Thermodynamic Cycles and Applications

Key Takeaways

  • The Carnot cycle has the maximum possible efficiency for a heat engine: η = 1 - TL/TH (temperatures in Kelvin).
  • The Rankine cycle is the basis for steam power plants: pump → boiler → turbine → condenser.
  • The Otto cycle models gasoline engines: η = 1 - 1/r^(k-1), where r is the compression ratio.
  • The Diesel cycle models diesel engines: higher compression ratio = higher efficiency than Otto.
  • Refrigeration cycles reverse the heat engine — COP = QL/W (cooling) or QH/W (heating).
  • Psychrometrics deals with air-water vapor mixtures: relative humidity, wet bulb temperature, and dew point.
Last updated: March 2026

Thermodynamic Cycles and Applications

Carnot Cycle (Theoretical Maximum)

The Carnot cycle consists of two isothermal and two adiabatic (isentropic) processes.

Efficiency: ηCarnot=1TLTH\eta_{Carnot} = 1 - \frac{T_L}{T_H}

where TL and TH are the absolute temperatures (Kelvin) of the cold and hot reservoirs.

Key Point: No real heat engine can be more efficient than a Carnot engine operating between the same temperatures. The Carnot efficiency sets the upper bound.

Power Cycles

Rankine Cycle (Steam Power Plants)

Components: Pump → Boiler → Turbine → Condenser

ProcessComponentType
1→2PumpIsentropic compression (liquid)
2→3BoilerConstant pressure heat addition
3→4TurbineIsentropic expansion
4→1CondenserConstant pressure heat rejection

Efficiency: η=WnetQin=(h3h4)(h2h1)h3h2\eta = \frac{W_{net}}{Q_{in}} = \frac{(h_3 - h_4) - (h_2 - h_1)}{h_3 - h_2}

Improvements: Superheating, reheating, regeneration (feedwater heating)

Otto Cycle (Gasoline Engines)

Ideal processes: Two isentropic + two isochoric (constant volume)

Efficiency: ηOtto=11rk1\eta_{Otto} = 1 - \frac{1}{r^{k-1}}

where r = V₁/V₂ = compression ratio, k = specific heat ratio (1.4 for air)

Example: r = 8, k = 1.4: η = 1 - 1/8^0.4 = 1 - 1/2.297 = 0.565 = 56.5%

Diesel Cycle

Ideal processes: Two isentropic + one isobaric (constant pressure) + one isochoric

ηDiesel=11rk1rck1k(rc1)\eta_{Diesel} = 1 - \frac{1}{r^{k-1}} \cdot \frac{r_c^k - 1}{k(r_c - 1)}

where rc = cutoff ratio (V₃/V₂).

The Diesel cycle is more efficient than the Otto cycle at the same compression ratio, and diesel engines operate at higher compression ratios.

Brayton Cycle (Gas Turbines)

Components: Compressor → Combustor → Turbine

ηBrayton=11rp(k1)/k\eta_{Brayton} = 1 - \frac{1}{r_p^{(k-1)/k}}

where rp = P₂/P₁ = pressure ratio.

Refrigeration Cycles

Vapor-Compression Refrigeration

Components: Compressor → Condenser → Expansion valve → Evaporator

ProcessComponentType
1→2CompressorIsentropic compression
2→3CondenserConstant pressure heat rejection
3→4Expansion valveThrottling (h₃ = h₄)
4→1EvaporatorConstant pressure heat absorption

Coefficient of Performance (COP)

Refrigerator (cooling): COPR=QLWnet=h1h4h2h1COP_R = \frac{Q_L}{W_{net}} = \frac{h_1 - h_4}{h_2 - h_1}

Heat Pump (heating): COPHP=QHWnet=COPR+1COP_{HP} = \frac{Q_H}{W_{net}} = COP_R + 1

Carnot COP: COPR,Carnot=TLTHTLCOP_{R,Carnot} = \frac{T_L}{T_H - T_L}

Combustion

Complete Combustion of Hydrocarbons

CxHy+(x+y/4)O2xCO2+(y/2)H2OC_x H_y + (x + y/4)O_2 \rightarrow xCO_2 + (y/2)H_2O

Air-fuel ratio: AFR = mass of air / mass of fuel

  • Stoichiometric AFR for gasoline ≈ 14.7:1
  • Lean mixture: excess air (AFR > stoichiometric)
  • Rich mixture: excess fuel (AFR < stoichiometric)

Combustion Products

  • Complete: CO₂ and H₂O
  • Incomplete: includes CO, unburned hydrocarbons
  • NOx: formed at high temperatures
  • Particulates: soot, ash

Psychrometrics (Air-Water Vapor Mixtures)

Key Properties

PropertyDefinition
Dry-bulb temperatureActual air temperature (regular thermometer)
Wet-bulb temperatureTemperature from evaporative cooling
Dew pointTemperature at which condensation begins
Relative humidity (φ)Pv/Psat × 100%
Humidity ratio (ω)Mass of water vapor per mass of dry air
Specific humiditySame as humidity ratio
Enthalpyh ≈ cpT + ω·hg

ω=0.622PvPatmPv\omega = 0.622 \frac{P_v}{P_{atm} - P_v}

Psychrometric Chart

Plots humidity ratio vs. dry-bulb temperature. Lines for:

  • Constant relative humidity (curves)
  • Constant wet-bulb (diagonal lines)
  • Constant enthalpy (approximately parallel to wet-bulb lines)
  • Constant specific volume (steep diagonal lines)
Test Your Knowledge

A Carnot heat engine operates between 600 K (hot) and 300 K (cold). What is its maximum efficiency?

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Test Your Knowledge

An Otto cycle has a compression ratio of 10 and k = 1.4. What is the ideal thermal efficiency?

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Test Your Knowledge

In a vapor-compression refrigeration cycle, the expansion valve process is best described as:

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Test Your Knowledge

The COP of a Carnot refrigerator operating between 250 K (cold) and 300 K (hot) is:

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Test Your Knowledge

Air at 20°C has a relative humidity of 60% and the saturation pressure at 20°C is 2.338 kPa. What is the partial pressure of water vapor?

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