Know

  • Passing score: ≥60/120 on KIW and ≥60/120 on GC to enter ranking; gunstige rangschikking requires a total at or above the cesuur set by the 1878 arts startquotum. +3 / 0 / −1 per item.
  • Assessment: One paper day: morning KIW (biology, physics, chemistry, mathematics; 3.5 hours from 09:45) and afternoon GC (EMCO then VAARDIG; 1.5 hours from 14:30). 2026 is a central pen-and-paper sitting at Brussels Expo. AHOVOKS supplies the formularium, periodic table, pen, highlighter and a simple calculator. This English four-option bank is a study adaptation of the 2026 leerstofoverzicht — not an official translation and not a simulation of the Dutch paper environment.
  • Time limit: KIW 3.5 hours (09:45 start) and GC 1.5 hours (14:30–16:00). Site access from 08:00; late start allowed until 10:45 without extra time.
  • Exam fee: EUR 65 per exam (non-refundable). Vlaanderen.be inschrijven, 2026.

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Toelatingsexamen Arts Study Tips from Top Performers

1Train the two-part gate: a high KIW score still fails ranking if GC is under 60/120, and vice versa.
2Wrong answers cost one point on the official paper, so skip when you cannot eliminate options.
3Use the official 2026 leerstofoverzicht — KIW is Flemish doorstroomfinaliteit science, not university medicine.
4Practise VAARDIG with short health-science texts and figures; 25 of 80 official items are passage-based.
5Keep arts, tandarts and dierenarts separate: dates, papers, ranking and startquota are independent.
6Complete these English items, then work official Dutch past papers; note that older official papers label the EMCO test as CLEAR. This bank is not a format or language simulation.

Frequently Asked Questions

What is the Flanders Toelatingsexamen Arts?

It is the AHOVOKS numerus-clausus exam required to start a geneeskunde bachelor at a Flemish university. A gunstige rangschikking for arts is not valid for tandheelkunde or diergeneeskunde.

How many official questions are there?

80 four-option items: 40 KIW (10 biology, 10 physics, 10 chemistry, 10 mathematics) and 40 GC (15 EMCO + 25 VAARDIG). This page's 100 English questions are a study bank, not the official paper.

What is the 2026 pass rule?

You need at least 60 of 120 points on KIW and 60 of 120 on GC. Ranked candidates are then ordered by total score; gunstige rangschikking is everyone at or above the cesuur set by the 1878 startquotum.

How is the exam scored?

Each question is +3 if correct, 0 if left blank and −1 if wrong. The whole exam is 240 points. There is no separate minimum per KIW subject.

How much does the 2026 sitting cost?

EUR 65 per exam, non-refundable. You pay separately for arts, tandarts and dierenarts if you sit more than one.

In what language is the official exam?

Dutch. AHOVOKS sets the paper and publishes the leerstofoverzicht, sample questions and past examenboeken in Dutch, and offers no translated version. This practice bank is an English-language MCQ study adaptation, not an official translation and not a simulation of the Dutch paper environment.

When is the 2026 arts exam?

Thursday 2 July 2026 at Brussels Expo (Heizel), with some extra-time candidates at the Hendrik Consciencegebouw. Enrolment ran 2 March to 18 May 2026 at noon.

Is this the same exam as the Wallonia medicine entrance test?

No. The Fédération Wallonie-Bruxelles runs a separate concours d'entrée. This bank covers only the Flemish AHOVOKS Toelatingsexamen Arts.