AC Circuits and Three-Phase Power

Key Takeaways

  • AC voltage: v(t) = Vm sin(ωt + φ), where Vm is peak voltage, ω = 2πf, and φ is phase angle.
  • RMS (root mean square) values: Vrms = Vm/√2 ≈ 0.707Vm; RMS is used for power calculations.
  • Impedance Z = R + jX combines resistance and reactance; |Z| = √(R² + X²), angle = arctan(X/R).
  • Capacitive reactance XC = 1/(ωC); inductive reactance XL = ωL.
  • Power factor = cos(φ) = P/S, where P is real power (W), S is apparent power (VA), Q is reactive power (VAR).
  • Three-phase power: P = √3 VL IL cos(φ) for balanced loads.
Last updated: March 2026

AC Circuits and Three-Phase Power

AC Fundamentals

Sinusoidal Waveform

v(t)=Vmsin(ωt+ϕ)v(t) = V_m \sin(\omega t + \phi)

where:

  • Vm = peak (maximum) voltage
  • ω = 2πf = angular frequency (rad/s)
  • f = frequency (Hz); standard in US: 60 Hz
  • φ = phase angle

RMS Values

Vrms=Vm20.707VmV_{rms} = \frac{V_m}{\sqrt{2}} \approx 0.707 V_m

RMS values are used for power calculations. When someone says "120 V" for household power, they mean 120 V rms (peak is about 170 V).

Impedance

Impedance Z is the AC equivalent of resistance: Z=R+jXZ = R + jX

where:

  • R = resistance (Ω) — real part
  • X = reactance (Ω) — imaginary part
  • j = √(-1)
ElementImpedanceReactanceCurrent leads/lags
ResistorZ = RX = 0In phase
CapacitorZ = -j/(ωC)XC = -1/(ωC)Current LEADS voltage by 90°
InductorZ = jωLXL = ωLCurrent LAGS voltage by 90°

Mnemonic: ELI the ICE man — In an inductor (L), voltage (E) leads current (I). In a capacitor (C), current (I) leads voltage (E).

Series RLC Circuit

Z=R+j(ωL1ωC)Z = R + j\left(\omega L - \frac{1}{\omega C}\right)

Z=R2+(XLXC)2|Z| = \sqrt{R^2 + (X_L - X_C)^2}

Resonance (XL = XC): f0=12πLCf_0 = \frac{1}{2\pi\sqrt{LC}}

At resonance: Z = R (purely resistive), current is maximum.

AC Power

Power Triangle

TypeSymbolFormulaUnit
Real (Active) PowerPVI cos(φ) = I²RWatts (W)
Reactive PowerQVI sin(φ) = I²XVAR
Apparent PowerSVI = I²Z

S=P+jQS = P + jQ S=P2+Q2|S| = \sqrt{P^2 + Q^2}

Power Factor

PF=cos(ϕ)=PS=RZPF = \cos(\phi) = \frac{P}{S} = \frac{R}{|Z|}

PFCircuitCorrection
1.0 (unity)Purely resistiveNone needed
< 1 (lagging)Inductive loadAdd capacitors
< 1 (leading)Capacitive loadAdd inductors

Most industrial loads are inductive (motors, transformers) with lagging power factor. Capacitors are added to improve (correct) power factor toward unity, reducing utility penalties.

Three-Phase Power

Balanced Three-Phase Systems

ConfigurationLine-Phase Relationship
Y (Wye/Star)VL = √3 Vφ, IL = Iφ
Δ (Delta)VL = Vφ, IL = √3 Iφ

where:

  • VL = line-to-line voltage
  • Vφ = phase voltage
  • IL = line current
  • Iφ = phase current

Three-Phase Power (Balanced Load)

Ptotal=3VLILcos(ϕ)P_{total} = \sqrt{3} V_L I_L \cos(\phi) Stotal=3VLILS_{total} = \sqrt{3} V_L I_L

Motor Efficiency

η=PoutPin=PmechanicalPelectrical\eta = \frac{P_{out}}{P_{in}} = \frac{P_{mechanical}}{P_{electrical}}

Example: A 3-phase motor draws 10 A at 480 V with PF = 0.85 and efficiency = 90%. Output power?

Pin = √3 × 480 × 10 × 0.85 = 7,064 W Pout = 0.90 × 7,064 = 6,358 W ≈ 8.5 hp (÷ 745.7)

Measuring Devices

DeviceMeasuresConnection
VoltmeterVoltage across elementIn parallel (high internal R)
AmmeterCurrent through elementIn series (low internal R)
WattmeterPower consumedVoltage coil in parallel, current coil in series
OhmmeterResistanceCircuit must be de-energized
Test Your Knowledge

A series RLC circuit has R = 30 Ω, XL = 40 Ω, and XC = 10 Ω. What is the impedance magnitude?

A
B
C
D
Test Your Knowledge

A load draws 5 kW of real power and 4 kVAR of reactive power. What is the power factor?

A
B
C
D
Test Your Knowledge

In a balanced 3-phase wye-connected system with line voltage VL = 480 V, what is the phase voltage?

A
B
C
D
Test Your Knowledge

At resonance in a series RLC circuit, which statement is true?

A
B
C
D