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5.6 Function Notation, Composition & Transformations

Key Takeaways

  • Interpret function notation f(x) as an input-output mapping rule: evaluate f at numerical constants and algebraic expressions by substituting the entire argument into every occurrence of x.

  • Evaluate composite functions (f ∘ g)(x) = f(g(x)) from the inside out: evaluate inner function g(x) first, then feed that output directly into outer function f.

  • Master rigid translations: f(x) + c shifts UP by c, f(x) - c shifts DOWN by c, f(x - c) shifts RIGHT by c, and f(x + c) shifts LEFT by c.

  • Master non-rigid stretches, compressions, and reflections: a · f(x) scales vertically (and reflects across x-axis if a < 0); f(cx) scales horizontally by factor 1/c (and reflects across y-axis if c < 0).

  • Track coordinate transformations using point mapping: under g(x) = a · f(c(x - h)) + k, any original point (x, y) on f transforms to (x/c + h, a · y + k).

Last updated: August 2026

Function Notation, Composition & Transformations

Function notation and transformations are fundamental to advanced mathematics on the Digital SAT. Questions assess evaluating functions with algebraic inputs, computing nested composite functions (f∘g)(x)(f \circ g)(x), and predicting how algebraic modifications alter graphs geometrically.


1. Function Notation Fluency & Algebraic Evaluation

Function notation f(x)f(x) reads "ff of xx" and represents the output value produced when input xx is processed by the function rule.

The "Empty Box" Substitution Method:

To avoid algebraic errors when evaluating f(expression)f(\text{expression}), replace every instance of the variable with parenthesized empty boxes before inserting the input:

If f(x)=2x2−5x+3f(x) = 2x^2 - 5x + 3:

f(□)=2(□)2−5(□)+3f(\Box) = 2(\Box)^2 - 5(\Box) + 3
  • Numerical Input: f(−3)=2(−3)2−5(−3)+3=2(9)+15+3=36f(-3) = 2(-3)^2 - 5(-3) + 3 = 2(9) + 15 + 3 = 36
  • Algebraic Input: f(2a−1)=2(2a−1)2−5(2a−1)+3f(2a - 1) = 2(2a - 1)^2 - 5(2a - 1) + 3 =2(4a2−4a+1)−10a+5+3=8a2−8a+2−10a+8=8a2−18a+10= 2(4a^2 - 4a + 1) - 10a + 5 + 3 = 8a^2 - 8a + 2 - 10a + 8 = 8a^2 - 18a + 10
+-----------------------------------------------------------------------------+
|                        FUNCTION INPUT SUBSTITUTION                          |
|                                                                             |
|   Given:  f(x) = x^2 - 3x                                                   |
|                                                                             |
|   Evaluate f(x + 2):                                                        |
|   Step 1: Replace x with parentheses:   (x + 2)^2 - 3(x + 2)                |
|   Step 2: Expand binomial square:       x^2 + 4x + 4 - 3x - 6               |
|   Step 3: Combine like terms:           x^2 + x - 2                         |
+-----------------------------------------------------------------------------+

2. Composite Functions: (f∘g)(x)=f(g(x))(f \circ g)(x) = f(g(x))

A composite function applies one function to the output of another. The notation (f∘g)(x)(f \circ g)(x) is defined as f(g(x))f(g(x)).

+-----------------------------------------------------------------------------+
|                      COMPOSITE FUNCTION FLOWCHART                           |
|                                                                             |
|               Input (x)  ====>  [ INNER FUNCTION: g(x) ]                    |
|                                                │                            |
|                                                v Output g(x)                |
|                                 [ OUTER FUNCTION: f( ) ]                    |
|                                                │                            |
|                                                v                            |
|                                         Final Output: f(g(x))               |
+-----------------------------------------------------------------------------+

Key Principles of Composition:

  1. Work Inside Out: Always evaluate the inner function g(x)g(x) first. Then use that result as the input for the outer function ff.
  2. Non-Commutative: In general, f(g(x))≠g(f(x))f(g(x)) \ne g(f(x)). Order of operations is paramount.

Example with Tabular Data:

xxf(x)f(x)g(x)g(x)
114433
221155
332211
553322
  • To find f(g(2))f(g(2)): First find g(2)=5g(2) = 5. Then find f(5)=3f(5) = 3. Thus, f(g(2))=3f(g(2)) = 3.
  • To find g(f(2))g(f(2)): First find f(2)=1f(2) = 1. Then find g(1)=3g(1) = 3. Thus, g(f(2))=3g(f(2)) = 3.

3. Master Transformation Rules

Transformations modify the position, size, or orientation of a parent graph y=f(x)y = f(x).

Transformation FormOperation TypeDirection / EffectCoordinate Mapping (x,y)→(x, y) \to
y=f(x)+cy = f(x) + cVertical ShiftShift UP by cc units(x,y+c)(x, y + c)
y=f(x)−cy = f(x) - cVertical ShiftShift DOWN by cc units(x,y−c)(x, y - c)
y=f(x−c)y = f(x - c)Horizontal ShiftShift RIGHT by cc units(x+c,y)(x + c, y)
y=f(x+c)y = f(x + c)Horizontal ShiftShift LEFT by cc units(x−c,y)(x - c, y)
y=a⋅f(x)  (a>1)y = a \cdot f(x) \; (a > 1)Vertical StretchStretch vertically by factor aa(x,a⋅y)(x, a \cdot y)
y=a⋅f(x)  (0<a<1)y = a \cdot f(x) \; (0 < a < 1)Vertical CompressCompress vertically by factor aa(x,a⋅y)(x, a \cdot y)
y=−f(x)y = -f(x)ReflectionReflect across xx-axis (flips upside down)(x,−y)(x, -y)
y=f(−x)y = f(-x)ReflectionReflect across yy-axis (flips left/right)(−x,y)(-x, y)
y=f(cx)  (c>1)y = f(c x) \; (c > 1)Horizontal CompressCompress horizontally by factor 1/c1/c(x/c,y)(x/c, y)
y=f(cx)  (0<c<1)y = f(c x) \; (0 < c < 1)Horizontal StretchStretch horizontally by factor 1/c1/c(x/c,y)(x/c, y)
+-----------------------------------------------------------------------------+
|                   HORIZONTAL VS. VERTICAL SHIFT RULES                       |
|                                                                             |
|   OUTSIDE MODIFICATION = VERTICAL (Direct):                                 |
|   f(x) + 4  ====>  UP 4 units           f(x) - 4  ====>  DOWN 4 units       |
|                                                                             |
|   INSIDE MODIFICATION = HORIZONTAL (Counter-Intuitive / Inverted):          |
|   f(x - 4)  ====>  RIGHT 4 units        f(x + 4)  ====>  LEFT 4 units       |
+-----------------------------------------------------------------------------+

Warning

The Horizontal Shift Sign Trap: Inside the function parentheses, operations behave in the opposite direction of their sign:

  • f(x−5)f(x - 5) moves the graph RIGHT +5+5 units.
  • f(x+5)f(x + 5) moves the graph LEFT −5-5 units.
  • To find where the new feature lands, set the interior expression equal to the original coordinate: x−5=0  ⟹  x=5x - 5 = 0 \implies x = 5.

4. Multi-Step Transformations & Point Mapping

When combining multiple transformations in the general form g(x)=a⋅f(c(x−h))+kg(x) = a \cdot f(c(x - h)) + k, use the Point Mapping Formula:

Original Point on f(x):(x,y)  ⟹  Transformed Point on g(x):(xc+h,  a⋅y+k)\text{Original Point on } f(x): (x, y) \implies \text{Transformed Point on } g(x): \left(\frac{x}{c} + h, \; a \cdot y + k\right)

Example Transformation Walkthrough:

Suppose y=f(x)y = f(x) has vertex (3,−4)(3, -4). What are the coordinates of the corresponding point on g(x)=−2f(x+4)+7g(x) = -2 f(x + 4) + 7?

  1. Horizontal transformation: x+4=3  ⟹  x=3−4=−1x + 4 = 3 \implies x = 3 - 4 = -1.
  2. Vertical transformation: ynew=−2(−4)+7=8+7=15y_{\text{new}} = -2(-4) + 7 = 8 + 7 = 15.
  3. New point on g(x)g(x) is (−1,15)(-1, 15).

5. Step-by-Step Worked SAT Exam Examples

Worked Example 1: Nested Composite Algebraic Evaluation

Problem: Given f(x)=3x−5f(x) = 3x - 5 and g(x)=x2+2xg(x) = x^2 + 2x, what is the value of g(f(3))−f(g(2))g(f(3)) - f(g(2))?

Step-by-Step Solution:

  1. Evaluate inner term f(3)f(3) for the first expression: f(3)=3(3)−5=9−5=4f(3) = 3(3) - 5 = 9 - 5 = 4
  2. Evaluate outer term g(4)g(4): g(4)=(4)2+2(4)=16+8=24  ⟹  g(f(3))=24g(4) = (4)^2 + 2(4) = 16 + 8 = 24 \implies g(f(3)) = 24
  3. Evaluate inner term g(2)g(2) for the second expression: g(2)=(2)2+2(2)=4+4=8g(2) = (2)^2 + 2(2) = 4 + 4 = 8
  4. Evaluate outer term f(8)f(8): f(8)=3(8)−5=24−5=19  ⟹  f(g(2))=19f(8) = 3(8) - 5 = 24 - 5 = 19 \implies f(g(2)) = 19
  5. Compute the difference: g(f(3))−f(g(2))=24−19=5g(f(3)) - f(g(2)) = 24 - 19 = 5

Worked Example 2: Determining Vertex Shift Under Transformation

Problem: The quadratic function f(x)=(x−6)2+8f(x) = (x - 6)^2 + 8 has a vertex at (6,8)(6, 8). If function hh is defined by h(x)=f(x+3)−5h(x) = f(x + 3) - 5, what is the minimum value of h(x)h(x) and at what value of xx does it occur?

Step-by-Step Solution:

  1. Analyze the horizontal shift: f(x+3)f(x + 3) shifts the graph 33 units to the left: xvertex=6−3=3x_{\text{vertex}} = 6 - 3 = 3.
  2. Analyze the vertical shift: −5- 5 shifts the graph 55 units down: yvertex=8−5=3y_{\text{vertex}} = 8 - 5 = 3.
  3. State the minimum: Since the parabola opens upward (a=1>0a = 1 > 0), the minimum value of h(x)h(x) is 33, occurring at x=3x = 3.

6. Desmos Testing Strategies for Functions & Transformations

Tip

Defining Functions and Nested Compositions in Desmos: Desmos supports direct function definition and composite evaluation:

  1. Type f(x) = 2x^2 - 3x + 1 on line 1.
  2. Type g(x) = 3x - 2 on line 2.
  3. Type f(g(2)) - g(f(2)) on line 3. Desmos will calculate the final numeric answer directly without manual substitution.

Note

Visualizing Graph Transformations: To check a transformation like g(x)=−2f(x+4)+7g(x) = -2f(x + 4) + 7:

  1. Plot the parent function f(x) = (x - 3)^2 - 4.
  2. On line 2, plot g(x) = -2 * f(x + 4) + 7.
  3. Click the vertex of both curves to confirm that (3,−4)(3, -4) transformed into (−1,15)(-1, 15).
Test Your Knowledge

Given f(x)=2x2−3x+1f(x) = 2x^2 - 3x + 1 and g(x)=3x−2g(x) = 3x - 2, what is the value of f(g(2))−g(f(2))f(g(2)) - g(f(2))?

A

−8-8

B

1010

C

1414

D

2828

Test Your Knowledge

The graph of y=f(x)y = f(x) contains the point (−3,8)(-3, 8). If the function gg is defined by g(x)=4f(x+5)−6g(x) = 4f(x + 5) - 6, which point must lie on the graph of y=g(x)y = g(x)?

A

(−8,26)(-8, 26)

B

(2,26)(2, 26)

C

(−8,38)(-8, 38)

D

(2,2)(2, 2)

Test Your Knowledge

The function f(x)f(x) has a minimum value of −7-7 at x=4x = 4. If the function h(x)h(x) is defined by h(x)=−3f(x−2)+5h(x) = -3 f(x - 2) + 5, what is the maximum value of h(x)h(x) and at what xx-value does it occur?

A

Minimum value of −16-16 at x=2x = 2

B

Maximum value of 2626 at x=2x = 2

C

Minimum value of −26-26 at x=6x = 6

D

Maximum value of 2626 at x=6x = 6

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