6.4 Present Worth, Life-Cycle Cost, and Sustainability
Key Takeaways
- Present worth converts future costs, savings, replacements, and salvage values to a common time-zero basis.
- Life-cycle cost (LCC) comparisons must include capital, operation, maintenance, energy, replacement, residual value, and service life.
- Use a real discount rate with constant dollars or a nominal rate with inflated dollars, but never mix the two.
- For mutually exclusive WRE alternatives, the lowest first cost can lose when energy, maintenance, or replacement costs dominate.
- Sustainability analysis should support, not replace, the economic comparison by addressing resource use, resilience, emissions, and public impact.
Put Alternatives on One Time Basis
The April 2024 WRE Project Planning specification includes economic and sustainability analysis: present worth, life-cycle costs, and comparison of alternatives. The exam usually gives the interest rate and cash flows, so the real challenge is building the timeline correctly. Never compare a low-bid pump station to a high-efficiency one on first cost alone when one option burns far more energy for 20 years.
Present worth (PW) converts every cost and benefit to equivalent dollars at time zero. The two factors you will use constantly are:
- Single payment: P = F(P/F, i, n) = F / (1 + i)^n
- Uniform series: P = A(P/A, i, n), where (P/A, i, n) = [(1 + i)^n − 1] / [i(1 + i)^n]
In a cost comparison, costs are positive and salvage or residual value is subtracted because it offsets cost at the end of the study period.
| Cash flow | WRE example | Present-worth treatment |
|---|---|---|
| Initial capital | Basin excavation, pumps, controls | Already at year 0 |
| Annual operation | Pump energy, chemicals, operator labor | Multiply by P/A factor |
| Periodic replacement | Pump overhaul, membrane swap | Multiply by P/F at the replacement year |
| Salvage / residual | Remaining equipment value | Subtract its present value |
| Avoided cost | Reduced flooding or hauling | Treat consistently as a benefit |
| External factor | Emissions, reuse, resilience | Quantify if data given; else discuss qualitatively |
Life-Cycle Cost Workflow
Use a repeatable setup so timing errors do not creep in:
- Confirm the study period (n) and the discount rate (i).
- Draw the cash-flow timeline for each alternative.
- Put all amounts on one dollar basis: constant dollars with a real rate, or inflated dollars with a nominal rate — never mixed.
- Discount each cost to present worth with the correct factor.
- Subtract salvage or residual value at the end of the period.
- Choose the alternative with the lower equivalent cost when service and non-cost requirements are equal.
- State non-economic (sustainability) considerations separately when the question asks for them.
Worked example — two pumps, 20-year period, i = 5%. Alternative A: $600,000 initial, $58,000/yr energy and maintenance, $90,000 overhaul in year 10, $50,000 salvage in year 20. Alternative B: $720,000 initial, $41,000/yr, $70,000 overhaul in year 10, $70,000 salvage in year 20. Factors: (P/A, 5%, 20) = 12.462; (P/F, 5%, 10) = 0.6139; (P/F, 5%, 20) = 0.3769.
- PW(A) = 600,000 + 58,000(12.462) + 90,000(0.6139) − 50,000(0.3769) = $1,359,301.
- PW(B) = 720,000 + 41,000(12.462) + 70,000(0.6139) − 70,000(0.3769) = $1,247,546.
Even though B costs $120,000 more up front, its present worth is about $111,800 lower because reduced energy, maintenance, overhaul, and higher salvage dominate over 20 years. The lowest-first-cost option (A) is the wrong economic choice.
Equivalent Annual Cost and Sustainability Interpretation
When alternatives have unequal service lives, do not compare raw present worths over different periods. Either analyze over a common period (often the least common multiple of the lives) or convert each present worth to an equivalent uniform annual cost (EUAC) using EUAC = PW × (A/P, i, n). Comparing EUAC values is the cleanest way to rank options with mismatched lives, such as a 15-year pump versus a 30-year gravity alternative.
Sustainability is not a slogan in an exam calculation; it becomes decisive only when tied to measurable outcomes:
- Lower annual energy use and greenhouse-gas emissions.
- Fewer chemical deliveries and reduced hauling miles.
- Reduced sanitary sewer overflows (SSOs) and improved permit compliance.
- More reliable drought supply, beneficial reuse, or recharge.
- Smaller disturbed area and better flood resilience.
The decision logic the exam expects: when two alternatives have similar present worth, sustainability criteria may justify the option with lower life-cycle emissions or better service continuity. But if an alternative fails a permit limit, a level-of-service target, or a public-safety requirement, a lower present worth does not make it acceptable — economics never override a hard constraint. A frequent trap is forgetting to subtract salvage, discounting a periodic overhaul with a P/A factor instead of P/F, or mixing a real discount rate with inflated future dollars.
Confirm the dollar basis and the timing of every cash flow before you compute the factor.
Factor Selection, Benefit-Cost, and Real vs. Nominal Rates
Pick the time-value factor by matching it to the cash-flow shape — this single habit prevents most economics errors:
| Cash flow shape | Factor | Use |
|---|---|---|
| One future amount → present | (P/F, i, n) | Overhaul, replacement, salvage |
| Uniform annual → present | (P/A, i, n) | Energy, O&M, chemicals |
| Present → uniform annual | (A/P, i, n) | Convert capital to EUAC; capital recovery |
| Uniform annual → future | (F/A, i, n) | Sinking-fund accumulation |
| Growing annual amount | gradient (P/G) or geometric | Escalating O&M |
The real vs. nominal rule is non-negotiable: a real (constant-dollar) discount rate pairs only with constant dollars, and a nominal rate pairs only with inflated (current) dollars. The relationship is (1 + nominal) = (1 + real)(1 + inflation), so with 5% real and 3% inflation the nominal rate is about 8.15%. Mixing the two systematically biases long-horizon WRE comparisons.
For publicly funded projects, the exam may ask for a benefit-cost ratio (BCR) = present worth of benefits ÷ present worth of costs. A BCR ≥ 1.0 indicates an economically justified project; for flood-control or water-supply alternatives, incremental B/C analysis ranks mutually exclusive options. Worked logic: if a $2.0M levee yields $2.6M present-worth flood-damage reduction, BCR = 1.30 and the project is justified; a competing $3.0M alternative adding only $0.5M more benefit fails the incremental test (ΔB/ΔC = 0.5/1.0 = 0.5 < 1.0) and is rejected even though its total BCR may still exceed 1.0.
Always anchor the analysis to the stated study period and discount rate, hold service level equal, and present sustainability findings as a separate, supporting layer rather than a substitute for the economic ranking.
A pump alternative has a $90,000 overhaul in year 10. At a 5 percent discount rate the single-payment present-worth factor (P/F, 5%, 10) is 0.6139. What present cost should be included for the overhaul?
Two stormwater retrofit alternatives meet the same hydraulic performance. Alternative X has lower first cost but higher annual maintenance for 25 years; Alternative Y has higher first cost and lower annual maintenance. What is the best economic comparison method?