2.3 Polynomial and Rational Functions
Key Takeaways
- A quadratic with negative leading coefficient opens downward; its maximum occurs at x = -b/(2a).
- For f(x) = -x² + 4x + 1, the vertex is at x = 2 and the maximum value is 5.
- Canceling (x - 2) in (x² - 4)/(x - 2) yields x + 2 for x ≠ 2, producing a hole at (2, 4) on the line y = x + 2.
- Vertical asymptotes occur at non-cancelled zeros of the denominator; holes occur at cancelled common factors.
- Praxis 5165 tests whether candidates preserve domain restrictions when simplifying rational expressions.
Why This Section Matters
Polynomial and rational functions anchor a large share of Praxis 5165 function items. ETS tests factoring, zeros, vertex analysis, end behavior, vertical asymptotes, horizontal asymptotes, and removable discontinuities (holes). Teaching-scenario stems frequently ask how to respond when a student graphs a simplified rational expression without marking an excluded value.
Polynomial Basics
A polynomial uses nonnegative integer exponents and finitely many terms. Key skills:
- Factoring to find zeros
- Vertex form for quadratics: f(x) = a(x - h)² + k
- End behavior from the leading term
| Leading Term | End Behavior (x → ±∞) |
|---|---|
| +x^n, n even | Both ends go up |
| -x^n, n even | Both ends go down |
| +x^n, n odd | Left down, right up |
| -x^n, n odd | Left up, right down |
Worked Example: Maximum of a Quadratic
Find the maximum of f(x) = -x² + 4x + 1.
The leading coefficient is negative, so the parabola opens downward and has a maximum at the vertex.
x = -b/(2a) = -4/(2(-1)) = 2
f(2) = -(4) + 8 + 1 = 5
The maximum value is 5 at x = 2. Praxis distractors often give 2 (the x-coordinate of the vertex) instead of 5 (the maximum value).
Zeros and Multiplicity
Solving x² - 5x + 6 = 0 factors to (x - 2)(x - 3) = 0, giving zeros 2 and 3.
If (x - 3)² is a factor, x = 3 is a zero with multiplicity 2 — the graph touches the x-axis at 3 but does not cross it.
Rational Functions: Structure
A rational function has the form R(x) = p(x)/q(x) where q(x) ≠ 0.
Domain
Exclude any x that makes q(x) = 0. For (x + 1)/(x - 4), the domain is all real numbers except x = 4.
Vertical Asymptotes vs. Holes
| Feature | Algebraic Signal | Graph |
|---|---|---|
| Vertical asymptote | Zero of denominator after cancellation | Curve approaches ±∞ |
| Hole (removable) | Common factor cancels | Open circle on an otherwise smooth curve |
| Horizontal asymptote | Compare degrees of p and q | End behavior levels off |
Worked Example: Hole on a Line
Simplify (x² - 4)/(x - 2) for x ≠ 2.
Factor numerator: (x - 2)(x + 2)
Cancel (x - 2): x + 2, with x ≠ 2
The graph matches y = x + 2 with a hole at (2, 4) because the original expression is undefined at x = 2.
Best teacher response: "For all x ≠ 2, the expressions are equivalent, so the graph follows the line y = x + 2 with a missing point — a hole — at (2, 4)."
Worked Example: Asymptotes
For f(x) = (2x + 1)/(x - 3):
- Vertical asymptote: x = 3 (denominator zero, no cancellation)
- Horizontal asymptote: degrees are equal (both 1), so y = 2/1 = 2 (ratio of leading coefficients)
Polynomial Division (When It Appears)
Long or synthetic division can rewrite improper rationals, but Praxis 5165 emphasizes factoring and interpretation over lengthy division drills. Know that division can reveal hidden linear behavior after cancellation.
Modeling and Graph Features
Polynomial models may describe projectile motion (quadratic), revenue curves, or volume constraints. Rational models often appear in average-cost or concentration settings where a variable appears in the denominator.
When sketching mentally, combine:
- Intercepts from zeros of numerator (watch domain)
- Asymptotes from uncancelled denominator zeros
- Holes from cancelled factors
Common Praxis Traps
- Dropping x ≠ 2 after simplifying (x² - 4)/(x - 2)
- Calling x = 2 a vertical asymptote when it is a hole
- Reporting vertex x instead of maximum/minimum value
- Assuming a rational graph cannot be linear away from discontinuities
Section Takeaways
Factor first, track excluded inputs, and connect algebraic simplification to holes and asymptotes on the graph. Drill vertex-maximum and rational-interpretation items on /practice/praxis-math.
Factoring Strategies for Praxis Items
When a polynomial is not obviously factorable, try these moves in order:
- Greatest common factor — factor out shared monomials first
- Trinomials — look for two numbers that multiply to ac and add to b in ax² + bx + c
- Difference of squares — a² - b² = (a - b)(a + b)
- Sum/difference of cubes — a³ ± b³ patterns appear occasionally
Worked Example: Finding Zeros
Find all real zeros of f(x) = x³ - 4x.
Factor: x(x² - 4) = x(x - 2)(x + 2).
Zeros: x = 0, 2, -2. The graph crosses the x-axis at each simple zero.
Graph Sketch Reasoning Without a Calculator
For f(x) = (x - 1)/(x + 2):
- Vertical asymptote at x = -2
- Horizontal asymptote y = 1 (equal degrees)
- x-intercept where numerator is zero: x = 1
- y-intercept at f(0) = -½
Listing these four features often suffices to eliminate three of four graph choices on Praxis 5165.
Connecting to Student Misconceptions
When students cancel (x - 2) and claim the domain is all reals, remind them that the original denominator still excluded x = 2. Simplified algebra does not erase the excluded input — it reveals a hole.
Similarly, students sometimes plot a vertical asymptote at a hole location. Teach them to factor first: if cancellation occurs, mark a hole; if not, mark an asymptote.
Polynomial Modeling Snapshot
| Degree | Typical Model Shape |
|---|---|
| 1 | Linear trend |
| 2 | Parabola — one turn |
| 3 | S-curve — one inflection |
| Higher | More turning points (up to n - 1 for degree n) |
Praxis modeling items usually stay at degree 2 or 3 with clear vertex or intercept meaning.
What is the maximum value of f(x) = -x² + 4x + 1?
A student says the graph of y = (x² - 4)/(x - 2) is unrelated to y = x + 2 because the rational form is undefined at x = 2. What is the best teacher response?