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Key Facts: Meisterprüfung Mechatronik Exam

€0

Fee for 1st & 2nd Attempt at Modules 1, 2, 3 and Unternehmerprüfung (Federally Funded Since 1 Jan 2024)

WKO Meisterprüfungsstellen & BMAW

Level 6

NQR / EQF Qualification Level (Bachelor-Equivalent)

Nationaler Qualifikationsrahmen (NQR) Österreich

5 Modules

Examination Structure (Practical, Oral, Written, Trainer, Business)

Mechatroniker-Meisterprüfungsordnung

§ 94 Z 49

Statutory Regulated Craft Listing in Austrian Trade Code (Gewerbeordnung 1994)

Gewerbeordnung 1994 (GewO 1994)

IEC 61131-3

International Standard for Programmable Logic Controller (PLC) Languages

IEC / EN 61131-3

EN ISO 13849-1

Machinery Functional Safety Standard (Performance Levels PL a–e)

European Harmonized Standard

EN 60204-1

Electrical Equipment of Machines Standard (Stop Categories 0, 1, 2)

ÖVE / ÖNORM EN 60204-1

Mst.

Legally Protected Master Craftsman Title Abbreviation

Gewerbeordnung 1994 (GewO 1994) § 21

The Austrian Meisterprüfung Mechatronik is the NQR Level 6 master craft qualification administered by the WKO across 5 modules: practical master assembly and PLC commissioning, oral commission exam, written technical project planning, apprentice trainer certification, and business management.

Sample Meisterprüfung Mechatronik Practice Questions

Try these sample questions to test your Meisterprüfung Mechatronik exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A two-stage spur gearbox (zweistufiges Stirnradgetriebe) is driven by an electric motor rotating at n_in = 1,440 rpm. The first gear stage has tooth counts z1 = 20 and z2 = 60; the second stage has tooth counts z3 = 15 and z4 = 75. What is the total gear ratio i_tot and the resulting output shaft speed n_out?

A.i_tot = 15.0 : 1 and n_out = 96 rpm

B.i_tot = 8.0 : 1 and n_out = 180 rpm

C.i_tot = 9.0 : 1 and n_out = 160 rpm

D.i_tot = 20.0 : 1 and n_out = 72 rpm

Explanation: The gear ratio for each stage is given by i = z_driven / z_driver. For the first stage, i1 = z2 / z1 = 60 / 20 = 3.0. For the second stage, i2 = z4 / z3 = 75 / 15 = 5.0. The total gear ratio is the product of the individual stage ratios: i_tot = i1 * i2 = 3.0 * 5.0 = 15.0. The output speed is n_out = n_in / i_tot = 1,440 rpm / 15.0 = 96 rpm.

2A simple planetary gearbox (Planetengetriebe) operates with a stationary ring gear (feststehendes Hohlrad, z_ring = 72 teeth). The input is driven via the sun gear (Sonnenrad, z_sun = 18 teeth) rotating at n_sun = 3,000 rpm, and the output is taken from the planet carrier (Steg). What is the gear ratio i and the output speed n_carrier?

A.i = 5.0 : 1 and n_carrier = 600 rpm

B.i = 4.0 : 1 and n_carrier = 750 rpm

C.i = 0.2 : 1 and n_carrier = 15,000 rpm

D.i = 3.0 : 1 and n_carrier = 1,000 rpm

Explanation: For a planetary gearset with fixed ring gear, the transmission ratio from sun gear to planet carrier is given by Willis' equation: i = 1 + (z_ring / z_sun) = 1 + (72 / 18) = 1 + 4.0 = 5.0. The output speed on the carrier is n_carrier = n_sun / i = 3,000 rpm / 5.0 = 600 rpm.

3A worm gearbox (Schneckengetriebe) has a single-start worm (Gangzahl z1 = 1) meshing with a worm wheel of z2 = 40 teeth. The drive motor supplies an input power P_in = 2.2 kW at n_in = 1,200 rpm. If the overall gearbox efficiency is eta = 0.75, what is the output torque T_out delivered at the worm wheel shaft?

A.525.2 Nm

B.700.3 Nm

C.13.1 Nm

D.393.9 Nm

Explanation: The gear ratio is i = z2 / z1 = 40 / 1 = 40. The output rotational speed is n_out = n_in / i = 1,200 / 40 = 30 rpm. The angular velocity is omega_out = 2 * pi * n_out / 60 = 2 * pi * 30 / 60 = pi rad/s ≈ 3.1416 rad/s. The output power is P_out = P_in * eta = 2,200 W * 0.75 = 1,650 W. Thus, output torque T_out = P_out / omega_out = 1,650 W / (pi rad/s) ≈ 525.21 Nm.

4A servo planetary gearbox with a speed reduction ratio i = 6.0 : 1 and a mechanical efficiency eta = 0.95 is driven by a servomotor producing an input torque T_in = 50.0 Nm. What is the static output torque T_out available at the planet carrier output shaft?

A.285.0 Nm

B.300.0 Nm

C.315.8 Nm

D.47.5 Nm

Explanation: The mechanical output torque of a reduction gearbox is given by T_out = T_in * i * eta. Substituting the given values: T_out = 50.0 Nm * 6.0 * 0.95 = 285.0 Nm.

5A three-phase asynchronous motor has a rated mechanical power P_N = 5.5 kW at a rated rotor speed n_N = 1,460 rpm. What is the rated mechanical torque T_N at the motor shaft?

A.36.0 Nm

B.3.77 Nm

C.226.0 Nm

D.75.3 Nm

Explanation: Rated torque is calculated from power and angular velocity: T_N = P_N / omega = P_N / (2 * pi * n_N / 60). For P_N = 5,500 W and n_N = 1,460 rpm: omega = 2 * pi * 1,460 / 60 ≈ 152.89 rad/s. T_N = 5,500 / 152.89 ≈ 35.97 Nm ≈ 36.0 Nm (or using standard engineering formula T ≈ 9550 * P[kW] / n[rpm] = 9550 * 5.5 / 1460 ≈ 35.98 Nm).

6A heavy rotary index table with a mass moment of inertia J_load = 0.450 kg·m² is driven by a servomotor via a speed reduction gearbox with ratio i = 5.0 : 1 (n_in / n_out = 5). Assuming an ideal gearbox (eta = 1.0), what is the reflected moment of inertia J_load,ref seen by the motor shaft?

A.0.018 kg·m²

B.0.090 kg·m²

C.2.250 kg·m²

D.11.25 kg·m²

Explanation: The moment of inertia reflected across a reduction gearbox is inversely proportional to the square of the gear ratio: J_load,ref = J_load / i^2. For J_load = 0.450 kg·m² and i = 5.0: J_load,ref = 0.450 / 5^2 = 0.450 / 25 = 0.018 kg·m².

7A high-dynamic direct-drive servomotor with combined motor and load inertia J_tot = 0.006 kg·m² must accelerate from standstill (n = 0 rpm) to n = 3,000 rpm in a linear ramp time of t_acc = 50 ms (0.050 s). Neglecting friction, what is the required dynamic acceleration torque M_acc?

A.37.70 Nm

B.0.36 Nm

C.6.00 Nm

D.18.85 Nm

Explanation: First calculate final angular velocity: omega = 2 * pi * n / 60 = 2 * pi * 3,000 / 60 = 100 * pi ≈ 314.159 rad/s. Angular acceleration is alpha = omega / t_acc = 314.159 rad/s / 0.050 s = 6,283.185 rad/s². The dynamic acceleration torque is M_acc = J_tot * alpha = 0.006 kg·m² * 6,283.185 rad/s² ≈ 37.70 Nm.

8A CNC linear axis uses a precision ball screw (Kugelgewindetrieb) with a lead (Steigung) p = 10 mm per revolution directly coupled to a servomotor. If the motor rotates at n = 1,800 rpm, what is the resulting linear feed velocity v of the slide table?

A.18.0 m/min (0.30 m/s)

B.1.8 m/min (0.03 m/s)

C.180.0 m/min (3.00 m/s)

D.11.3 m/min (0.19 m/s)

Explanation: Linear velocity is given by v = n * p. For n = 1,800 rev/min and p = 10 mm/rev = 0.010 m/rev: v = 1,800 rev/min * 10 mm/rev = 18,000 mm/min = 18.0 m/min. In SI units: v = 18.0 / 60 = 0.30 m/s (or 300 mm/s).

9A ball screw drive with screw lead p = 5.0 mm (0.005 m) and mechanical efficiency eta = 0.90 must exert an axial thrust feed force F_ax = 3,600 N to push a cutting carriage. What driving torque T_mot must the motor apply to the screw shaft to maintain this thrust force?

A.3.18 Nm

B.2.87 Nm

C.18.00 Nm

D.0.51 Nm

Explanation: The relationship between axial thrust force and motor torque for a screw drive is T = (F_ax * p) / (2 * pi * eta). Substituting the given values: T = (3,600 N * 0.005 m) / (2 * pi * 0.90) = 18.0 / (5.65487) ≈ 3.183 Nm ≈ 3.18 Nm.

10A machine slide with a total moving mass m = 120 kg is linearly driven by a ball screw with lead p = 10 mm per revolution. What is the equivalent mass moment of inertia J_lin reflected at the rotating screw shaft?

A.3.04 * 10^-4 kg·m² (0.000304 kg·m²)

B.1.20 * 10^-2 kg·m² (0.012 kg·m²)

C.1.91 * 10^-3 kg·m² (0.00191 kg·m²)

D.3.82 * 10^-5 kg·m² (0.000038 kg·m²)

Explanation: The reflected moment of inertia of a linearly translating mass driven by a screw is given by J_lin = m * (p / (2 * pi))^2. For m = 120 kg and p = 0.010 m: p / (2 * pi) = 0.010 / 6.283185 ≈ 0.00159155 m/rad. Thus, J_lin = 120 * (0.00159155)^2 = 120 * 2.53303 * 10^-6 ≈ 3.0396 * 10^-4 kg·m² (approx. 3.04 * 10^-4 kg·m²).

About the Meisterprüfung Mechatronik Exam

The Meisterprüfung Mechatronik is the statutory master craft qualification in Austria for the mechatronics trade, regulated under § 94 Z 49 of the Austrian Trade Code (Gewerbeordnung 1994, GewO 1994) as a reglementiertes Gewerbe (Handwerk). Governed by the Mechatroniker-Meisterprüfungsordnungen of the Bundesinnung der Mechatroniker (covering branches such as Maschinen- und Fertigungstechnik, Elektromaschinenbau und Automatisierung, Elektronik/EDV-Systemtechnik, and Medizingerätetechnik), it is positioned at Level 6 of the Austrian National and European Qualifications Framework (NQR/EQF Level 6, bachelor-equivalent). Passing the examination grants the legally protected title of 'Meister' (abbreviated 'Mst.') per § 21 GewO 1994 and the statutory right to operate an independent mechatronics enterprise, train apprentices, and sign off official machine CE declarations and electrical safety test protocols. This practice bank offers an English-language MCQ study adaptation covering mechanical drive systems, electrical drives and power electronics, control engineering (IEC 61131-3 PLC), fluidics, industrial robotics, and European machine safety standards (EN ISO 13849-1 and EN 60204-1).

Assessment

Five modules under the Mechatroniker-Meisterprüfungsordnung; the Meisterprüfung is the statutory Befähigungsnachweis for the regulated trade under § 94 Z 49 GewO 1994 and is assigned to Level 6 of the Austrian National Qualifications Framework (NQR Level 6). Modul 1: Fachlich praktische Prüfung — Teil A 'Prüfarbeit auf Niveau der Lehrabschlussprüfung' plus Teil B 'Meisterarbeit' (complex mechanical/electrical assembly, commissioning, PLC programming, and measurement protocols). Modul 2: Fachlich mündliche Prüfung — Teil A 'Fachgespräch auf Niveau der Lehrabschlussprüfung' and Teil B covering advanced mechatronic systems, drives, automation, safety, and standards before the commission. Modul 3: Fachlich schriftliche Prüfung — comprehensive project work in technical engineering design, schematics, and cost calculation. Modul 4: Ausbilderprüfung under §§ 29a ff BAG (or Ausbilderkurs under § 29g BAG). Modul 5: Unternehmerprüfung under the Unternehmerprüfungsordnung. Teil A of Modules 1 and 2 is credited to holders of a relevant Lehrabschlussprüfung.

Time Limit

Set per module: practical multi-day project (Modul 1), written technical calculations and planning 4–6 h (Modul 3), oral commission interview 30–60 min (Modul 2)

Passing Score

Austrian school grade scale 'Sehr gut' (1) to 'Nicht genügend' (5); a module passes when every subject is at least 'Genügend' (4), with 'mit gutem Erfolg' and 'mit Auszeichnung' as higher tiers

Exam Fee

Free for the 1st & 2nd attempt at Modules 1, 2, 3 and the Unternehmerprüfung (federally funded since 1 Jan 2024); from the 3rd attempt the Allgemeine Prüfungsordnung fee schedule applies (WKO Meisterprüfungsstellen / Bundesinnung der Mechatroniker)

Meisterprüfung Mechatronik Exam Content Outline

25% of this practice bank

Mechanics and Mechanical Drive Systems (Mechanik & Antriebstechnik)

Kinematics, gearboxes (spur, bevel, planetary, worm), rolling and plain bearings, linear guides and ball screws, belt and chain drives, ISO 286 tolerances and fits, mechanical power & torque transmission, materials testing, and structural mechanics.

25% of this practice bank

Electrical Drives, Power Electronics & Sensors (Elektrische Antriebe, Leistungselektronik & Sensorik)

Three-phase AC induction and permanent magnet synchronous motors (PMSM/BLDC), servo drives, stepper motors, frequency converters (V/f control, field-oriented FOC/vector control), rotary encoders (incremental, absolute EnDat/SSI, resolvers), inductive/capacitive/optical sensors, signal conditioning, and A/D conversion.

25% of this practice bank

Control Engineering, PLC & Fluidics (Regelungstechnik, SPS & Fluidtechnik)

Closed-loop control systems, PID controller tuning (Ziegler-Nichols, step response), IEC 61131-3 PLC programming languages (Structured Text ST, Function Block Diagram FBD, Ladder Diagram LAD), industrial fieldbuses (PROFINET, IO-Link, CANopen), pneumatic and electro-pneumatic circuits, and hydraulic proportional valves.

25% of this practice bank

Robotics, Machine Safety & Regulations (Robotik, Maschinensicherheit & Normen)

Industrial robotics (kinematics, forward/inverse transformation, tool center point TCP, collaborative robots ISO/TS 15066), European Machinery Directive 2006/42/EC / EU Machinery Regulation 2023/1230, EN ISO 13849-1 functional safety (Performance Level PL a-e, Category B-4, MTTFd, DCavg, CCF), electrical equipment of machines EN 60204-1, commissioning, troubleshooting diagnostics, costing, and Austrian trade law (GewO 1994 § 94 Z 49).

How to Pass the Meisterprüfung Mechatronik Exam

What You Need to Know

Passing score: Austrian school grade scale 'Sehr gut' (1) to 'Nicht genügend' (5); a module passes when every subject is at least 'Genügend' (4), with 'mit gutem Erfolg' and 'mit Auszeichnung' as higher tiers
Assessment: Five modules under the Mechatroniker-Meisterprüfungsordnung; the Meisterprüfung is the statutory Befähigungsnachweis for the regulated trade under § 94 Z 49 GewO 1994 and is assigned to Level 6 of the Austrian National Qualifications Framework (NQR Level 6). Modul 1: Fachlich praktische Prüfung — Teil A 'Prüfarbeit auf Niveau der Lehrabschlussprüfung' plus Teil B 'Meisterarbeit' (complex mechanical/electrical assembly, commissioning, PLC programming, and measurement protocols). Modul 2: Fachlich mündliche Prüfung — Teil A 'Fachgespräch auf Niveau der Lehrabschlussprüfung' and Teil B covering advanced mechatronic systems, drives, automation, safety, and standards before the commission. Modul 3: Fachlich schriftliche Prüfung — comprehensive project work in technical engineering design, schematics, and cost calculation. Modul 4: Ausbilderprüfung under §§ 29a ff BAG (or Ausbilderkurs under § 29g BAG). Modul 5: Unternehmerprüfung under the Unternehmerprüfungsordnung. Teil A of Modules 1 and 2 is credited to holders of a relevant Lehrabschlussprüfung.
Time limit: Set per module: practical multi-day project (Modul 1), written technical calculations and planning 4–6 h (Modul 3), oral commission interview 30–60 min (Modul 2)
Exam fee: Free for the 1st & 2nd attempt at Modules 1, 2, 3 and the Unternehmerprüfung (federally funded since 1 Jan 2024); from the 3rd attempt the Allgemeine Prüfungsordnung fee schedule applies

Keys to Passing

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Meisterprüfung Mechatronik Study Tips from Top Performers

1Master mechanical drive calculations: be fluent in gear ratios (i = z2 / z1), planetary gearbox ratios (i = 1 + z_ring / z_sun), motor torque equations (T = P / omega), and reflected rotational inertia across gearboxes (J_ref = J_load / i^2).

2Memorize the relationship between electrical frequency, pole pairs, and synchronous motor speed: n_s = (60 * f) / p, and slip calculation s = (n_s - n_N) / n_s.

3Understand Field-Oriented Control (FOC): know how Clarke and Park transformations decouple three-phase stator currents into independent direct (d, flux) and quadrature (q, torque) axis components.

4Review EN ISO 13849-1 functional safety architectures: distinguish Categories B, 1, 2, 3, and 4, and know the definitions of PL a through PL e alongside Safe Torque Off (STO), Safe Stop 1 (SS1), and Safe Stop 2 (SS2) per EN 61800-5-2.

5Practice IEC 61131-3 Structured Text (ST) and function block operation: master standard timer behaviors (TON, TOF, TP), edge detection (R_TRIG, F_TRIG), and stateful Function Blocks versus stateless Functions.

6Review electrical machine safety per EN 60204-1: memorize Stop Categories (0 = uncontrolled instant power disconnect, 1 = controlled ramp stop then power removal, 2 = controlled ramp stop with power maintained to hold position) and safety light curtain distance formula S = (K * T) + C per EN ISO 13855.

Frequently Asked Questions

What is the Meisterprüfung Mechatronik in Austria?

The Meisterprüfung Mechatronik is the official master craftsman qualifying examination in Austria for the mechatronics trade, listed under § 94 Z 49 of the Austrian Trade Code (Gewerbeordnung 1994, GewO 1994) as a regulated craft (reglementiertes Handwerk). Administered by the Meisterprüfungsstellen of the Austrian Economic Chambers (WKO), it qualifies individuals at Level 6 of the National Qualifications Framework (NQR/EQF Level 6, equivalent to a Bachelor's degree), conferring the legally protected title of 'Meister' (Mst.) and granting the statutory authority to establish an independent enterprise, train apprentices, and certify mechatronic machinery installations.

What are the 5 modules of the Austrian Mechatronik Meisterprüfung?

The examination consists of 5 modular components: Modul 1 is the practical examination (Teil A work sample at apprenticeship level and Teil B master project in mechanical assembly, electrical wiring, PLC programming, commissioning, and test protocols); Modul 2 is the oral examination (Teil A basic technical dialogue and Teil B advanced technical mastery, safety, and standards before the commission); Modul 3 is the written theoretical examination (technical planning, schematics, and calculations); Modul 4 is the Ausbilderprüfung (apprentice trainer exam under the Berufsausbildungsgesetz); and Modul 5 is the Unternehmerprüfung (business management, tax, and commercial law). Holders of a relevant Lehrabschlussprüfung are credited with Teil A of Modules 1 and 2.

What functional safety standards must a mechatronics master master in Austria?

Mechatronics master craft candidates must thoroughly understand European and Austrian functional safety standards under the Machinery Directive 2006/42/EC (and EU Machinery Regulation 2023/1230), specifically EN ISO 13849-1 (Safety-related parts of control systems — Performance Levels PL a to PL e, Categories B to 4, MTTFd, Diagnostic Coverage DCavg, and Common Cause Failure CCF), EN 62061 (Safety Integrity Levels SIL 1 to 3), and EN 60204-1 (Safety of machinery — Electrical equipment of machines, covering stop categories 0, 1, 2, protective bonding, and insulation testing).

How much does the Austrian Meisterprüfung cost?

Since 1 January 2024 (applied retroactively to 1 July 2023), the Austrian federal government covers 100% of the examination fees for the first and second attempt at Modules 1, 2, 3 and the Unternehmerprüfung, making those attempts free of charge (€0) for candidates. From the third attempt onwards, examination fees are levied under the Allgemeine Prüfungsordnung (BGBl. II Nr. 110/2004) as calculated by the responsible provincial Meisterprüfungsstelle.

What programming standards are evaluated in Module 3 and Module 1?

The technical planning and programming components require proficiency in IEC 61131-3 standardized PLC programming languages (primarily Structured Text ST, Function Block Diagram FBD, and Ladder Diagram LAD), industrial communication protocols (PROFINET RT/IRT, IO-Link, CANopen), and PID closed-loop control algorithms.

How does this practice question bank adapt the Austrian Meisterprüfung?

The official Austrian master craftsman examination is conducted in German and consists of practical master projects, written technical calculations, and an oral commission interview. This practice question bank is an English-language multiple-choice study adaptation designed to reinforce theoretical concepts, mathematical formulas, drive engineering, PLC logic, and European regulatory standards (such as EN ISO 13849-1, EN 60204-1, ISO 286, and GewO 1994) while preserving authentic German and standard technical terminology.