Stress Transformation and Material Failure

Key Takeaways

  • Mohr's circle graphically represents the state of stress at a point and finds principal stresses and maximum shear stress.
  • Principal stresses σ₁ and σ₂ are the maximum and minimum normal stresses — shear stress is zero on principal planes.
  • Maximum shear stress τmax = (σ₁ - σ₂)/2, occurring on planes at 45° to the principal planes.
  • Von Mises criterion (ductile materials): failure when σ_VM = √(σ₁² - σ₁σ₂ + σ₂²) ≥ σy.
  • Euler buckling load Pcr = π²EI/(KL)² determines when slender columns fail by elastic instability.
  • Factor of safety against buckling: FS = Pcr/P; effective length factor K depends on end conditions.
Last updated: March 2026

Stress Transformation and Material Failure

Plane Stress Transformation

For a 2D stress state (σx, σy, τxy), the stresses on a plane at angle θ:

σx=σx+σy2+σxσy2cos2θ+τxysin2θ\sigma_{x'} = \frac{\sigma_x + \sigma_y}{2} + \frac{\sigma_x - \sigma_y}{2}\cos 2\theta + \tau_{xy}\sin 2\theta

τxy=σxσy2sin2θ+τxycos2θ\tau_{x'y'} = -\frac{\sigma_x - \sigma_y}{2}\sin 2\theta + \tau_{xy}\cos 2\theta

Principal Stresses

σ1,2=σx+σy2±(σxσy2)2+τxy2\sigma_{1,2} = \frac{\sigma_x + \sigma_y}{2} \pm \sqrt{\left(\frac{\sigma_x - \sigma_y}{2}\right)^2 + \tau_{xy}^2}

Principal plane angle: tan2θp=2τxyσxσy\tan 2\theta_p = \frac{2\tau_{xy}}{\sigma_x - \sigma_y}

On principal planes, shear stress is zero.

Maximum Shear Stress

τmax=(σxσy2)2+τxy2=σ1σ22\tau_{max} = \sqrt{\left(\frac{\sigma_x - \sigma_y}{2}\right)^2 + \tau_{xy}^2} = \frac{\sigma_1 - \sigma_2}{2}

Maximum shear stress planes are at 45° to the principal planes.

Mohr's Circle

Mohr's circle is a graphical method for stress transformation:

Construction:

  1. Plot point A: (σx, τxy) — note: some conventions use (σx, -τxy)
  2. Plot point B: (σy, -τxy)
  3. Center C is at ((σx + σy)/2, 0)
  4. Radius R = √((σx - σy)/2)² + τxy²)
  5. Principal stresses: σ₁ = C + R, σ₂ = C - R
  6. Maximum shear stress: τmax = R

Failure Theories

Maximum Shear Stress (Tresca) — Ductile Materials

Failure when: τmax ≥ σy/2

Or equivalently: |σ₁ - σ₂| ≥ σy

Distortion Energy (von Mises) — Ductile Materials

Failure when: σVM=σ12σ1σ2+σ22σy\sigma_{VM} = \sqrt{\sigma_1^2 - \sigma_1\sigma_2 + \sigma_2^2} \geq \sigma_y

For general 3D stress: σVM=12(σ1σ2)2+(σ2σ3)2+(σ3σ1)2\sigma_{VM} = \frac{1}{\sqrt{2}}\sqrt{(\sigma_1-\sigma_2)^2 + (\sigma_2-\sigma_3)^2 + (\sigma_3-\sigma_1)^2}

Von Mises is more accurate than Tresca for ductile materials and is used more often in practice.

Maximum Normal Stress — Brittle Materials

Failure when: σ₁ ≥ σut (ultimate tensile) or |σ₂| ≥ σuc (ultimate compressive)

Column Buckling (Euler's Formula)

Critical buckling load for long, slender columns:

Pcr=π2EI(KL)2P_{cr} = \frac{\pi^2 EI}{(KL)^2}

Or in terms of critical stress: σcr=π2E(KL/r)2\sigma_{cr} = \frac{\pi^2 E}{(KL/r)^2}

where KL/r is the slenderness ratio and r = √(I/A) is the radius of gyration.

Effective Length Factor K

End ConditionsKPcr relative
Fixed-Fixed0.54× higher
Fixed-Pinned0.72× higher
Pinned-Pinned1.0Reference
Fixed-Free (cantilever)2.04× lower

Always use the smallest I (about the weakest axis) for buckling calculations — the column buckles about its weakest axis.

Stress Concentrations

Near geometric discontinuities (holes, notches, fillets), stress is amplified:

σmax=Ktσnominal\sigma_{max} = K_t \cdot \sigma_{nominal}

where Kt is the stress concentration factor (always ≥ 1).

For a small circular hole in a wide plate under tension: Kt ≈ 3.

Fatigue and Creep

PhenomenonDescription
FatigueFailure under cyclic loading at stress below ultimate strength
Endurance limitStress below which fatigue failure does not occur (for steel ≈ 0.5σu)
CreepTime-dependent permanent deformation under sustained load at high temperature
Test Your Knowledge

A stress element has σx = 80 MPa, σy = -40 MPa, τxy = 30 MPa. What is the maximum shear stress?

A
B
C
D
Test Your Knowledge

A column is 3 m long, pinned at both ends, with E = 200 GPa and I = 5 × 10⁶ mm⁴. What is the critical buckling load?

A
B
C
D