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100+ Free Meisterprüfung Kälte- und Klimatechnik Practice Questions

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2026 Statistics

Key Facts: Meisterprüfung Kälte- und Klimatechnik Exam

€0

Fee for 1st & 2nd Attempt at Modules 1, 2, 3 and Unternehmerprüfung (Federally Funded Since 1 Jan 2024)

WKO Meisterprüfungsstellen & BMAW

Level 6

NQR / EQF Qualification Level (Bachelor-Equivalent)

Nationaler Qualifikationsrahmen (NQR) Österreich

5 Modules

Examination Structure (Meisterarbeit, Fachgespräch, Projektarbeit, Ausbilder, Unternehmer)

Kälte- und Klimatechnik-Meisterprüfungsordnung

§ 94 Z 37

Statutory Regulated Craft Listing in Austrian Trade Code (Gewerbeordnung 1994)

Gewerbeordnung 1994 (GewO 1994)

GWP < 150

F-Gas Regulation (EU) 2024/573 Limit for Most New Commercial & Plug-in Systems

EU F-Gas Regulation (EU) 2024/573

73.8 bar

Critical Pressure of R744 (Carbon Dioxide) with Critical Temperature 31.0 °C

Thermodynamic Refrigerant Properties (IIR / ASHRAE)

>= 5 t CO2-eq

Threshold Mandating Statutory Periodic Leak Checks under F-Gas Regulations

EU F-Gas Regulation & Austrian Fluorierte Treibhausgase-VO

Mst.

Legally Protected Master Craftsman Title Abbreviation

Gewerbeordnung 1994 (GewO 1994) § 21

The Austrian Meisterprüfung Kälte- und Klimatechnik is the NQR Level 6 master craft competence qualification administered by WKO across 5 modules: practical master project, oral commission exam, written thermodynamic engineering calculations, apprentice trainer certification, and business administration.

Sample Meisterprüfung Kälte- und Klimatechnik Practice Questions

Try these sample questions to test your Meisterprüfung Kälte- und Klimatechnik exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A standard single-stage vapor compression cycle operating with R134a has a specific enthalpy at the evaporator outlet (suction) of h_1 = 402 kJ/kg and a specific enthalpy at the expansion valve inlet of h_4 = 252 kJ/kg. What is the specific refrigerating capacity (spezifische Kälteleistung q_0)?
A.150 kJ/kg
B.654 kJ/kg
C.252 kJ/kg
D.1.60 kJ/kg
Explanation: Specific refrigerating capacity q_0 is calculated as the enthalpy difference across the evaporator: q_0 = h_1 - h_4 (since throttling across the expansion valve is isenthalpic, h_4 = h_3). Here, q_0 = 402 kJ/kg - 252 kJ/kg = 150 kJ/kg.
2In an R449A refrigeration system, the specific refrigerating capacity is q_0 = 160 kJ/kg and the specific isentropic work of compression is w_c = 32 kJ/kg. What is the theoretical coefficient of performance (Kälteleistungszahl COP / ε)?
A.5.0
B.0.20
C.4.0
D.6.0
Explanation: The theoretical coefficient of performance (Kälteleistungszahl ε / COP) is the quotient of specific refrigerating capacity q_0 and specific compression work w_c: COP = q_0 / w_c = 160 kJ/kg / 32 kJ/kg = 5.0.
3A cold storage facility requires a total cooling capacity of Q_0 = 36 kW. If the specific refrigerating capacity of the cycle is q_0 = 180 kJ/kg, what is the required refrigerant mass flow rate (Kältemittel-Massenstrom m_dot)?
A.0.20 kg/s (12.0 kg/min)
B.0.05 kg/s (3.0 kg/min)
C.5.00 kg/s (300 kg/min)
D.6.48 kg/s (388.8 kg/min)
Explanation: The refrigerant mass flow rate m_dot is calculated from total cooling capacity and specific cooling capacity: m_dot = Q_0 / q_0. Substituting the values: m_dot = 36 kW / 180 kJ/kg = 0.20 kg/s (or 0.20 * 60 = 12.0 kg/min = 720 kg/h).
4A refrigeration system operates with an evaporator cooling capacity of Q_0 = 50 kW. The compressor indicated mechanical power input to the refrigerant is P_i = 15 kW. Neglecting heat losses from the compressor housing and piping, what is the total condenser heat rejection rate (Verflüssigerleistung Q_c)?
A.65 kW
B.35 kW
C.750 kW
D.3.33 kW
Explanation: According to the first law of thermodynamics (energy balance for a closed steady-state refrigeration cycle), the heat rejected at the condenser equals the evaporator heat absorbed plus the compressor mechanical work imparted to the refrigerant: Q_c = Q_0 + P_i = 50 kW + 15 kW = 65 kW.
5An ideal Carnot refrigeration cycle operates between an evaporating temperature of t_0 = -10 °C and a condensing temperature of t_c = +35 °C. What is the theoretical Carnot coefficient of performance (Carnot-Kälteleistungszahl ε_C)?
A.5.85
B.0.29
C.-0.22
D.6.85
Explanation: Carnot COP must be calculated using absolute thermodynamic temperatures in Kelvin: T_0 = -10 + 273.15 = 263.15 K, and T_c = 35 + 273.15 = 308.15 K. ε_C = T_0 / (T_c - T_0) = 263.15 / (308.15 - 263.15) = 263.15 / 45.0 = 5.8477 ≈ 5.85.
6A semi-hermetic reciprocating compressor has a geometric displacement (theoretischer Hubvolumenstrom) of V_h = 60.0 m³/h. At operating conditions, the volumetric efficiency (Liefergrad) is λ = 0.75, suction vapor specific volume is v_1 = 0.060 m³/kg, and specific refrigerating capacity is q_0 = 150 kJ/kg. What is the effective cooling capacity (Kälteleistung Q_0)?
A.31.25 kW
B.41.67 kW
C.112.5 kW
D.18.75 kW
Explanation: First, calculate effective suction volume flow: V_eff = V_h * λ = 60.0 * 0.75 = 45.0 m³/h = 45.0 / 3600 = 0.0125 m³/s. Refrigerant mass flow rate: m_dot = V_eff / v_1 = 0.0125 / 0.060 = 0.20833 kg/s. Cooling capacity: Q_0 = m_dot * q_0 = 0.20833 kg/s * 150 kJ/kg = 31.25 kW.
7In refrigeration thermodynamics, what is the fundamental distinction between useful superheat (nutzbare Überhitzung) and non-useful superheat (nicht nutzbare Überhitzung)?
A.Useful superheat takes place within the refrigerated space or internal heat exchanger to provide effective cooling, whereas non-useful superheat occurs in ambient suction lines outside the cold room.
B.Useful superheat is generated exclusively inside the compressor cylinder, while non-useful superheat occurs inside the condenser.
C.Useful superheat occurs during condensation at high pressure, while non-useful superheat occurs during throttling in the expansion valve.
D.Useful superheat reduces compressor discharge temperature, while non-useful superheat causes liquid slugging.
Explanation: Useful superheat (nutzbare Überhitzung) absorbs heat from the target refrigerated space (inside the evaporator or via an internal suction line heat exchanger), contributing directly to the useful cooling effect. Non-useful superheat (nicht nutzbare Überhitzung) occurs in uninsulated suction lines exposed to ambient air outside the refrigerated space; it increases suction gas temperature, lowers suction density, and raises compressor discharge temperature without contributing to room cooling.
8How does increasing liquid subcooling (Unterkühlung) prior to the thermostatic expansion valve affect the refrigeration cycle on an h,log(p) enthalpy diagram?
A.It shifts the liquid state point to the left (lower enthalpy), thereby increasing specific refrigerating capacity (q_0) with no increase in specific compressor work.
B.It shifts the evaporating pressure line upwards, lowering compressor pressure ratio.
C.It decreases specific refrigerating capacity by reducing refrigerant mass density at the evaporator inlet.
D.It shifts the compressor discharge point to the right, significantly increasing compressor power consumption.
Explanation: On an h,log(p) diagram, subcooling the liquid below its bubble-point temperature shifts point 3/4 to the left towards lower enthalpy (h_4 < h_3_sat). Because throttling is isenthalpic (h_4 = h_inlet_evap), the enthalpy at the evaporator entrance is lower. Thus, specific refrigerating capacity q_0 = h_1 - h_4 increases without changing the compression path (h_2 - h_1), which directly improves the COP.
9A low-temperature refrigeration plant operates at an evaporating pressure of p_0 = 1.20 bar (absolute) and a condensing pressure of p_c = 15.60 bar (absolute). What is the compression pressure ratio (Druckverhältnis Π)?
A.13.0
B.14.4
C.18.7
D.0.077
Explanation: The pressure ratio (Druckverhältnis Π) is defined as the quotient of absolute discharge/condensing pressure to absolute suction/evaporating pressure: Π = p_c / p_0 = 15.60 bar / 1.20 bar = 13.0.
10In a two-stage compression system operating between an evaporating pressure of p_0 = 1.50 bar (abs) and a condensing pressure of p_c = 24.00 bar (abs), what is the optimal theoretical intermediate pressure (idealer Mitteldruck p_m) for equal stage pressure ratios?
A.6.00 bar (abs)
B.12.75 bar (abs)
C.4.00 bar (abs)
D.8.00 bar (abs)
Explanation: The optimal intermediate pressure p_m that equalizes the pressure ratio across both stages and minimizes overall compression work is the geometric mean of evaporating and condensing pressures: p_m = sqrt(p_0 * p_c) = sqrt(1.50 * 24.00) = sqrt(36.00) = 6.00 bar (abs). Each stage operates with a pressure ratio of Π_1 = 6.0/1.5 = 4.0 and Π_2 = 24.0/6.0 = 4.0.

About the Meisterprüfung Kälte- und Klimatechnik Exam

The Meisterprüfung Kälte- und Klimatechnik is the statutory master craft qualification in Austria for refrigeration and air conditioning engineering, regulated under § 94 Z 37 of the Austrian Trade Code (Gewerbeordnung 1994, GewO 1994) as a regulated trade (reglementiertes Gewerbe). Positioned at Level 6 of the Austrian National and European Qualifications Framework (NQR/EQF Level 6, bachelor-equivalent), passing the examination confers the legally protected title of 'Meister' (Mst.) and grants the statutory right to operate an independent refrigeration, air conditioning, and heat pump contracting enterprise, sign off statutory leak testing and safety inspection protocols under ÖNORM EN 378 and the EU F-Gas Regulation (EU) 2024/573, and train apprentices. This practice question bank offers an English-language MCQ study adaptation covering refrigeration thermodynamics, h,log(p) cycle analysis, COP calculations, natural refrigerants (CO2/R744 transcritical, R290, R717), system components, oil management, Mollier h,x psychrometrics, and Austrian statutory safety standards.

Assessment

Five modules under the Kälte- und Klimatechnik-Meisterprüfungsordnung; the Meisterprüfung represents the statutory qualification under § 94 Z 37 of the Austrian Trade Code (GewO 1994) and is classified at Level 6 of the Austrian National Qualifications Framework (NQR). Modul 1: Fachlich praktische Prüfung (Teil A work samples: pipe brazing, flaring, electrical control wiring, sensor calibration, commissioning, troubleshooting; Teil B Meisterarbeit / practical refrigeration project). Modul 2: Fachlich mündliche Prüfung (Teil A & Teil B oral commission defense / Fachgespräch covering cycle thermodynamics, components, environmental legislation, and safety engineering). Modul 3: Fachlich schriftliche Prüfung (comprehensive written engineering design, cooling load calculations, h,log(p) cycle analysis, pipe sizing, Mollier h,x psychrometric calculations, and cost estimation). Modul 4: Ausbilderprüfung under §§ 29a ff BAG. Modul 5: Unternehmerprüfung under the Unternehmerprüfungsordnung.

Time Limit

Set per module: practical multi-day project 14–20 h (Modul 1), written technical calculations and planning 4–6 h (Modul 3), oral commission interview 30–60 min (Modul 2)

Passing Score

Austrian school grading scale from 'Sehr gut' (1) to 'Nicht genügend' (5); a module passes when every subject receives at least 'Genügend' (4), with 'mit gutem Erfolg' and 'mit Auszeichnung' awarded for superior performance

Exam Fee

Free for the 1st & 2nd attempt at Modules 1, 2, 3 and the Unternehmerprüfung (100% federally funded since 1 Jan 2024); from the 3rd attempt, statutory fees under the Allgemeine Prüfungsordnung (BGBl. II Nr. 110/2004) apply (WKO Meisterprüfungsstellen / Bundesinnung der Mechatroniker)

Meisterprüfung Kälte- und Klimatechnik Exam Content Outline

25% of this practice bank

Thermodynamics of Refrigeration Cycles & Enthalpy Diagrams (Thermodynamik & h,log(p)-Diagramme)

Vapor compression cycle analysis, pressure-enthalpy (h,log(p)) diagrams, evaporating and condensing temperatures, useful and total superheat (Überhitzung), liquid subcooling (Unterkühlung), coefficient of performance (COP / Kälteleistungszahl ε), compressor volumetric and isentropic efficiencies, pressure ratio (Druckverhältnis), multi-stage compression with intercooling, and cascade refrigeration systems.

25% of this practice bank

Refrigerants, Environmental Legislation & Safety Standards (Kältemittel, Umweltrecht & ÖNORM EN 378)

EU F-Gas Regulation (EU) 2024/573, Austrian Fluorierte Treibhausgase-Verordnung, GWP calculations and phase-down quotas, natural refrigerants (R744 / CO2 subcritical and transcritical booster systems, R290 / propane safety charges and ventilation, R717 / ammonia industrial systems), ASHRAE/EN 378 safety classifications (A1, A2L, A3, B2L), leak detection thresholds, recovery procedures, and logbook mandates.

25% of this practice bank

System Components, Hydraulics & Electrical Control Engineering (Anlagenkomponenten, Hydraulik & Steuerungstechnik)

Compressor technologies (semi-hermetic reciprocating, scroll, screw, inverter-driven), evaporators (direct expansion, flooded, frost formation), condensers (air-cooled, evaporative, water-cooled with cooling towers), expansion devices (thermostatic TXV with MOP/ballast charges, electronic EXV stepper valves), oil management (miscibility, oil separators, oil return velocities, traps), hot gas and electric defrost systems, and electrical power/control schematics.

25% of this practice bank

Air Conditioning Design, Psychrometrics, Safety & Trade Law (Klimatechnik, h,x-Diagramm, Sicherheit & Gewerberecht)

Mollier psychrometric chart (h,x-Diagramm), sensible and latent heat loads, room air conditioning processes (heating, cooling, dehumidification, adiabatic/steam humidification), air change and ventilation rates per ÖNORM EN 16798, chilled water systems, safety engineering per ÖNORM EN 378 Parts 1–4, Pressure Equipment Directive (DGR / DGRL 2014/68/EU), Austrian Trade Code (GewO 1994 § 94 Z 37), and project costing.

How to Pass the Meisterprüfung Kälte- und Klimatechnik Exam

What You Need to Know

  • Passing score: Austrian school grading scale from 'Sehr gut' (1) to 'Nicht genügend' (5); a module passes when every subject receives at least 'Genügend' (4), with 'mit gutem Erfolg' and 'mit Auszeichnung' awarded for superior performance
  • Assessment: Five modules under the Kälte- und Klimatechnik-Meisterprüfungsordnung; the Meisterprüfung represents the statutory qualification under § 94 Z 37 of the Austrian Trade Code (GewO 1994) and is classified at Level 6 of the Austrian National Qualifications Framework (NQR). Modul 1: Fachlich praktische Prüfung (Teil A work samples: pipe brazing, flaring, electrical control wiring, sensor calibration, commissioning, troubleshooting; Teil B Meisterarbeit / practical refrigeration project). Modul 2: Fachlich mündliche Prüfung (Teil A & Teil B oral commission defense / Fachgespräch covering cycle thermodynamics, components, environmental legislation, and safety engineering). Modul 3: Fachlich schriftliche Prüfung (comprehensive written engineering design, cooling load calculations, h,log(p) cycle analysis, pipe sizing, Mollier h,x psychrometric calculations, and cost estimation). Modul 4: Ausbilderprüfung under §§ 29a ff BAG. Modul 5: Unternehmerprüfung under the Unternehmerprüfungsordnung.
  • Time limit: Set per module: practical multi-day project 14–20 h (Modul 1), written technical calculations and planning 4–6 h (Modul 3), oral commission interview 30–60 min (Modul 2)
  • Exam fee: Free for the 1st & 2nd attempt at Modules 1, 2, 3 and the Unternehmerprüfung (100% federally funded since 1 Jan 2024); from the 3rd attempt, statutory fees under the Allgemeine Prüfungsordnung (BGBl. II Nr. 110/2004) apply

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Meisterprüfung Kälte- und Klimatechnik Study Tips from Top Performers

1Master refrigeration cycle calculations on the h,log(p) diagram: specific refrigerating capacity q_0 = h_1 - h_4 (kJ/kg), specific work of compression w_c = h_2 - h_1 (kJ/kg), coefficient of performance COP = q_0 / w_c, mass flow rate m_dot = Q_0 / q_0 (kg/s), and compressor electrical power P_el = (m_dot * w_c) / (eta_is * eta_m * eta_el).
2Understand the difference between useful superheat (nutzbare Überhitzung) in the evaporator and total superheat (Gesamtüberhitzung) at the compressor suction port, as well as liquid subcooling (Unterkühlung) in the condenser/subcooler which increases specific cooling capacity without increasing compressor work.
3Memorize key provisions of the EU F-Gas Regulation (EU) 2024/573: GWP thresholds (e.g., GWP < 150 for self-contained commercial refrigeration), leak check intervals based on CO2 equivalent (>= 5 t CO2-eq: 12 months; >= 50 t: 6 months; >= 500 t: 3 months, halved if automatic leak detection is installed), and mandatory electronic logbooks.
4Study transcritical CO2 (R744) cycle mechanics: high operating pressures (up to 120 bar), gas cooler outlet temperature controlling high side pressure (optimum COP control curve), flash gas valve (Mitteldruckventil) regulating intermediate receiver pressure (35–45 bar), and parallel compression (Parallelverdichtung) energy benefits.
5Practice Mollier h,x psychrometric chart calculations: sensible heat factor (SHF = Q_s / Q_tot), mixing of two air streams, cooling with dehumidification along the saturation curve (Taupunkt), and adiabatic vs. isothermal steam humidification.
6Review ÖNORM EN 378 safety engineering: refrigerant toxicity and flammability classifications (A1, A2L, A2, A3, B1, B2L, B2, B3), maximum allowable charge calculations for human occupancy spaces (practical limit / Grenzwert), machinery room mechanical emergency ventilation (V = 14 * m^(2/3) m³/h), and safety relief valve (Sicherheitsventil) discharge sizing.

Frequently Asked Questions

What is the Meisterprüfung Kälte- und Klimatechnik in Austria?

The Meisterprüfung Kälte- und Klimatechnik is the official Austrian master craft examination for refrigeration, air conditioning, and heat pump engineering, regulated under § 94 Z 37 of the Austrian Trade Code (Gewerbeordnung 1994, GewO 1994). Administered by the Meisterprüfungsstellen of the Austrian Economic Chambers (WKO), it is aligned with Level 6 of the Austrian National Qualifications Framework (NQR Level 6, bachelor-equivalent). Earning the master certificate confers the legally protected title of 'Meister' (Mst.) per § 21 GewO 1994 and qualifies the holder for full commercial licensing to manage an independent contracting enterprise, certify high-capacity refrigeration installations, and train apprentices.

What are the 5 modules of the Austrian Kälte- und Klimatechnik Meisterprüfung?

The master examination consists of 5 modular components: Modul 1 is the practical examination (Fachlich praktische Prüfung), comprising practical work samples (brazing, flaring, electrical controls, commissioning, troubleshooting) and the Meisterarbeit project; Modul 2 is the oral examination (Fachlich mündliche Prüfung / Fachgespräch) covering thermodynamics, components, environmental laws, and safety; Modul 3 is the written theoretical and engineering calculation examination (Fachlich schriftliche Prüfung) covering thermodynamic cycle design, psychrometrics, pipe sizing, and costing; Modul 4 is the apprentice trainer examination (Ausbilderprüfung under §§ 29a ff BAG); and Modul 5 is the business administration examination (Unternehmerprüfung).

How much does the Austrian Kälte- und Klimatechnik Meisterprüfung cost?

Since 1 January 2024 (applied retroactively to 1 July 2023), examination fees for the first and second attempt at Modules 1, 2, 3 and the Unternehmerprüfung are 100% covered by the Austrian federal government and are completely free of charge (€0) for candidates. If a candidate requires a third or subsequent attempt, standard examination fees apply in accordance with the Allgemeine Prüfungsordnung (BGBl. II Nr. 110/2004).

What safety standards and environmental regulations are tested on the exam?

The examination thoroughly tests European and Austrian statutory standards, foremost the revised EU F-Gas Regulation (EU) 2024/573 (phase-down schedules, GWP limits, certified personnel requirements), the Austrian Fluorierte Treibhausgase-Verordnung, ÖNORM EN 378 Parts 1–4 (safety requirements, charge limits, toxicity/flammability classifications A1 to A3, machinery room ventilation), the Pressure Equipment Directive (DGRL 2014/68/EU / DGR), and ArbeitnehmerInnenschutzgesetz (ASchG) workplace safety rules.

How are natural refrigerants like R744 (CO2) and R290 (Propane) emphasized?

Due to EU F-Gas phase-down mandates restricting high-GWP hydrofluorocarbons (HFCs), natural refrigerants are heavily tested. Candidates must master transcritical and subcritical R744 (CO2) booster systems, high-pressure gas coolers, intermediate receivers, flash gas bypass valves, and parallel compression. For hydrocarbon systems like R290 (Propane / A3), candidates must know exact charge limits per ÖNORM EN 378, ATEX zone classifications, leak ventilation requirements, and spark-free component selection.

How does this practice question bank adapt the Austrian Meisterprüfung?

The official Austrian master examination is administered in German before a WKO examination board through practical tasks, written engineering calculations, and oral commission defense dialogues. This practice question bank provides 100 rigorous English-language multiple-choice questions designed to test theoretical principles, mathematical formulas, and regulatory mandates while preserving authentic Austrian German technical terminology (e.g., h,log(p)-Diagramm, Mollier h,x-Diagramm, Überhitzung, Unterkühlung, Kälteleistungszahl, and ÖNORM standards).