Heat Transfer: Conduction, Convection, and Radiation

Key Takeaways

  • Conduction: heat transfer through a solid or stationary fluid — Q = -kA(dT/dx) (Fourier's Law).
  • Convection: heat transfer between a surface and a moving fluid — Q = hA(Ts - T∞) (Newton's Law of Cooling).
  • Radiation: heat transfer by electromagnetic waves — Q = εσA(T₁⁴ - T₂⁴) (Stefan-Boltzmann Law).
  • Thermal resistance: R = ΔT/Q̇ — resistances add in series (like electrical resistors).
  • For a plane wall: R = L/(kA); for convection: R = 1/(hA).
  • Heat exchangers transfer heat between two fluids: use LMTD or effectiveness-NTU methods.
Last updated: March 2026

Heat Transfer: Conduction, Convection, and Radiation

Conduction

Fourier's Law: Q˙=kAdTdx\dot{Q} = -kA\frac{dT}{dx}

For a plane wall (steady state, 1D): Q˙=kA(T1T2)L\dot{Q} = \frac{kA(T_1 - T_2)}{L}

Thermal Resistance (conduction through plane wall): Rcond=LkAR_{cond} = \frac{L}{kA}

Composite Walls (Series Resistance)

For walls in series: Q˙=T1TnRi=ΔToverallRtotal\dot{Q} = \frac{T_1 - T_n}{\sum R_i} = \frac{\Delta T_{overall}}{R_{total}}

Cylindrical Wall (Radial Conduction)

Q˙=2πkL(T1T2)ln(r2/r1)\dot{Q} = \frac{2\pi kL(T_1 - T_2)}{\ln(r_2/r_1)}

Rcyl=ln(r2/r1)2πkLR_{cyl} = \frac{\ln(r_2/r_1)}{2\pi kL}

Thermal Conductivity Values

Materialk (W/m·K)
Copper401
Aluminum237
Carbon Steel50
Stainless Steel16
Concrete1.0
Glass0.8
Wood0.15
Fiberglass insulation0.04
Air (still)0.026

Convection

Newton's Law of Cooling: Q˙=hA(TsT)\dot{Q} = hA(T_s - T_\infty)

Thermal Resistance (convection): Rconv=1hAR_{conv} = \frac{1}{hA}

Convection Coefficient (h) Ranges

Typeh (W/m²·K)
Natural convection (air)5-25
Forced convection (air)25-250
Natural convection (water)50-1,000
Forced convection (water)100-20,000
Boiling water2,500-25,000
Condensing steam5,000-100,000

Dimensionless Numbers for Convection

NumberFormulaMeaning
Nusselt (Nu)hL/kConvection / Conduction
Prandtl (Pr)ν/α = cpμ/kMomentum / Thermal diffusivity
Grashof (Gr)gβΔTL³/ν²Buoyancy / Viscous forces
Rayleigh (Ra)Gr × PrNatural convection driving force

Radiation

Stefan-Boltzmann Law: Q˙=ϵσA(Ts4Tsurr4)\dot{Q} = \epsilon \sigma A (T_s^4 - T_{surr}^4)

where:

  • ε = emissivity (0 to 1; 1 for a blackbody)
  • σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/(m²·K⁴)
  • T in Kelvin (absolute temperature!)

Radiation between two surfaces: Q˙12=σ(T14T24)1ϵ1ϵ1A1+1A1F12+1ϵ2ϵ2A2\dot{Q}_{1 \to 2} = \frac{\sigma(T_1^4 - T_2^4)}{\frac{1-\epsilon_1}{\epsilon_1 A_1} + \frac{1}{A_1 F_{12}} + \frac{1-\epsilon_2}{\epsilon_2 A_2}}

where F₁₂ is the view factor (fraction of radiation leaving surface 1 that reaches surface 2).

Key Radiation Properties

  • Emissivity (ε): Ratio of emitted radiation to blackbody radiation
  • Absorptivity (α): Fraction of incident radiation absorbed
  • Reflectivity (ρ): Fraction reflected
  • Transmissivity (τ): Fraction transmitted
  • Kirchhoff's Law: α = ε at thermal equilibrium

Overall Heat Transfer Coefficient (U)

For a composite wall with convection on both sides:

1UA=1h1A1+LkA+1h2A2\frac{1}{UA} = \frac{1}{h_1 A_1} + \frac{L}{kA} + \frac{1}{h_2 A_2}

Q˙=UAΔT\dot{Q} = UA \cdot \Delta T

Heat Exchangers — LMTD Method

Q˙=UALMTD\dot{Q} = UA \cdot LMTD

Log Mean Temperature Difference: LMTD=ΔT1ΔT2ln(ΔT1/ΔT2)LMTD = \frac{\Delta T_1 - \Delta T_2}{\ln(\Delta T_1 / \Delta T_2)}

Counterflow heat exchangers are more effective than parallel flow for the same surface area.

Test Your Knowledge

A wall is 0.2 m thick with k = 1.5 W/(m·K). If the surface temperatures are 200°C and 50°C, what is the heat flux (per unit area)?

A
B
C
D
Test Your Knowledge

A blackbody (ε = 1) at 500 K radiates heat. If its temperature doubles to 1,000 K, the radiated power:

A
B
C
D
Test Your Knowledge

Which heat exchanger configuration is more thermally effective?

A
B
C
D