Key Takeaways

  • Memorize key formulas: Area of triangle = 1/2 base times height; Area of circle = pi times r^2.
  • The sum of angles in a triangle is always 180 degrees; in a quadrilateral, 360 degrees.
  • The Pythagorean theorem (a^2 + b^2 = c^2) applies only to right triangles.
  • Know the special right triangles: 30-60-90 (1, sqrt(3), 2) and 45-45-90 (1, 1, sqrt(2)).
  • For volume problems, multiply the base area by height for prisms and cylinders.
Last updated: January 2026

Geometry

MK Subtest: Geometry questions make up about 30-35% of the Mathematics Knowledge section. Memorize the key formulas!

Angles

Types of Angles

TypeDegreesExample
AcuteLess than 90°45°
RightExactly 90°90°
ObtuseBetween 90° and 180°120°
StraightExactly 180°180°

Angle Relationships

RelationshipProperty
ComplementaryTwo angles that sum to 90°
SupplementaryTwo angles that sum to 180°
VerticalOpposite angles formed by intersecting lines (equal)

Worked Example: Complementary Angles

Problem: Two angles are complementary. One angle is 35°. What is the other?

Solution: 90°35°=55°90° - 35° = 55°

Triangles

Triangle Angle Sum

The sum of all angles in a triangle is always 180°.

Types of Triangles

By SidesDescriptionBy AnglesDescription
EquilateralAll sides equalAcuteAll angles < 90°
IsoscelesTwo sides equalRightOne angle = 90°
ScaleneNo sides equalObtuseOne angle > 90°

The Pythagorean Theorem

For right triangles only:

a2+b2=c2a^2 + b^2 = c^2

where cc is the hypotenuse (longest side, opposite the right angle)

Common Pythagorean Triples (Memorize These!)

TripleMultiple Examples
3, 4, 56-8-10, 9-12-15, 12-16-20
5, 12, 1310-24-26
8, 15, 17
7, 24, 25

Worked Example: Pythagorean Theorem

Problem: A right triangle has legs of 6 and 8. Find the hypotenuse.

Solution: Recognize 6-8-? is a multiple of 3-4-5 (multiplied by 2):

  • If 3-4-5, then 6-8-10

Or calculate: c2=62+82=36+64=100c^2 = 6^2 + 8^2 = 36 + 64 = 100, so c=10c = 10

Special Right Triangles

45-45-90 Triangle (Isosceles Right):

  • Sides in ratio: 1:1:21 : 1 : \sqrt{2}
  • If legs = 5, hypotenuse = 525\sqrt{2}

30-60-90 Triangle:

  • Sides in ratio: 1:3:21 : \sqrt{3} : 2
  • Opposite 30°: shortest side (1)
  • Opposite 60°: middle side (3\sqrt{3})
  • Opposite 90°: longest side (2)

Triangle Area

Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}

Worked Example: Triangle Area

Problem: Find the area of a triangle with base 12 and height 8.

Solution: Area=12×12×8=48\text{Area} = \frac{1}{2} \times 12 \times 8 = 48 square units

Quadrilaterals

Quadrilateral Properties

ShapePropertiesArea Formula
Square4 equal sides, 4 right angless2s^2
RectangleOpposite sides equal, 4 right anglesl×wl \times w
ParallelogramOpposite sides parallel and equalb×hb \times h
TrapezoidOne pair of parallel sides12(b1+b2)×h\frac{1}{2}(b_1 + b_2) \times h

Worked Example: Trapezoid Area

Problem: A trapezoid has parallel sides of 8 and 12, with height 5. Find the area.

Solution: Area=12(8+12)×5=12(20)×5=50\text{Area} = \frac{1}{2}(8 + 12) \times 5 = \frac{1}{2}(20) \times 5 = 50 square units

Circles

Circle Formulas

MeasurementFormula
CircumferenceC=2πr=πdC = 2\pi r = \pi d
AreaA=πr2A = \pi r^2

Approximation: Use π3.14\pi \approx 3.14 or 227\frac{22}{7} for calculations

Key Terms

  • Radius (r): Distance from center to edge
  • Diameter (d): Distance across through center (d=2rd = 2r)
  • Chord: Line segment connecting two points on the circle
  • Arc: Portion of the circumference

Worked Example: Circle Calculations

Problem: A circle has radius 7. Find its circumference and area.

Solution:

  • Circumference: C=2π(7)=14π44C = 2\pi(7) = 14\pi \approx 44 units
  • Area: A=π(7)2=49π154A = \pi(7)^2 = 49\pi \approx 154 square units

Volume and Surface Area

3D Shape Formulas

ShapeVolumeSurface Area
Cubes3s^36s26s^2
Rectangular Prisml×w×hl \times w \times h2(lw+lh+wh)2(lw + lh + wh)
Cylinderπr2h\pi r^2 h2πr2+2πrh2\pi r^2 + 2\pi rh
Sphere43πr3\frac{4}{3}\pi r^34πr24\pi r^2
Cone13πr2h\frac{1}{3}\pi r^2 hπr2+πrs\pi r^2 + \pi r s

Worked Example: Cylinder Volume

Problem: Find the volume of a cylinder with radius 3 and height 10.

Solution: V=πr2h=π(3)2(10)=90π283V = \pi r^2 h = \pi (3)^2 (10) = 90\pi \approx 283 cubic units

Test Your Knowledge

A right triangle has legs of 5 and 12. What is the length of the hypotenuse?

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Test Your Knowledge

What is the area of a circle with radius 5? (Use pi = 3.14)

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Test Your Knowledge

Two angles are supplementary. If one angle measures 115 degrees, what is the measure of the other angle?

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Test Your Knowledge

A rectangular box has dimensions 4 x 5 x 6. What is its volume?

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