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6.1 Psychrometric Principles & Air-Conditioning Processes

Key Takeaways

  • Moist air obeys Dalton's law of partial pressures (p=pa+pwp = p_a + p_w), where the humidity ratio ω=0.622pwp−pw\omega = 0.622 \frac{p_w}{p - p_w} quantifies moisture mass per unit mass of dry air.

  • Sensible heating and cooling occur at a constant humidity ratio (Δω=0\Delta \omega = 0), governed by the standard air heat rate formula q˙s=1.08×CFM×ΔT\dot{q}_s = 1.08 \times CFM \times \Delta T in US Customary units (1.23×V˙L/s×ΔT1.23 \times \dot{V}_{L/s} \times \Delta T in SI units).

  • Cooling with dehumidification occurs when coil surface temperatures fall below the entering air dew point, characterized by the Apparatus Dew Point (ADP) and coil Bypass Factor (BFBF).

  • The total heat transfer rate across any psychrometric process is proportional to the enthalpy difference: q˙t=4.5×CFM×Δh\dot{q}_t = 4.5 \times CFM \times \Delta h in US Customary units (1.20×V˙L/s×Δh1.20 \times \dot{V}_{L/s} \times \Delta h in SI units), with the Sensible Heat Ratio defined as SHR=q˙s/q˙tSHR = \dot{q}_s / \dot{q}_t.

  • Adiabatic mixing of two moist air streams follows conservation of dry air mass and enthalpy, forming a mixed state point that lies on the straight line connecting the entering states according to the lever rule: Tdb,3−Tdb,1Tdb,2−Tdb,3=m˙da,2m˙da,1\frac{T_{db,3} - T_{db,1}}{T_{db,2} - T_{db,3}} = \frac{\dot{m}_{da,2}}{\dot{m}_{da,1}}.

Last updated: August 2026

Psychrometric Principles & Air-Conditioning Processes

Psychrometrics is the branch of thermodynamics dedicated to atmospheric air combined with water vapor. It serves as the foundational core for heating, ventilating, air-conditioning, and refrigeration (HVAC&R) system design. On the NCEES PE Mechanical exam, psychrometric analysis is essential for evaluating air handling unit (AHU) performance, sizing direct expansion (DX) and chilled water cooling coils, determining required supply airflow rates, and analyzing mixing plenums and evaporative coolers.


1. Thermodynamic Properties of Moist Air & Dalton's Law

Atmospheric moist air is treated as a binary mixture of dry air (a pseudo-pure gas with apparent molecular weight Ma=28.966 lbm/lbmol=28.966 kg/kmolM_a = 28.966\text{ lbm/lbmol} = 28.966\text{ kg/kmol}) and water vapor (Mw=18.015 lbm/lbmol=18.015 kg/kmolM_w = 18.015\text{ lbm/lbmol} = 18.015\text{ kg/kmol}). Under typical HVAC operating ranges (temperatures from −40∘F-40^\circ\text{F} to 140∘F140^\circ\text{F} and pressures near atmospheric), both dry air and water vapor behave in close accordance with the ideal gas law (pV=mRTp V = m R T).

+-----------------------------------------------------------------------------------------+
|                        MOIST AIR CONSTITUENTS & DALTON'S LAW                            |
|                                                                                         |
|   Total Barometric Pressure:   p = p_a + p_w                                            |
|                                                                                         |
|   - Dry Air Partial Pressure:   p_a = \frac{m_a R_a T}{V}                                |
|   - Water Vapor Partial Press:  p_w = \frac{m_w R_w T}{V}                                |
|   - Standard Atmospheric Press: p = 14.696 psia = 29.921 in. Hg = 101.325 kPa            |
+-----------------------------------------------------------------------------------------+

Primary Psychrometric Variables

  1. Dry-Bulb Temperature (TdbT_{db} or TT): The true thermodynamic temperature of the moist air mixture measured by an ordinary, unshielded thermometer unaffected by radiation or moisture.
  2. Wet-Bulb Temperature (TwbT_{wb} or T∗T^*): The equilibrium temperature registered by an accurate thermometer whose sensor is covered by a wetted wick and exposed to rapid airflow (>900 FPM> 900\text{ FPM}). At saturation (100% relative humidity), dry-bulb, wet-bulb, and dew-point temperatures are all identical: Tdb=Twb=TdpT_{db} = T_{wb} = T_{dp}.
  3. Dew-Point Temperature (TdpT_{dp}): The temperature at which water vapor in moist air begins to condense when the mixture is cooled at constant moisture content (ω=const\omega = \text{const}) and constant total pressure (p=constp = \text{const}). TdpT_{dp} is strictly a function of the water vapor partial pressure pwp_w, satisfying pw=pws(Tdp)p_w = p_{ws}(T_{dp}), where pwsp_{ws} is the saturation pressure of water.
  4. Relative Humidity (ϕ\phi): The ratio of the actual water vapor partial pressure pwp_w to the saturation pressure pwsp_{ws} at the same dry-bulb temperature: ϕ=(pwpws)Tdb×100\phi = \left(\frac{p_w}{p_{ws}}\right)_{T_{db}} \times 100
  5. Humidity Ratio / Specific Humidity (ω\omega or WW): The ratio of the mass of water vapor (mwm_w) to the mass of dry air (mdam_{da}): ω=mwmda=MwpwMapa=18.01528.966(pwp−pw)=0.622pwp−pw[lbmwlbmda or kgwkgda]\omega = \frac{m_w}{m_{da}} = \frac{M_w p_w}{M_a p_a} = \frac{18.015}{28.966} \left(\frac{p_w}{p - p_w}\right) = 0.622 \frac{p_w}{p - p_w} \quad \left[\frac{\text{lbm}_w}{\text{lbm}_{da}} \text{ or } \frac{\text{kg}_w}{\text{kg}_{da}}\right] In US Customary units, moisture content is frequently expressed in grains of moisture per pound of dry air (1 lbm=7,000 grains1\text{ lbm} = 7,000\text{ grains}): Wgr=7,000×ω[grainswlbmda]W_{gr} = 7,000 \times \omega \quad \left[\frac{\text{grains}_w}{\text{lbm}_{da}}\right]
  6. Specific Volume (vv): The total volume of the moist air mixture per unit mass of dry air: v=Vmda=RaTpa=RaTp−pw=RaT(1+1.608ω)p[ft3lbmda or m3kgda]v = \frac{V}{m_{da}} = \frac{R_a T}{p_a} = \frac{R_a T}{p - p_w} = \frac{R_a T (1 + 1.608\omega)}{p} \quad \left[\frac{\text{ft}^3}{\text{lbm}_{da}} \text{ or } \frac{\text{m}^3}{\text{kg}_{da}}\right] Where Ra=53.35 ft⋅lbf/(lbm⋅∘R)=0.2870 kJ/(kg⋅K)R_a = 53.35\text{ ft}\cdot\text{lbf}/(\text{lbm}\cdot^\circ\text{R}) = 0.2870\text{ kJ}/(\text{kg}\cdot\text{K}) and TT is absolute temperature (∘R^\circ\text{R} or K\text{K}).
  7. Specific Enthalpy (hh): The total thermal energy of the moist air mixture per unit mass of dry air, using 0∘F0^\circ\text{F} (or 0∘C0^\circ\text{C}) dry air and 32∘F32^\circ\text{F} liquid water as reference states:
    • US Customary Units: h=cpaTdb+ωhg≈0.240Tdb+ω(1061+0.444Tdb)[BTUlbmda]h = c_{pa} T_{db} + \omega h_g \approx 0.240 T_{db} + \omega (1061 + 0.444 T_{db}) \quad \left[\frac{\text{BTU}}{\text{lbm}_{da}}\right]
    • SI Units: h=cpaTdb+ωhg≈1.006Tdb+ω(2501+1.86Tdb)[kJkgda]h = c_{pa} T_{db} + \omega h_g \approx 1.006 T_{db} + \omega (2501 + 1.86 T_{db}) \quad \left[\frac{\text{kJ}}{\text{kg}_{da}}\right]

2. Navigating the Standard Psychrometric Chart

The standard sea-level psychrometric chart (p=14.696 psia=101.325 kPap = 14.696\text{ psia} = 101.325\text{ kPa}) plots thermodynamic properties on a 2D coordinate system.

+-----------------------------------------------------------------------------------------+
|                        PSYCHROMETRIC CHART GEOMETRY & AXES                              |
|                                                                                         |
|   Humidity Ratio (\omega) / Enthalpy (h)                                                  |
|   ^                                                                                     |
|   |                                                      / Constant Volume (v)          |
|   |                                        Saturation   /                               |
|   |                                        Curve       /                                |
|   |                                        (\phi=100%)/    Constant Wet-Bulb (T_wb)     |
|   |                                          ,-''''' /    /  & Specific Enthalpy (h)    |
|   |                                      _,-'       /   ,'                              |
|   |                                  _,-'          /  ,'                                |
|   |                              _,-'             / ,'                                  |
|   |                          _,-'                /,'    --- Constant Relative           |
|   |                      _,-'                   /'          Humidity (\phi = 50%)       |
|   |                  _,-'                      /                                        |
|   |              _,-'                         /                                         |
|   |          _,-'                            /                                          |
|   |      _,-'                               /                                           |
|   +----+-----------------------------------+-------------------------------------->     |
|       Dew Point (T_dp)                    Dry-Bulb Temperature (T_db)                   |
+-----------------------------------------------------------------------------------------+
PropertyChart Orientation & Geometry
Dry-Bulb Temperature (TdbT_{db})Vertical lines originating along the horizontal baseline axis
Humidity Ratio (ω\omega / WW)Horizontal lines reading onto the right-hand vertical axis
Saturation Curve (ϕ=100%\phi = 100\%)Boundary curve along the upper-left envelope of the chart
Relative Humidity (ϕ\phi)Non-linear curved lines paralleling the outer saturation curve
Wet-Bulb Temperature (TwbT_{wb})Moderately steep diagonal lines extending downward to the right
Specific Enthalpy (hh)Diagonal lines nearly parallel to lines of constant wet-bulb temperature
Specific Volume (vv)Steeply pitched straight diagonal lines

Important

Altitude and Barometric Corrections: Standard psychrometric charts are valid only at sea level (14.696 psia=101.325 kPa14.696\text{ psia} = 101.325\text{ kPa}). At higher elevations (e.g., Denver at 5,000 ft5,000\text{ ft}, p≈12.23 psiap \approx 12.23\text{ psia}), atmospheric pressure decreases, causing the humidity ratio ω=0.622pwp−pw\omega = 0.622 \frac{p_w}{p - p_w} and specific volume vv to increase for the same dry-bulb temperature and dew point. Always use an elevation-corrected chart or Dalton's law formulas when solving non-sea-level problems.


3. Core Psychrometric Air-Conditioning Processes

Every HVAC cycle decomposes into basic linear or multi-step psychrometric transformations on the chart.

+-----------------------------------------------------------------------------------------+
|                        SUMMARY OF CORE PSYCHROMETRIC PROCESSES                          |
|                                                                                         |
|                      [2] Humidification Only (\Delta T_db = 0, \omega \uparrow)           |
|                                     ^                                                   |
|   [6] Evaporative Cooling           |             [1] Sensible Heating                  |
|       (Adiabatic Saturation)        |                 (\omega = const, T_db \uparrow)   |
|         \                           |            /                                      |
|          \                          |           /                                       |
|           \                         |          /                                        |
|            <---------------------- [0] ---------------------->                          |
|           /                     State Point    \                                        |
|          /                          |           \                                       |
|         /                           |            \                                      |
|   [4] Cooling & Dehumidification    |             [5] Chemical Dehumidification         |
|       (T_db \downarrow, \omega \downarrow)   v                 (T_db \uparrow, \omega \downarrow)  |
|                      [3] Dehumidification Only (\Delta T_db = 0, \omega \downarrow)       |
+-----------------------------------------------------------------------------------------+

1. Sensible Heating and Cooling

Sensible processes occur when moist air passes over a heating or cooling coil whose surface temperature remains above the dew-point temperature of the entering air (Tsurface>TdpT_{\text{surface}} > T_{dp}). Moisture is neither added nor removed (Δω=0\Delta \omega = 0).

q˙s=m˙dacpaΔT=(ρ⋅CFM⋅60)cpaΔT\dot{q}_s = \dot{m}_{da} c_{pa} \Delta T = (\rho \cdot CFM \cdot 60) c_{pa} \Delta T

Applying standard sea-level air properties (ρ=0.075 lbm/ft3\rho = 0.075\text{ lbm/ft}^3, cpa=0.240 BTU/lbm⋅∘Fc_{pa} = 0.240\text{ BTU/lbm}\cdot^\circ\text{F}):

q˙s=(0.075)(60)(0.240)×CFM×ΔT=1.08×CFM×ΔT[BTU/hr]\dot{q}_s = (0.075)(60)(0.240) \times CFM \times \Delta T = 1.08 \times CFM \times \Delta T \quad [\text{BTU/hr}]

In SI units (ρ=1.204 kg/m3\rho = 1.204\text{ kg/m}^3, cpa=1.006 kJ/kg⋅Kc_{pa} = 1.006\text{ kJ/kg}\cdot\text{K}):

q˙s=(1.204)(1.006)×V˙L/s×ΔT=1.23×V˙L/s×ΔT[W]\dot{q}_s = (1.204)(1.006) \times \dot{V}_{L/s} \times \Delta T = 1.23 \times \dot{V}_{L/s} \times \Delta T \quad [\text{W}]

2. Cooling and Dehumidification

When air passes over a cooling coil whose effective surface temperature is below the entering air dew point (Tcoil<TdpT_{\text{coil}} < T_{dp}), moisture condenses out of the air stream. The process line on the psychrometric chart curves downward and leftward toward the Apparatus Dew Point (ADP), which represents the effective coil surface temperature on the saturation curve (ϕ=100%\phi = 100\%).

+-----------------------------------------------------------------------------------------+
|                        COIL BYPASS FACTOR & APPARATUS DEW POINT                         |
|                                                                                         |
|   Saturation Curve                                                                      |
|          ,-'                                                                            |
|        ,'                                                                               |
|      ,'   [ADP] (T_adp, \omega_adp)                                                     |
|     /       \                                                                           |
|    /         \______ [Leaving Air Point: 2] (T_db,2, \omega_2)                          |
|   /                 \                                                                   |
|  /                   \______ [Entering Air Point: 1] (T_db,1, \omega_1)                 |
| /                                                                                       |
+-----------------------------------------------------------------------------------------+
  • Bypass Factor (BFBF): The fraction of total airflow that passes through the cooling coil completely unconditioned: BF=Tdb,2−TADPTdb,1−TADP=ω2−ωADPω1−ωADP=h2−hADPh1−hADPBF = \frac{T_{db,2} - T_{ADP}}{T_{db,1} - T_{ADP}} = \frac{\omega_2 - \omega_{ADP}}{\omega_1 - \omega_{ADP}} = \frac{h_2 - h_{ADP}}{h_1 - h_{ADP}}
  • Contact Factor (CFCF): The fraction of total air that comes into direct contact with the coil surface and achieves thermal equilibrium at the ADP: CF=1−BFCF = 1 - BF

3. Latent Heat and Total Heat Equations

  • Latent Heat Transfer Rate (Moisture Addition or Removal): q˙L=m˙dahfgΔω=(0.075)(60)(1076)×CFM×Δω=4840×CFM×Δω[BTU/hr]\dot{q}_L = \dot{m}_{da} h_{fg} \Delta \omega = (0.075)(60)(1076) \times CFM \times \Delta \omega = 4840 \times CFM \times \Delta \omega \quad [\text{BTU/hr}] When moisture is given in grains per pound of dry air (WgrW_{gr}): q˙L=48407000×CFM×ΔWgr≈0.69×CFM×ΔWgr[BTU/hr]\dot{q}_L = \frac{4840}{7000} \times CFM \times \Delta W_{gr} \approx 0.69 \times CFM \times \Delta W_{gr} \quad [\text{BTU/hr}]
  • Total Heat Transfer Rate (Enthalpy Method): q˙t=q˙s+q˙L=m˙daΔh=(0.075)(60)×CFM×Δh=4.5×CFM×Δh[BTU/hr]\dot{q}_t = \dot{q}_s + \dot{q}_L = \dot{m}_{da} \Delta h = (0.075)(60) \times CFM \times \Delta h = 4.5 \times CFM \times \Delta h \quad [\text{BTU/hr}] In SI units: q˙t=1.20×V˙L/s×Δh[W]\dot{q}_t = 1.20 \times \dot{V}_{L/s} \times \Delta h \quad [\text{W}]

4. Sensible Heat Ratio (SHR)

The ratio of sensible heat removal rate to total heat removal rate:

SHR=q˙sq˙t=q˙sq˙s+q˙LSHR = \frac{\dot{q}_s}{\dot{q}_t} = \frac{\dot{q}_s}{\dot{q}_s + \dot{q}_L}
  • Room Sensible Heat Ratio (RSHR): q˙s,roomq˙t,room\frac{\dot{q}_{s,\text{room}}}{\dot{q}_{t,\text{room}}}, defining the slope of the condition line between the supply air state and the room design state.
  • Grand Sensible Heat Ratio (GSHR): q˙s,totalq˙t,total\frac{\dot{q}_{s,\text{total}}}{\dot{q}_{t,\text{total}}}, defining the slope of the process line across the central cooling coil.

4. Adiabatic Mixing of Two Air Streams

In standard air handling systems, outdoor ventilation air (Stream 1) mixes adiabatically with recirculated return air (Stream 2) to produce mixed air (Stream 3) entering the conditioning coils.

+-----------------------------------------------------------------------------------------+
|                        ADIABATIC AIR STREAM MIXING SCHEMATIC                            |
|                                                                                         |
|   Outdoor Air (Stream 1)   ---> [  MIXING  ] ---> Mixed Air (Stream 3)                  |
|   (m_1, T_1, \omega_1, h_1)      [ PLENUM  ]      (m_3 = m_1 + m_2, T_3, \omega_3, h_3) |
|   Return Air (Stream 2)    ---> [          ]                                            |
|   (m_2, T_2, \omega_2, h_2)                                                             |
+-----------------------------------------------------------------------------------------+

Conservation Governing Equations:

  1. Dry Air Mass Balance: m˙da,3=m˙da,1+m˙da,2\dot{m}_{da,3} = \dot{m}_{da,1} + \dot{m}_{da,2}
  2. Energy Balance: m˙da,1h1+m˙da,2h2=m˙da,3h3  ⟹  h3=m˙da,1h1+m˙da,2h2m˙da,1+m˙da,2\dot{m}_{da,1} h_1 + \dot{m}_{da,2} h_2 = \dot{m}_{da,3} h_3 \implies h_3 = \frac{\dot{m}_{da,1} h_1 + \dot{m}_{da,2} h_2}{\dot{m}_{da,1} + \dot{m}_{da,2}}
  3. Moisture Balance: m˙da,1ω1+m˙da,2ω2=m˙da,3ω3  ⟹  ω3=m˙da,1ω1+m˙da,2ω2m˙da,1+m˙da,2\dot{m}_{da,1} \omega_1 + \dot{m}_{da,2} \omega_2 = \dot{m}_{da,3} \omega_3 \implies \omega_3 = \frac{\dot{m}_{da,1} \omega_1 + \dot{m}_{da,2} \omega_2}{\dot{m}_{da,1} + \dot{m}_{da,2}}
  4. Dry-Bulb Temperature Approximation (Volumetric Basis): Tdb,3≈CFM1Tdb,1+CFM2Tdb,2CFM1+CFM2T_{db,3} \approx \frac{CFM_1 T_{db,1} + CFM_2 T_{db,2}}{CFM_1 + CFM_2}

The Psychrometric Lever Rule

The mixed state point (Point 3) lies on the straight line connecting Point 1 and Point 2 on the psychrometric chart. The line segment lengths are inversely proportional to the mass flow rates:

Distance (1−3)Distance (1−2)=m˙da,2m˙da,1+m˙da,2=CFM2CFM3\frac{\text{Distance }(1-3)}{\text{Distance }(1-2)} = \frac{\dot{m}_{da,2}}{\dot{m}_{da,1} + \dot{m}_{da,2}} = \frac{CFM_2}{CFM_3} Tdb,3−Tdb,1Tdb,2−Tdb,3=m˙da,2m˙da,1\frac{T_{db,3} - T_{db,1}}{T_{db,2} - T_{db,3}} = \frac{\dot{m}_{da,2}}{\dot{m}_{da,1}}

5. Evaporative Cooling (Adiabatic Saturation)

In direct evaporative cooling (swamp coolers), unsaturated air passes through a wetted porous medium without external heat transfer (q˙=0\dot{q} = 0).

  • The sensible heat of the air stream provides the latent heat required to vaporize the liquid water.
  • Thermodynamic Path: The process moves upward and leftward along a constant wet-bulb temperature / constant enthalpy line (Twb=constT_{wb} = \text{const}, h≈consth \approx \text{const}).
  • Outcome: Dry-bulb temperature decreases (Tdb↓T_{db} \downarrow), while humidity ratio increases (ω↑\omega \uparrow) and relative humidity increases (ϕ↑\phi \uparrow).
  • Direct Evaporative Saturation Effectiveness (ϵevap\epsilon_{\text{evap}}): ϵevap=Tdb,in−Tdb,outTdb,in−Twb,in\epsilon_{\text{evap}} = \frac{T_{db,\text{in}} - T_{db,\text{out}}}{T_{db,\text{in}} - T_{wb,\text{in}}}
  • Indirect Evaporative Cooling: Primary air passes through dry channels of a heat exchanger while secondary air is cooled evaporatively in adjacent wet channels, providing sensible cooling at constant moisture content (ω=const\omega = \text{const}) without adding humidity to the supply air.

6. Step-by-Step Worked Engineering Problem

Problem Statement

An air handling unit (AHU) serves a commercial office zone. The space design condition is 75.0∘F Tdb75.0^\circ\text{F } T_{db} and 50% RH50\%\text{ RH} (hroom=28.10 BTU/lbmda,ωroom=0.00925 lbm/lbmdah_{\text{room}} = 28.10\text{ BTU/lbm}_{da}, \omega_{\text{room}} = 0.00925\text{ lbm/lbm}_{da}). The total supply airflow rate is 12,000 CFM12,000\text{ CFM}.

  • Outdoor Air (OA): 3,000 CFM3,000\text{ CFM} at 95.0∘F Tdb95.0^\circ\text{F } T_{db} and 76.0∘F Twb76.0^\circ\text{F } T_{wb} (hOA=39.40 BTU/lbmda,ωOA=0.01480 lbm/lbmdah_{\text{OA}} = 39.40\text{ BTU/lbm}_{da}, \omega_{\text{OA}} = 0.01480\text{ lbm/lbm}_{da}).
  • Return Air (RA): 9,000 CFM9,000\text{ CFM} at room conditions (75.0∘F Tdb,50% RH75.0^\circ\text{F } T_{db}, 50\%\text{ RH}).
  • The mixed air enters a chilled water cooling coil with an Apparatus Dew Point (ADP) of 52.0∘F52.0^\circ\text{F} (hADP=21.40 BTU/lbmda,ωADP=0.00820 lbm/lbmdah_{\text{ADP}} = 21.40\text{ BTU/lbm}_{da}, \omega_{\text{ADP}} = 0.00820\text{ lbm/lbm}_{da}) and a Bypass Factor (BFBF) of 0.120.12.

Calculate:

  1. The mixed air dry-bulb temperature (Tdb,mT_{db,m}), enthalpy (hmh_m), and humidity ratio (ωm\omega_m).
  2. The leaving air dry-bulb temperature (Tdb,LT_{db,L}) and enthalpy (hLh_L).
  3. The total cooling coil capacity required in Tons of Refrigeration (TR).
  4. The coil Sensible Heat Ratio (SHR).
+-----------------------------------------------------------------------------------------+
|                          AHU COIL CALCULATION SCHEMATIC                                 |
|                                                                                         |
|   OA: 3,000 CFM, 95°F ----> [ MIXING ]                                                  |
|                             [ PLENUM ] ---> MIXED AIR ---> [ COOLING COIL ] ---> SUPPLY |
|   RA: 9,000 CFM, 75°F ----> [        ]     (T_m, h_m)      [ ADP = 52°F   ]     (T_L, h_L)|
|                                                            [ BF = 0.12    ]             |
+-----------------------------------------------------------------------------------------+

Step 1: Mixed Air Properties

Fraction of Outdoor Air: xOA=3,00012,000=0.25x_{OA} = \frac{3,000}{12,000} = 0.25, Fraction of Return Air: xRA=9,00012,000=0.75x_{RA} = \frac{9,000}{12,000} = 0.75.

Tdb,m=xOATdb,OA+xRATdb,RA=(0.25)(95.0∘F)+(0.75)(75.0∘F)=23.75+56.25=80.0∘FT_{db,m} = x_{OA} T_{db,OA} + x_{RA} T_{db,RA} = (0.25)(95.0^\circ\text{F}) + (0.75)(75.0^\circ\text{F}) = 23.75 + 56.25 = 80.0^\circ\text{F} hm=xOAhOA+xRAhRA=(0.25)(39.40)+(0.75)(28.10)=9.85+21.075=30.925 BTU/lbmdah_m = x_{OA} h_{OA} + x_{RA} h_{RA} = (0.25)(39.40) + (0.75)(28.10) = 9.85 + 21.075 = 30.925\text{ BTU/lbm}_{da} ωm=(0.25)(0.01480)+(0.75)(0.00925)=0.00370+0.0069375=0.010638 lbm/lbmda\omega_m = (0.25)(0.01480) + (0.75)(0.00925) = 0.00370 + 0.0069375 = 0.010638\text{ lbm/lbm}_{da}

Step 2: Leaving Air Conditions from Coil Bypass Factor

Tdb,L=TADP+BF(Tdb,m−TADP)=52.0∘F+0.12(80.0∘F−52.0∘F)=52.0+0.12(28.0)=55.36∘FT_{db,L} = T_{ADP} + BF(T_{db,m} - T_{ADP}) = 52.0^\circ\text{F} + 0.12(80.0^\circ\text{F} - 52.0^\circ\text{F}) = 52.0 + 0.12(28.0) = 55.36^\circ\text{F} hL=hADP+BF(hm−hADP)=21.40+0.12(30.925−21.40)=21.40+0.12(9.525)=22.543 BTU/lbmdah_L = h_{ADP} + BF(h_m - h_{ADP}) = 21.40 + 0.12(30.925 - 21.40) = 21.40 + 0.12(9.525) = 22.543\text{ BTU/lbm}_{da} ωL=ωADP+BF(ωm−ωADP)=0.00820+0.12(0.010638−0.00820)=0.008493 lbm/lbmda\omega_L = \omega_{ADP} + BF(\omega_m - \omega_{ADP}) = 0.00820 + 0.12(0.010638 - 0.00820) = 0.008493\text{ lbm/lbm}_{da}

Step 3: Total Cooling Coil Capacity

q˙t=4.5×CFM×(hm−hL)=4.5×12,000×(30.925−22.543)=54,000×8.382=452,628 BTU/hr\dot{q}_t = 4.5 \times CFM \times (h_m - h_L) = 4.5 \times 12,000 \times (30.925 - 22.543) = 54,000 \times 8.382 = 452,628\text{ BTU/hr} Cooling Capacity in TR=452,628 BTU/hr12,000 BTU/hr⋅TR=37.72 TR\text{Cooling Capacity in TR} = \frac{452,628\text{ BTU/hr}}{12,000\text{ BTU/hr}\cdot\text{TR}} = 37.72\text{ TR}

Step 4: Sensible Coil Capacity & SHR

q˙s=1.08×CFM×(Tdb,m−Tdb,L)=1.08×12,000×(80.0−55.36)=12,960×24.64=319,334 BTU/hr\dot{q}_s = 1.08 \times CFM \times (T_{db,m} - T_{db,L}) = 1.08 \times 12,000 \times (80.0 - 55.36) = 12,960 \times 24.64 = 319,334\text{ BTU/hr} SHR=q˙sq˙t=319,334452,628=0.7055≈0.71SHR = \frac{\dot{q}_s}{\dot{q}_t} = \frac{319,334}{452,628} = 0.7055 \approx 0.71

7. Common Exam Traps & PE Pro-Tips

  • Trap 1 — Using Standard Air Multipliers at High Elevation: The constants 1.081.08, 48404840, and 4.54.5 are valid only at standard sea-level air density (ρ=0.075 lbm/ft3\rho = 0.075\text{ lbm/ft}^3, p=14.696 psiap = 14.696\text{ psia}). At non-standard altitudes, you must calculate mass flow directly using m˙=ρV˙=pV˙RaT\dot{m} = \rho \dot{V} = \frac{p \dot{V}}{R_a T} and apply q˙s=m˙cpΔT\dot{q}_s = \dot{m} c_p \Delta T and q˙t=m˙Δh\dot{q}_t = \dot{m} \Delta h.
  • Trap 2 — Misinterpreting Apparatus Dew Point Location: The Apparatus Dew Point (ADP) is always located on the saturation curve (ϕ=100%\phi = 100\%). It represents the effective coil surface temperature if the coil had a bypass factor of zero (BF=0BF = 0). Leaving air dry-bulb is always higher than the ADP whenever BF>0BF > 0.
  • Trap 3 — Mixing Moisture Units: When computing latent heat with humidity ratio ω\omega in lbmw/lbmda\text{lbm}_w/\text{lbm}_{da}, use the 48404840 constant. When using moisture in grains per pound (WgrW_{gr}), use the 0.690.69 constant (4840/7000=0.6914840 / 7000 = 0.691).
Test Your Knowledge

At standard atmospheric pressure (14.696 psia), moist air has a dry-bulb temperature of 82°F and a water vapor partial pressure of 0.285 psia. What is the humidity ratio of this air mixture?

A

0.01230 lbm_w / lbm_da

B

0.01939 lbm_w / lbm_da

C

0.00765 lbm_w / lbm_da

D

0.01540 lbm_w / lbm_da

Test Your Knowledge

An air stream of 5,000 CFM at 92°F dry-bulb and 40% RH mixes adiabatically with 10,000 CFM of return air at 74°F dry-bulb and 50% RH. Assuming standard atmospheric pressure, what is the resulting mixed air dry-bulb temperature?

A

83.0°F

B

80.0°F

C

78.0°F

D

86.0°F

Test Your Knowledge

A cooling coil receives 10,000 CFM of moist air at an entering enthalpy of 35.0 BTU/lbm_da and discharges the air at a leaving enthalpy of 25.0 BTU/lbm_da. If the sensible cooling heat removal rate is 315,000 BTU/hr, what is the coil Sensible Heat Ratio (SHR)?

A

0.85

B

0.70

C

0.58

D

0.30

Test Your Knowledge

In a direct evaporative cooler operating with an adiabatic saturation process, what happens to the specific enthalpy and relative humidity of the air as it passes through the wetted media?

A

Specific enthalpy increases while relative humidity decreases

B

Specific enthalpy decreases while relative humidity increases

C

Both specific enthalpy and relative humidity remain constant

D

Specific enthalpy remains approximately constant while relative humidity increases

Sections you finish are checked off in the contents.